If the temperature of a reversible reaction in dynamic equilibrium decreases, how will the equilibrium change?

A. It will shift towards the endothermic reaction.
B. It will not change.
C. It will shift towards the products.
D. It will shift towards the exothermic reaction.

Answers

Answer 1

Answer:

D. It will shift towards the exothermic reaction.

Explanation:


Related Questions

How many grams of hydrogen is produced from 12.5 G of MG reacting with hydrochloric acid in this balanced equation?
Mg+ 2HCL —>MgCl2+H2

Answers

Answer:

1.03 grams of hydrogen is produced from 12.5 g of Mg reacting with hydrochloric acid.

Explanation:

The balanced reaction is:

Mg+ 2 HCl → MgCl₂ + H₂

By stoichiometry of the reaction, the following amounts of moles of each compound participate in the reaction:

Mg: 1 moleHCl: 2 molesMgCl₂: 1 moleH₂: 1 mole

Being the molar mass of each compound:

Mg: 24.31 g/moleHCl: 36.45 g/moleMgCl₂: 95.21 g/moleH₂: 2 g/mole

By reaction stoichiometry, the following mass amounts of each compound participate in the reaction:

Mg: 1 mole* 24.31 g/mole= 24.31 gHCl: 2 moles* 36.45 g/mole= 72.9 gMgCl₂: 1 mole* 95.21 g/mole= 95.21 gH₂: 1 mole* 2 g/mole= 2 g

Then you can apply the following rule of three: if by stoichiometry 24.31 grams of Mg produces 2 grams of H₂, 12.5 grams of Mg produces how much mass of H₂?

[tex]mass of H_{2} =\frac{12.5 grams of Mg* 2 grams of H_{2}}{24.31 grams of Mg}[/tex]

mass of H₂= 1.03 grams

1.03 grams of hydrogen is produced from 12.5 g of Mg reacting with hydrochloric acid.

Analyse the temperature versus time graph of water, given below.

Which part of graph represent only liquid state and gaseous state and why?​

Answers

Answer:

Phase C - Liquid State

Phase E - Gaseous State

Explanation:

Usually, in phases of water, we have the following;

When temperature is less than zero, it is said to be in its solid phase as ice.

When temperature is between 0 to 100, we can say it is in the liquid phase as water.

When temperature is above 100°C, It is said to be in the gaseous phase as vapour.

From the diagram;

Phase C is the only liquid state because it falls between temperature of 0°C and 100°

Also, only phase E is in the gaseous phase because the temperature is above 100°C.

what is transition state​

Answers

Answer:

transition state is a point in which electrons been removed from the atom

Answer:

The highest energy structure in the reaction coordinate.

Explanation:

Indicar que elemento es de transición *

a) Calcio

b) Radio

c) Hierro

d) Carbono

e) Azufre

Sabiendo que las configuraciones electrónicas son correctas, determinar qué analogía es incorrecta *

a) 47Ag: [Kr] 5s2 4d9  I – B
b) 27Co: [Ar] 4s2 3d7  VIII – B
c) 41Nb: [Kr] 5s2 4d3  V – A
d) 50Sn: [Kr] 5s2 4d10 5p2  IV – A
e) N.A.

porfaaaaaaaaaaaaaaaaaaaa

Answers

Answer:

c hierro

no se la otra sorry

How are the vapor pressure and boiling point of alkynes affected as the chain length increases?

Answers

Answer:

Answer to the following question is as follows;

Explanation:

Alkynes' vapour pressure and normal boiling points are altered when chain length grows, since vapour pressure rises while boiling point falls.

Vapour pressure always include pressure entered by vapour with its condensed phase, pressure include molecules force of attraction include vapour

Exprese la concentración de una solución de H3PO4 al 30 % en masa y con una densidad de 1.39 g/mL en: M, y N.

Answers

Respuesta:

4.26 M; 12.8 N

Explicación:

Primer paso: Calcular la concentración volumétrica (Cv)

Usaremos la siguiente expression.

