If f(x) = 2x-5, then f(4) is ___.

If F(x) = 2x-5, Then F(4) Is ___.

Answers

Answer 1

Answer:

3

Step-by-step explanation:

f(x) = 2x-5

Let x = 4

f(4) = 2*4 - 5

Multiply

f(4) = 8 -5

Subtract

f(4) = 3


Related Questions

The roots of 7x^2 + x - 5 = 0 are a and b. Compute (a - 4)(b - 4). Thank you!

Answers

Answer:

Step-by-step explanation:

a = 7 ;  b = 1 ;  c = -5

D = b² - 4ac

  = 1 - 4*7*(-5)

  = 1 + 140

  = 141

x =( - b ± √D ) / 2a

 = (-1 ± √141)/2*7

 = (-1±√141) / 14

[tex]a = \frac{-1+\sqrt{141} }{14}= \frac{-1+11.87}{14}= \frac{10.87}{14}=0.78\\\\b = \frac{-1-\sqrt{141}}{14}= \frac{-1-11.87}{14}= \frac{-12.87}{14}=3.59\\\\\\[/tex]

(a -4 )(b -4) = (0.78 - 4)(-3.59-4) = (-3.22)(-7.59)

= 24.4398

Which of these is the lowest unit price for apples? $8.00 per 10-pound bag $21.40 per 3-pound bag $4.10 per 5-pound bag $.79 per pound Click on the correct answer.​

Answers

Answer:

.79 cents a pound is the lowest unit price for apples

Step-by-step explanation:

Which equation represents a quadratic function with a leading coefficient of 2 and a constant term of –3?

Answers

Answer:

[tex]2x^{2} +bx-3=0[/tex]

Step-by-step explanation:

General form. A quadratic function [tex]f(x)[/tex] is of the form [tex](ax^2+bx+c)[/tex] where [tex]a,b,c[/tex] ∈ R or C and [tex]a[/tex] ≠ [tex]0[/tex].

We obtain an equation when [tex]f(x)=0[/tex]

⇒ [tex]ax^{2} +bx+c=0[/tex] is an quadratic equation.

Solution.

Given, [tex]a=2,c=-3[/tex], but b is not given

Thus the quadratic function with leading coefficient [tex]a=2[/tex] and constant term [tex]c=-3[/tex] is given by

[tex]f(x)=2x^{2} +bx-3[/tex]

∴ the required quadratic equation is

[tex]2x^{2} +bx-3=0[/tex]

Find the values of a and b that make the second expression equivalent to the first expression. Assume that x > 0 and y ≥ 0.

Answers

Answer:

a= 16

b= 2

Step-by-step explanation:

edge 2021

Answer:

a=16 and b=2

Step-by-step explanation:

next one is B.

Find the value of x in the isosceles triangle shown below.

Answers

x²+16=20
x²=4
x=sqrt(4)
x=2

Hope this helps!!

Identify the least common multiple of:


(x + 1), (x - 1), & (x^2 - 1)

Answers

Given:

The expressions are [tex](x+1),\ (x-1)[/tex] and [tex](x^2-1)[/tex].

To find:

The least common multiple of given expressions.

Solution:

The expressions are [tex](x+1),\ (x-1)[/tex] and [tex](x^2-1)[/tex]. The factor forms of these expressions are:

[tex](x+1)=1\times (x+1)[/tex]

[tex](x-1)=1\times (x-1)[/tex]

[tex](x^2-1)=(x-1)(x+1)[/tex]                 [tex][\because a^2-b^2=(a-b)(a+b)][/tex]

The least common multiple is the product of all distinct factors with its highest degree. So,

[tex]L.C.M.=1\times (x+1)\times (x-1)[/tex]

[tex]L.C.M.=(x+1)(x-1)[/tex]

[tex]L.C.M.=x^2-1^2[/tex]                [tex][\because a^2-b^2=(a-b)(a+b)][/tex]

[tex]L.C.M.=x^2-1[/tex]

Therefore, the least common multiple of given expressions is [tex]x^2-1[/tex].

