If we transform the parabola y=(x+1)^2+2 by shifting 7 units to the right and 5 units down, what is the vertex of the resulting parabola? Vertex of resulting parabola: (__ a0,__ a1)

Answer:

Option A is the correct option.

Step-by-step explanation:

Surface area of the rectangle base = 9 × 5 = 45 in²

Surface area of lateral square = ( 5 )² = 25 in²

Surface area of lateral rectangle = 6.4 × 5 = 32 in²

Surface area of top square = ( 5 )² = 25 in²

Surface area of two parallel trapezoids:

[tex] (\frac{1}{2} (9 + 5) \times 5) \times 2[/tex]

= 7 × 5 × 2

= 70 in²

Total surface area:

= 45 + 25 + 32 + 25 + 70

= 197 in²

Hope I helped!

Best regards!

Answer:

see explanation

Step-by-step explanation:

f(g(2)) = f(0) = -2

g(f(1)) = g(0) = 0

Answer:

The correct answers for both of them is -2 and 0.

Step-by-step explanation:

I)

[tex](f\circ g)(2)=f(g(2))[/tex]

From the red graph, we can see that g(2) is 0.

Therefore, f(g(2)) is equal to f(0).

And from the blue graph, we can see that f(0) is -2.

Therefore:

[tex](f\circ g)(2)=-2[/tex]

II)

[tex](g\circ f)(1)=g(f(1))[/tex]

From the blue graph, we can see that f(1) is 0.

Therefore, g(f(1)) is equal to g(0).

And from the red graph, g(0) is 0.

Therefore:

[tex](g\circ f)(1)=0[/tex]

So, you got one correct. Nicely done!

Answer:

going from new to original would be times 2.5

from original to new would be time 0.4

Step-by-step explanation:

new to original is the 250/100

original to new is 100/250

Answer:

-60%

Step-by-step explanation:

First, find the difference

250 - 100 = 150

Then divide the decrease by the original number

150/250 = 0.6

And to convert this to a percentage all you have to do is multiply it by 100

0.6(100) = 60

The percent of change is -60% which is a decrease since it's negative

Answer:

Step-by-step explanation:

The rule for the sequence is

[tex]A(n) = 5. {2}^{x - 1} [/tex]

where x is the number of terms

For the first term

x = 1

That's

[tex]A(1) = 5. {2}^{1 - 1} [/tex]

[tex]A(1) = 5. {2}^{0} [/tex]

A(1) = 5(1)

For the fourth term

x = 4

[tex]A(4) = 5. {2}^{4 - 1} [/tex]

[tex]A(4) = 5. {2}^{3} [/tex]

A(4) = 5(8)

For the eighth term

x = 8

[tex]A(8) = 5. {2}^{8 - 1} [/tex]

[tex]A(8 ) = 5. {2}^{7} [/tex]

A(8) = 5(128)

Hope this helps you

Answer:

The first option.

Step-by-step explanation:

The first term of the sequence would be...

A(1) = -5 * 2^(1 - 1)

= -5 * 2^0

= -5 * 1

= -5

The fourth would be...

A(4) = -5 * 2^(4 - 1)

= -5 * 2^3

= -5 * 8

= -40

The eighth would be...

A(8) = -5 * 2^(8 - 1)

= -5 * 2^7

= -5 * 128

= -640

So, the correct answer is the first option.

Hope this helps!

Answer:

x = 148

Step-by-step explanation:

CPD is a straight line so it equals 180

CPB + BCD = CPD

x + 32 = 180

Subtract 32 from each side

x+32-32 = 180-32

x =148

Answer:

998

Step-by-step explanation:

I haven't included the 1 or the 1000

Answer:

There are 200 numbers between 1 and 1000  that do not contain the digits 8, and 9.

Step-by-step explanation:

1-100

=(8,9,18,19,28,29,38,39,48,49,58,59,68,69,78,79,88,89,98,99)=20

101-200

=(108,109,118,119,128,129,138,139,148,149,158,159,168,169,178,179,188,189,198,199)=

201-300=20

.......

