Answer:
I think 4 days
Explanation:
I just think it is 4 i think i am worng tho
True or false, The ideal gas lead allows us to figure out a fourth variable about a gas when the other 3 are given
Answer:
true
Explanation:
PV=nRT
The ideal gas law states that PV = NkT, where P is the absolute pressure of a gas, V is the volume it occupies, N is the number of atoms and molecules in the gas, and T is its absolute temperature. The constant R is called the Boltzmann constant
plz answer (g) i will give rating 5 and thanks who answer plz fast
Answer:
Like many common group 2 metal carbonates, magnesium carbonate reacts with aqueous acids to release carbon dioxide and water
MgCO3 + 2 HCl → MgCl2 + CO2 + H2O.
The procedure to obtain pure magnesium chloride from the reaction is as thus
Step 1: Reaction
- Leave the dilute hydrochloric acid in a beaker.
- Add Magnesium carbonate slowly until it is in excess or until no more gas seem to be getting liberated.
Step 2: Filtration
- Filter with filter paper and funnel.
- Filter off the excess magnesium carbonate as magnesium chloride will be in aqueous form (liquid) and will come out with the filtrate. The residue is the excess magnesium carbonate.
Step 3: Crystallization to obtain solid crystals from the filtrate.
- Pour filtrate solution into evaporating dish/basin
- Provide heat using Bunsen burner
- Pour solution into an evaporating basin and heat over a water bath
- Stop heating when crystals start to form
allow water to evaporate until pure crystals remain.
- Dry crystals using absorbent paper or warm oven.
Precautions
- Use personal protective equipment such as gloves, a lab coat and wear eye protection, especially when heating.
- Avoid inhaling unnecessary gases during the whole process.
Using the equation below, calculate how many grams of water (H2O) you have if you start with 12 grams of
hydrogen?
2 H2 + O2 → 2 H2O
Answer:
12g
Explanation:
The following equation is given in this question:
2H2 + O2 → 2H2O
According to this balanced chemical equation, 2 moles of hydrogen gas is used to produce 2 moles of water molecule.
Hence, if 12 grams of hydrogen is used, 12 × 2/2 = 24/2
= 12 grams of H2O will be produced.
What is the name of the molecule shown below?
A) ethanol
B) ethanal
C) ethanoic acid
D) ethylamine
The name of the molecule shown is Ethanol.
What is Ethanol?Ethanol is a alcoholic substance that is formed from fermentation of glucose in the presence of yeast or microorganisms.
It has a chemical group that have methyl group, hydroxyl group OH which is bonded to carbon atom.
Therefore, The name of the molecule shown is Ethanol.
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Calcium sulfate is a white solid found as two hydrates, a hemihydrate known as plaster of Paris and a dehydrate known as gypsum. The hemihydrate is a white solid. Given that the molar mass of the anhydrous calcium sulfate is 136.14 g/mol, the molar mass of the hemihydrate is 145.15 g/mol, and the molar mass of water is 18.015 g/mol, which formula gives the correct ratio for the hemihydrate
Answer:
2(CaSO4)*H2O
Explanation:
To solve this question we need to find the moles water, H2O, of calcium sulfate, CaSO4 as follows:
The molar mass of the anhydrous CaSO4 are 136.14g/mol and the molar mass of the hemihydrate is 145.15g/mol. The differences in molar mass represents the additional mass that water is producing:
145.15g/mol - 136.14g/mol = 9.01g/mol
A 1 mole of water weighs 18.015g/mol, the additional mass of water is due the addition of 1/2 moles of H2O. That means we have 1 mole of CaSO4 per 1/2 mole of H2O. That is the same:
2(CaSO4)*H2O
And this is the formula that gives the correct ratio for the hemihydrate.
Help please and thank youu
Answer:
elementos original
set onde
nhóm nào gồm tất cả các kim loại tan trong axit sunfuric đặc nóng nhưng không tan trong axit sunfuric loãng là
Answer:Nhóm gồm tất cả các kim loại tan trong axit sunfuric đặc nóng nhưng không tan trong axit sunfuric lo
Al, Cu, Au.
Al, Fe, Cr.
Ag, Fe, Pt.
Ag, Cu, Hg.
Explanation:
True or false, We use the ideal gas law when a gas changes
we use the ideal has law when a bad changes false
Situación 1: Cierto catión divalente posee 2 electrones en n=5. Además, su número de masa es igual a 118. Hallar lo siguiente:
1. Su distribución electrónica
2. Su número de neutrones
3. Protones más electrones
4. Sus posibles números cuánticos de su último electrón
…………………………………………………………………………………………………
El catión divalente descrito en la pregunta es [tex]Sn^{2+}[/tex]. Divalente significa que ha perdido dos electrones.
