If using the method of completing the square to solve the quadratic equation
x^2 + 8x – 4 = 0, which number would have to be added to "complete the square"?

Answer:

She must buy more than 5 lbs

Step-by-step explanation:

First write the inequality

cost per pound * number of pounds >  total cost

8 * lbs > 40

Divide each side by 8

8 lbs /8 > 40/8

lbs > 5

She must buy more than 5 lbs

Answer:

No entiendo

Step-by-step explanation:

right triangle

Hope this helps! :)

Answer:

C) 5.66

Step-by-step explanation:

For a 45-45-90 triangle, the length of each leg length (not including the hypotenuse) is congruent to each other. If 8=y√2, then y=8/√2=4√2=5.66

Answer:

5.66

Step-by-step explanation:

take 45 degree as reference angle

using cos rule

cos 45 =adjacent /hypotenuse

[tex]\frac{1}{\sqrt{2} }[/tex] =y/8

[tex]\frac{1}{\sqrt{2} } *8=y[/tex]

[tex]\frac{8}{\sqrt{2} }=y[/tex]

[tex]4\sqrt{2} =y[/tex]

5.66=y

Given:

x-intercepts of the hyperbola are ±4.

The foci of hyperbola are [tex]\pm 2\sqrt{5}[/tex].

Center of the hyperbola is at origin.

To find:

The equation of the hyperbola.

Solution:

The general equation of a hyperbola:

[tex]\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1[/tex]            ...(i)

Where, (h,k) is the center of the hyperbola, ±a are x-intercepts, [tex](\pm c,0)[/tex] are foci.

Center of the hyperbola is at origin. So, h=0 and k=0.

x-intercepts of the hyperbola are ±4. So,

[tex]\pm a=\pm 4[/tex]

[tex]a=4[/tex]

The foci of hyperbola are [tex]\pm 2\sqrt{5}[/tex].

[tex]\pm c=\pm 2\sqrt{5}[/tex]

[tex]c=2\sqrt{5}[/tex]

We know that,

[tex]a^2+b^2=c^2[/tex]

[tex](4)^2+b^2=(2\sqrt{5})^2[/tex]

[tex]16+b^2=20[/tex]

[tex]b^2=20-16[/tex]

[tex]b^2=4[/tex]

Taking square root on both sides, we get

[tex]b=\sqrt{4}[/tex]                    [b>0]

[tex]b=2[/tex]

Substituting [tex]h=0,k=0,a=4,b=2[/tex] in (i), we get

[tex]\dfrac{(x-0)^2}{4^2}-\dfrac{(y-0)^2}{2^2}=1[/tex]

[tex]\dfrac{x^2}{4^2}-\dfrac{y^2}{2^2}=1[/tex]

Therefore, the correct option is (d).

[tex]\longrightarrow{\green{7 \frac{20}{21}}}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex]1 \frac{6}{9} + 5 \frac{9}{7} \\ \\ = \frac{15}{9} + \frac{44}{7} \\ \\ = \frac{15 \times 7}{9 \times 7} + \frac{44 \times 9}{7 \times 9} \\ \\ = \frac{105 + 396}{63} \\ \\ = \frac{501}{63} \\ \\ = \frac{167}{21} \\ \\ = 7 \frac{20}{21} [/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}[/tex]

[tex] \large \boxed{(f + g)(x) = f(x) + g(x)}[/tex]

Use the following property above to find the value. Substitute f(x) and g(x) in.

[tex] \large{(2x + 3) + ( {x}^{2} - 8)} \\ \large{2x + 3 + {x}^{2} - 8}[/tex]

Evaluate/Combine like terms.

[tex] \large{2x + {x}^{2} - 5}[/tex]

This step is optional but it's the best to arrange the degree.

[tex] \large{ {x}^{2} + 2x - 5} \\ \large{(f + g)(x) = {x}^{2} + 2x - 5}[/tex]

Answer

Let me know if you have any doubts!

