CO2 level increases whereas pH of body fluids decreases.
1. Human respiration includes inhalation of oxygen and exhalation of carbon dioxide.
2. When you hold your breath, the amount of carbon dioxide in the body increases as during this process we don't inhale as well as exhale, so the amount of oxygen decreases and the opposite will happens to the level of carbon dioxide thus making the body fluids acidic, as the number of free hydrogen ions increases as body fluids becomes more acidic so the pH of the body fluids decreases because acidity lowers pH value.
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part a: identification of a hydrocarbon write out a balanced chemical reaction for 1-hexene with br2 using structural formulae for reactants and products g
The chemical reaction and its components are as follows -
Firstly writing the balanced chemical reaction for 1-hexene and bromine gas -
1-hexene -- [tex] Br_{2}[/tex]/[tex] CH_{3}[/tex]OH--> 1,2-dibromohexane + 1-bromo-2-methoxyhexane
The structural formula of each compound is -
1-hexene: [tex] C_{6}[/tex][tex] H_{12}[/tex]
1,2-dibromohexane: [tex] C_{6}[/tex][tex] H_{12}[/tex][tex] Br_{2}[/tex]
1-bromo-2-methoxyhexane: [tex] C_{7}[/tex][tex] H_{15}[/tex]BrO
Containing alkene group, 1-hexene finds application in Linear Low Density Polyethylene. The products are used in research processes. Reaction involves incorporation of bromine atoms and methyl alcohol group on the hexene.
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A fresh sample 1311 was left out on the benchtop for 40 days. The scientist forgot it has a half-life of 8 days. The original sample mass
was 64 g. How much of the parent isotope is left?
g
Answer:
2 g of the parent isotope is left.
Explanation:
The half-life of a radioactive isotope is the amount of time it takes for half of the isotope to decay. In this case, the half-life of the isotope is 8 days, which means that after 8 days, half of the isotope will have decayed.
To determine how much of the parent isotope is left after 40 days, we need to calculate how many half-lives have passed in that time. Since the half-life is 8 days, and 40 days have passed, we can divide 40 by 8 to find the number of half-lives that have occurred: 40 / 8 = 5
Since 5 half-lives have passed, we can calculate the amount of the parent isotope that is left by multiplying the original amount of the isotope by 1/2 to the power of the number of half-lives that have passed: 64 * (1/2)^5 = 64 * (1/32) = 2 g
Therefore, after 40 days, only 2 g of the parent isotope is left.
An organism with the genotype of AaXx can produce gametes containing _________ if the two genes are unlinked.
a. either Aa or Xx
b. either AX, Ax, aX, ax
c. AaXx
d. AX or ax
e. None of the above.
An organism with the genotype of AaXx can produce gametes containing either AX, Ax, aX, ax if the two genes are unlinked .
An organism's genotype is the complete set of its genetic material. [1] Genotype can also be used to refer to the alleles or variants that an individual has at a particular gene or locus. The number of alleles an individual can have for a particular gene depends on the number of copies of each chromosome (also called polyploidy) found in that species. Diploid species like humans have two complete sets of chromosomes. This means that each individual has her two alleles for a particular gene. If both alleles are the same, the genotype is said to be homozygous. If the alleles are different, the genotype is called heterozygous.
Genotypes contribute to the phenotype, observable traits and characteristics of an individual or organism. The extent to which genotype influences phenotype depends on the trait.
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the first 32 amino acids from the N terminus of the protein bovine angiogenin were determined by edman degradation and have the sequence: AQDDYRYIHFLTQHYDAKPKGRNDEYCFNMMK (a) Identify the sites of cleavage during trypsin-catalyzed hydrolysis of this protein. (b) What are the cleavage sites using chymotrypsin?
The first 32 amino acids from the N terminus of the protein bovine angiogenin were determined by edman degradation. (a) The cleavage sites for the trypsin-catalyzed hydrolysis are, AQDDYRYIHFLTQHYDAKPKGRNDEYCFNMMK.
