If p is true and ~ q is false, then p ~ q is _____ false.
a. sometimes
b. always
c. never

Answer:

Answer A

Step-by-step explanation:

[tex]\displaystyle \lim_{n \to -\infty} (3x^3+28)=-\infty\\\\minimum\ of \ f(x)=6\\\\Answer\ A[/tex]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

The hypothesis :

H0 : σ²= 47.1

H1 : σ² > 47.1

α = 5% = 0.05

Population variance, σ² = 47.1

Sample variance, s² = 83.2

Sample size, n = 15

The test statistic = (n-1)*s²/σ²

Test statistic, T = [(15 - 1) * 83.2] ÷ 47.1

Test statistic = T = [(14 * 83.2)] * 47.1

Test statistic = 1164.8 / 47.1

Test statistic = 24.73

The degree of freedom, df = n - 1 ; 10 = 9

Critical value (0.05, 9) = 16.92 (Chisquare distribution table)

Reject H0 ; If Test statistic > Critical value

Since ; 24.73 > 16.92 ; Reject H0 and conclude that variance is greater.

Answer:

- 5 > b

Step-by-step explanation:

- 9 > 3b + 6

- 9 - 6 > 3b

- 15 > 3b

Divide 3 on both sides,

- 5 > b

Answer:

-5 >b

Step-by-step explanation:

-9 > 3b + 6

Subtract 6 from each side

-9-6 > 3b + 6-6

-15 > 3b

Divide each side by 3

-15/3 > 3b/3

-5 >b

Step-by-step explanation:

By the law of exponent :

(a^n)^m=a^n×m

Option C

b^n×m is the correct answer...

hope it helps

Answer:

weight =48.71228786pounds

Step-by-step explanation:

[tex]w = \frac{k}{ {d}^{2} } \\ 50 = \frac{k}{ {3960}^{2} } \\ \\ k = 50 \times {3960}^{2} \\ k = 50 \times 15681600 \\ k = 784080000 \\ \\ w = \frac{784080000}{ {d}^{2} } \\ w = \frac{784080000}{16120225} \\ \\ w = 48.71228786 \\ w = 48.7pounds[/tex]

If a body weighs 50 pounds when it is 3,960 miles from Earth's center, it would weigh approximately 48.547 pounds if it were 4,015 miles from Earth's center, according to the inverse square law formula.

We know the inverse square law formula:

W₁ / W₂ = D²₂ / D²₁

Where W₁ is the weight of the body at the initial distance D₁, and W₂ is the weight at the final distance D₂.

So we have,

W₁ = 50

D₁  = 3,960

D₂  = 4015

We know that the body weighs 50 pounds when it is 3,960 miles from Earth's center,

So we can plug in those values as follows:

50 / W₂ = (4,015)²/ (3,960)²

To solve for W₂, we can cross-multiply and simplify as follows:

W₂ = 50 x (3,960)² / (4,015)²

W₂ = 50 x 15,681,600 / 16,120,225

W₂ = 48.547 pounds (rounded to three decimal places)

Therefore, if the body were 4,015 miles from Earth's center, it would weigh approximately 48.547 pounds.

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Answer:

Step-by-step explanation:

There are two possible equations, but neither matches the the choices you listed. The choices seem to have several typographical errors.

Point-slope form of an equation of the line through the points (-4, 7) and (5,-3) is y - 7 =(-10/9)(x + 4).

Slope

[tex]$= \frac{y_{2} -y_{1}}{x_{2} -x_{1}}[/tex]

= (-3 - 7) / (5 - (-4))

= -10/9

The point-slope equation for the line of slope -(10/9) that passes through the point (5, -3).

y + 3 = (-10/9)(x - 5)

Point slope equation for the line of slope -(10/9) that passes through the point (-4, 7)

Point-slope form of an equation of the line through the points (-4, 7) and (5,-3) is y - 7 = (-10/9)(x + 4).

Therefore, the correct answer is y - 7 = (-10/9)(x + 4).

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y=x²-10x-7

a>0 so we will be looking for minimum

x=-b/2a=10/2=5

y=25-50-7=-32

Answer: (5;32)

y=-4x²-8x+1

а<0 so we will be looking for maximum

х=-b/2a=8/-8=-1

у=4+8+1=13

Maximum point (-1;13)

Answer:

384 cars

Step-by-step explanation:

To find the total number of spaces in the carpark, we must multiply the number of rows by how many cars they can accommodate:

34 ⋅ 40 = 1360

As you can see, we have 1360 total spaces. Since there are 976 cars parked, and we want to find out how many spaces are left, we have to subtract the amount of cars parked from the total spaces.

