Answer:
€1.39
Step-by-step explanation:
£0.72 ÷ 0.72 = 1÷0.72
£1= €1.39
simplify 3[(15-3)^2 + 4]
Answer:
444
Step-by-step explanation:
3 [ ( 15 - 3 )^2 + 4 ]
= 3 [ ( 15 - 3 )^2 + 4 ]
= 3 [ ( 12 )^2 + 4 ]
= 3 [ 144 + 4 ]
= 3 [ 148 ]
= 444
Step-by-step explanation:
3(15-3)²+4
3(12)²+4
3×144+4
432+4
436 Answer
(Algebra ll) Given the function below
Answer: B
Step-by-step explanation:
To find the values of x, we first need to write the function into an equation. We can derive 2 equations from the problem.
Equation 1: y=2|x+6|-4
Equation 2: y=6
Now, we can substitute.
2|x+6|-4=6
Let's solve for x.
2|x+6|-4=6 [add both sides by 4]
2|x+6|=10 [divide both sides by 2]
|x+6|=5 [subtract both sides by 6]
x=-1
Now that we know x=-1 is one of the solutions, we can eliminate C and D.
We know that the absolute value makes the number inside positive always. Therefore, let's solve for x with -5 instead.
|x+6|=-5 [subtract both sides by 6]
x=-11
Therefore, we know that B is the correct answer.
Summer school math problem
Hello!
4/18 = 6/27 ?
4 × 27 = 18 × 6
108 = 18 × 6
108 = 108 => 4/18 = 6/27
4/6 = 16/36 ?
4 × 36 = 6 × 16
144 = 6 × 16
144 ≠ 96 => 4/6 ≠ 16/36
3/4 = 9/12 ?
3 × 12 = 4 × 9
36 = 4 × 9
36 = 36 => 3/4 = 9/12
5/9 = 8/12 ?
5 × 12 = 9 × 8
60 = 9 × 8
60 ≠ 72 => 5/9 ≠ 8/12
Good luck! :)
Given ACM, angle C=90º. AP=9, PM=12. Find AC, CM, AM.
Answer:
AM = 25, AC = 15, CM = 20
Step-by-step explanation:
The given parameters are;
In ΔACM, ∠C = 90°, [tex]\overline{CP}[/tex] ⊥ [tex]\overline{AM}[/tex], AP = 9, and PM = 16
[tex]\overline{AC}[/tex]² + [tex]\overline{CM}[/tex]² = [tex]\overline{AM}[/tex]²
[tex]\overline{AM}[/tex] = [tex]\overline{AP}[/tex] + PM = 9 + 16 = 25
[tex]\overline{AM}[/tex] = 25
[tex]\overline{AC}[/tex]² = [tex]\overline{AP}[/tex]² + [tex]\overline{CP}[/tex]² = 9² + [tex]\overline{CP}[/tex]²
∴ [tex]\overline{AC}[/tex]² = 9² + [tex]\overline{CP}[/tex]²
Similarly we get;
[tex]\overline{CM}[/tex]² = 16² + [tex]\overline{CP}[/tex]²
Therefore, we get;
[tex]\overline{AC}[/tex]² + [tex]\overline{CM}[/tex]² = 9² + [tex]\overline{CP}[/tex]² + 16² + [tex]\overline{CP}[/tex]² = [tex]\overline{AM}[/tex]² = 25²
2·[tex]\overline{CP}[/tex]² = 25² - (9² + 16²) = 288
[tex]\overline{CP}[/tex]² = 288/2 = 144
[tex]\overline{CP}[/tex] = √144 = 12
From [tex]\overline{AC}[/tex]² = 9² + [tex]\overline{CP}[/tex]², we get
[tex]\overline{AC}[/tex] = √(9² + 12²) = 15
[tex]\overline{AC}[/tex] = 15
From, [tex]\overline{CM}[/tex]² = 16² + [tex]\overline{CP}[/tex]², we get;
[tex]\overline{CM}[/tex] = √(16² + 12²) = 20
[tex]\overline{CM}[/tex] = 20.
Work out the area of the shaded
Hi there!