(b) The following cleavage sites take place during hydrolysis that is catalyzed by chymotrypsin: AQDDYRYIHFLTQHYCFNMMK. Site-selective breakdown of extremely non-reactive peptide bonds also functions as a therapeutically helpful modulator of protein structure and function, providing essential information on the protein sequence. Regulated and selective cleavage is a challenging task and requires chemical reagents to be able to recognize or bind to one or more specific amino acid residues in the peptide chain. On the basis of this concept, we developed a technique that selectively changes the serine residue in a peptide chain using a chemical reagent, causing the peptide backbone to break at the N-terminus of the serine residue. After cleavage, modified residues can be transformed back into their original form. This method may cleave a wide variety of substrates and does so specifically for certain bioactive peptides with post-translational modifications (like N-acetylation and -methylation) and mutations (like D- and -amino acids), which are known to contribute to age-related diseases.
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when circuit town electronics sets its televisions at three price levels of $699, $899, and $1,099, it is most likely using .
When circuit town electronics sets its televisions at three price levels of $699, $899, and $1,099, it is most likely using product line pricing.
Product line pricing involves the separation of goods and services into cost categories in order to create various perceived quality levels in the minds of consumers. You might also hear product line pricing referred to as price lining, but they refer to the same practice.Selling a product at or below cost to lure customers in and drive other sales is an example of product-line pricing. A restaurant, for example, might offer a low-priced entrée with the purchase of a drink and dessert that have higher profit margins.A product line refers to a particular good or service that a company makes and markets to customers. A food company may extend a product line by adding various similar or related products (e.g., adding mesquite BBQ flavor to its existing potato chips line), and create a more diversified product family.Using product line pricing allows companies to target customers with low-end, mid-range and high-end budgets. By offering two, three or more product tiers, a company can reach a much larger range of customers. This grants companies the potential to attain more sales and greater brand recognition.
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Compound A is an alkyne with molecular formula CsH8- When treated with aqueous sulfuric acid and mercuric sulfate, two different products with molecular formula C5H1oo are obtained in equal amounts. 0 Get help answering Molecular Drawing questions. Draw the structure of compound A. Edit 0 Get help answering Molecular Drawing questions. Draw the two products obtained in the box below Edit
Alkynes are hydrocarbons containing a carbon-carbon triple bond. Their general formula is CnH2n-2 for molecules with triple bonds.
Alkynes undergo many of the same reactions as alkenes but can react twice due to the presence of two p-bonds on the triple bond. Ethyne is commonly known by the trivial name acetylene. It is the simplest alkyne, consisting of two carbon atoms joined by a triple bond, where each carbon can bond to a hydrogen atom.
Molecules containing a triple bond between two carbon atoms are called alkynes. A triple bond consists of one σ bond and two π bonds. As for the hydrogen atoms, this compound is unsaturated, so the extra electrons are exchanged with two carbon atoms forming a double bond.
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neutrons are useful particles for nuclear bombardment processes because they have charge and are not repelled by a target nucleus. positively charged particles must have sufficient kinetic to overcome repulsion if they are to be used in this way. this is achieved by using a particle .
Neutron is not attracted to the positively charged nucleus since it has no charge. As a result, a neutron can bombard a nucleus even if it is very weak.
As a result, a nuclear reaction can be started by even a very weak neutron bombarding a nucleus. Thus, in a nuclear reaction, a neutron is employed to bombard the nucleus. Neutrons have no charge, therefore they are neither drawn to nor repelled by atoms' nuclei and electrons. Neutron is therefore the best projectile. The connections holding the nucleus together contain enormous energy. These connections can be broken, which will release the nuclear energy. A high-energy neutron is used to start nuclear fission by bombarding a nucleus, which causes the release of further neutrons. The nucleus does not reject a neutron since it has no charge.
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On a hot afternoon (311 K) a party balloon was filled with 2.07 L of helium. That evening the temperature dropped to 295 K. What is the
new volumen of the balloon?
Answer:
2.02 L
Explanation:
The volume of a gas is directly proportional to its temperature, according to the ideal gas law. This means that as the temperature of a gas decreases, its volume will also decrease.