1360 - 976 = 384

Therefore, our answer is 384, specifically, 384 cars.

Answer:

384 cars.

Step-by-step explanation:

40 * 34 - 976

= 1360 - 976

= 384.

Answer:

7,0, -1 and -2

Step-by-step explanation:

Just substitute the values,

a. f(g(7))=f(-1) [g(7)=-1 given]

            =7 [f(-1)=7 given]

b.f(g(-1))=f(3)=0 [g(-1)=3 Given]

c.g(f(-1))=g(7)=-1 [f(-1)=7 given]

d.g(f(7))=g(5)=-2 [f(7)=g(5) given]

Answer:

i.)1,2,3,4,6,12

ii).the number itself

iii.)1

Answer:

240 i.e 40*6

Step-by-step explanation:

if rose works 8hrs per day then she works 40 hrs per week (5 days) therefore 40 hrs per 6 weeks =40*6=240

Answer:

40

Step-by-step explanation:

9514 1404 393

Answer:

  90°, 60°, 30°

Step-by-step explanation:

The remaining angles have a ratio of 2:1, so total 3 "ratio units". The first angle is equal to that sum: 3 ratio units, so all of the angles together total 3+2+1 = 6 ratio units. The total of angles is 180°, so each ratio unit is 180°/6 = 30°.

The first angle is 3 ratio units, or 90°.

The second angle is 2 ratio units, or 60°.

The third angle is half that, or 30°.

The three angles are 90°, 60°, 30°.

Answer:

5, - 1, - 3, - 5, - 11

Step-by-step explanation:

The equation of the line is y=-4x-11. The y values corresponding to x are 5, - 1, - 3, - 5, - 11

Answer:

yall do school right now???and i forgot how to do these sorry

Answer:

18 = 2x-14

or, 2x =18+14

or, 2x =32

or, x=32/2

x=16

2(6x-7)=10

or, 12x-14=10

or, 12x=10+14

or, x=24/12

x=2

Answer:

y=2x-5

Step-by-step explanation:

By using two-points form:

y-y1/y2-y1=x-x1/x2-x1

p(x1,y1)=(4,3)

p(x2,y2)=(2,-1)

Subtitute points in formula:

y-3/-1-3=x-4/2-4

y-3/-4=x-4/-2

y-3/-2=x-4/-1

1(y-3)=2(x-4)

y-3=2x-8

y=2x-8+3

y=2x-5

Note:if you need to ask any question please let me know.

The three main log rules you'll encounter are

The first rule allows us to go from a log of some product, to a sum of two logs. In short, we go from product to sum. The second rule allows us to go from a quotient to a difference. Lastly, the third rule allows to go from an exponential to a product.

Here are examples of each rule being used (in the exact order they were given earlier).

----------------

Here's a slightly more complicated example where the log rules are used.

log(x^2y/z)

log(x^2y) - log(z)

log(x^2) + log(y) - log(z)

2*log(x) + log(y) - log(z)

Hopefully you can see which rules are being used for any given step. If not, then let me know and I'll go into more detail.

So far she worked 4 days at 5 1/2 hours a day for a total of 22 hours.

22 hours x $8.50 = $187

Subtract that from the cost of the computer:

899-187 = $712

She needs $712 more.

Amount she makes per shift: $8.50 x 5 1/2 hours = $46.75

Divide what she needs by amount per shift:

712 / 46.75 = 15.22 shifts

She needs to work 16 more shifts.

Answer:

(C) The value of r indicates that the number of sales decreases as the price increases.

ED2021.

The best statement, given the correlation coefficient of -0.63 is: value of r indicates that the number of sales decreases as the price increases.

A negative correlation coefficient has a negative sign, and implies a negative relationship between two variables.

This means that, as one variable decreases, the other variable increases.

Thus, a correlation coefficient of -0.63 shows a negative relationship between prices of smartphones and the number of sales.

Therefore, the best statement, given the correlation coefficient of -0.63 is: value of r indicates that the number of sales decreases as the price increases.