Joseph and Mark have $230. Joseph and Kevin have $130. Mark had 3 times as much money as Kelvin. How much money does Kelvin have?

Answers

Answer:

Step-by-step explanation:

Let's call Joseph "J", Mark "M", and Kevin "K" for ease. We need a system of equations to solve this, 3 equations for 3 unknowns. The first equation is

J + M = 230. The second equation is

J + K = 130. The third equation is

M = 3K. Sub that 3K into the first equation and get

J + 3K = 230. Now take th second equation and solve it for J:

J = 130 - K. Now sub 130 - K into the re-written first equation to get a whole new equation in terms of K only:

130 - K + 3K = 230 and

2K = 100 so

K = 50

Kevin has $50

If (a,3) is the point lying on the graph of the equation 5x + 2y = -4, Then find a.​

Answers

Answer:

I've attached the Answer

Answer:

a = - 2

Step-by-step explanation:

Given x = a, y = 3 lies on the equation. That is the values satisfies the equation when substituted.

Find a :

Equation : 5x + 2y = - 4

                5 ( a ) + 2 ( 3) = - 4

                5a + 6 = - 4

                 5a + 6 - 6 = - 4 - 6               [ subtracting both sides by 6 ]

                 5a  + 0 = - 10

                   5a = - 10

                    a = - 2                               [ dividing both sides by 5]

[ fact check : If (-2 , 3 ) lies on the equation : 5x + 2y = - 4

                                                                    5(-2) + 2( 3 ) = - 4

                                                                   - 10 + 6 = - 4

                                                                         - 4 = - 4 ]

Quadrilateral GHIJ is similar to quadrilateral KLMN. Find the measure of
side LM. Round your answer to the nearest tenth if necessary.

Answers

Answer:

LM = 24.3

Step-by-step explanation:

In terms of similar shapes, we know that the ratio of the value of one side to its corresponding side value is equal to another. In other words, we know that LK and HG are corresponding sides by looking at the quadrilaterals. The ratio of LK to HG is equal to the ratio of another pair of corresponding sides, such as LM and IH.

Therefore, the ratio of LK and HG (LK/HG) is equal to the ratio of LM and IH (LM/IH) . Make sure to keep the same quadrilateral's sides on top/bottom. In this example, LM and LK are on the same quadrilateral, and are therefore both on top. Similarly, IH and HG are of the same quadrilateral and are both on bottom. We can write this as

LK / HG = LM / IH

34/7 = LM / 5

Multiply both sides by 5

34*5/7 = LM

LM ≈ 24.2857

Rounding to the nearest tenth, LM = 24.3

Answer:

24.3

Step-by-step explanation:

In Which Quadrant is this true

Answers

Given:

[tex]\sin \theta <0[/tex]

[tex]\tan \theta <0[/tex]

To find:

The quadrant in which [tex]\theta[/tex] lie.

Solution:

Quadrant concept:

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II, only [tex]\sin\theta[/tex] and [tex]\csc\theta[/tex] are positive.

In Quadrant III, only [tex]\tan\theta[/tex] and [tex]\cot\theta[/tex] are positive.

In Quadrant IV, only [tex]\cos\theta[/tex] and [tex]\sec\theta[/tex] are positive.

We have,

[tex]\sin \theta <0[/tex]

[tex]\tan \theta <0[/tex]

Here, [tex]\sin\theta[/tex] is negative and [tex]\tan\theta[/tex] is also negative. It is possible, if [tex]\theta [/tex] lies in the Quadrant IV.

Therefore, the correct option is D.

HELP!!!!
Best answer gets brainliest.

Answers

Answer:

t-6=7 .................

Answer:

t - 6 = 7

Step-by-step explanation:

Which formula gives the coordinates of the midpoint of the segment connecting points (u, v) and (s, 6,t),


Answers

Answer:

[tex](\frac{u+s}{2} , \frac{v+t}{2} )[/tex] (the first option)

Step-by-step explanation:

The midpoint of a segment connecting two points [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] can be described by the following formula: [tex]\frac{x_1 + x_2}{2} = x_{mid}[/tex] and [tex]\frac{y_1 + y_2}{2} = y_{mid}[/tex]. As you can see, the formula essentially takes the average of the x- and y-coordinates to find the point in the middle.