To determine the new volume of the balloon as the temperature drops from 311 K to 295 K, we can use the ideal gas law to calculate the new volume of the gas:
PV = nRT
Where:
P = the pressure of the gas (assuming it remains constant)
V = the new volume of the gas
n = the number of moles of the gas (assuming it remains constant)
R = the universal gas constant
T = the new temperature of the gas
Since we know the pressure, number of moles, and universal gas constant, we can solve for the new volume of the gas by substituting in the known values and solving for V:
V = nRT / P
Substituting in the values from the problem, we get:
V = (n * R * 295 K) / P
Since the number of moles and the universal gas constant are constants, we can simplify the equation to:
V = k / P
Where k is a constant equal to the product of the number of moles, the universal gas constant, and the original temperature of the gas (in this case, k = n * R * 311 K).
Since we know the value of k and the pressure of the gas, we can solve for the new volume of the gas by substituting in the known values:
V = (k / P)
= (n * R * 311 K) / P
= (2.07 L * 8.31 L * atm / mol * K * 311 K) / P
= 2.02 L
Therefore, the new volume of the balloon is approximately 2.02 L.
Based on your data and using deductive reasoning, what can you conclude about the trends in the solubilities of the compounds of the alkaline earth metals?
onclude about the trends in the solubilities of the compounds of the alkaline earth metals
The solubility or, as we can say, the activity of the chemical, increases as one moves down the group. Since barium is more active
Chemical element barium (Ba), an alkaline-earth metal belonging to Group 2 (IIa) of the periodic chart. The substance is utilized in metallurgy, and pyrotechnics, petroleum production, and radiology all make use of its constituents.What is the purpose of barium?
Barium is solely utilized for GI tract imaging tests. An upper GI series may include a barium swallow test in addition to or instead of it. In this series, the esophagus, stomach, and first segment of the small intestine are examined (duodenum). During a barium swallow test, fluoroscopy is frequently employed.
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What is the number of atoms in a mole of any element? (3 points)
Avogadro's number
Graham's number
Its atomic number
Its mass number
Answer:
Avogadro's number
Explanation:
Metallic Solids - metal atoms with very loose electrons form a lattice of nuclei held together by a sea of electrons, or metallic bonds.
A lattice of nuclei held together by a sea of electrons or metallic bonds, or metallic atoms with extremely loose electrons. Covalent bonds connect nonmetal atoms to create molecules.
Intermolecular forces of attraction hold the molecules in a solid together. Electrostatic attraction between metal cations and delocalized electrons produces metallic bonds. The kind of metallic bonding that exists explains a lot of the physical properties of metals, including conductivity and malleability. Positive metal ions and the valence electrons that are constantly circling them are attracted to one another by metallic bonds. The metallic linkages keep the ions in their lattice-like configuration. The valence electrons of the interacting metal atoms' s and p orbitals delocalize in metallic bonding. The positively charged atomic nuclei of the interacting metal ions are surrounded by a "sea" of electrons instead of orbiting their individual metal atoms.
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For how many electrons is the value of ml +2
Only two electrons can be filled in an orbital with a magnetic quantum number (ml) +2.
What are the quantum numbers?The set of numbers that defines the position and energy of the electron filled in a specific orbital are called quantum numbers. Four quantum numbers are principal, azimuthal quantum number, magnetic, and spin quantum numbers.
The principal quantum number (n) denotes the principal electron shell of the atom and the most probable distance between the nucleus and the electrons. The azimuthal quantum number (l) denotes the shape of an orbital in which an electron is present.
The magnetic quantum number denotes the total number of orbitals in a subshell and the orientation of these orbitals. The value of the spin quantum number (s) denotes the direction in which the electron is spinning.
For the value of n = 2, we have five values of ml which are +2, +1, 0, -1, and -2. Every value of ml represents one d-orbital. Each orbital can have two electrons.
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most to least concentration in the troposphere: carbon monoxide, carbon dioxide, ozone, and hydroxyl radical
The correct arrangement on the basis of most to least concentration in troposphere will be: Cardon dioxide > Ozone > Carbon mono oxide > Hydroxyl radical.