Answer:

Percentage of U.S resident who used the Internet for e-mail were Hispanic=9.19%

Step-by-step explanation:

We are given that

Population was Caucasian=64%

Population was African-American=11%

Population was Hispanic=10%

Let the population of U.S=10000

Now,

Population was Caucasian=[tex]\frac{64}{100}\times10000=6400[/tex]

Population was African-American=[tex]\frac{11}{100}\times 10000=1100[/tex]

Population was Hispanic=[tex]\frac{10}{100}\times 10000=1000[/tex]

Population of others=10000-(6400+1100+1000)=1500

Population of Caucasians used the Internet for e-mail=86% of 6400

Population of Caucasians used the Internet for e-mail=[tex]\frac{86}{100}\times 6400[/tex]

Population of Caucasians used the Internet for e-mail=5504

Population of African-American used the Internet for e-mail=77% of 1100

Population of African-American used the Internet for e-mail=[tex]\frac{77}{100}\times 1100=847[/tex]

Population of Hispanics used the Internet for e-mail=77% of 1000

Population of Hispanics used the Internet for e-mail=[tex]\frac{77}{100}\times 1000=770[/tex]

Population of others used the Internet for e-mail=84% of 1500

Population of others used the Internet for e-mail=[tex]\frac{84}{100}\times 1500=1260[/tex]

Total population used the Internet for e-mail=5504+847+770+1260

Total population used the Internet for e-mail=8381

Percentage of U.S resident who used the Internet for e-mail were Hispanic

=[tex]\frac{Population \;of \;Hispanics \;used \;the \;Internet \;for \;e-mail}{total\;population\; used \;the \;Internet \;for\; e-mail}\times 100[/tex]

Percentage of U.S resident who used the Internet for e-mail were Hispanic=[tex]\frac{770}{8381}\times 100[/tex]

Percentage of U.S resident who used the Internet for e-mail were Hispanic=9.19%

Answer:

There are more females dropping than males each year and that there are more females than males

Answer:

A) 3 ways

B) sorry don't know.

Step-by-step explanation:

2 P and 2 N

3P and 1 N

4P

So 3 ways.

Answer:

I'm gonna guess your length is positive and you made a typing mistake. If that's so....

Step-by-step explanation:

Area= length x breadth

       =[tex]\frac{3}{7\\}[/tex] x [tex]\frac{16}{3}[/tex]

       =[tex]\frac{16}{7}[/tex]

       =2.29 [tex]unit^{2}[/tex]

Let q be the number of quarts of pure antifreeze that needs to be added to get the desired solution.

8 quarts of 40% solution contains 0.40 × 8 = 3.2 quarts of antifreeze.

The new solution would have a total volume of 8 + q quarts, and it would contain a total amount of 3.2 + q quarts of antifreeze. You want to end up with a concentration of 60% antifreeze, which means

(3.2 + q) / (8 + q) = 0.60

Solve for q :

3.2 + q = 0.60 (8 + q)

3.2 + q = 4.8 + 0.6q

0.4q = 1.6

q = 4

Answer:

44.94

Step-by-step explanation:

Answer: You didnt mention how much Dan mows in 1 hour, but just do that divided by 60

Step-by-step explanation:

Answer:

Step-by-step explanation:

The element decay percentage rate of change 2.22% per minute.

Radioisotope, radionuclide, or radioactive nuclide, any of several species of the same chemical element with different masses whose nuclei are unstable and dissipate excess energy by spontaneously emitting radiation in the form of alpha, beta, and gamma rays.

Here, mass decreases by 73% every hour.

Weight of element X is 680 grams.

According to question,

f(t) = 680 (1 - 73%)ⁿ

f(t) = 680 (1 - 0.73)ⁿ

f(t) = 680 X 0.27ⁿ

f(t) = 680 X 0.9778ⁿ

f(t) = 680 X (1 - 0.02322)ⁿ

Thus, the element decay percentage rate of change 2.22% per minute.

