Answer:
False
Step-by-step explanation:
To show that this is false, all we have to do is find one example.
9 is an odd number less than 15
9 is composite
9 =3*3
The following data were collected from a simple random sample from an infinite population.
13 15 14 16 12
The point estimate of the population standard deviation is _____.
a. 1.581
b. 2.500
c. 2.000
d. 1.414
Answer:
1.581
Step-by-step explanation:
Given the data:
13 15 14 16 12
The point estimate of the standard deviation will be :
√Σ(x - mean)²/n-1
Mean = Σx / n = 70 / 5 = 14
√[(13 - 14)² + (15 - 14)² + (14 - 14)² + (16 - 14)² + (12 - 14)² / (5 - 1)]
The point estimate of standard deviation is :
1.581
A projectile is fired from ground level with an initial velocity of 35 m/s at an angle of 35° with the horizontal. How long
will it take for the projectile to reach the ground?
Answer:
Step-by-step explanation:
We will work in the y-dimension only here. What we need to remember is that acceleration in this dimension is -9.8 m/s/s and that when the projectile reaches its max height, it is here that the final velocity = 0. Another thing we have to remember is that an object reaches its max height exactly halfway through its travels. Putting all of that together, we will solve for t using the following equation.
[tex]v=v_0+at[/tex]
BUT we do not have the upwards velocity of the projectile, we only have the "blanket" velocity. Initial velocity is different in both the x and y dimension. We have formulas to find the initial velocity having been given the "blanket" (or generic) velocity and the angle of inclination. Since we are only working in the y dimension, the formula is
[tex]v_{0y}=V_0sin\theta[/tex] so solving for this initial velocity specific to the y dimension:
[tex]v_{0y}=35sin(35)[/tex] so
[tex]v_{0y}=[/tex] 2.0 × 10¹ m/s
NOW we can fill in our equation from above:
0 = 2.0 × 10¹ + (-9.8)t and
-2.0 × 10¹ = -9.8t so
t = 2.0 seconds
This is how long it takes for the projectile to reach its max height. It will then fall back down to the ground for a total time of 4.0 seconds.
1 cm = 5km scale ratio
Answer: Definition: Ratio of the size of the map to its subject: Scale ... so scale = 1 cm / 100,000 cm = 1/100,000. - Scale ... STEP 1: - 2 cm represents 5 km
Step-by-step explanation:
STEP 1: - 2 cm represents 5 km - (write in full)
- STEP 2: - 1 cm represents 2.5 km - (divide so left side = 1)
- STEP 3: - 1 cm represents 250,000 cm - (convert to same units)
- STEP 4: - scale is 1 : 250,000 - (express as a representative fraction)
every student from different schools planted as many plants of their number if they planted 4225 plants how many students were there
Answer:
65 students.
Step-by-step explanation:
Given that :
Every student planted as many plant as their number ;
Then let the number of student = x
Then the number of plant planted by each student will also = x
The total number of plants planted by all the students = 4225
The Number of students can be obtained thus ;
Total number of plants = Number of plants * number of plants per student
4225 = x * x
4225 = x²
√4225 = x
65 = x
Hence, there are 65 students
If $3000 is invested at 3% interest, find the value of the investment at the end of 7 years if the interest is compounded as follows. (Round your answers to the nearest cent.)
(i) annually
(ii) semiannually
(iii) monthly
(iv) weekly
(v) daily
(vi) continuously
Answer:
annualy=$3689.62
semiannually=$3695.27
monthly=$3700.06
weekly=$3700.81
daily=$3701.00
Continuously=$3701.03
Step-by-step explanation:
Given:
P=3000
r=3%
t=7 years
Formula used:
Where,
A represents Accumulated amount
P represents (or) invested amount
r represents interest rate
t represents time in years
n represents accumulated or compounded number of times per year
Solution:
(i)annually
n=1 time per year
[tex]A=3000[1+\frac{0.03}{1} ]^1^(^7^)\\ =3000(1.03)^7\\ =3689.621596\\[/tex]
On approximating the values,
A=$3689.62
(ii)semiannually
n=2 times per year
[tex]A=3000[1+\frac{0.03}{2}^{2(4)} ]\\ =3000[1+0.815]^14\\ =3695.267192[/tex]
On approximating the values,
A=$3695.27
(iii)monthly
n=12 times per year
[tex]A=3000[1+\frac{0.03}{12}^{12(7)} \\ =3000[1+0.0025]^84\\ =3700.0644[/tex]
On approximating,
A=$3700.06
(iv) weekly
n=52 times per year
[tex]A=3000[1+\frac{0.03}{52}]^3^6 \\ =3000(1.23360336)\\ =3700.81003[/tex]
On approximating,
A=$3700.81
(v) daily
n=365 time per year
[tex]A=3000[1+\frac{0.03}{365}]^{365(7)} \\ =3000[1.000082192]^{2555}\\ =3701.002234[/tex]
On approximating the values,
A=$3701.00
(vi) Continuously
[tex]A=Pe^r^t\\ =3000e^{\frac{0.03}{1}(7) }\\ =3000e^{0.21} \\ =3000(1.23367806)\\ =3701.03418\\[/tex]
On approximating the value,
A=$3701.03
The number of runners in the London Marathon on 25th April, 2010 was 37 527.