La distribución electrónica de [tex]Sn^{2+}[/tex] es;
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10
El número másico de estaño es 118 y [tex]Sn^{2+}[/tex] tiene 50 protones.
Por lo tanto, el número de masa de Sn =[tex]118 - 50 = 68 neutrones[/tex]
El número de electrones es 49 y el número de protones es 50 en [tex]Sn^{2+}[/tex]por tanto;
El número de electrones + protones = 99
El último electrón está en el orbital, 5s2, por lo que sus posibles números cuánticos son;
n = 5, l = 0, m = 0, s = ±1/2
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aluminuim is many factured by the electrolysis of molten aluminium oxide what are the gasses formed
Answer:
oxygen
Explanation:
oxygen ions will be oxidised to form oxygen gas at the anode
0 / 5 points
Order the following chemicals from lowest to highest melting point.
Water
Paraffin wax
Hydrogen sulfide
Ethanol
Carbon dioxide
Answer:
Ethanol - -173.5°FHydrogen sulfide - -121.9°FCarbon dioxide - -69.9 °FWater - 32°FParaffin wax - 115 to 154 °FExplanation:
Ethanol is a chemical, grain alcohol is a volatile and flammable, colorless, and odorless substance. The versatile solvent has many acidic compositions. Paraffin wax is an soft and colorless solid that is made from petroleum coal and oil. It is an excellent material for storing heat.what is solution, colloid, suspension?
Explanation:
SOLUTION:Solution is a homogenous mixture of two or more substances in relative amounts that can be varied continuously up to what is called the limit of solubility.
COLLOID:A mixture in which one substance is divided into minute particles (called colloidal particles) and dispersed throughout a second substance
SUSPENSION:A suspension is a heterogeneous mixture of a finely distributed solid in a liquid. The solid is not dissolved in the liquid, as is the case with a mixture of salt and water.
8. What is the oxidation number of N in KNO3?
Answer:
The oxidation state of N in the KNO3 is +5
Explanation:
Oxidation rules:
1. Oxygen is -2, unless in peroxides.
2. Group 1 metals = +1
3. Group 2 metals = +2
4. If the molecule is neutral, all of the oxidation numbers have to add up to zero.
5. If the molecule is charged, all of the oxidation numbers have to add up to the charge of the molecule.
So, the given formula represents the salt compound formula unit of potassium nitrate: KNO3
The formula unit is uncharged.
From our rules, we know that,
O = -2
And we can find K on the periodic table, in the first group, thus giving it a +1 charge. Now let's put it all together.
K = +1
N = x
O = -2
Let's take into account the number of atoms of each element we have and make an equation since we know everything has to add up to zero since the molecules are neutral.
+1 +x+3 (-2) = 0 (notice we multiplied 3 by -2 because in the formula we have 3 atoms of oxygen with -2 charge each)
x - 5 = 0
x = 5
Therefore, the oxidation number of N in KNO3 is +5.
. The Ksp of barium sulfate is 1.1 × 10–10. What is the sulfate-ion concentration of a 1.0-L saturated solution of BaSO4 to which 0.025 mol of Ba(NO3)2 is added? 4.4 × 10–9M 1.0 × 10–5M 6.6 × 10–5M 2.8 × 10–12M
Answer:
[tex][SO_4^{2-}]=4.4*10^{-9}M[/tex]
Explanation:
From the question we are told that:
[tex]Ksp=1.1*10^{-10}[/tex]
Volume of [tex]SO_4^{2-}=1.O[/tex]
Moles of [tex]Ba(NO_3)^2 =0.025[/tex]
Generally the equation for Ksp is mathematically given by
[tex]Ksp=[Ba^{2+}][SO_4^{2-}][/tex]
[tex]1.1*10^{-10}=[0.025][SO_4^{2-}][/tex]
Therefore
[tex][SO_4^{2-}]=4.4*10^{-9}M[/tex]
What is chemical reaction ?
Answer:
CHEMICAL REACTION : A process in which new substances with new properties are formed from one or more substances.
REACTANTS - Substances which take part in a chemical reaction.PRODUCTS - Substances which are formed in a chemical reaction.Examples of chemical reactions : Digestion of food, respiration, rusting of iron, burning of magnesium ribbon, formation of curd etc.
Answer:
Explanation:
Chemical reaction is one or more reactants react with each other to from new products.