Learn more about radioactive isotope from:

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Answer:

[tex]\% = 11.96\%[/tex]

Step-by-step explanation:

Given

See attachment for box plot

Required

Percentage greater than or equal to 233

From the box plot, the maximum is:

[tex]Max = 244[/tex]

The minimum is:

[tex]Min = 152[/tex]

Percentage greater than 233 is calculated as:

[tex]\% = \frac{Max - 233}{Max - Min}[/tex]

[tex]\% = \frac{244 - 233}{244-152}[/tex]

[tex]\% = \frac{11}{92}[/tex]

Express as percentage

[tex]\% = \frac{11}{92}*100\%[/tex]

[tex]\% = \frac{1100}{92}\%[/tex]

[tex]\% = 11.96\%[/tex]

Answer:

24 per day

Step-by-step explanation:

'x' = days, so since 24 is with x, the rate of change is 24

Answer:

[tex]GQ =25[/tex] --- GoTV

Step-by-step explanation:

Given

[tex]GQ = 2x + 3[/tex]

[tex]GH= 5x - 5[/tex]

Required

Find GQ

Since Q is the midpoint, then:

[tex]GH = 2 * GQ[/tex]

This gives:

[tex]5x - 5 = 2[2x+3][/tex]

Open bracket

[tex]5x - 5 = 4x+6[/tex]

Collect like terms

[tex]5x - 4x = 5+6[/tex]

[tex]x =11[/tex]

We have:

[tex]GQ =2x+3[/tex]

This gives:

[tex]GQ =2*11+3[/tex]

[tex]GQ =25[/tex]

Answer:

28/16=14/8 true

3/5=9/15 true

4/32=10/78 false

3/4=12/16 true

Step-by-step explanation:

DID IT ON BRIDGE

the graph that he needs to do is a straight line from the origin that passes through (3, 0.75), the correct option is the last one.

He knows the relation:

3 cups of granola ⇒ 0.75 cups of raisins.

Assuming this is a proportional relation of the form:

y = k*x

Where k is a constant.

Then when x = 0, we also have y = 0, so the line also passes through the point (0, 0), which is the origin.

Then the graph that he needs to do is a straight line from the origin that passes through (3, 0.75), the correct option is the last one.

If you want to learn more about proportional relationships:

https://brainly.com/question/12242745

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Answer:

Step-by-step explanation:

The formula to find the angle between 2 vectors is

[tex]cos\theta=\frac{u*v}{|u||v|}[/tex] which is the dot product of u*v over the (magnitude of u times the magnitude of v). We also know that θ = [tex]\frac{\sqrt{2} }{2}[/tex]. Filling in that formula requires us to find the dot product of u and v, which is

u·v = (2×(-6)) + (a×8) so

u·v = -12 + 8a. Then we need the magnitudes of both u and v:

[tex]|u|=\sqrt{2^2+a^2}=\sqrt{4+a^2}[/tex] and

[tex]|v|=\sqrt{(-6)^2+8^2}=\sqrt{100}=10[/tex]

Putting all of together looks like this:

[tex]\frac{\sqrt{2} }{2}=\frac{-12+8a}{10\sqrt{4+a^2} }[/tex] . Cross multiply to get

[tex]10\sqrt{2}(\sqrt{4+a^2})=2(-12+8a)[/tex] which is tricky to simplify. You really need to know the rules for multiplying radicals to do this correctly. The simplification is

[tex]10\sqrt{8+2a^2}=-24+16a[/tex] and we need to solve for a. Begin by squaring both sides to get rid of the square root to get:

100(8 + 2a²) = 256a² - 768a +576 and simplify some more by distributing through the parenthesis to get

800 + 200a² = 256a² -768a + 576. Combine like terms to come up with

0 = 56a² - 768a - 224 and we need to factor that. Assuming since you're this far in math (pre-calc or maybe late algebra 2) you know how to factor, when you do, you get values for a of - .285714... and 14.