Work out an estimate for the number of these runners whose birthday was on that day.
Answer:
Hi 34
Step-by-step explanation:
Hi
Help and explain explain !!!!!!!!!!
Answer:
[tex]x=-1\text{ or }x=11[/tex]
Step-by-step explanation:
For [tex]a=|b|[/tex], we have two cases:
[tex]\begin{cases}a=b,\\a=-b\end{cases}[/tex]
Therefore, for [tex]18=|15-3x|[/tex], we have the following cases:
[tex]\begin{cases}18=15-3x,\\18=-(15-3x)\end{cases}[/tex]
Solving, we have:
[tex]\begin{cases}18=15-3x, -3x=3, x=\boxed{-1},\\18=-(15-3x), 18=-15+3x, 33=3x, x=\boxed{11}\end{cases}[/tex].
Therefore,
[tex]\implies \boxed{x=-1\text{ or }x=11}[/tex]
Find the length of an arc of a circle with a 8-cm radius associated with a central angle of 240 degrees. Give your answer in exact and approximate form to the nearest hundredth.
Answer:
l = 1920 cm
Step-by-step explanation:
Given that,
The radius of circle, r = 8 cm
The central angle is 240 degrees
We need to find the length of the arc. We know that,
[tex]l=r\theta[/tex]
Where
l is the length of the arc
So,
[tex]l=8\times 240[/tex]
[tex]\implies l=1920\ cm[/tex]
so, the length of the arc is equal to 1920 cm.
The system of equations y = negative one-fifth x minus 6 and y = –2x + 3 is shown on the graph below.
On a coordinate plane, 2 lines intersect at (5, negative 7).
According to the graph, what is the solution to this system of equations?
(5, –7)
(–7, 5)
(5, 7)
(7, 5)
Answer:
According to graph, solution is (5, –7)
Answer:
A) (5, –7)
Step-by-step explanation:
I got 100%, please brainlist
Which of the following is a secant on the circle below?
Н
G
13-
125
K
o
A.
B. JK
C. HG
D. K
Answer:
D. KI
Step-by-step explanation:
KI intersects a minimum of two points meaning it is the definition of a secant.
If f(x) = 4^x-8 and g(x) = 5x+6, find (f + g)(x)
A. (F+g)(x) = -4^x - 5x + 2
B.(F+g)(x) = 4^x + 5x - 2
C.(F+g)(x) = 4^x - 3x + 6
D.(F+g)(x) = 9x - 2
Hey there!
We are given two functions - one is Exponential while the another one is Linear.
[tex] \large{ \begin{cases} f(x) = {4}^{x} - 8 \\ g(x) = 5x + 6 \end{cases}}[/tex]
1. Operation of Function
(f+g)(x) is a factored form of f(x)+g(x). We can common factor out x. Therefore:[tex] \large{(f + g)(x) = f(x) + g(x)}[/tex]
2. Substitution
Next, we substitute f(x) = 4^x+8 and g(x) = 5x+6.[tex] \large{(f + g)(x) = ( {4}^{x} - 8) + (5x + 6)}[/tex]
3. Evaluate/Simplify
Cancel out the brackets and combine like terms.[tex] \large{(f + g)(x) = {4}^{x} - 8 + 5x + 6} \\ \large{(f + g)(x) = {4}^{x} + 5x - 8 + 6} \\ \large{(f + g)(x) = {4}^{x} + 5x - 2}[/tex]
4. Final Answer
(f+g)(x) = 4^x+5x-2f(x,y)=x10-3xy2then fz=
A. 10 x9 - 3y2
B. 20 x9 - 3y2
C. 2y2
D. 10x10 + xy2
which option is correct please
Given:
The function is:
[tex]f(x,y)=x^{10}-3xy^2[/tex]
To find:
The value of [tex]f_x[/tex].