Cv = Cg × ρ

Cv = 30 g%g × 1.39 g/mL = 41.7 g%mL

Segundo paso: Calcular la molaridad

La concentración volumetrica es 41.7 g%mL, es decir, hay 41.7 gramos de soluto cada 100 mL de solución. Usaremos la siguiente fórmula para molaridad.

M = masa de soluto / masa molar de soluto × litros de solución

M = 41.7 g / 97.99 g/mol × 0.1 L = 4.26 M

Tercer paso: Calcular la normalidad

Usaremos la siguiente fórmula.

N = M × Z

donde Z para un ácido es igual al número de protones.

N = M × Z

N = 4.26 mol/L × 3 eq/mol = 12.8 N

which particle is an atom with only 10 neutrons in its nucleus ?

Answers

Answer:

fluorine

Explanation:

If you hit the surface of Iron with a photon of energy and find that the ejected electron has a wavelength of .75 nm, what is the wavelength of the incoming photon in nanometers?

Answers

Answer:

The wavelength of the incoming photon is 172.8 nm

Explanation:

The wavelength of the incoming photon can be calculated with the photoelectric equation:

[tex] KE = h\frac{c}{\lambda_{p}} - \phi [/tex]   (1)

Where:

KE: is the kinetic energy of the electron

h: is Planck's constant = 6.62x10⁻³⁴ J.s  

c: is the speed of light = 3.00x10⁸ m/s

[tex]\lambda_{p}[/tex]: is the wavelength of the photon =?  

Φ: is the work function of the surface (Iron) = 4.5 eV        

The kinetic energy of the electron is given by:

[tex] KE = \frac{p^{2}}{2m} = \frac{(\frac{h}{\lambda_{e}})^{2}}{2m} [/tex]  (2)

Where:  

p: is the linear momentum = h/λ

m: is the electron's mass = 9.1x10⁻³¹ kg

[tex]\lambda_{e}[/tex]: is the wavelength of the electron = 0.75 nm = 0.75x10⁻⁹ m

Hence, the wavelength of the photon is:

[tex] \frac{(\frac{h}{\lambda_{e}})^{2}}{2m} = h\frac{c}{\lambda_{p}} - \phi [/tex]

[tex]\lambda_{p} = \frac{hc}{\frac{h^{2}}{2m\lambda_{e}^{2}} + \phi} = \frac{6.62 \cdot 10^{-34} J.s*3.00\cdot 10^{8} m/s}{\frac{(6.62 \cdot 10^{-34} J.s)^{2}}{2*9.1 \cdot 10^{-31} kg*(0.75 \cdot 10^{-9} m)^{2}} + 4.5 eV*\frac{1.602 \cdot 10^{-19} J}{1 eV}} = 1.728 \cdot 10^{-7} m = 172.8 nm[/tex]      

Therefore, the wavelength of the incoming photon is 172.8 nm.

I hope it helps you!        

Draw the following structures and name them :
I. CH3CH2(OH)
II.CH3CH2CH(CH3)C(Cl)2C(l)2CH(F)OH
III.CH3CH(CH3)CHO
IV.CH2=CH(OH)
V.CH3OCH2CH3

Answers

Answer:

hope this helps.answer is in the picture

nguyên tử sắt có điện tích hạt nhân là 26+. trong nguyên tử, số hạt mang điện nhiều hơn số hạt không mang điện là 22. Hãy xác định số khối của nguyên tử sắt

Answers

Answer:

I don't know yr language

Anyone please help I’m in summer school please

Answers

Answer:

1. Absolute time, also known as Newtonian time is a time that exists independent of the observer of the time, and therefore, can only be expressed through mathematics

Absolute dating is a dating method that makes use of the radioactive property of matter and is determined through dating of radioactive isotopes present

Absolute time (dating) is found through radioactive dating

2. Radioactive isotopes are atoms that have the property of unstable proton neutron combination or excess energy nucleus. They can be fined as unstable element

3. A stabilized isotope are the decay product atoms of the element which are non radioactive.

4. The half life is the time it takes the original isotope to decay into the decay product

5. To determine the age of a rock, the proportion of the original isotope to the amount of decay product in the rock is compared