100*10=1000

20*10=200

Answer:

Bottom right option

Step-by-step explanation:

To find this, we can calculate:

1/2 * 4.32 * 10⁻⁴

= (1/2 * 4.32) * 10⁻⁴

= 2.16 * 10⁻⁴

The diameter of a new cell is 2.16×10−⁴millimeters

First step is to calculate 4.32×10−⁴ to the original numbers

4.32×10−⁴ =0.000432

Second step is to determine the diameter of a new cell

New cell diameter=0.000432×1/2

New cell diameter=0.000216

New cell diameter=2.16×10−⁴millimeters

Inconclusion The diameter of a new cell is 2.16×10−⁴millimeters

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Step-by-step explanation:

Hello, there!!!

The answer is option D.

I have given solution on the picture.

Hope it helps.....

Answer:

using the equilateral formula of solution

Answer:

[tex]x^2-3\geq 12[/tex]

Step-by-step explanation:

[tex]x^{2} -3[/tex] is the difference of a number squared and three

is at least 12, means that is greater but not less

[tex]x^2-3\geq 12[/tex]

Answer:

I think it is b

Step-by-step explanation:

Answer:

1/6 or 16.7% chance

Step-by-step explanation:

A die has 6 sides, and there is only one side with a number divisible by 5, which is the number 5.

So, the probability of rolling a number divisible by 5 is 1/6.

= 1/6 or 0.167

The odds in favor of obtaining a number divisible by 5 will be 1/6 or 0.1667.

Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.

The die is rolled for a single time. Then the total number of the events will be

Total event = 6 {1, 2, 3, 4, 5, 6}

The odds in favor of obtaining a number divisible by 5 will be

There is only one number that is divisible by 5 which is 5.

Then the number of favorable events will be

Favorable event = 1 {5}

Then the probability will be

P = 1 / 6

P = 0.1667

The odds in favor of obtaining a number divisible by 5 will be 1/6 or 0.1667.

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Answer:

The conjugate is 2+5i and the product is 29.

Step-by-step explanation:

The conjugate of a complex number [tex]a+bi[/tex] is [tex]a-bi[/tex]

Our complex number is 2-5i.

Here, a = 2 and b = -5

Thus, the conjugate of 2-5i is

[tex]2-(-5i)=2+5i[/tex]

Using this rule:

[tex](a+b)(a-b)=a^{2}-b^{2}[/tex]

And the fact that [tex]i^{2} = -1[/tex]

We can find the product of any complex number and its conjugate:

[tex](a+bi)(a-bi)=a^{2} - (bi)^{2}=a^{2} - b^{2} i^{2} = a^{2} + b^{2}[/tex]

As our complex number is [tex]2-5i[/tex], the product with its conjugate will be

[tex]2^{2} + (-5)^{2} =4+25=29[/tex]

[tex]\dfrac{\dfrac{1}{p-2}}{\dfrac{4p^2}{p^2+p-6}}=\\\\\\\dfrac{1}{p-2}\cdot\dfrac{p^2+p-6}{4p^2}=\\\\\dfrac{1}{p-2}\cdot\dfrac{p^2+3p-2p-6}{4p^2}=\\\\\dfrac{1}{p-2}\cdot\dfrac{p(p+3)-2(p+3)}{4p^2}=\\\\\dfrac{1}{p-2}\cdot\dfrac{(p-2)(p+3)}{4p^2}=\\\\\dfrac{p+3}{4p^2}[/tex]

--------------------------------------------------------------------

[tex]\dfrac{6n}{3n+2}-\dfrac{2}{2n-2}=\\\\\dfrac{6n(2n-2)}{(3n+2)(2n-2)}-\dfrac{2(3n+2)}{(3n+2)(2n-2)}=\\\\\dfrac{12n^2-12n-(6n+4)}{6n^2-6n+4n-4}=\\\\\dfrac{12n^2-12n-6n-4}{6n^2-2n-4}=\\\\\dfrac{12n^2-18n-4}{6n^2-2n-4}=\\\\\dfrac{2(6n^2-9n-2)}{2(3n^2-n-2)}=\\\\\dfrac{6n^2-9n-2}{3n^2-n-2}[/tex]

