If the data rate is 10 Mbps and the token is 64 bytes long (the 10-Mbps Ethernet minimum packet size), what is the average wait to receive the token on an idle network with 40 stations? (The average number of stations the token must pass through is 40/2 = 20.) Ignore the propagation delay and the gap Ethernet requires between packets.

Answer: APIPA

Explanation:

Automatic Private IP Addressing (APIPA) is a Windows based operating systems feature that allows a computer to assign itself automatically to an IP address even though there is DHCP server to perform the function.

From the information that has been provided in the question, we can see that the type of address that is used is APIPA.

Answer:

Following are the algorithm to this question:

Explanation:

In the RSA algorithm can be defined as follows:  

In this algorithm, we select two separate prime numbers that are the "P and Q", To protection purposes, both p and q combines are supposed to become dynamically chosen but must be similar in scale but 'unique in length' so render it easier to influence. Its value can be found by the main analysis effectively.  

Computing N = PQ.  

In this, N can be used for key pair, that is public and private together as the unit and the Length was its key length, normally is spoken bits. Measure,

[tex]\lambda (N) = \ lcm( \lambda (P), \lambda (Q)) = \ lcm(P- 1, Q - 1)[/tex]  where [tex]\lambda[/tex] is the total function of Carmichaels. It is a privately held value. Selecting the integer E to be relatively prime from [tex]1<E < \lambda (N)[/tex]and [tex]gcd(E, \lambda (N) ) = 1;[/tex] that is [tex]E \ \ and \ \ \lambda (N)[/tex].  D was its complex number equivalent to E (modulo [tex]\lambda (N)[/tex] ); that is d was its design multiplicative equivalent of E-1.  

It's more evident as a fix for d provided of DE ≡ 1 (modulo [tex]\lambda (N)[/tex] ).E with an automatic warning latitude or little mass of bigging contribute most frequently to 216 + 1 = 65,537 more qualified encrypted data.

In some situations it's was shown that far lower E values (such as 3) are less stable.  

E is eligible as a supporter of the public key.  

D is retained as the personal supporter of its key.  

Its digital signature was its module N and the assistance for the community (or authentication). Its secret key includes that modulus N and coded (or decoding) sponsor D, that must be kept private. P, Q, and [tex]\lambda (N)[/tex] will also be confined as they can be used in measuring D. The Euler totient operates [tex]\varphi (N) = (P-1)(Q - 1)[/tex] however, could even, as mentioned throughout the initial RSA paper, have been used to compute the private exponent D rather than λ(N).

It applies because [tex]\varphi (N)[/tex], which can always be split into  [tex]\lambda (N)[/tex], and thus any D satisfying DE ≡ 1, it can also satisfy (mod  [tex]\lambda (N)[/tex]). It works because [tex]\varphi (N)[/tex], will always be divided by [tex]\varphi (N)[/tex],. That d issue, in this case, measurement provides a result which is larger than necessary (i.e. D >   [tex]\lambda (N)[/tex] ) for time - to - time). Many RSA frameworks assume notation are generated either by methodology, however, some concepts like fips, 186-4, may demand that D<   [tex]\lambda (N)[/tex]. if they use a private follower D, rather than by streamlined decoding method mostly based on a china rest theorem. Every sensitive "over-sized" exponential which does not cooperate may always be reduced to a shorter corresponding exponential by modulo  [tex]\lambda (N)[/tex].

As there are common threads (P− 1) and (Q – 1) which are present throughout the [tex]N-1 = PQ-1 = (P -1)(Q - 1)+ (P-1) + (Q- 1))[/tex], it's also possible, if there are any, for all the common factors [tex](P -1) \ \ \ and \ \ (Q - 1)[/tex]to become very small, if necessary.  

Indication: Its original writers of RSA articles conduct their main age range by choosing E as a modular D-reverse (module [tex]\varphi (N)[/tex]) multiplying. Because a low value (e.g. 65,537) is beneficial for E to improve the testing purpose, existing RSA implementation, such as PKCS#1, rather use E and compute D.