With points (u, v) and (s, t), the midpoint becomes [tex](\frac{u+s}{2} , \frac{v+t}{2} )[/tex] (the first option).

A car covered 450km in 5 hours. find the speed in meters per second​

Answers

Step-by-step explanation:

Hey there!

Given;

Distance (d) = 450 km = 450*1000 = 450000 m

Time(t) = 5 hours = 5*60*60 = 18000s

Now;

Speed (s) = Distance (d) /Time(t)

Or, s = 450000/18000

Or, s = 25m/s.

Therefore, the speed is 25m/s.

Hope it helps!

Answer:

The car has a velocity of 25 m/s.

Step-by-step explanation:

There are two ways to solve this problem.

First way :

450km = 450.000m

5h = 5x 3.600s =18.000s

v = s/t = 450.000 / 18.000 = 25m/s

Second way :

Velocity = speed/time = 450 / 5 = 90 km/h

90/3.6 = 25 m/s

Either way, the car has a velocity of 25 m/s.

What’s the equation of the blue line?

Answers

Answer:

Step-by-step explanation:

The equation of blue line A is x = 1.

That of blue line B is y = 4.

Put these numbers in order from least to greatest.

1/8,1/2,0.13, and 7/8

Answers

Answer: 1/8, 0.13, 1/2, 7/8

Step-by-step explanation: Mental Math

Step-by-step explanation:

0.13,1/2,1/8,and 7/8

hope it is helpful to you

10 points!!!!! Do 14 and 15 only hurry please.

Answers

Answer:

8. x = 16

9. x = 10

14.

m ∠RSU = 130°

m ∠UST = 50°

15.

m ∠RSU = 124°

m ∠UST = 56°

Step-by-step explanation:

8.

GivenDEF is bisected by EG. That is , ∠DEG = ∠GEF

That is , (x + 15)° = 31°

                x = 31 - 15 =  16

9.

GivenDEF is bisected by EG. That is , ∠DEG = ∠GEF

That is ,

           (6x - 4)° = 56°

            6x = 56 + 4

               6x = 60

                 x = 10

14.

13x + 5x = 180°                       [straight line angles ]

18x = 180

x = 10

m ∠RSU = 130°

m ∠UST = 50°

15.

4x + 12 + 2x = 180°                       [ straight line angles]

6x = 180 - 12

6x = 168

x = 28

m ∠RSU = 4(28) + 12 = 112 + 12 = 124°

m ∠UST = 2(28) = 56°

Answer:

14. 13x+5x

=18x

180(angles on a st. line)= 18x

180/18

=10

RSU=13*10=130

UST=5*10=50

how u work it
and answer ​

Answers

Answer:

B

Step-by-step explanation:

So if B is the midpoint of AC, AB must be 1/2 of AC.

If D is the midpoint of AB, it must be 1/2 of 1/2 of AC, which is 1/4 of AC.

So AC= 4 DB

)) A farmer placed an order for 16 2/3 tons of fertilizer. He calculates that the corn fields
will require 8 5/6 tons of it. How much fertilizer will the farmer have left for his other crops?

Answers

Answer:

7 5/6

Step-by-step explanation:

16 2/3 - 8 5/6

16 4/6- 8 5/6

7 5/6

A side of the triangle below has been extended to form an exterior angle of 129°. Find the value of x.

Answers

129° + x = 180°. [Linear pair]

=> x = 180° - 129°

=> x = 51°

Ryder used front end estimation to estimate the product of -24.98 - 1.29 what is the zestimate​

Answers

Answer:

20

Step-by-step explanation:

The numbers whose product are to be obtained :

(–24.98)(–1.29)

To use front end approximation, numbers are rounded to the greatest place value :

For :

(-24.98) is rounded to - 20 (4 is rounded here to 0)

(-1.29) is rounder to - 1 (2 is rounded to 0)

Then, the product of the two numbers will be :

-20 * - 1 = 20

which graph shows the solution to this system of linear inequalities?​

Answers

Answer:

c or b

tep-by-step explanation:

In the given figure alongside,prove that
Triangle ABC is simalar to Triangle SRT
Find the length of AC​

Answers

Answer:

let's use Pythagoras theorem,

h²=b²+l²

so,

ad²=ac²+dc²

6²=ac²+3²

36-9=ac²=27

√27 can be written as 3√3,

hence ac= 3√3

Jodi has two bank accounts. Her parents started Account A for her. It currently has $100 in it, and Jodi deposits $20 into it each month. Jodi's grandparents started Account B for her. It currently has $300 in it, and her grandparents deposit $40 into it each month.