In this lowest layer, the air is the densest. In actuality, the troposphere makes about 75 percent of the total weight of the atmosphere. The two most common gases are nitrogen (78%) and oxygen (21%), with argon (.9%) and a trace amount of hydrogen ozone (a kind of oxygen) making up the remaining 1% of all gases. The troposphere's temperature and water vapor concentration drop sharply with altitude.
Carbon monoxide background levels across the world vary from 0.06 to [tex]0.14 mg/m^3[/tex] (0.05– 0.12 ppm).
About 3 billion metric tons of ozone are present in the atmosphere as a whole. Even while that may seem like a lot, the atmosphere only makes up 0.00006 percent of it.
The concentration of hydroxyl radical is the minimum.
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When some of the sugar added to iced tea remains undissolved at the bottom of the glass, the solution is Most studied answer a) dilute b) unsaturated c) saturated d) polar e) nonpolar
When some of the sugar added to iced tea remains undissolved at the bottom of the glass, the solution is Saturated.
Solution is saturated which means no more solute can be dissolved in the solvent at the given/present temperature and pressure conditions. To dissolve more sugar in the tea we need to increase the temperature of the tea so that the tea becomes unsaturated, for the given conditions also the solubility of the solids increases with the increase in the temperature, so more of the sugar can be dissolved if the temperature of the solvent is increased.
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The density of an unknown element in the gaseous state is 1.60 g at 300 K and 1 atm. Which of the following could be the element?
a. He
b. Ne
c. Ar
d.O2
e. Cl2
What come first egg or hen?
Hen because who makes the egg?
Which group is known as the halogens?
A.01
B.2
C.17
D. 18
The correct answer is d) 17, because the halogens lie on the left side of the noble gases.
Explain more about halogens?The boiling point and density of halogens rise down the group, as seen in the graph. This is explained by the fact that as atomic size and mass grow, Van der Waals forces get stronger. The transition of an element's phase from gas to liquid to solid allows us to detect this transformation. The only group in the periodic table with 33 states of matter is the halogens. Since hydrogen can be found in both group IA (alkali metals) and group VIIA of several periodic tables due to its ability to create compounds with both oxidation values of +1 and -1. (halogens). Because noble gas configurations for atoms are so stable, elements must either lose or gain electrons to achieve them.To learn more about halogens refer to:
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Calculate the amount of heat needed to boil 120.g of acetic acid (HCH3CO2), beginning from a temperature of 16.7°C. Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol.
The energy required to bring 120 g of acetic acid (HCH3CO2) to a boil at a starting temperature of 16.7 °C is 72.2116 kJ.
Given that ;
mass of acetic acid = 120.0 g
initial temperatureT₁ = 16.7 °C = (16.7 + 273.15 ) K = 298.85 K
standard molar mass of acetic acid = 60.052 g/mol
The number of moles of acetic acid can therefore be calculated as follows: number of moles of acetic acid = mass of acetic acid/molar mass of acetic acid
number of moles of acetic acid = 120.0 g/ 60.052 g/mol
number of moles of acetic acid = 1.998 moles
For acetic acid:
standard boiling point T₂ = 118.1 °C = ( 118.1 + 273.15 ) K = 391.25 K
enthalpy of vaporization of acetic acid ΔH[tex]_{vap}[/tex] = 23.7 kJ/mol
heat capacity of acetic acid c = 2.043 J/g.K
change in temperature Δ T = T₂ - T₁
Δ T = (391.25 - 289.85)K
Δ T = 101.4 K
The heat required to raise the liquid acetic acid's temperature from 16.7°C to its boiling point is;
q = mcΔT
From our values above;
q = 120 g × 2.043 J/g.K × 101.4 K
q = 24859.2 J
q = 24859 /1000 kJ
q = 24.859 kJ
We already determined that we have 1.998 moles of acetic acid;
Thus;
the needed amount of heat = Δ[tex]_{vap}[/tex]*number of moles
The needed amount of heat = 47.3526 kJ
Hence;
The total amount of heat needed = 24.859 kJ + 47.3526 kJ
The total amount of heat needed = 72.2116 kJ
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Compound S (C8H16) reacts with one mole of bromine to form a compound with molecular formula C8H16Br2. The broadband proton-decoupled 13C spectrum of S is given below. Propose a structure for S.
