If you flip a penny, toss a 1–6 number cube, and flip a quarter, how many outcomes are possible?

Answer:

0.15

Step-by-step explanation:

first get three percent:

3/100 = 3%

then use of operation:

3% of 5;

= (3/100) * 5

Answer:

60%

Step-by-step explanation:

To change a fraction to a percentage, multiply the fraction by 100% , then

[tex]\frac{3}{5}[/tex] × 100% = [tex]\frac{3(100)}{5}[/tex] = [tex]\frac{300}{5}[/tex] = 60%

Answer:

Step-by-step explanation:

C looks right

as shown in the graphs  :P

Answer:

b

Step-by-step explanation:

[tex]\frac{x^4}{x^7} =x^4 \times x^{-7} =x^{4-7} =x^{-3}[/tex]

7

Step-by-step explanation:

To solve this you need to use trigonometry:

1. Identify the sides. In this case, x is opposite and 10 is adjacent.

2. Identify which part of SOHCAHTOA you need to use. In this case, you need to use TOA.

3. Form your equation. In this case, x = tany x A

4. Substitute numbers into your equation. In this case, x = tan35° x 10

5. Calculate this equation using a scientific calculator. In this case the answer is 7.

Answer:

x = 6

Step-by-step explanation:

5 (x - 3) + 2 = 5 (2x - 8) - 3

remove the parenteses

5x - 15 + 2 = 10x - 40 - 3

5x - 13 = 10x - 43

5x - 10x = -43 + 13

-5x = -30

Solution

x = 6

Answer:

in 90 minutes he ran 30 laps

there is 60 minutes in a hour so the fraction would be

2/3 so we have to multiply this by 30

2/3*30=20

He can run 20 laps in a hour

Hope This Helps!!!

Hey there!

To solve this problem, we will be using Trigonometric Ratio. Trigonometry is always helpful when it comes to finding a missing side with specific measure/angle.

1. Cosine Ratio

2. Adjacent and Hypotenuse

Hope you understand this topic! If not, feel free to ask!

3. Solve The Problem

Therefore, the equation for the problem is:

[tex] \large{cos62 \degree = \frac{x}{12} }[/tex]

*cos is the short form of cosine*

At this part, we need a calculator to find the value of cos62 degrees. That's because it is not a degree like 0, 30, 45, 60 and 90 which can be found without a calculator.

When we put cos62 in a calculator, make sure to put it in degree mode since a calculator has two modes which are degree and radian.

When we put cos62 in, we should get 0.46947156... Because you want a one decimal place, we round the value up to the nearest tenth as we get 0.5 because 6 is greater than 5 and should be rounded up and not down. That makes the equation to:

[tex] \large{0.5 = \frac{x}{12} }[/tex]

Oh well! Finally to the equation part. Whenever you have to solve the equation that has decimal numbers in it, the best way to deal with decimal numbers is to make them into a whole number or integer. But how? Simply multiply the whole equation by 10. Because 0.5×10 is 5 thus 0.5 becomes an integer after multiplying 10.

[tex] \large{0.5 \times 10 = \frac{x}{12} \times 10} \\ \large{5 = \frac{10x}{12} }[/tex]

10x/12 can be simplified again.

[tex] \large{5 = \frac{5x}{6} }[/tex]

Then we isolate x-value by multiplying 6 the whole equation.

[tex] \large{5 \times 6 = \frac{5x}{6} \times 6} \\ \large{30 = 5x} \\ \large{x = 6}[/tex]

Huh, that's awkward! We want the answer in a 1 decimal place but seems like the answer for this is 6. Why? Well that is not an exact answer, but more like an approximation. Because the value of cos62 degree is actually a repeating decimal and doesn't have exact value.

When we put the equation cos62 = x/12 in the equation and solve. It appears that the the answer is 5.63365875. Because we round up to nearest tenth, it gives an approximation to 5.63365875 instead.

Hence, the equation and value above is just a rounded to the whole number from 5.63365875.

Because you want a one place decimal. Hence,

4. Final Answer

Answer:

Step-by-step explanation:

On the day of the canteen, 800 coupons were sold, the price of each coupon was RM 30 and RM 50 respectively. The amount of money earned from the sale of coupons was RM30000. How many copies of RM30 and RM50 coupons were sold?