[tex]\large\boxed{73m^2}}[/tex]
Once again, divide the figure into 3 rectangles:
Top rectangle:
3m × 5m = 15m²
Long rectangle (subtract 5m from 9m to get the width):
12m × 4m = 48m²
Bottom rectangle:
2m × 5m = 10m²
Add up areas:
15m² + 48m² + 10m² = 73m²
The equation of line r is y = 1/2 * x + 1 line runs parallel to line r and passes through (2, 5) what would be the equation of line 8 ?help please
Answer:
x - 2y + 8 = 0
Step-by-step explanation:
that is the procedure above
Helpp m and explain ,I will mark brainlest:)
Answer:
(0,3) ; (2,3) ; (0,0) ; (3.5,0)
Step-by-step explanation:
Firstly, we have to plot all the giving inequalities as constraints
Not to forget, f(x) can be written as y
Kindly find the plot as an attachment
Upon plotting, we have the following vertices;
(0,3) ; (2,3) ; (0,0) ; (3.5,0)
Please help, im confused ;w;
Answer:
[tex]x=7\text{ and } m\angle KLM = 34^\circ[/tex]
Step-by-step explanation:
We are given ethat KM and JN are parallel.
And we want to find the value of x.
Notice that ∠JKM and ∠LKM form a linear pair. Linear pairs total 180°. Therefore:
[tex]m\angle JKM + m\angle LKM = 180[/tex]
We know that ∠JKM measures (14x + 8). Substitute:
[tex](14x+8)+m\angle LKM =180[/tex]
Solve for ∠LKM:
[tex]m\angle LKM = 172-14x[/tex]
Next, since KM and JN are parallel, by the Corresponding Angles Theorem:
[tex]\angle JNM \cong \angle KML[/tex]
Since we know that ∠JNM measure (10x + 2), we can conclude that:
[tex]m\angle KML = 10x+2[/tex]
Next, recall that the three interior angles of a triangle must total 180°. Therefore:
[tex]m\angle KLM + m\angle LKM + m\angle KML = 180[/tex]
Substitute:
[tex](5x-1)+(172-14x)+(10x+2)=180[/tex]
Solve for x. Rewrite:
[tex](5x-14x+10x)+(-1+172+2)=180[/tex]
Combine like terms:
[tex](1x)+(173)=180[/tex]
Therefore:
[tex]x=7[/tex]
To find ∠KLM, substitute in 7 for x and evaluate. So:
[tex]m\angle KLM = 5(7) - 1 =34^\circ[/tex]
Adya and Ashley complete a work separately in 20 and 25 days respectively. After 10 days of their working together, they both left then Amber came and completed the remaining work in 3 days. If Amber alone would do the work, calculate how many days he would take to complete the work.?
[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]
Number of days Adya took to complete the work = 20
Work done by Adya in 1 day = [tex]\frac{1}{20}[/tex]
Number of days Ashley took to complete the work = 25
Work done by Ashley in 1 day = [tex]\frac{1}{25}[/tex]
So,
Total work by Adya & Ashley in 1 day =
[tex] \frac{1}{20} + \frac{1}{20} \\ = \frac{5 + 4}{100} \\ = \frac{9}{100} [/tex]
•°• Their total work in 10 days =
[tex] \frac{9 \times 10}{100} \\ = \frac{90}{100} \\ = \frac{9}{10} [/tex]
Now,
The work left to be completed =
[tex]1 - \frac{9}{10} \\ = \frac{10}{10} - \frac{9}{10} \\ = \frac{1}{10} [/tex]
From this we know that,
Amber completes [tex]\frac{1}{10}[/tex] of the work in 3 days.
So,
Time taken by Amber to complete the whole work =
[tex]3 \times 10 \\ = 30 \: \: days[/tex]
↦ If Amber alone would do the whole work, he would take [tex]\boxed{30 \ \ days}[/tex] to complete it.
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ ツ
꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐
Which of the following is ordered pair for point C?
Answer:
B. (4,2)
Step-by-step explanation:
Answer:
B(4,2)
Step-by-step explanation:
as you can see that if want to find coordinates u should know that the position of x and y is (x,y). So u can that c on the x is lower than 5 so that u can say it is 4 and y is too far away from 5 also u it will be 2.
I have a lot of algebra problems. Someone help me even with this one please!
X -Y =44 will represent the number of glasses of ice tea .
ratio and proportion
One of the angle of pair of supplementary angle is 120 degree. find the ratio of pair of supplementary angles.