Answer:

Here is the Python program:

import keyword  #module that contains list of keywords of python

filename = input("Enter Python source code filename: ") # prompts user to enter the filename of a source code

code = open(filename, "r") # opens the file in read mode

keywords = keyword.kwlist #extract list of all keywords of Python and stored it into keywords

dictionary = dict() #creates a dictionary to store each keyword and its number of occurrence in source code

for statement in code: # iterates through each line of the source code in the file

   statement = statement.strip() # removes the spaces in the statement of source code  

   words = statement.split(" ") #break each statement of the source code into a list of words by empty space separator

   for word in words:# iterates through each word/item of the words list  

       if word in keywords:#checks if word in the code is present in the keywords list of Python  

           if word in dictionary: #checks if word is already present in the dictionary

               dictionary[word] = dictionary[word] + 1 #if word is present in dictionary add one to the count of the existing word

           else: #if word is not already present in the dictionary  

               dictionary[word] = 1 #add the word to the dictionary and set the count of word to 1

for key in list(dictionary.keys()): #iterates through each word in the list of all keys in dictionary  

   print(key, ":", dictionary[key])# prints keyword: occurrences in key:value format of dict

Explanation:

The program is well explained in the comments attached with each line of the program.  

The program prompts the user to enter the name of the file that contains the Python source code. Then the file is opened in read mode using open() method.

Then the keyword.kwlist statement contains the list of all keywords of Python. These are stored in keywords.

Then a dictionary is created which is used to store the words from the source code that are the keywords along with their number of occurrences in the file.

Then source code is split into the lines (statements) and the first for loop iterates through each line and removes the spaces in the statement of source code .

Then the lines are split into a list of words using split() method. The second for loop is used to iterate through each word in the list of words of the source code. Now each word is matched with the list of keywords of Python that is stored in keywords. If a word in the source code of the file is present in the keywords then that word is added to the dictionary and the count of that word is set to 1. If the word is already present in the dictionary. For example if there are 3 "import" keywords in the source code and if 1 of the import keywords is already in the dictionary. So when the second import keyword is found, then the count of that keyword is increased by 1 so that becomes 2.

Then the last loop is used to print each word of the Python that is a keyword along with its number of occurrences in the file.

The program and its output is attached in a screenshot. I have used this program as source code file.

Answer:

Redundancy

Req. 1 and Req. 3 are seemed to say the same thing. We need to remove the first sentence in Req. 1

Conflict and understandability

Req. 1 states that access is through web browser while Req. 4 states that access is via html. We have to re-write the Req. 3 to make it clear that users do not actually have to write directly html to communicate with the system.

Completeness

Req. 5 states that print out will “mainly” be documents. What else might be printed? What other inputs will be produced?

Either remove mainly or clarify other print out.

What version of html or web browser is assumed in Req. 1 and Req. 3?

Explanation:

Answer:

A computer user should only have as much access as required to do their job.

Explanation:

A computer user should not be able to access resources outside of their job requirement, as this poses a potential attack vector for an insider threat.  By limiting the scope of resources to just what is needed for the user's specific job, the threat to the system or company can be mitigated with additional access control features for the computer user.  Never allow permission higher than what are needed to accomplish the task.

Cheers.

Answer:

yesnono

Explanation:

mystr = 'yes'

yourstr = 'no'

mystr += yourstr * 2

Answer:

mouse printer CPU touch screen

Explanation:

on a tablet computer hope this helps you :)

Answer:

B. Full tunnel.

Explanation:

In this scenario, an organization is planning to implement a virtual private network (VPN). They want to ensure that after a VPN client connects to the VPN server, all traffic from the VPN client is encrypted. The best method to meet this goal is to use a full tunnel.

A full tunnel is a type of virtual private network that routes and encrypts all traffics or request on a particular network. It is a bidirectional form of encrypting all traffics in a network.

On the other hand, a split tunnel is a type of virtual private network that only encrypts traffic from the internet to the VPN client.

Hence, the full tunnel method is the most secured type of virtual private network.