Therefore, the value for a is 14. I checked it...it works

Answer:

a = 14, U = (2, 14)

Step-by-step explanation:

the other answer is correct.

just to add the solution path for the quadratic equation

0 = 56a² - 768a - 224

in general, a quadratic equation usually expressed in x

0 = ax² + bx + c

has its solution as

x = (-b ± sqrt(b² - 4ac))/(2a)

for us here this looks like this then

a = (768 ± sqrt(768² - 4×56×-224))/(2×56) =

= (768 ± sqrt(589824 + 4×56×224))/112 =

= (768 ± sqrt(589824 + 50176))/112 =

= (768 ± sqrt(640000))/112 = (768 ± 800)/112

a1 = (768 + 800)/112 = 1568/112 = 14

a2 = (768 - 800)/112 = -32/112 = -0.29

and the negative solution would be for a vector solution in the wrong direction (down instead of up). as V is pointing up left, and the angle is only 45 degrees (pi/4), also U has to point up.

so, 14 is the solution for U.

Answer:

both apply

Step-by-step explanation:

i guessed just do it

Answer:

2

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

Answer: 0.973

Step-by-step explanation:

The probability mass function of geometric distribution is

[tex]f(x)=(1-p)^{x-1}p,\ \ \ x=1,2,3,...[/tex], p= probability of success on a trial.

As per given, we have

p=0.7

The probability that we'll have at most 3 orders [tex]P(X\leq3)=P(x=1)+P(x=2)+P(x=3)[/tex]

[tex]=(1-0.7)^{1-1}(0.7)+(1-0.7)^{2-1}(0.7)+(1-0.7)^{3-1}(0.7)\\\\=0.7+0.21+0.063\\\\=0.973[/tex]

hence, the required probability = 0.973

The probability that we'll have at most 3 orders will be "0.973".

According to the question,

→ [tex]x \sim Geometric (p)[/tex]

here,

p = 0.7

then,

→ [tex]P(X=x) = (1-p)^{x-1}\times p[/tex]

By putting the given values, we get

                   [tex]= (1-0.7)^{x-1}\times 0.7[/tex]

hence,

The probability that we'll have at most 3 orders will be:

→ [tex]P(X \leq 3)=P(X=1)+P(X=2)+P(X=3)[/tex]

                   [tex]=0.7+0.21+0.063[/tex]

                   [tex]=0.973[/tex]

Thus the above response is correct.

Learn more about probability here:

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Answer:

[tex]( {x}^{2} + 12)(x + 2)[/tex]

Step-by-step explanation:

[tex] {x}^{3} +2 {x}^{2} +12x+24[/tex]

[tex]( {x}^{3}+2 {x}^{2} )+12x+24[/tex]

[tex] {x}^{2} (x+2)+12(x+2)[/tex]

[tex]( {x}^{2} + 12)(x + 2)[/tex]

Answer:

Step-by-step explanation:

A customer satisfaction survey refers to a questionnaire that's designed by a company in order for businesses to know what customers think about their products.

Since the manager of a local car dealership wants to conduct a customer satisfaction survey, then the group of people should make up a sample of the population will be the people who bought cars from the dealership

Answer:

c

Step-by-step explanation:

See the graph in the attached image.

Answer:

334.4 m²

Step-by-step explanation:

The formula for the area of a sector is given as:

1/2 × r² × θ

Where θ = Central angle

Area of a Circle = 700 m²

The formula for the area of a circle = πr²

r = Radius of a circle

r² = Area / π

r = √Area / π

r = √700/π

r = 14.927053304 m

Approximately, r = 14.93 m

Therefore, the area of the sector

= 1/2 × r² × θ

= 1/2 × 14.93² × 3 rad

= 334.35735 m²

Approximately, Area of the sector = 334.4 m²