----------------------------------------------------------------------

[tex]\dfrac{2x}{3x^2+18x}+\dfrac{3}{2}=\\\\\dfrac{2}{3x+18}+\dfrac{3}{2}=\\\\\dfrac{2\cdot2}{2(3x+18)}+\dfrac{3(3x+18)}{2(3x+18)}=\\\\\dfrac{4+9x+54}{6x+36}=\\\\\dfrac{9x+58}{6x+36}[/tex]

Answer:

p^3−10p^2+1

——————        We find roots of zeros  F(p) = p^3 - 10p^2 + 1 and see there

      p^2                                             are no rational roots

Step-by-step explanation:

                 p^2

Simplify   ——

                 p^2

1.1    Canceling out p^2 as it appears on both sides of the fraction line

   Equation at the end of step 1

:1

 ((————-(4•1))+p)-6

   (p^2)

STEP 2: working left to right

                  1

Simplify   ——

                 p^2

Equation at the end of step 2:    

1 /p^2 ((—— -  4) +  p) -  6

STEP 3:

Rewriting the whole as an Equivalent Fraction

3.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  p^2  as the denominator :

          4         4 • p^2

   4 =  —  =  ——————

           1             p^2  

Equivalent fraction

: The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

             1 - (4 • p^2)                 1 - 4p^2

————————————  =  ———————

                    p^2                             p^2  

Equation at the end of step 3:

        (1 - 4p^2)          

 (————————— +  p) -  6

             p^2              

STEP 4:

Rewriting the whole as an Equivalent Fraction

4.1   Adding a whole to a fraction

Rewrite the whole as a fraction using  p2  as the denominator :

           p         p • p^2

   p =  —  =  ——————

           1             p^2  

Trying to factor as a Difference of Squares:

4.2      Factoring:  1 - 4p^2

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check :  1  is the square of  1

Check : 4 is the square of 2

Check :  p^2  is the square of  p^1

Factorization is :       (1 + 2p)  •  (1 - 2p)

Adding fractions that have a common denominator :

4.3       Adding up the two equivalent fractions

                (2p+1) • (1-2p) + p • p^2                                   p^3 - 4p^2 + 1

————————————————————————  =  ————————————

                               p^2                                                            p^2    

Equation at the end of step

4:

        (p^3 - 4p^2 + 1)    

 —————————————— -  6

                 p^2          

STEP 5:

Rewriting the whole as an Equivalent Fraction

5.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  p^2  as the denominator :

           6         6 • p^2

   6 =  —  =  ——————

           1             p^2  

Polynomial Roots Calculator :

5.2    Find roots (zeroes) of :       F(p) = p^3 - 4p^2 + 1

Polynomial Roots Calculator is a set of methods aimed at finding values of  p  for which   F(p)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  p  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  1  and the Trailing Constant is  1.

The factor(s) are:

of the Leading Coefficient :  1

of the Trailing Constant :  1

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        -4.00    

     1       1        1.00        -2.00    

Polynomial Roots Calculator found no rational roots

Adding fractions that have a common denominator :

5.3       Adding up the two equivalent fractions

(p3-4p2+1) - (6 • p2)     p3 - 10p2 + 1

—————————————————————  =  —————————————

         p2                    p2      

Polynomial Roots Calculator :

5.4    Find roots (zeroes) of :       F(p) = p3 - 10p2 + 1

    See theory in step 5.2

In this case, the Leading Coefficient is  1  and the Trailing Constant is  1.

The factor(s) are:

of the Leading Coefficient :  1

of the Trailing Constant :  1

Let us test ....