Answer:

b. obA.c 5;

d. ClassA.b=23;

f. ClassA.d = 99;

Explanation:

Java is a programming language for object oriented programs. It is high level programming language developed by Sun Microsystems. Java is used to create applications that can run on single computer. Static variable act as global variable in Java and can be shared among all objects. The non static variable is specific to instance object in which it is created.

Answer:

def inputNumber():

   l = []

   num = int(input("Enter the number of integers you want to enter\n"))

   for i in range(0,num):

       print("Enter the ", i+1, " integers ")

       a = float(input())

       l.append(a)

   return l

def averageCalculator(l):

   total = 0

   for i in l:

       total += i

   avg = total/len(l)

   return avg

def printoutput(avg):

   print("The average of numbers is ", avg)

l = inputNumber()

avg = averageCalculator(l)

printoutput(avg)

Explanation:

A subprogram may be considered as a method where we pass some values in the arguments and return some value.

The answer is written in python language, where we have used

inputNumber() subprogram to get the input from the user.

function averageCalculator() to calculate the average.

printoutput() subprogram to print the output or the average of the numbers.

Please refer to the attached image for better understanding of the indentation of code.

Now, let us learn about them one by one:

inputNumber(): We get the number of values to be entered as an integer value and then get the numbers as float.

Store the values in a list and return the list to the caller main program.

averageCalculator(l): Contains a list as argument as we got from inputNumber(). It sums all the numbers and divides with total number to find the average. Returns the average value to the caller main program.

printoutput(avg): Contains an argument which is the average calculated in the averageCalculator(). It prints the argument passed to it.

Answer:

b. Both incremental and iterative development.

Explanation:

Agile software development is based on both incremental and iterative development. It is an iterative method to software delivery in which at the start of a project, software are built incrementally rather than completing and delivering them at once as they near completion.

Incremental development means that various components of the system are developed at different rates and are joined together upon confirmation of completion, while Iterative development means that the team intends to check again components that makes the system with a view to revising and improving on them for optimal performance.

Agile as an approach to software development lay emphasis on incremental delivery(developing system parts at different time), team work, continuous planning and learning, hence encourages rapid and flexible response to change.

Answer:

The answer is below

Explanation:

Elements of Server software that is built-in, in Windows workstations are:

1. Hard drives,

2. RAM (Random Access Memory)

3. Processors

4. Network adapters.

Windows Professional OS is not considered a server due to the following:

1. Windows Professional OS has a limit on the number of client connections it allowed.

2. Unlike Server, Professional OS uses less memory

2. In comparison to Server, Professional OS uses the CPU less efficiently

4. Professional OS is not built to process background tasks, unlike Server that is configured to perform background tasks.

Answer:

I am writing the program in JAVA and C++

JAVA:

public int createLicenseNum(int customID){  //class that takes the customID as parameter and creates and returns the licenseNum

       licenseNum = (100000 * customID) + licenseYear;  //licenseNum creation formula

       return(licenseNum);     }

In C++ :

void DogLicense::CreateLicenseNum(int customID){ //class that takes the customID as parameter and creates the licenseNum

licenseNum = (100000 * customID) + licenseYear; } //licenseNum creation formula

Explanation:

createLicenseNum method takes customID as its parameter. The formula inside the function is:

licenseNum = (100000 * customID) + licenseYear;

This multiplies 100000 to the customID and adds the result to the licenseYear and assigns the result of this whole expression to licenseNum.

For example if the SetYear(2014) means the value of licenseYear is set to 2014 and CreateLicenseNum(777) this statement calls createLicenseNum method by passing 777 value as customID to this function. So this means licenseYear = 2014 and customID  = 777

When the CreateLicenseNum function is invoked it computes and returns the value of licenseNum as:

licenseNum = (100000 * customID) + licenseYear;

                     = (100000 * 777) + 2014

                     = 77700000 + 2014

licenseNum = 77702014                                                                                                        

So the output is:

Dog license: 77702014          

To call this function in JAVA:

public class CallDogLicense {

public static void main(String[] args) {//start of main() function

    DogLicense dog1 = new DogLicense();//create instance of Dog class

dog1.setYear(2014); // calls setYear passing 2014

dog1.createLicenseNum(777);// calls createLicenseNum passing 777 as customID value

System.out.println("Dog license: " + dog1.getLicenseNum()); //calls getLicenseNum to get the computed licenceNum value

return; } }

Both the programs along with the output are attached as a screenshot.