Solution:
We need to find the value of [tex]f_x[/tex]. So, we have to find the first order partial derivative of the given function with respect to x.
We have,
[tex]f(x,y)=x^{10}-3xy^2[/tex]
Differentiate partially with respect to x.
[tex]f(x,y)=\dfrac{\partial}{\partial x}x^{10}-3y^2\dfrac{\partial}{\partial x}x[/tex]
[tex]f_x=10x^{10-1}-3y^2(1)[/tex]
[tex]f_x=10x^{9}-3y^2[/tex]
Therefore, the correct option is A.
If you spin two times, what is the probability of landing on
green both times? (leave answer in fraction form in lowest
terms)
Red
Green
Yellow
Red
1/9
1/30
1/6
1/360
At a bake sale, pies cost $8 each. One customer buys $64 worth of pies.
The customer bought 8 pies.
To find the total amount of pies the customer bought, simply divide 64 by 8 to recieve your answer of 8 pies.
I hope this is correct and helps!
Solve: 3x - 1 = 8(x + 1) + 1
O A. x= -
3
5
O B. x= -2
O C. x = -
CT 00
O D. There are infinitely many solutions.
Answer:
x=-2
Step-by-step explanation:
3x-1=8x+8+1
3x-1 = 8x+9
3x-1+1=8x+9+1
3x= 8x+10
3x-8x=8x+10-8x
-5x=10
-5x ÷-5
10 ÷-5
x=-2
y.y3 write without exponts
Answer:
Y x Y x Y x Y
Step-by-step explanation:
The exponent tells how many times that number is multiplied.
So, x^3 is the same as multiplying x 3 times.
the area of triangle
HELP PLEASE!!! So for this problem is got 0.48 however I just wanted to confirm that my answer is correct. Can someone please help me if the answer is wrong and how to solve it. Thank your for your time
Answer:
ur answer is correct
A =xy
A = 1.6×0.3 = 0.48
The Sureset Concrete Company produces concrete. Two ingredients in concrete are sand (costs $6 per ton) and gravel (costs $8 per ton). Sand and gravel together must make up exactly 75% of the weight of the concrete. Also, no more than 40% of the concrete can be sand and at least 30% of the concrete be gravel. Each day 2000 tons of concrete are produced. To minimize costs, how many tons of gravel and sand should be purchased each day
Answer:
The Sureset Concrete Company
The tons of gravel and sand that should be purchased each day are:
Sand = 800 tons
Gravel = 700 tons
Step-by-step explanation:
Two ingredients for producing concrete = sand and gravel
Cost of sand per ton = $6
Cost of gravel per ton = $8
Sand and gravel = 75% of the concrete
Therefore 25% (100 - 75%) will be made up of cement and water
Tons of concrete produced each day = 2,000
Sand and gravel = 1,500 (2,000 * 75%)
Sand <= 40% of 2,000 = 800 tons
Gravel => 30% of 2,000 = 700 (1,500 - 800) tons
To minimize costs, 800 tons of gravel and 700 tons of sand should be purchased each day.
Total cost incurred daily for both sand and gravel = $10,400 (800 * $6 + 700 * $8)
The sum of the first ten terms of an arithmetic progression consisting of
positive integer terms is equal to the sum of the 20th, 21st and 22nd term.
If the first term is less than 20, find how many terms are required to give
a sum of 960.
Answer: [tex]n=13[/tex]
Step-by-step explanation:
Given
Sum of the first 10 terms is equal to sum of 20, 21, and 22 term
[tex]\Rightarrow \dfrac{10}{2}[2a+(10-1)d]=[a+19d]+[a+20d]+[a+21d]\\\\\Rightarrow 5[2a+9d]=3a+60d\\\Rightarrow 10a+45d=3a+60d\\\Rightarrow 7a=15d[/tex]
No of terms to give a sum of 960
[tex]\Rightarrow 960=\dfrac{n}{2}[2a+(n-1)d]\\\\\Rightarrow 1920=n[2a+(n-1)\cdot \dfrac{7}{15}a]\\\\\Rightarrow 28,800=n[30a+7a(n-1)]\\\\\Rightarrow a=\dfrac{28,800}{n[30+7n-7]}\\\\\Rightarrow a=\dfrac{28,800}{n[23+7n]}[/tex]
Value of first term is less than 20
[tex]\therefore \dfrac{28,800}{n[23+7n]}<20\\\\\Rightarrow 28,800<20n[23+7n]\\\Rightarrow 0<460n+140n^2-28,800\\\Rightarrow 140n^2+460n-28,800>0\\\\\Rightarrow n>12.79\\\\\text{For integer value }\\\Rightarrow n=13[/tex]
Answer:
15
Step-by-step explanation:
In the previous answer halfway through they used the equation: 960 = (n÷2)×(2a+(n-1)×(7a÷15))
Using this equation we can substitute an number to replace n, the higher the number is the smaller a would be.