Let:

RM 30 = x

RM 50 = y

x + y = 800 - - - (1)

30x + 50y = 30000 - - - (2)

From (1)

x = 800 - y

Put x = 800 - y in (2)

30(800 - y) + 50y = 30000

24000 - 30y + 50y = 30000

24000 + 20y = 30000

20y = 30000 - 24000

20y = 6000

y =

Answer:

x = 3     y = 5

Step-by-step explanation:

     y=x+2

+    y=-x +8

2y = 10

y = 5

y = -x + 8

5 = -x + 8

x = 3

Answer:

56 different outfits

Step-by-step explanation:

Answer:

The plane arrives Los Angeles at 9:00 am

Step-by-step explanation:

The Pacific Standard Time (PST) in Los Angeles is 3 hours earlier than the Eastern Standard Time (EST) in Boston

Therefore,

7:00 am at Boston = 4:00 am in Los Angeles

If the plane takes 5 hours

What is time when you arrive in Los Angeles

The plane arrives Los Angeles at 4:00 am + 5:00 hours

= 9:00 am

The plane arrives Los Angeles at 9:00 am

Answer:

10

Step-by-step explanation:

10 percentage for this question answer

Answer:

x > 3

Step-by-step explanation:

Given the inequality :

-2(5 – 4x) < 6x – 4

Expand the equation in bracket :

-10 + 8x < 6x - 4

Collect like terms

-10 + 4 < 6x - 8x

-6 < - 2x

Divude both sides by - 2

-6 / - 2 < - 2x / - 2

3 < x

x > 3

Addition of a positive and negative number always means that you are going to subtract the number e. g. 4+-1 = 3. However, multiplication of a positive and negative number means the answer is always negative e. g. 5 x - 3 = - 15.

The addition of positive and negative number will always subtract with sign of maximum value.

The multiplication of positive and negative number will have a negative sign always.

When two numbers which have different sign are added, they will always be subtracted from each other. The sign will vary accordingly.

Example: Consider two number -5 and 4

= -5 + 4

= -1

Here, 5 is the larger value. So, the sign comes is negative.

Example: consider two number 5 and -4.

= 5 + (-4)

= 1

Here, 5 is the large number. So, the sign comes is positive.

When two numbers with opposite signs are multiplied, the answer is always a negative number.

Example; Consider two numbers 4 and -5.

On multiplication,

4×(-5) = -20

Thus, the multiplication of two numbers with different signs will always give a negative number.

To know more about rational and irrational numbers, here

https://brainly.com/question/5796983

#SPJ2

As we know,

In a triangle, the sum of lengths of two side is greater than the third side.

[tex]20 + 25 > b[/tex]

[tex]b + 20 > 25[/tex]

[tex]25 + b > 20[/tex]

Answer = 15m

Answer:

We can calculate the price with both  sales by multiplying the 75.5 units of money by both percentages (to multiply them, we divide them by 100 first):

75.5 * 0.24 * 0.6 [tex]\approx.[/tex] 10.8

Answer:

"85.7%" is the right answer.

Step-by-step explanation:

According to the question,

The total capacity of water tank will be:

⇒ [tex]v_1=A\times 14[/tex]

The total volume of water will be:

⇒ [tex]v_2=A\times 12[/tex]

Now,

The percentage of total capacity will be:

= [tex]\frac{100\times v_2}{v_1}[/tex]

= [tex]\frac{v_2}{v_1}\times 100[/tex]

By putting the values, we get

= [tex]\frac{A\times 12}{A\times 14}\times 100[/tex]

= [tex]85.7[/tex]%

Answer:

(2x + y)(4x² - 2xy + y²)

Step-by-step explanation:

8x³ + y³ ← is a sum of cubes and factors in general as

a³ + b³ = (a + b)(a² - ab + b²) , then

8x³ + y³

= (2x)³ + y³

= (2x + y)((2x)² - 2xy + y²) , that is

(2x + y)(4x² - 2xy + y²)

Answer:

Area = 14.5

Step-by-step explanation:

Let's label the given coordinates A, B, C;

Thus;

A = (2, 3)

B = (-1, 0)

C = (2, -4)

From the coordinate geometry formula, the formula for area of a triangle with 3 vertices is;

Area = [Ax(By - Cy) + Bx(Cy - Ay) + Cx(Ay - By)]/2

Area = [2(0 - (-4)) + (-1)(-4 - 3) + 2(3 - (-4))]/2

Area = 29/2

Area = 14.5

Answer:

b) 2 Km para o leste

Step-by-step explanation:

1. 2 km N

2. 2 km W

3. 1 km S

4. 4 km E

5. 2 km S

Sul e Norte:

(1.) 2 km N + (3.) 1 km S + (5.) 2 km S = 2 km - 1 km - 2 km = 0

Este e Oeste:

(2.) 2 km W + (4.) 4 km E = -2 km + 4 km = 2 km E

Veja imagem abaixo.

Answer:

Pam laid 60 tiles on Saturday and 20 on Sunday.

Step-by-step explanation:

Given that Pam laid three times as many tiles on Saturday as she laid on Sunday, if Pam laid 80 tiles over the weekend altogether, to determine how many tiles did she lay on Saturday the following calculation must be performed:

3X + X = 80

4X = 80

X = 80/4

X = 20

Therefore, Pam laid 60 tiles on Saturday and 20 on Sunday.