Answer:

public int createLicenseNum(int customID){

  licenseNum = (100000 * customID) + licenseYear;

  return(licenseNum);    

}

Explanation:

Answer:

Which sentence best matches the context of the word reticent as it is used in the following example?

We could talk about anything for hours. However, the moment I brought up dating, he was extremely reticent about his personal life.

Explanation:

Which sentence best matches the context of the word reticent as it is used in the following example?

We could talk about anything for hours. However, the moment I brought up dating, he was extremely reticent about his personal life.

Answer:

Pick up roller

Explanation:

you should first check the pickup roller component. This component is the part of the printer that picks paper up from the paper tray. The pickup roller links the printer and the paper. When the printer printer is running, the roller would take paper from the paper tray for the printer to print on. One of the issues it can have is Paper jam where the roller would stop turning so that it will no longer be picking papers up from the tray.

Answer:

total_owls = 0

num_owls_A = int(input())

num_owls_B = int(input())

total_owls = num_owls_A + num_owls_B

print("Number of owls:", total_owls)

Explanation:

Initialize the  total_owls as 0

Ask the user to enter num_owls_A and num_owls_B, convert the input to int

Sum the num_owls_A and num_owls_B and set it to the total_owls

Print the total_owls

avg_owls=0.0

num_owls_zooA = int(input())

num_owls_zooB = int(input())

num_owls_zooC = int(input())

num_zoos = 3

avg_owls = (num_owls_zooA + num_owls_zooB + num_owls_zooC) / num_zoos

print('Average owls per zoo:', int(avg_owls))

There is a problem while you are trying the calculate the average owls per zoo.

As you may know, in order to calculate the average, you need to get the total number of owls in all the zoos, then divide it to the number of zoos. That is why you need to sum num_owls_zooA + num_owls_zooB + num_owls_zooC and divide the result by num_zoos

Be aware that the average is printed as integer value. That is why you need to cast the avg_owls to an int as int(avg_owls)

Learn more about integer value on:

https://brainly.com/question/31945383

#SPJ6

Answer:

Replace

/* Your solution goes here */

with

if (bagOunces < 2) {

   System.out.print("Too Small");

}

else if(bagOunces > 10) {

   System.out.print("Too Large");

}

else {

   System.out.print((bagOunces * 6)+" seconds");

}

Explanation:

This line checks if bagOunces is less than 2;

if (bagOunces < 2) {

If yes, the string "Too Small" is printed

   System.out.print("Too Small");

}

This line checks if bagOunces is greater than 10

else if(bagOunces > 10) {

If yes, the string "Too Large" is printed

   System.out.print("Too Large");

}

The following condition is executed if the above conditions are false

else {

This multiplies bagOunces by 6 and adds seconds

   System.out.print((bagOunces * 6)+" seconds");

}

Answer:

def case_convertfile( file_name):

    with open(" new_file","x") as file:

         file.close( )

    with open("file_name", "r") as txt_file:

     while True:

            word = txt_file.readline( )

            word_split= word.split(" ")

            for word in word_split:

                  upper_case = word.uppercase( )

                  file= open("new_file","w+")

                  file= open("new_file","a+")

                  file.write(upper_case)

     txt_file.close( )

     file.close( )

Explanation:

This python function would open an existing file with read privilege and a new file with write and append privileges read and capitalize the content of the old file and store it in the new file.

Answer:

Polymorphism

Explanation:

If we use polymorphism so we can apply the names that could be easy to remember for the methods' purpose.

The information regarding the polymorphism is as follows:

Therefore we can conclude that If we use polymorphism so we can apply the names that could be easy to remember for the methods' purpose.