  P       Q    P/Q       F(P/Q)  Divisor

     -1      1        -1.00       -10.00    

       1      1    1.00       -8.00    

Polynomial Roots Calculator found no rational roots

Final result :

             p3 - 10p2 + 1

 —————————————

                 p2      

[tex]k+\frac{k}{2}+\frac{k}{6}=120\\\\6k+3k+k=720\\10k=720\\k=72[/tex]

72,36,12

answer: 36

Hence, the m∠DCA is 59.2

An angle is a combination of two rays (half-lines) with a common endpoint. The latter is known as the vertex of the angle and the rays as the sides, sometimes as the legs, and sometimes the arms of the angle.

m∠DCB = (4x) + (6x-58) = 90

10x = 148

x = 14.8

m∠DCA = 4x

             = 4(14.8)

             = 59.2

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Answer:

Numbers provided:

-56, 90, -84, 59, -80, 48

The smallest number is -84.

The highest number is 90.

1st: -84

2nd: -80

3rd: -56

4th: 48

5th: 59

6th: 90

Answer:

  13.4 meters

Step-by-step explanation:

About the diagram

Attached is a diagram of the problem. The directions North and East are shown so that the usual clockwise from +x measurement of angles will correspond to the bearing angles given in the problem. That is, the bearing of 120° is an angle of 120° measured from North toward East. (The mirroring across the line y=x can be a little mind-bending, but it is isomorphic, so all angles and lengths remain unchanged.)

The other feature of this diagram is the projection of the 3-D problem into two dimensions. Effectively, the center angle rabbit-O-coyote represents a plan view (in the plane of the ground), and the triangles coyote-O-C1 and rabbit-O-R1 represent side views (views in the vertical plane).

The side views let us work out the ground distances O-rabbit and O-coyote, so that we can find the ground distance rabbit-coyote as the problem requests.

__

Problem solution

The distance from the tree (O) to the rabbit is the "adjacent" leg of the 30° angle of elevation from the rabbit to the tree top. The 10 m tree height is the "opposite" leg of that rabbit-O-R1 right triangle. We know the ratio of opposite to adjacent sides gives the tangent of the angle, so we have ...

  tan(30°) = 10/(rabbit distance from tree)

Solving for the rabbit distance, we get

  rabbit distance = 10/tan(30°) ≈ 17.3205 m

Similarly, the coyote distance from the tree will be ...

  coyote distance = 10/tan(20°) ≈ 27.4748 m

__

These are two legs of the rabbit-O-coyote triangle. The angle at O between the rabbit and coyote is 120° -97° = 23°. These values are sufficient to let us use the Law of Cosines to find the distance d from rabbit to coyote:

  d² = r² +c² -2rc·cos(23°)

  d² = 17.3205² +27.4748² -2·17.3205·27.4748·cos(23°) ≈ 178.769

  d ≈ √178.769 ≈ 13.37 . . . . meters

The distance from the rabbit to the coyote is about 13.4 meters.

_____

Additional comment

Note that the angle of depression to the rabbit from the horizontal is the same as the angle of elevation from the rabbit. This lets us draw the diagram without a bunch of extra lines.

Answer:

25

Step-by-step explanation:

The overall range of all scores in all three sections is 25.

In mathematics, the middle value—which is determined by dividing the sum of all the values by the total number of values—is the average value in a set of numbers. To calculate the average of a set of data, add up all the values and divide the result by the total number of values.

Given:

The range of 3 sections is 28, 25 and 22.

So, the overall range of all scores in all three sections

= (28+ 25+ 22)/ 3

= 75/3

= 25

Hence, the overall range of all scores in all three sections is 25.

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Answer:

A. 1010 FT^3

Step-by-step explanation:

19 x 14.5 x 5 = 1377.5

you need to subtract now, so the only option would be A

Answer:

[tex]1,010 ft^{3}[/tex]

Step-by-step explanation:

You can break the figure into 2 sections; one with the dimensions of 4, 5 and 7; the other with dimensions of 14.5, 5, and 12.

Multiply the first three dimensions (4, 5 and 7) to get 140 ft cubed.

Multiply the last three dimensions (14.5, 5, and 12) to get 870 ft cubed.

Now, just add both volumes together to get 1,010 ft cubed!

Hope that helps and maybe earns a brainliest!

Have a great day! :)

Answer:

8.48

Step-by-step explanation:

After removing the perfect square inside √72 we get,

6√2

The given square root is,

√72

Since we know that,

A perfect square is a number that is stated as the product of an integer multiplied by itself. The perfect square is also represented as the second exponent of an integer since the same number is multiplied twice. The squares of all integers are hence referred to as perfect squares.