6. The isotope used to date organic materials is carbon-14

7. The isotope used to date rocks with comparable age to the Earth is Uranium-238 that has a half life of 4.468 billion years

8. The half life of carbon-14 is only 5,700 years while the age of a dinosaur is between 245 and 66 million years ago, and therefore, carbon is absent in most fossils

9. Uranium-238 is only found in igneous or volcanic rocks and not in metamorphic rocks, therefore, fossils  of dinosaur as well as other fossils that are buried in sedimentary materials, including sand and clay, cannot be determined by Uranium-238

Explanation:

Chromium forms a complex with diphenylcarbazide whose molar absorptivity is 4.17*10^4 at 540nm. Calculate the absorbance of a 7.68*10^-6 M solution of the complex at 540nm when measured in a 1.00cm cell and the transmittance of the solution.

Answers

Answer:

0.32 liters/mole cm.

Explanation:

According to Beer Lambert's law;

A= εcl

ε = molar absorptivity

c= concentration

l= path length

A= 4.17*10^4 × 7.68*10^-6 × 1

A= 0.32 liters/mole cm.

Calculate the molar mass AND identify the gas if 3.25 kg of this gas is stored in a 15.00 L tank and exerts a pressure of 120.0 atm at a constant temperature of 66.0°C.

Answers

Answer:

is your question correct

.

..

.

.

.

or not

Which element has 2 valence electrons in the 2s sublevel?

Answers

Answer:

beryllium is the answer.

I hope this will help you

hii pls help me to write the ionic equation ​

Answers

Answer:

net ionic equation

[tex]\boxed{ SO_4{}^{2-} {}_{(aq.)} + Ba^{2+} {}_{(aq.)} \rightarrow BaSO_4 {}_{(s)}} [/tex]

Question 8 of 10
Which of the following is made of matter?

A. Light
B. Energy
C. The sun
D. Heat

Answers

The answer would have to be letter b. Energy

Answer: i Choose the sun

because it has mass

Explanation: matter is anything that has mass and occupies space / Volume

and the sun has mass though it is not a solid one, and is made up of matter

HOPE THIS HELPSS!!!!

Is this population more likely to grows slowly or quickly in the next 10 years

Answers

nobody can say it is uncertain but in my opinion it will grow quickly in the next 10 years

What is the total pressure in millimeters of mercury,
exerted by the gas mixture

P= _______ units?

Answers

Answer:

87059.50558 pa

Explanation:

Dalton's law of partial pressure states that Ptotal=P1 +P2+ P3

417mmHg + 150mmHg +86mmHg =653 mmHg

convert it to Pa, your answer is 87059.50558Pa.

I hope I'm of help to you

TIMED HELP ASAP

19.11 g of MgSO₄ is placed into 100.0 mL of water. The water's temperature increases by 6.70°C. Calculate ∆H, in kJ/mol, for the dissolution of MgSO₄. (The specific heat of water is 4.184 J/g・°C and the density of the water is 1.00 g/mL). You can assume that the specific heat of the solution is the same as that of water.

Answers

Answer:

TIMED HELP ASAP

19.11 g of MgSO₄ is placed into 100.0 mL of water. The water's temperature increases by 6.70°C. Calculate ∆H, in kJ/mol, for the dissolution of MgSO₄. (The specific heat of water is 4.184 J/g・°C and the density of the water is 1.00 g/mL). You can assume that the specific heat of the solution is the same as that of water.

Answer:

-21.03 kJ/mol

Explanation:

∆H is enthalpy. Enthalpy is the total heat content of a system.

So we can establish that ∆H = q (heat)

The formula for heat (q)

q = cm∆T

c = specific heat capacity

m = mass of substance

∆T= change of temperature

Since we are calculating the enthalpy of the SOLUTION. We must account for both the mass of water and the mass of MgSO₄ in our q formula.

All you gotta do is plug and chug at this stage.

∆H = q     = cm∆T = (4.184)(19.11+100.0)(6.70) = 3338.986808 Joules

We have now calculated the heat (aka enthalpy) of the solution.

BUT

Remember! The problem asked for enthalpy in kj....