Learn more about the behavior here: brainly.com/question/9152289

Answer:

Answered below

Explanation:

A macro or macroinstruction is a programmable pattern which translates a sequence of inputs into output. It is a rule that specifies how a certain input sequence is mapped to a replacement output sequence. Macros makes tasks less repetitive by representing complicated keystrokes, mouse clicks and commands.

By thoroughly testing a macro before deployment, you are able to observe the flow of the macro and also see the result of each action that occurs. This helps to isolate any action that causes an error or produces unwanted results and enable it to be consistent across end user platforms.

Answer:

the answer is 300 feet in the daytime

Answer:

A total of 79.3mb will be needed

Answer:

system unit

Explanation:

A system unit is the part of a computer that contains the brain or central processing unit. The primary device such as central processing unit as contained in the system unit perform operations hence produces result for complex calculations.

The system unit also house other main components of a computer system like hard drive , CPU, motherboard and RAM. The major work that a computer is required to do or performed is carried out by the system unit. Other peripheral devices are the keyboard, monitor and mouse.

Answer:

A. UC ONE Self-Service Center

Explanation:

The UC ONE Self-Service Center is an online platform where one can get detailed information about registration, classes, finances, and other personal details. This is also the portal where one can check class schedule, bill payment, viewing available courses, checking final grades, book ordering, etc.

it gives students all the convenience required for effective learning experience.

The UC ONE platform is a platform found in the portal of University of the Cumberland.

Explanation:

the answer is false ........

The fact that the speed of a vehicle is lower than the prescribed limits shall relieve the driver from the duty to decrease speed when approaching and crossing an intersection is not true.

An intersection serves as the point where many lanes cross on the road which is a point where driver is required to follow the traffic rules.

However, the above statement is not true because , a driver can decide not  decrease speed when approaching and crossing an intersection, even though it is a punishable offense in traffic rules.

Read more on traffic rules here: https://brainly.com/question/1071840

#SPJ2

Answer:

The programming language is not stated; However, the program written in C++ is as follows: (See Attachment)

#include<iostream>

using namespace std;

string capt(string result)

{

result[0] = toupper(result[0]);

for(int i =0;i<result.length();i++){

 if(result[i]=='.' || result[i]=='?' ||result[i]=='!')  {

 if(result[i+1]==' ') {

  result[i+2] = toupper(result[i+2]);

 }

 if(result[i+2]==' ')  {

  result[i+3] = toupper(result[i+3]);

 }

 } }

return result;

}

int main(){

string sentence;

getline(cin,sentence);

cout<<capt(sentence);

return 0;

}

Explanation:

The method to capitalize first letters of string starts here

string capt(string result){

This line capitalizes the first letter of the sentence

result[0] = toupper(result[0]);

This iteration iterates through each letter of the input sentence

for(int i =0;i<result.length();i++){

This checks if the current character is a period (.), a question mark (?) or an exclamation mark (!)

if(result[i]=='.' || result[i]=='?' ||result[i]=='!')  {

 if(result[i+1]==' '){  ->This condition checks if the sentence is single spaced

  result[i+2] = toupper(result[i+2]);

-> If both conditions are satisfied, a sentence is detected and the first letter is capitalized

 }

 if(result[i+2]==' '){ ->This condition checks if the sentence is double spaced

  result[i+3] = toupper(result[i+3]);

-> If both conditions are satisfied, a sentence is detected and the first letter is capitalized

 }

}

}  The iteration ends here

return result;  ->The new string is returned here.

}

The main method starts here

int main(){

This declares a string variable named sentence

string sentence;

This gets the user input

getline(cin,sentence);

This passes the input string to the method defined above

cout<<capt(sentence);

return 0;

}

Answer:

The generator function using yield from:

def scale(s, k):

   yield from map(lambda x: x * k, s)

Another way to implement generator function that works same as above using only yield:

def scale(s, k):

  for i in s:

       yield i * k

Explanation:

The complete program is:

def scale(s, k):

   """Yield elements of the iterable s scaled by a number k.  