Note: All structures should be drawn with no bonds between carbon and hydrogen.
Compound S (C8H16) reacts with one mole of bromine to form a compound with molecular formula C8H16Br2. Its unsaturation is demonstrated by the fact that S decolorizes bromine.
The atomic number 35 and symbol Br are assigned to the chemical element bromine. At room temperature, it is a flammable red-brown liquid that readily evaporates to form a vapour of a similar hue. It is the third-lightest element in group 17 of the periodic table (halogens). Its properties are halfway between those of chlorine and iodine. It was independently discovered by two chemists, Carl Jacob Löwig (1825) and Antoine Jérôme Balard (1826), and was given the name o (bromos), which in Ancient Greek indicates to its pungent and potent smell. The mineral halide salts, which resemble table salt and are white, soluble, and crystalline, contain the element bromine because of its strong reactivity, which prevents it from occurring naturally as a native element. All halogens, including bromine, are actually so reactive that they can only ever form pairs of bonds with other atoms. Despite being very infrequent in the crust of the Earth, the bromide ion (Br) has accumulated in the oceans due to its high solubility.
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the hydrogen generated in this lab was a product of the reaction between magnesium and hydrochloric acid. which of the reactants is the limiting reactant?
a.) magnesium
b.) hydrochloric acid.
Suppose that when you inverted the eudiometer, a bubble of air became trapped inside it. Would this make your experimental value of R larger, smaller, or have no effect?
a.) larger
b.) smaller
c.)no effect
The limiting reagent in this reaction is HCl.
Supply and the stoichiometric equation are used to identify the limiting reactant of these reactants. So, both reactants are able to act as limited reagents according to these conditions.
They limit how far reactions can go in terms of producing products because they are reactants with a finite supply.
Hydrogen gas is created in the following manner in a reaction between magnesium and hydrochloric acid:
Mg + HCl ------------> MgCl₂ + H₂
HCl has two times the molecular weight of magnesium. As a result, no reactant will be limiting if both reactants are provided in the required proportion.
HCl will become limiting if the amount of moles supplied is not at least twice that of Mg. Furthermore, Mg will be limited if the amount supplied is not equal to half the amount HCl supplied.
Therefore, the limiting reagent in this reaction is HCl.
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using curved arrow notation, write lewis acid/base equations for each of the following. remember to place formal charge on the appropriate atoms. a. aici3- b. phyp: bf3 bh3
AlCl 3 is Lewis base,PH3 is Lewis base,BH3 is Lewis acid ,BF3 is Lewis acid.
The crucial step is AlCl 3 accepting a chloride ion lone-pair to generate AlCl 4 and the highly acidic, or electrophilic, carbonium ion. Lewis bases: RCl +AlCl 3 → R + + AlCl 4−, etc. [ edit] The highest occupied molecular orbital (HOMO) of an atomic or molecular species that is strongly localised is known as a Lewis base.Lewis acid borane (BH3) has three hydrogen atoms and one boron atom in its molecule. The Lewis structure of borane features a single connection connecting each hydrogen atom to boron (BH3). Only three bonds surround the boron atom, and there are no lone pairs on the atom itself. We will learn how to draw the BH3 Lewis structure in this lesson.Only six electrons orbit the boron atom, according the Lewis structure of BF3. As a result, the boron atom's octal is incomplete. Borane BF3 is therefore regarded as a Lewis acid.A highly poisonous gaseous chemical is phosphorus. Three sigma bonds and one lone pair are present around the phosphorus atom in the Lewis structure of phosphine (PH3). Hydrogen and phosphorous atoms have no charges. The trigonal pyramidal shape of PH3 is a fundamental shape.
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a metal oxide with the formula m2o contains 11.18% oxygen by mass. in the box below, type the symbol for the element represented by m. [a]
Strontium, whose atomic symbol is Sr, is the metal that is present in the specified metal oxide.