Use this conversion factor.

1000 J = 1 kJ

3338.986808 Joules * 1kJ/1000 J = 3.338986808 kJ

We were asked to find ∆H for the dissolution of MgSO4  in units of kj/mol so we are not finished.

Take the grams of MgSO4 in the problem  and convert it into moles using its molar mass.

MgSO4 molar mass = 120.3676 g

1 mol = 120.3676 g MgSO4   <---- Use this as a conversion factor

19.11 g MgSO4 * 1 mol MgSO4/120.3676 g = 0.15876365 mol MgSO4

Now that you've calculated the moles of MgSO4 in this solution. You can divide your heat by it.

q dissolution = 3.338.986808 kJ/ 0.15876365 mol =  21.03 kj/mol

Note that the problem tells us that the temperature of water increases.

This means that the water is experiencing an endothermic process (heat is being absorbed from MgSO4) . Mathematically, this would be indicated by a positive sign. ---> +q

We can assume MgSO4 is losing heat as it is placed into the water. It is experiencing an exothermic process (heat is being lost).  Mathematically, this would be indicated by a negative sign. ----> -q

So if we're calculating the enthalpy for the dissolution of MgSO₄ ....the value we've arrived at must be negative.

Answer

∆H = 21.03 kj/mol :)))))

I hope that helped...I feel like my explanation was a bit convoluted.

draw the structure of iso -pentylpropanoate​

Answers

i dont know how to draw bu tjisy drow stick people sjdiwkicksickenf

How much heat must be transferred to 55 g of ice to change the ice's
temperature from -13°C to -5.0°C? (The specific heat capacity of ice is 2.11
J/g.°C)


Answers

928.4 J/.C

Q= m x c x t
M= 55 g
C=2.11
T=8

What is the pH of a 1.0 x 10-3 M KOH solution?
A. 10
B. 4.0
C. 11
D. 3.0

Answers

Answer:

Option C. 11

Explanation:

We'll begin by calculating the concentration of the hydroxide ion [OH¯] in the solution. This can be obtained as follow:

In solution, KOH will dissociate as follow:

KOH (aq) <=> K⁺(aq) + OH¯(aq)

From the balanced equation above,

1 mole of KOH reacted to produce 1 mole of OH¯.

Therefore, 1×10¯³ M KOH will also react to produce 1×10¯³ M OH¯.

Thus, the concentration of hydroxide ion [OH¯] in the solution is 1×10¯³ M

Next, we shall determine the pOH of the solution. This can be obtained as follow:

Concentration of hydroxide ion [OH¯] = 1×10¯³ M

pOH =?

pOH = –Log [OH¯]

pOH = –Log 1×10¯³

pOH = 3

Finally, we shall determine the pH of the solution. This can be obtained as follow:

pOH = 3

pH =?

pH + pOH = 14

pH + 3 = 14

Collect like terms

pH = 14 – 3

pH = 11

what are the intermolecular forces of Sulfate ion

Answers

Answer:

oh it's easy

Explanation:

Take the hydrate

N

a

2

S

2

O

3

5

H

2

O

. Are there ionic forces between the

N

a

+

and the

S

2

O

2

3

and ion-dipole forces between the cation/anions and the water?

Which diagram represents this molecule

Answers

Answer:

I think it is C

Explanation:

Hope this helps!! :)

If I'm wrong, then greatest apologies

Name each compound. Do not capitalize element names. An example can be seen
below.
Ex. SF6: sulfur hexfluoride
a. H2O:
b. PC15:
C. SiF4:
d. N20

Answers

Answer:

a. H2O: dihydrogen monoxide

b. PCl5: Phosphorus pentachloride

c. SiF4: Silicon tetrafluoride

d. N20: dinitrogen oxide

make a 450 gram solution with the mass by mass concentration of 7% how much salt and water do you need to mix​

Answers

you’d need to mix over have the mass of the 450 gram solution

copper II carbonate in a crucible produced only 7g of copper II oxide. What was the percentage yield of copper II oxide​

Answers

The question is incomplete, the complete question is;