   >>> s = scale([1, 5, 2], 5)

   >>> type(s)

   <class 'generator'>

   >>> list(s)

   [5, 25, 10]  

   >>> m = scale(naturals(), 2)

   >>> [next(m) for _ in range(5)]

   [2, 4, 6, 8, 10]

   """

   yield from map(lambda x: x * k, s)

If you want to see the working of the above generator function scale() as per mentioned in the above comments, use the following statements :

s = scale([1, 5, 2], 5)  

print(type(s))  

#The above print statement outputs:

#<class 'generator'>

print(list(s))

#The above print statement outputs a list s with following items:

#[5, 25, 10]                                                                                                                    

The function def scale(s, k): is

def scale(s, k):

   yield from map(lambda x: x * k, s)    

This function takes two parameters i.e. s and k and this function yields elements of the given iterable s, scaled by k.

In this statement:    yield from map(lambda x: x * k, s)    

yield from is used which allows to refactor a generator in a simple way by splitting up generator into multiple generators.

The yield from is used inside the body of a generator function.

The lambda function is a function that has any number of arguments but can only have one expression. This expression is evaluated to an iterable from which an iterator will be extracted. This iterator yields and receives values to or from the caller of the generator. Here the expression is x: x * k and iterable is s. This expression multiplies each item to k.

map() method applies the defined function for each time in an iterable.

The generator function can also be defined as:

def scale(s, k):

  for i in s:

       yield i * k

For the above example

s = scale([1, 5, 2], 5)  

def scale(s,k): works as follows:

s = [1, 5, 2]

k = 5

for loop iterates for each item i in iterable s and yields i*k

i*k multiplies each element i.e 1,5 and 2 to k=5 and returns a list

At first iteration, for example, i*k = 1 * 5 = 5, next iteration i*k = 5*5 = 25 and last iteration i*k = 2*5 = 10. So the output. So

s = scale([1, 5, 2], 5)  In this statement now s contains 5, 25 and 10

print(list(s))  prints the values of s in a list as: [5, 25, 10] So output is:

[5, 25, 10]

Answer:

H cannot update it because it is probably protected.

If you cannot click in the table of contents, it is probably because it is protected. To disable this protection, choose Tools > Options > OpenOffice.org Writer > Formatting Aids, and then select Enable in the Cursor in protected areas section. If you wish to edit the table of contents without enabling the cursor, you can access it from the Navigator.

Explanation:

. To update a table of contents when changes are made to the document:

Right-click anywhere in the TOC.

From the pop-up menu, choose Update Index/Table. Writer updates the table of contents to reflect the changes in the document.

You can also update the index from the Navigator by right-clicking on Indexes > Table of Contents1 and choosing Index > Update from the pop-up menu.

Answer:

The file can be read only by a user with the decryption key

Explanation:

The way encryption works is it scrambles the data in a file following the rules of the encryption algorithm using a certain key to tell it how to scramble everything.

Without the key, the computer doesn't know how to decrypt it.

This is true no matter who has access to the file, be it a system administrator, a hacker, or even a legitimate user who has somehow lost access to the key

Strictly speaking, encryption can be broken, but, especially with modern encryption, that's a matter of centuries, and isn't really feasible

The statement that is true of an encrypted file is that The file can be read only by a user with the decryption key.

A decryption key is known to be a key that is given to Customers by a specific Distributor.

This key allows Customers to open and access the Software that they bought. The decryption key is a  mechanism that  permit  that a file can be read only by a user.

Learn more about decryption key from

https://brainly.com/question/9979590

Answer:

Open ended investigation

Explanation:

The above is an example of an open ended investigation. In understanding what an open ended investigation is, we first of all need to understand what open endedness means. Open endedness means whether one solution or answer is possible. In other words it means that there may be various ways and alternatives to solve or answer a question or bring solution to an investigation.

From the definition, we can deduce that an open ended investigation is a practical investigation that requires students to utilize procedural and substantive skills in arriving at conclusion through evidence gathered from open ended research or experiment(as in not close ended, not limited to ready made options, freedom to explore all possibilities). This is seen in the example question where students are asked to explore the different examples of physical controls and displays and also discuss their observations. Here students are not required to produce a predefined answer but are free to proffer their own solutions