Answer:

Domain = ( -∞ , ∞ )

Range = ( ∞ , ∞ )

Step-by-step explanation:

A function is given to us and we need to find the domain and range of the given function .

The function :-

[tex]\rm \implies y = \dfrac{1}{4}x - 6 [/tex]

Definitions :-

In this case, there is no real number that makes the expression undefined. Therefore the domain will be :-

Domain :-

[tex]\rm Domain = ( -\infty , \infty ) [/tex]

or

[tex]\rm Domain = \{ x | x \in \mathbb{R} \}[/tex]

Range :-

[tex]\rm Range = ( -\infty , \infty ) [/tex]

or

[tex]\rm Range = \{ y | y \in \mathbb{R}\} [/tex]

Answer:

Create a table or a graph of the function. The domain represents all input values and the range represents all output values. The domain and range contain all real numbers.

Step-by-step explanation:

Answer:

[tex] \rm Numbers = 4 \ and \ -3.[/tex]

Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

[tex]\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}[/tex]

Hence the numbers are 4 and -3

Let integers be x and x-1

ATQ

[tex]\\ \sf\longmapsto 2x-1=1[/tex]

[tex]\\ \sf\longmapsto 2x=1+1[/tex]

[tex]\\ \sf\longmapsto 2x+2[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{2}{2}[/tex]

[tex]\\ \sf\longmapsto x=1[/tex]

Now

[tex]\\ \sf\longmapsto x-1=1-1=0[/tex]

But

Integers can be x and 1-x as their sum is 1

[tex]\\ \sf\longmapsto x(1-x)=-12[/tex]

[tex]\\ \sf\longmapsto x- x^2=-12[/tex]

[tex]\\ \sf\longmapsto x^2-x-12=0[/tex]

[tex]\\ \sf\longmapsto x^2-4x+3x-12=0[/tex]

[tex]\\ \sf\longmapsto x(x-4)+3(x-4)=0[/tex]

[tex]\\ \sf\longmapsto (x-4)(x+3)=0[/tex]

[tex]\\ \sf\longmapsto x=4,-3[/tex]

Answer:

The probability of picking 1 red candle followed by another red candle is 16.66%.

Step-by-step explanation:

Since Alfred draws candles randomly from a pack containing 4 colored candles of the same shape and size, and there are 2 red candles, 1 green candle, and 1 blue candle, and he draws 1 candle and then draws another candle without replacing the first one, to find the probability of picking 1 red candle followed by another red candle, the following calculation must be performed:

2/4 x 1/3 = X

0.5 x 0.333 = X

0.16666 = X

Therefore, the probability of picking 1 red candle followed by another red candle is 16.66%.

Answer:

1/6

Step-by-step explanation:

2/4 x 1/3 = 1/6

Answer:

[tex]x=1[/tex]

[tex]y=2[/tex]

Step-by-step explanation:

[tex]y=x^2+3x-2[/tex] , [tex]y+3=5x[/tex]

Replace all occurrences of [tex]y[/tex] in [tex]y+3=5x[/tex] with [tex]x^2+3x-2.[/tex]

[tex](x^2+3x-2)+3=5x[/tex]

[tex]y=x^2+3x-2[/tex]

Add [tex]-2[/tex] and 3.

[tex]x^2+3x+1=5x[/tex]

[tex]y=x^2+3x-2[/tex]

Subtract 5x from both sides of the equation.

[tex]x^2+3x+1-5x=0[/tex]

[tex]y=x^2+3x-2[/tex]

Subtract 5x from 3x.

[tex]x^2-2x+1=0[/tex]

[tex]y=x^2+3x-2[/tex]

Rewrite 1 as [tex]1^2[/tex].

[tex]x^2-2x+1^2=0[/tex]

[tex]y=x^2+3x-2[/tex]

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

[tex]2x=2[/tex] · [tex]x[/tex] · [tex]1[/tex]

[tex]y=x^2+3x-2[/tex]

Rewrite the polynomial.

[tex]x^2-2[/tex] · [tex]x[/tex] · [tex]1[/tex] [tex]+[/tex] [tex]1^2=0[/tex]

[tex]y=x^2+3x-2[/tex]

Factor using the perfect square

trinomial rule [tex]a^2-2ab+b^2=(a-b)^2,[/tex]

where a = x and b = 1.

[tex](x-1)^2=0[/tex]

[tex]y=x^2+3x-2[/tex]

Set the [tex]x-1[/tex] equal to 0.

[tex]x-1=0[/tex]

[tex]y=x^2+3x-2[/tex]

Add 1 to both sides of the equation.

[tex]x=1[/tex]

[tex]y=x^2+3x-2[/tex]

Replace all occurrences of [tex]x[/tex] in

[tex]y=x^2+3x-2[/tex] with 1.

[tex]y=(1)^2+3(1)-2[/tex]

[tex]x=1[/tex]

[tex]y=2[/tex]