.On heating 12.4 g of copper (II) carbonate in a crucible only 7.0g of copper (II) oxide was produced. What was the % yield of copper (II) oxide ? [Cu=64,C=12,O=16]

Answer:

87.5%

Explanation:

CuCO3 -------> CuO + CO2

Number of moles of CuCO3 = 12.4g/123.55 g/mol = 0.1 moles

Since the reaction is 1:1,

Mass of CuO produced = 0.1 moles × 80g/mol = 8 g

Hence,

% yield = actual yield/theoretical yield × 100

% yield = 7/8 × 100

% yield = 87.5%

is SrO a conductor of electricity

Answers

Answer:

No and Yes

Explanation:

it depends bc its an ionic compound, therefore can't conduct electricity when SOLID, BUT unless it DISSOLVES in water it can conduct

PLEASE HELP QUICK!!! How many molecules are there in 4.00 L of
glucose, C6H1206? Please show your work!!

Answers

As 1 L is 1000 g
So mass= 4000g
Molar mass of Glucose= 180 g/mol
As Number of molecules= mass/molar mass x Avogadro’s no.
Number of molecules= 4000/180 x 6.022 x 10^23
Number of molecules = 1.3 x 10^25 molecules




Molar mass of NO2= 46
Number of molecules = 14/46 x 6.022 x 10^23
Number of molecules= 1.8 x 10^23 molecules

PLZ HELP According to the atomic model Which particles are found In the same part of the atom
a. protons electrons neutrons
B.protons and neutrons
C.protons and ​electrons
D.electrons and neutrons​

Answers

protons and neutrons
B I think its the best answer
Hope its help for your questions
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A helicopter hovers 500 m above a long straight road. There is a truck to the left and right of the helicopter. The angles of depression of the two trucks from the helicopter are 60 and 20. How far apart are the two trucks? can anyone please help me Find the surface area of the cylinder and round to the nearest tenth and its recommended that you use pie or 3.14 also the radius is half the diameter define tourism profession During the eighteenth century France witnessed the emergence of a middle class. Reason (R): The emergence of the middle class happened on account of royal patronage. *1 pointA Both A and R are true and R is the correct explanation of A.B Both A and R are true and R is not the correct explanation of A.C A is true but R is false.D A is false but R is true. I want to know the distance Which of the following are typical weather patterns in North Carolina? Check all that applyyear-round precipitation in the form of rainlarge amounts of winter precipitation in the form of snowmild temperatures throughout the winter monthswarm temperatures in the summer and fallextremely dry, hot summers SCALCET8 4.7.011. Consider the following problem: A farmer with 950 ft of fencing wants to enclose a rectangular area and then divide it into four pens with fencing parallel to one side of the rectangle. What is the largest possible total area of the four pens were considered the upper class of colonial society. At December 31, Hawke Company reports the following results for its calendar year. Cash sales $1,432,910 Credit sales $3,376,000 In addition, its unadjusted trial balance includes the following items. Accounts receivable $1,022,928 debit Allowance for doubtful accounts $11,560 debitRequired: Prepare the adjusting entry for this company to recognize bad debts Find the length of each segment.W XY--5055. WX6. WY In figure above, if l1 | | l2 then value of x is:a) 40b) 50c) 80d) 100 FIRST ANSWER GETS BRAINLIEST!!(sorry for the colors on the picture) write your answer in simplest radical form What are the two specific benefits for social health? and explain them in ur own words. How is a monopolistically competitive market similar to a perfectly competitive market? A. Producers with market power set their own prices. B. Both have differentiated products with close substitutes. C. There are no restrictions on the entry of new firms. D. Both have homogeneous products with no close substitutes. Which of the following common features do monopolistically competitive markets and monopolies share? A. Barriers restrict new firms from entering. B. Consumers with market power set prices. C. Firms face downward-sloping demand curves. D. Producers with no market power set their own prices. Find the midpoint of the segment with the given endpoints.(7,10) and (-1,- 8) When the economy was expanding,new housing developments being to,_______:when times are lean, construction slacks off. Helpppp please!!!!!! (x-3).(x+3)-(x+5).(x-1)