If force F, volume V and density D are taken as fundamental quantities, then the representation of pressure P will be​

Answers

Answer 1

Using the principle of dimensional analysis, the representation of Pressure would be [tex] P = F^{1}V^{-\frac{2}{3}}D^{0}[/tex]

Pressure is related to Force, Volume and Density thus :

[tex] Pressure, P = F^{a}V^{b}D^{c}[/tex]

Using dimensional analysis :

Pressure, P = ML¯¹T¯²

Substituting the dimension into the relation :

[tex] ML^{-1}T^{-2}= [MLT¯²]^{a} [L³]^{b} [ML¯³]^{c} [/tex]

[tex] ML^{-1}T^{-2} = M^{a+c}L^{a+3b-3c}T^{-2a} [/tex]

Equating the power ;

a + c = 1 - - - (1)

a + 3b - 3c = - 1 - - - (2)

-2a = - 2

a = - 2/-2

a = 1

From (1)

1 + c = 1

c = 1 - 1 = 0

c = 0

From (2) :

1 + 3b - 3(0) = - 1

1 + 3b = - 1

3b = - 2

b = - 2/3

Hence, [tex] P = F^{1}V^{-\frac{2}{3}}D^{0}[/tex]

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Answer 2

The representation of pressure is:

[tex]P=FV^{-\frac{2}{3} }[/tex]

Given that:

Force F, volume V and density D are taken as fundamental quantities, hence pressure P is:

[tex]P=F^aV^bD^c\\\\(ML^{-1}T^{-2})=(MLT^{-2})^a(L^3)^b(ML^{-3})^c\\\\\\(ML^{-1}T^{-2})=(M)^{a+c}(L)^{a+3b-3c}(T)^{-2a}[/tex]

Hence:-

2 = -2a

a = 1

a + c = 1

1 + c = 1

c = 0

a + 3b - 3c = -1

1 + 3b - 3(0) = -1

3b = -2b = -2/3

Hence the representation of pressure is:

[tex]P=FV^{\frac{-2}{3} }D^{0}\\\\P=FV^{\frac{-2}{3} }[/tex]

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The magnitude of force acting on the body is 36N

An object weighs 15 N in air and 13 N when submerged in mineral spirits, which has a density of 788 kg/m3. Determine the density of the object

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The density of the object is 5911.94 kg/m³

An object's buoyancy is the upward force produced by a fluid in opposition to the weight of a partly or totally submerged object.

The buoyancy = weight of the object - weight in water

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The buoyancy force can also be determined by using the expressed:

[tex]\mathbf{F_B = Volume (V) \times density ( \rho) \times g}[/tex]

[tex]\mathbf{2 = Volume (V) \times788 \ kg/m^3 \times9.8 }[/tex]

[tex]\mathbf{ Volume (V) = \dfrac{2}{ 788 \ kg/m^3 \times9.8 }}[/tex]

volume (v) = 2.589 × 10⁻⁴m³

Recall that:

The mass of an object can be estimated by using the formula:

Weight = mass × gravity

mass = Weight / gravity

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mass = 1.5306 kg

The density of the object can now be calculated using the relation

Density = mass/volume

Density = 1.5306 kg / 2.589 × 10⁻⁴m³

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Answer:

Answer below

Explanation:

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The rotating movement of bodies is described by angular velocity. It determines how quickly they rotate around a central point. Rotations may be divided into two categories. The first explains the motion of an object's centre of mass around a certain point in space, which is referred to as an origin. Planets orbiting the Sun, for example, or an automobile exiting a roadway are two instances.

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So directly the cell density value in a rectangle is:

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Next, let's calculate the density from the calculated area:

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In this way, the calculation represents that there is:

[tex]5*10^{17} cells/cm^{2}[/tex]

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When the sum of all the forces acting on a block.

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Answer:

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Answer:

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Explanation:

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Answer:

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Explanation:

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Two 4 kg blocks hang from a rope that passes over two frictionless pulleys . What is the tension in the horizontal portion of the rope if the blocks are not moving and the rope and the two pulleys have negligible mass?

Answers

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A cable pulls a car up a mountain with a force of 4 × 103 N at a vertical constant velocity of 5 m.s-1. It takes 5 minutes to reach the top.

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Answers

Answer:

(a) 6,000,000J      

(b)  3,000,000J

(c)  For A 20,000W

But for B 10,000W

The work done in getting  the car to the top is equal to 6 ×10⁶ J. If the vertical speed is 2.5 m/s then, the work done will be  3 ×10⁶ J. The power exerted on the car is in 5 minutes is 20000 J/s.

What is work done ?

In physics, work done is the dot  product of force and displacement. Let w be the work done and F and ds be the force and displacement. Then

W = F.ds

It is given that the, the force of the cable is 4 × 10³ N. The velocity is 5 m/s and time is 5 minutes or 300 seconds. Now, the displacement is the product of time and velocity.

ds = velocity ×  time

    =  300 s ×  5 m/s

    = 1500 m.

Thus the work done = F × ds

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Answer:

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Answer:

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Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. You have determined that the football would travel 15.1 m before landing.

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Answer:

Work done,W= 250J

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Hence , 4.16 N of Force is applied on the body.

Please find attached photograph for your answer.

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An irregularly shaped stone was lowered into a graduated cylinder holding a volume of water equal to 20L. The height of water rose to 30.2mL. If the mass of the stone was 25g what was its density?

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Answer:

2.45 g/mL

Explanation:

(assuming that the original volume was 20 mL and not L)

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Answer: G

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Answer:

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Answer:

thats a force

Explanation:

Answer:

force

Explanation:

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Answers

Answer:

Radio waves

Explanation:

The radio operates by the principles of radio wave.

Electromagnetic wave is a type of wave which does not require material medium for its propagation. A radio wave is an example of electromagnetic wave.

The radio operates in the principle of electromagnetic wave because it does not require material medium for its propagation and it has one of the longest frequency of electromagnetic spectrum.

Thus, we can conclude that the radio operates by the principles of radio wave.

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Answer:

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Explanation:

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