Simplify the square root of 72.

Factor 72 into 36 and 2,

Giving us the square root of 36 times the square root of 2.

Therefore,

√72 = √36 x √2

We know that the square root of 36 is 6,

So we can substitute that in:

√72 = 6 x √2

Hence after removing the perfect square inside √72 we get,

6√2.

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Answer:

$4661.77

Step-by-step explanation:

100 + 4.7 = 104.7%

104.7% = 1.047

$2340.73 x 1.047^15 = $4661.77

The type of model best fits the given situation is a quadratic equation

Quadratic equations are equation that has a leading degree of 2.

From the given question, the motion of the rocket from the launch point to the landing point will be parabolic in nature and since the graph of a quadratic function is a parabola, hence the type of model best fits the given situation is a quadratic equation

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Answer:

D) (–5,0), (0,2), (5,0), (0,–2)

Step-by-step explanation:

The vertices are basically the x and y intercepts.

Answer:

10

Step-by-step explanation

Answer:

10

Step-by-step explanation:

Answer:

a is the answer 28.50 + b = 45.50

Step-by-step explanation:

so if i move 28.50 to the right side then it becomes b=45.50-28.50 and that equals to 17 . hope i helped have a great day

=================================================

Explanation:

28.50 = cost of shirt

b = cost of belt, some unknown value

45.50 = total cost (given)

28.50+b = total cost (add the first two items shown above)

equate the two total cost expressions to end up with 28.50+b = 45.50

Answer: interval from -8 to 5

In interval notation, we would write [-8, 5]

The domain is the set of allowed x inputs to a function. The left-most point is (-8,0) so x = -8 is the smallest x value allowed. The largest x value allowed is x = 5 due to the point (5,0) being the right-most point.

The use of square brackets in interval notation says "include this endpoint as part of the interval".

Answer:

[tex]\mathbf{V = [\dfrac{ 8 \pi }{3}] }[/tex]

Step-by-step explanation:

Given that:

y = 6x - x² , y = 8  about  x = 2

To find the volume of the region bounded by the curves about x = 2; we have the radius of the cylindrical shell to be x - 1, the circumference to be 2 π (x -2 ) and the height to be 6x - x² - 8

6x - x² - 8

6x - x² - 8 = 0

-x² + 6x - 8 = 0

x² - 6x + 8 = 0

(x -4) (x - 2  ) = 0

So;

x = 2 , x = 4

Thus, the region bound of the integral  are from a = 2 and b = 4

Therefore , the volume of the solid can be computed as :

[tex]V = \int \limits ^b _a \ 2x \times f(x) \ dx[/tex]

[tex]V = \int \limits ^4_2 2 \pi (x -2) (6x -x^2 -8) \ dx[/tex]

[tex]V = 2 \pi \int \limits ^4_2 (6x^2 - x^3 -8x -12 x - 2x^2 +16) \ dx[/tex]

[tex]V = 2 \pi \int \limits ^4_2 (8x^2 -x^3-20x +16) \ dx[/tex]

[tex]V = 2 \pi \int \limits ^4_2 ( -x^3+8x^2-20x +16) \ dx[/tex]

[tex]V = 2 \pi [\dfrac{ -x^7}{4}+\dfrac{8x^3}{3} -\dfrac{20x^2}{2} +16x]^4_2[/tex]

[tex]V = 2 \pi [\dfrac{ -(4^4-2^4)}{4}+\dfrac{8(4^3-2^3)}{3} -\dfrac{20(4^2-2^2)}{2} +16(4-2) ]^4_2[/tex]

[tex]V = 2 \pi [\dfrac{ -(256-16)}{4}+\dfrac{8(64-8)}{3} -10(16-4)} +16(2) ][/tex]

[tex]V = 2 \pi [\dfrac{ 4}{3}][/tex]

[tex]\mathbf{V = [\dfrac{ 8 \pi }{3}] }[/tex]