Answer:
2 : 1
Step-by-step explanation:
Supplementary angles are two angles whose measures add up to 180°
If one of the angle = 120°
The other angle = sum of supplementary angle - one of the angle
= 180° - 120°
= 60°
The other angle = 60°
ratio of pair of supplementary aangle = 120° : 60°
= 120° / 60°
= 2/1
= 2 : 1
ratio of pair of supplementary aangle = 2 : 1
this is my last set of questions if anyone could get them all completed I have 15 points on it If you could add a small explanation so I can learn from it really appreciate it :) brainliest for anyone who does all 3 questions
Answer:
832.5
A unit rate is a rate with 1 in the denominator.
Which is the pair of congruent right angles?
A).CAB=DAE
B).CBA=DEA
C).BCA=EDA
D).ACB=ADE
Answer:
It's C
Step-by-step explanation:
Which of the following describes point D?
The coordinates that describe the point D are: Option C: (0, 4)
How to find the coordinates of the graph?The graph shows that the vertical axis is labelled as the y-axis while the horizontal axis is labelled as the x -axis.
Normally, the coordinate system of writing the given points of the graph is (x, y)
Thus, the point D on the graph is seem to be 4 units on the positive y-axis and 0 units on the positive x-axis and as such, we can say that the coordinates of point D are:
D(0, 4)
Read more about Graph Coordinates at: https://brainly.com/question/11337174
Complete question is:
Which of the following describes point D?
(-4, 0)
(0, -4)
(0, 4)
(4, 0)
Which of the following numbers does not have
factors that include the smallest factor (other
than 1) of 119 ?
A. 28
B. 35
C. 40
D. 63
Answer:
C. 40
Step-by-step explanation:
The smallest factor of 119 (other than 1) is 7.
28/7 = 4,
35/7 = 5,
40/7 = 5 5/7
63/7 = 9
So it is 40
What is the surface area of this right circular cone?
radius=12
height=40
Answer:
2026.75 (units) squared
Step-by-step explanation:
SA of a cone = πr(r+h2+r2)
SA = π(12)(12+√(40^2)+(12^2))
SA = 12π(12+√1744)
Put in calculator and get 2026.75
Quadrilateral ABCD is reflected across the x-axis and then reflect across the y-axis to form quadrilateral A′B′C′D′. If the coordinates of vertex A are (-7, 3), what are the coordinates of vertex A′?
Let N be the smallest positive integer whose sum of its digits is 2021. What is the sum of the digits of N + 2021?
Answer:
[tex]10[/tex].
Step-by-step explanation:
See below for a proof of why all but the first digit of this [tex]N[/tex] must be "[tex]9[/tex]".
Taking that lemma as a fact, assume that there are [tex]x[/tex] digits in [tex]N[/tex] after the first digit, [tex]\text{A}[/tex]:
[tex]N = \overline{\text{A} \, \underbrace{9 \cdots 9}_{\text{$x$ digits}}}[/tex], where [tex]x[/tex] is a positive integer.
Sum of these digits:
[tex]\text{A} + 9\, x= 2021[/tex].
Since [tex]\text{A}[/tex] is a digit, it must be an integer between [tex]0[/tex] and [tex]9[/tex]. The only possible value that would ensure [tex]\text{A} + 9\, x= 2021[/tex] is [tex]\text{A} = 5[/tex] and [tex]x = 224[/tex].
Therefore:
[tex]N = \overline{5 \, \underbrace{9 \cdots 9}_{\text{$224$ digits}}}[/tex].
[tex]N + 1 = \overline{6 \, \underbrace{000 \cdots 000000}_{\text{$224$ digits}}}[/tex].
[tex]N + 2021 = 2020 + (N + 1) = \overline{6 \, \underbrace{000 \cdots 002020}_{\text{$224$ digits}}}[/tex].
Hence, the sum of the digits of [tex](N + 2021)[/tex] would be [tex]6 + 2 + 2 = 10[/tex].
Lemma: all digits of this [tex]N[/tex] other than the first digit must be "[tex]9[/tex]".
Proof:
The question assumes that [tex]N\![/tex] is the smallest positive integer whose sum of digits is [tex]2021[/tex]. Assume by contradiction that the claim is not true, such that at least one of the non-leading digits of [tex]N[/tex] is not "[tex]9[/tex]".