Hydrogen has one electron in its electron shell…
Answer:
iii) Figure 2 needs to have one X in the intersection, and one O in the intersection. This is because hydrogen requires 2 electrons in it’s outer shell to become stable. By sharing, both hydrogen atoms can become stable.
c) (i) Universal indicator.
i’m not 100% sure, however i’m quite certain :)
For the following reaction of N2O4, the equilibrium constant is 0.593 at a particular temperature.
N2O4(g) ⇌ 2 NO2(g)
If the initial concentration of N2O4 is 0.880M, what are the equilibrium concentrations?
Please show work!
Answer:
"0.583" is the appropriate answer.
Explanation:
Let,
The initial constant of [tex]N_2O_4[/tex] be "C".
Amount of [tex]N_2O_4[/tex] dissociated into [tex]NO_2[/tex] be "x".
now,
[tex]N_2O_4 \rightleftharpoons 2NO_2[/tex]
Initial constant C -
Equilibrium constant C 2x
The Kc is given as:
⇒ [tex]K_c = \frac{[NO_2]^2}{[N_2O_4]}[/tex]
[tex]=\frac{(2x)^2}{C-x}[/tex]
[tex]0.593=\frac{4x^2}{0.88-x}[/tex]
[tex]4x^2=0.593(0.88-x)[/tex]
[tex]4x^2=0.512-0.593\ x[/tex]
[tex]x=0.291[/tex]
hence,
The constant of [tex]NO_2[/tex] will be:
= [tex]2x[/tex]
= [tex]0.583[/tex]
number of protons in carbon-12
Answer:
6
Note:
Please check Rasputin020's answer instead of this, It's more detailed.
Plz someone help plz show your work and I’ll transfer pay u❤️
Calculate the volume (in L) that 3.25 mol of helium gas will occupy at a temperature of 25.0 °C and a pressure of 799 mm Hg.
Answer:
V = 6.34 L
Explanation:
Given that,
Number of moles of Helium gas, n = 3.25 mol
Temperature, T = 25 °C = 298 K
Pressure, P = 799 mm Hg
We know that,
PV = nRT
Where
R is the gas constant, R = 62.4 L-mm Hg/mol K
So,
[tex]V=\dfrac{nRT}{P}\\\\V=\dfrac{3.25\times 62.4\times 25}{799}\\\\V=6.34\ L[/tex]
So, the volume of the gas is 6.34 L.
Cuál es el punto de ebullición de una solución acuosa de urea al 20 % m/m (20g de soluto por cada 80g de solvente) , si la masa molar de urea es 60 g/mol. (Ke= 0,52 °C/m)
The question is: What is the boiling point of an aqueous solution of urea at 20% m / m (20g of solute for every 80g of solvent), if the molar mass of urea is 60 g / mol. (Kb = 0.52 ° C / m)
Answer: The boiling point of given aqueous solution of urea is [tex]2.145^{o}C[/tex].
Explanation:
Given: Mass of solute = 20 g
Mass of solvent = 80 g (1 g = 0.001 kg) = 0.08 kg
[tex]K_{b} = 0.52^{o}C/m[/tex]
Molar mass of urea = 60 g
Molality is the number of moles of solute present in a kg of solvent.
Moles is the mass of a substance divided by its molar mass. So, moles of urea is calculated as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{20 g}{60 g/mol}\\= 0.33 mol[/tex]
Now, molality of given solution is as follows.
[tex]Molality = \frac{moles}{mass(in kg)}\\= \frac{0.33 mol}{0.08 kg}\\= 4.125 m[/tex]
Formula used to calculate the boiling point is as follows.
[tex]\Delta T_{b} = K_{b}m\\= 0.52^{o}C/m \times 4.125 m\\= 2.145^{o}C[/tex]
Thus, we can conclude the the boiling point of given aqueous solution of urea is [tex]2.145^{o}C[/tex].
40 POINTS!! Will Mark Brainliest if all work is shown as well as correct answer
The following reaction can be used to convert carbon dioxide to oxygen gas.
4 KO₂ (s) + 2 CO₂(g) → 2 K₂CO₃(s) + 3 O₂(g)
The theoretical yield for the reaction is 0.296 g O₂. Given that the reaction has a percent yield of 83.4%, what is the mass in g of oxygen gas that is actually produced?