The unit of measurement for substance is the mole. The term "mole" refers to the relationship between a substance's molar mass and its overall mass. It is defined as the molar mass (g/mol) of a material divided by the substance's mass in grams.
The following phrase can be used to determine the number of moles:
The supplied metal oxide MO has an oxygen content of 15.44%, which translates to 15.44 g of oxygen per 100 g of the metal oxide MO. According to the periodic table, strontium, which has a molar mass of roughly 87.7 g, is the metal present in 100 g of metal oxide (Sr). Therefore, strontium oxide is the metal oxide.
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cold water can hold more dissolved oxygen than warm water because the solubility of oxygen decreases as temperature increases. T/F
The solubility of oxygen reduces with increasing temperature, hence cold water can store more dissolved oxygen than warm water. The chemical element with the letters O.
And the atomic number 8 is called oxygen. It belongs to the chalcogen group of the periodic table and is a highly reactive nonmetal that rapidly forms oxides with most elements as well as with other compounds. Understanding the makeup of matter developed together with the creation of the concepts of the elements. The substance has been viewed as either continuous or discontinuous at various points throughout history. It is possible to hypothesise that continuous substance is homogenous, infinitely divisible, and has parts that are all the same size.
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which of the following concerning molecular geometry and dipole moments is correct? all molecules with polar bonds have a permanent dipole moment. all square planar molecules are nonpolar. all linear molecules are nonpolar. only molecules with polar bonds may have a permanent dipole moment. a molecule with nonpolar bonds could have a permanent dipole moment, depending on the molecular geometry.
Answer:
only molecules with polar bonds may have a permanent dipole moment.
Explanation:
draw the structure or structures produced by the catalytic reduction of the given compound, in which h2 is in excess.
Structures produced by catalytic reduction of certain compounds where H2 is H2. 1-Ethylcyclohexa-1,4-diene and excess hydrogen-ethyl-2-methylcyclohexane are formed.
Specific compound 1-Ethylcyclohexa-1,4-diene and excess hydrogen-ethyl-2-methylcyclohexane are formed. One compound has the R, S configuration and the other has the S, R configuration. Using the CIP rule, preference is given to groups attached to chiral carbons.
CIP rules are based on the atomic mass of the combined groups, so the group with the highest atomic mass has the lowest number. Since it is a mixture of two enantiomers, it can be called a Rekamic mixture. Selective catalytic reduction refers to the reduction of nitrogen oxides with oxygen and selective inorganic or organic reducing agents.
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Consider the following reaction at 276 K.
1 A + 2 B → C + D
where rate = rate=k[A][B]2. An experiment was performed for a certain number of seconds where [A]o = 0.000847 M and [B]o = 1.11 M. A plot of ln[A] vs time had a slope of -9.43. What will the rate of this reaction be if a new experiment is preformed when [A] = [B] = 0.779 M?
1 A + two C and d → C + S t where rate=k[A][B][rate] 2. An experiment with [A]o = 0.000847 T s as well as [B]o = 1.11 M was run for a predefined number of seconds. The slope of a ln[A] vs. grown steadily was -9.43. rate of reaction is 3.62m/s
Slope and slant both refer to an incline up from a reference surface or line that is generally straight. The ground slopes (either upward or straight down) sharply here. To slope is to slope vertically in an ambiguous path A line's steepness could be determined by looking at its slope. Altitude is calculated mathematically as "rise over run."
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Find the volume, in mL, of an object whose density is 400 g/mL and has a mass of 600
mg.
The volume of the object is 1.5ml.
What is the volume of an object?This refers to the space occupied within the boundaries of an object in three-dimensional space. It is also called the capacity of the object.
In the question:
ρ = 400 g/mL
m = 600 mg
v = ?
Formular for calculating density ρ:
ρ = m/v
Where,
ρ= Density of the object
m= Mass of the object
v = volume of the object
Were are given the values of density and mass in the question. We are to calculate the volume.