For example: [tex]N = \overline{(\text{A})\cdots (\text{P})(\text{B}) \cdots (\text{C})}[/tex], where [tex]\text{A}[/tex], [tex]\text{P}[/tex], [tex]\text{B}[/tex], and [tex]\text{C}[/tex] are digits. (It is easy to show that [tex]N[/tex] contains at least [tex]5[/tex] digits.) Assume that [tex]\text{B} \![/tex] is one of the non-leading non-"[tex]9[/tex]" digits.
Either of the following must be true:
[tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex] is a "[tex]0[/tex]", or[tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex] is not a "[tex]0[/tex]".If [tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex], is a "[tex]0[/tex]", then let [tex]N^{\prime}[/tex] be [tex]N[/tex] with that "[tex]0\![/tex]" digit deleted: [tex]N^{\prime} :=\overline{(\text{A})\cdots (\text{B}) \cdots (\text{C})}[/tex].
The digits of [tex]N^{\prime}[/tex] would still add up to [tex]2021[/tex]:
[tex]\begin{aligned}& \text{A} + \cdots + \text{B} + \cdots + \text{C} \\ &= \text{A} + \cdots + 0 + \text{B} + \cdots + \text{C} \\ &= \text{A} + \cdots + \text{P} + \text{B} + \cdots + \text{C} \\ &= 2021\end{aligned}[/tex].
However, with one fewer digit, [tex]N^{\prime} < N[/tex]. This observation would contradict the assumption that [tex]N\![/tex] is the smallest positive integer whose digits add up to [tex]2021\![/tex].
On the other hand, if [tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex], is not "[tex]0[/tex]", then [tex](\text{P} - 1)[/tex] would still be a digit.
Since [tex]\text{B}[/tex] is not the digit [tex]9[/tex], [tex](\text{B} + 1)[/tex] would also be a digit.
let [tex]N^{\prime}[/tex] be [tex]N[/tex] with digit [tex]\text{P}[/tex] replaced with [tex](\text{P} - 1)[/tex], and [tex]\text{B}[/tex] replaced with [tex](\text{B} + 1)[/tex]: [tex]N^{\prime} :=\overline{(\text{A})\cdots (\text{P}-1) \, (\text{B} + 1) \cdots (\text{C})}[/tex].
The digits of [tex]N^{\prime}[/tex] would still add up to [tex]2021[/tex]:
[tex]\begin{aligned}& \text{A} + \cdots + (\text{P} - 1) + (\text{B} + 1) + \cdots + \text{C} \\ &= \text{A} + \cdots + \text{P} + \text{B} + \cdots + \text{C} \\ &= 2021\end{aligned}[/tex].
However, with a smaller digit in place of [tex]\text{P}[/tex], [tex]N^{\prime} < N[/tex]. This observation would also contradict the assumption that [tex]N\![/tex] is the smallest positive integer whose digits add up to [tex]2021\![/tex].
Either way, there would be a contradiction. Hence, the claim is verified: all digits of this [tex]N[/tex] other than the first digit must be "[tex]9[/tex]".
Therefore, [tex]N[/tex] would be in the form: [tex]N = \overline{\text{A} \, \underbrace{9 \cdots 9}_{\text{many digits}}}[/tex], where [tex]\text{A}[/tex], the leading digit, could also be [tex]9[/tex].
someone help me please with this algebra problem
Answer:
60
Step-by-step explanation:
5x + 10y = 800
y = 50
5x + 10(50) = 800
5x + 500 = 800
5x = 300
x = 60
Answer: 60
Step-by-step explanation:
If x = small vehicles and if y = large vehicles and y = 50, then substitute and solve for x. So,
5x + 10(50) = 800
5x + 500 = 800
5x = 300
x = 60
So, the number of small vehicles is 60.
A company that manufactures hair ribbons knows that the number of ribbons it can sell each week, x, is related to the price p per ribbon by the equation below.
x = 1,000 − 100p
At what price should the company sell the ribbons if it wants the weekly revenue to be $1,600? (Remember: The equation for revenue is R = xp.)
p = $ (smaller value)
p = $ (larger value)
Given:
The number of ribbons it can sell each week, x, is related to the price p per ribbon by the equation:
[tex]x=1000-100p[/tex]
To find:
The selling price if the company wants the weekly revenue to be $1,600.
Solution:
We know that the revenue is the product of quantity and price.
