If two of the ordered pairs was removed which two data points will cause the correlation to decrease the most? Select Two points

1) Data point A

2) Data point B

3) Data point C

4) Data point D

Answer:

-i

Step-by-step explanation:

(-i)^0 = 1

(-i)^1 = -i

(-i)^2 = -1

(-i)^3 = -i

(-i)^4 = 1

(-i)^5 = -i

etc.

From this pattern, you see that when the exponent is a multiple of 4, you get 1. When the exponent is a multiple of 4 plus 1, you get -i, etc.

213 = 4 * 53 + 1

213 is 1 more than a multiple of 4.

(-i)^213 = (-i)^1 = -i

Answer:

0.88175960442

Step-by-step explanation:

The square root of 0.7775 is 0.88175960442

The value of standard deviation will be;

⇒ 0.8803

What is mean by square root of a number?

A square root of a number is a value that multiplied by itself gives the same number.

Given that;

The value of Variance = 0.7775

Now,

Since, The standard deviation is the square root of the variance.

Hence, We can formulate;

The value of standard deviation = √0.7775

                                                 = 0.8803

Thus, The value of standard deviation will be;

⇒ 0.8803

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Answer:

The functions are [tex]f(x) = 7\cdot x+10[/tex] and [tex]g(x) = \frac{1}{x^{2}}[/tex], respectively.

Step-by-step explanation:

Let suppose that [tex]g(x) = \frac{1}{x^{2}}[/tex], then [tex]f(g(x))[/tex] is:

[tex]f(g(x)) = 7\cdot \left(\frac{1}{x^{2}} \right) + 10[/tex]

[tex]f(g(x)) = 7\cdot g(x) + 10[/tex]

Thus,

[tex]f(x) = 7\cdot x + 10[/tex]

The functions are [tex]f(x) = 7\cdot x+10[/tex] and [tex]g(x) = \frac{1}{x^{2}}[/tex], respectively.