Makinig v subject of the formular we have:
v = m/ρ
v = 600 mg
400 g/mL
v = 1.5ml
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place the following carboxylic acid derivatives in order of increasing reactivity toward nucleophiles, starting with the least reactive at the top of the list. EsterAcid chloide
AmideAcid anhydride
Acid Chloride, followed by Acid Anhydride, Acid Ester, and Acid Amide, is the sequence of reactivity for carboxylic acid derivatives. Acid amides are the least reactive, while acid chlorides are more so.
This is as a result of the leaving group's basicity order, which is as follows.
Acid Chloride, followed by Acid Anhydride,, Acid Ester, and Acid Amide, is the sequence of reactivity for carboxylic acid derivatives. Acid amides are the least reactive, while acid chlorides are more so. This is as a result of the leaving group's basicity order, which is as follows. Was this response useful? The following carboxylic acids should be arranged in decreasing order of reactivity. The carboxylic acid must first be activated before a nucleophilic substitution may take place. Acid chlorides can be transformed into amides, esters, or acid anhydrides. Because acid chlorides are the most reactive of the compounds, these reactions are feasible.
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Each sketch below shows a flask with some gas and a pool of mercury in it. The gas is at a pressure of 1 atm. A J-shaped tube is connected to the bottom of the flask, and the mercury can freely flow in or out of this tube. (You can assume that there is so much more mercury in the pool than can fit into the tube that even if the J-tube is completely filled, the level of mercury in the pool won't change.) Notice also that in the left sketch the J-tube is open at its other end, so that air from the atmosphere can freely flow. On the other hand, in the right sketch the J-tube is closed at its other end, and you should assume there is no gas between the mercury and the closed end of the tube To answer this question, you must decide what the mercury level will be when the mercury finally stops flowing in or out of the tube. By moving the sliders back and forth, you'll see different levels of mercury in the J-tube.
The mercury level will be when the mercury finally stops flowing in or out of the tube. By moving the sliders back and forth, you'll see different levels of mercury in the J-tube at 1,5 m and 2.26 m respectively.
Open Tube:
Gravity: 1.5 m
PBulb: 1 atm 760 mmHg 1 atm | = 760 mmHg = 0.760 mHg
PEX:-1 atm (760 mmHg) 1 atm =-760 mmHg = -0.760 mHg
Total Rise: 1.5 m + 0.760 m + -0.760 m = 1.5 m.
Close Tube:
Gravity: 1.5 m
PBulb: 1 atm (760 mmHg 1 atm | = 760 mmHg = 0.760 mHg
Total Rise: 1.5 m + 0.760 m = 2.26 m.
The Earth's atmosphere is a layer of gas, collectively known as air, held by the Earth's gravity that surrounds the planet and forms the planet's atmosphere. Not only does it contain the oxygen we need for life, it also protects us from the sun's harmful UV rays.
Liquid water cannot exist on the surface of the earth without pressure. And it warms our planet, keeping it at a habitable temperature for our living planet. The atmosphere is the layer of gas that envelops the planet and is held in place by the gravity of the planetary body.
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Correct the volume of 2.90 L of a gas at –12 °C to the volume occupied at 25 °C. Remember to convert between °C and K.
The volume occupied at 25 °C. Remember to convert between °C and K. V2 = 3.311 L is the correct answer.
What is volume?
Volume is the measure of the amount of space occupied by an object or a substance. It is measured in three dimensions: length, width, and height. In the International System of Units (SI), it is measured in cubic meters (m3). Volume is also commonly measured in liters (L), gallons (gal), or cubic feet (ft3). Volume can also refer to the amount of a substance or object, such as the volume of a gas or the volume of a liquid.
Temperature and Volume equation
Given,
The volume at -12°C = 2.90L
Temperature, T1 = -12°C
= (-12°C + 273)
= 261K
And, Volume at 25°C = ?
(25°C + 273)K
= 298K
Now, by using this equation:-
V1/T1 = V2/T2
V2 = V1 x T2/T1
V2 = 2.90L x 298K/261K
V2 = 3.311L
Hence, The volume at 25°C will be 3.311L
To learn more about Temperature and Volume equation
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