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Answer:

F = 27

Step-by-step explanation:

50/2 = (F - 3) + 1

25 = F - 2

F = 27

Step-by-step explanation:

xx is the Roman number of 20

Answer:

[tex]8(2a- b)(4a^2+ 2ab+ b^2)[/tex]

Step-by-step explanation:

factor out the 8

then you have the sum/difference of cubes..

look that up SOAP: same opposite, always a plus

[tex]64a^3 -8b^3\\8(8a^3 -b^3)[/tex]

[tex]8(2a- b)(4a^2+ 2ab+ b^2)[/tex]

Split up the integral:

[tex]\displaystyle\int\frac{x+2019}{x^2+9}\,\mathrm dx = \int\frac{x}{x^2+9}\,\mathrm dx + \int\frac{2019}{x^2+9}\,\mathrm dx[/tex]

For the first integral, substitute y = x ² + 9 and dy = 2x dx. For the second integral, take x = 3 tan(z) and dx = 3 sec²(z) dz. Then you get

[tex]\displaystyle \int\frac x{x^2+9}\,\mathrm dx = \frac12\int{2x}{x^2+9}\,\mathrm dx \\\\ = \frac12\int\frac{\mathrm du}u \\\\ = \frac12\ln|u| + C \\\\ =\frac12\ln\left(x^2+9\right)[/tex]

and

[tex]\displaystyle \int\frac{2019}{x^2+9}\,\mathrm dx = 2019\int\frac{3\sec^2(z)}{(3\tan(z))^2+9}\,\mathrm dz \\\\ = 2019\int\frac{3\sec^2(z)}{9\tan^2(z)+9}\,\mathrm dz \\\\ = 673\int\frac{\sec^2(z)}{\tan^2(z)+1}\,\mathrm dz \\\\ = 673\int\frac{\sec^2(z)}{\sec^2(z)}\,\mathrm dz \\\\ = 673\int\mathrm dz \\\\ = 673z+C \\\\ = 673\arctan\left(\frac x3\right)+C[/tex]

Then

[tex]\displaystyle\int\frac{x+2019}{x^2+9}\,\mathrm dx = \boxed{\frac12\ln\left(x^2+9\right) + 673\arctan\left(\frac x3\right) + C}[/tex]

Step-by-step explanation:

Tan² theta = sec² theta - 1

Cot² theta = cosec² theta - 1

Tan²+Cot² = sec²-1+cosec²-1

= sec²+cosec²-2

Please find attached herewith the solution of your question.

If you have any doubt, please comment.

Answer:

50%

Step-by-step explanation:

35 is halve of 70 therefore it is 50%

hope it helps u...........

Answer:

made up of about 20 common amino acids. The proportion of these amino acids varies as a characteristic of a given protein, but all food proteins—with the exception of gelatin—contain some of each. Amino nitrogen accounts for approximately 16% of the weight of proteins. Amino acids are required for the synthesis of body protein and other important nitrogen-containing compounds, such as creatine, peptide hormones, and some neurotransmitters. Although allowances are expressed as protein, a the biological requirement is for amino acids.

Proteins and other nitrogenous compounds are being degraded and resynthesized continuously. Several times more protein is turned over daily within the body than is ordinarily consumed, indicating that reutilization of amino acids is a major feature of the economy of protein metabolism. This process of recapture is not completely efficient, and some amino acids are lost by oxidative catabolism. Metabolic products of amino acids (urea, creatinine, uric acid, and other nitrogenous products) are excreted in the urine; nitrogen is also lost in feces, sweat, and other body secretions and in sloughed skin, hair, and nails. A continuous supply of dietary amino acids is required to replace these losses, even after growth has ceased.

Amino acids consumed in excess of the amounts needed for the synthesis of nitrogenous tissue constituents are not stored but are degraded; the nitrogen is excreted as urea, and the keto acids left after removal of the amino groups are either utilized directly as sources of energy or are converted to carbohydrate or fat.

Answer:

29/44

Step-by-step explanation:

[tex]\frac{4}{11} +\frac{5}{22} +\frac{3}{44} =\\[/tex]

-find the common denominator

[tex]\frac{4*4}{4*11} + \frac{2*5}{2*22} +\frac{3}{44} =[/tex]

[tex]\frac{16}{44} +\frac{10}{44} +\frac{3}{44} =[/tex]

-add the fractions and solve

[tex]\frac{16+10+3}{44} =[/tex]

[tex]\frac{29}{44}[/tex]

Answer:

[tex]y=4x[/tex]

Answer:

y = -4x

hope that helped.........