Answers

Answer:

(f+g)(x) = 60x + 400

Step-by-step explanation:

Given :

Amount in account A:

f(x) = 20x + 100

Amount in account B :

g(x) = 40x + 300

Total amount in Account A and B:

f(x) + g(x) = (20x + 100) + (40x + 300)

(f+g)(x) = (20x + 40x) + (100 + 300)

(f+g)(x) = 60x + 400

Let $z$ and $w$ be complex numbers satisfying $|z| = 5, |w| = 2,$ and $z\overline{w} = 6+8i.$ Then enter in the numbers \[|z+w|^2, |zw|^2, |z-w|^2, \left| \dfrac{z}{w} \right|^2 \]below, in the order listed above. If any of these cannot be uniquely determined from the information given, enter in a question mark. Don't even know where to start.

I got 49 for the first one, 100 for the second one, 9 for the 3rd one, and 6.25 for the 4th one. But it was wrong, so I don't know how to do this question.

Answers

Answer:

1st entry: 41

3rd entry: 17

Step-by-step explanation:

The 1st and 3rd entry are incorrect.

We will use the following for the 1st and 3rd:

[tex]|z+w|=|z|^2+|w|^2+2R(z\overline{w})[/tex]

[tex]|z-w|=|z|^2+|w|^2-2R(z\overline{w})[/tex]

where [tex]R(z\overline{w})[/tex] means 'real part of [tex]z\overline{w}[/tex]'.

Let's do part 1 now)

25+4+2(6)

29+12

41

Let's do part 3 now)

25+4-2(6)

29-12

17

Given that X = - 2 and y = 4 , Evaluate the expression. 5y – 4x

Answers

Answer: 28

Step-by-step explanation: 5(4)-4(-2) which is 20+8 and that is 28.

NEED HELLPPPPP !!!!

Answers

Answer:

x = 14

Step-by-step explanation:

Triagle GIA and Triangle GNT are congruent.

Jamal puts $100 in an account that does not earn any interest. Every month after that, he deposits the same amount of money. This sequence represents his account balance for the first few months. $100, $125, $150, What is the explicit formula in function form for the amount of money in his account at the beginning of month n?

Answers

Answer:

Tn = 75+25n

Step-by-step explanation:

The balance are in arithmetic progression

$100, $125, $150...

The formula for calculating the nth term of the sequence is expressed as;

Tn = a+(n-1)d

a =100

d = 125 - 100 = 150 - 125

d = 25

n is the number of terms

Substitute

Tn = 100+(n-1)*25

Tn = 100 + 25n-25

Tn = 75+25n

Hence the nth term of the sequence is Tn = 75+25n

Find angle C!!!!! See the image below! I need this answer fast

Answers

Answer:

55

Angle C is a inscribed angle of the of Arc Ba.

CA is the diameter so that means Arc BA equal 110 becuase

110+70=180.

Angle C is half of Arc BA so Angle C is

[tex]55[/tex]

The ages of five children in a family are 6, 1, 3, 10, and 17. Which statement is true for this group of data?

mode>mean
median>mean
median=mode
mean>median

Answers

Answer:D - mean>median

Step-by-step explanation:

There are no repeating variables to have a mode so median and mean are the only options. The mean of this data set is 7.4 and the median is 6. Therefore mean greater than median

if a triangle has one angle that measure 81 degrees and another that measures 47 degrees, what is the measure of the third angle?

Answers

Answer: 52

Step-by-step explanation:

81 + 47 is 128.

180 - 128 =52 degrees.

:)

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