[tex]R=xp[/tex]
[tex]R=(1000-100p)p[/tex]
[tex]R=1000p-100p^2[/tex]
We need to find the value of p when the value of R is $1600.
[tex]1600=1000p-100p^2[/tex]
[tex]1600-1000p+100p^2=0[/tex]
[tex]100(16-10p+p^2)=0[/tex]
Divide both sides by 100.
[tex]p^2-10p+16=0[/tex]
Splitting the middle term, we get
[tex]p^2-8p-2p+16=0[/tex]
[tex]p(p-8)-2(p-8)=0[/tex]
[tex](p-8)(p-2)=0[/tex]
Using zero product property, we get
[tex]p-8=0[/tex] or [tex]p-2=0[/tex]
[tex]p=8[/tex] or [tex]p=2[/tex]
Therefore, the smaller value of p is $2 and the larger value of p is $8.
In the equation 17x2 = 12x, the value of c is:
O
0 12
O 17
Answer:
ok ok ok ok ok ok ok
Step-by-step explanation:
I need help pls !!!!!!!
what is the mid point of AB?
Answer:
G
Step-by-step explanation:
I did this on edge and it was right
Answer:
O Point G
Step-by-step explanation:
A = -6
B = 8
To find the midpoint, calculate how much would it take for both points to have a value of zero.
-6 + ? = 0
-6 + 6 = 0
8 - ? = 0
8 - 8 = 0
so the midpoint will be about 7 (between 6 & 8)
Now which of the points best shows 7 units apart of AB
Answer: point G
Shjdksjcksmcjcsnuckamc
Answer:
you should make the picture more clear, i cant see the answer choices
Answer:
use pythogoream theorem that is,
Step-by-step explanation:
c*2=a*2+b*2
so in order to find a*2;
a*2=c*2-b*2
Joel Trump is paid one and one-half times the regular hourly rate for all hours worked in excess of 40 hours per week and double time for work on Sunday. Trump's regular rate is $8 per hour. During the week ended October 10, he worked 9 hours each day from Monday through Friday, 6 hours on Saturday, and 4 hours on Sunday. Trump's total earnings for the week ended October 10 are a.$320. b.$430. c.$516. d.$110.
Answer:
C. $516
Step-by-step explanation:
His regular rate is $8 per hour.
Since it's 40 hours a week, it means from Monday to Friday his regular work time is 8 hours per day.
Thus, for the regular week work, he is to be paid;
40 × 8 = $320
Now, we are told he worked 9 hours each day from Monday through Friday.
This means that;
He worked 1 hour each day.
That is 5 hours extra from Monday to Friday.
He is paid one and one-half times the regular hourly rate.
Thus, for this 5 extra hours, he will be paid 1½ × 5 × 8 = $60
He works 6 hours on Saturday, and 4 hours on Sunday.
Thus;
For Saturday, he is also paid one and one-half of regular pay. Thus, he is due for;
1½ × 8 × 6 = $72
He is paid double the regular hourly pay for Sundays.
Thus, for 4 hours on Sunday, he is paid;
2 × 8 × 4 = $64
Total he is due = $320 + $60 + $72 + $64 = $516
[tex]\sqrt{x} 8xyx^{2}[/tex]
Answer:
nom nom
Step-by-step explanation:
nom nommy nom nom
PLEASE ASAP
c) Next, you will make a scatterplot. Name a point that will be on your scatterplot and describe what it represents.
d) Using the regression calculator in your tool bar, create a scatterplot using your data set from step 1. Insert a screenshot of your scatterplot, or recreate it below.
The data is in the pic below
If u want more points for the answer, pls answer the previous question (same one) in my profile worth 30 points)
THX
Answer:
C)Ok i pick the point (18,4)
this point represents that if this person studied from 18 hours they got a GPA of 4.0
D) the chart below is the scatter plot
Hope This Helps!!!
Hello please help ASAP!
10 ^ (th) term for AP-5,-10,-15,..... is :-(A) -955 (B) 50 (C) -50 (D) 955
Answer:
C
Step-by-step explanation:
The nth term of an AP is
[tex]a_{n}[/tex] = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = - 5 and d = a₂ - a₁ = - 10 - (- 5) = - 10 + 5 = - 5 , then
a₁₀ = - 5 + (9 × - 5) = - 5 - 45 = - 50 → C