Answer:
0.3549
Explanation:
the percentage yield is the percentage of the product formed based on the theoretical yield.in this question the percentage yield and theoretical yield have been given all that's left is the actual yield.so you use the formula
percentage yield=theoretical yield/actual yield×100
83.4=0.296/ay×100
83.4ay/83.4=100×0.296/83.4
ay=0.3549
I hope this helps
15 ft is the same as how many yards
how many grams of potassium cyanide would be needed to make a saturated solution for the volumes indicated below? The solubility of potassium cyanide is 50.0g/100ml
A. 0.150L
B. 75.0mL
C. 1.10L
D. 225mL
Chemicals used in hot packs do not produce fire, so what makes the hot packs feel hot?
Answer:
chemical wsed in hot packs do not produce fire, so what makes the hot packs feel hot? Because it is a exothermic reaction it has chemicals that bunch up together.
The table below gives the equilibrium concentrations for this reaction at a certain temperature : N2(g) + O2(g) 2NO(g) what is the equilibrium constant for the reaction?
A. 1 x 10-5
B. 7 x 10-3
C. 70
D. 100
The equilibrium concentrations for the given reaction at a certain temperature will be 100.
What is equilibrium?During a reversible chemical process, chemical equilibrium is the state where there would be no net change in the number of reactants as well as products.
What is the reaction?The reaction is the process in which by the combination of more than one element new kind of element will be formed.
Given data:
The given reaction is [tex]N_{2} (g) + O_{2} (g)[/tex] → [tex]2NO(g)[/tex]
The equilibrium constant (K) = [tex][NO]^{2} /[N_{2}][O_{2}][/tex]
Put the value of the given data in the above equation.
K = [tex]=[0.002 M]^{2} / [0.65M][0.45M]\\=[4*10^{-6} ]/ [0.2950]\\= [4*10^{-6} ] / 2950*10^{-4}\\= 1.35 * 10^{-5}[/tex]
Therefore, the equilibrium constant will be 1.35 × [tex]10^{-5}[/tex]
To know more about reaction and equilibrium
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2HGO(s) + 43.4 kcal -> 2Hg(I) + O2(g)
Answer:
x = -9, 0 = -1, x \ne 0
Explanation:
[-54/x = 6 0x = 9]
Isolate x for - 54/x = 6 : x = -9
-54/x = 6
Multiply both sides by x
-54/x = 6x
Simplify - 54/x x : -54
-54x x = 6x
Multiply fractions: a . b/c = a . b/c
= -54x/x
Cancel the common factor: x
= -54
- 54 = 6x
Switch sides
6x = -54
Divide both sides by 6
6x/6 = -54/6
Simplify
6x/6 = -54/6
Simplify 6x/6: -9
6x/6
Divide the numbers: 6/6 = 1
= x
Simplify
-54/6
Apply the fraction rule: -a/b = -a/b
= -54/6
Divide the numbers: 54/6 = 9
= -9
x = -9
Verify solutions
Find underfined (singularity) point: x = 0
Take the denominator (s) of - 54/x and compare to zero
x = 0
Combine undefined points with solutions:
x = -9
Substitute x = -9
[ o(-9) = 9]
Simplify
0(-9) = 9
Simplify
0(-9): -90
Remove parentheses: (-a) = -a
= -0 . 9
-90 = 9
[-90 = 9]
Isolate o for -90 = 9 : o = -1
-90 = 9
Divide both sides by -9
-90/-9 = 9/-9
Simplify
0 = -1
The solutions to the system of equations are:
x = -9, 0 = -1, x \ne 0
On a plateau on a heating curve, _____.
phase changes are occurring
no heat is being absorbed
all the absorbed heat is being used to overcome forces of attraction between the particles or molecules and phase changes are occurring
all the absorbed heat is being used to overcome forces of attraction between the particles or molecules
Answer:
On a Plateu on a heating curve phase changes are occuring
Explanation:
The first Phase is melting during which the temrature stays the same while water melts.Other phase changes are freezing sublimation Vaourization condensation and deposition
Oxoacids have the general formula illustrated, where the number of bonds to the central element E can vary. For the same element E, acid strength will _____ as the number of O atoms increases. For the same number of O atoms, acid strength increases as the _____ of element E increases. Multiple choice question. decrease; electronegativity
Answer:
Hence the correct answer is increase, electronegativity.
Explanation:
Oxoacids have the general formula illustrated, where the number of bonds to the central element E can vary. For the same element E, acid strength will increase as the number of O atoms increases. For the same number of O atoms, acid strength increases as the electronegativity of element E increases.
HELP ME PLZ Which of the following describes the structure of a fish's swim bladder?
A. Expands and contracts to allow the fish to rise or sink in the water
B. Internal organ filled with liquid
c. Holds urine until it can be released into the environment
D. Internal organ filled with air sacs