When we substitute 15 into a, then it leaves us with the answer to be a = 15 which is a positive integer and also is smaller than 20, this then let’s us know that 15 is how many terms can be summed up to make 960.
To double check this answer you can find that d = 7 by changing the a into 15 in the formula 7a/15 (found in the previous answer.
Then in the expression: (n÷2)×(2a+(n-1)×d)
substitute:
n = 14 (must be an even number for the equation to work)
a = 15
d = 7
This will give you an answer of 847, but this is only 14 terms as we changed n into 14. To add the final term you need to complete the following equation: 847+(a+(n-1)×d)
substituting:
n = 15
a = 15
d = 7
This will give you the answer of 960, again proving that it takes 15 terms to sum together to make the number 960.
I hope this has helped you.
P.S. Everything in the previous solution was right apart from the start of the last section and the answer
The head of maintenance at XYZ Rent-A-Car believes that the mean number of miles between services is 4959 miles, with a standard deviation of 448 miles. If he is correct, what is the probability that the mean of a sample of 43 cars would differ from the population mean by less than 111 miles
Answer:
0.8948 = 89.48% probability that the mean of a sample of 43 cars would differ from the population mean by less than 111 miles
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
The mean number of miles between services is 4959 miles, with a standard deviation of 448 miles
This means that [tex]\mu = 4959, \sigma = 448[/tex]
Sample of 43:
This means that [tex]n = 43, s = \frac{448}{\sqrt{43}}[/tex]
What is the probability that the mean of a sample of 43 cars would differ from the population mean by less than 111 miles?
p-value of Z when X = 4959 + 111 = 5070 subtracted by the p-value of Z when X = 4959 - 111 = 4848, that is, probability the sample mean is between these two values.
X = 5070
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{5070 - 4959}{\frac{448}{\sqrt{43}}}[/tex]
[tex]Z = 1.62[/tex]
[tex]Z = 1.62[/tex] has a p-value of 0.9474
X = 4848
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{4848 - 4959}{\frac{448}{\sqrt{43}}}[/tex]
[tex]Z = -1.62[/tex]
[tex]Z = -1.62[/tex] has a p-value of 0.0526
0.9474 - 0.0526 = 0.8948
0.8948 = 89.48% probability that the mean of a sample of 43 cars would differ from the population mean by less than 111 miles
One number is 2/3 of another number. The sum of the two numbers is 40. Find
the two numbers.
Answer:
5353454
Step-by-step explanation:
Answer: 16 and 24
Step-by-step explanation:
2x+3x= 40
5x = 40
x=8
that means 2x8 equal 16 and 3x8 equals 24 which leads us to the answer
FastForward has net income of $19,090 and assets at the beginning of the year of $209,000. Its assets at the end of the year total $264,000. Compute its return on assets.
Given:
Net income = $19,090
Assets at the beginning of the year = $209,000.
Assets at the end of the year total = $264,000.
To find:
The return on assets.
Solution:
Formula used:
[tex]\text{Return of assets}=\dfrac{\text{Net income}}{\text{Average of assets at the beginning and at the end}}[/tex]
Using the above formula, we get
[tex]\text{Return of assets}=\dfrac{19090}{\dfrac{20900+264000}{2}}[/tex]
[tex]\text{Return of assets}=\dfrac{19090}{\dfrac{473000}{2}}[/tex]
[tex]\text{Return of assets}=\dfrac{19090}{236500}[/tex]
[tex]\text{Return of assets}\approx 0.0807[/tex]
The percentage form of 0.0807 is 8.07%.
Therefore, the return on assets is 8.07%.
what is the value of digit 6 in9.78265.
Answer: uhh I think 60?
Step-by-step explanation:
the answer is 6p because after any value place is zero hoped I helped
Please help, I’m running out of time. Please.
Answer:
which standard questions is it
When Claire chooses a piece of fruit from a fruit bowl, there is a 22% chance that it will be a plum, an 18%
chance that it will be an orange, and a 60% chance that it will be an apple. Which type of fruit is she least likely
to choose?
Answer:
Orange
Step-by-step explanation:
As the chance of choosing orange is 18% which is the least.
How high up the wall can a 12-foot ladder reach if its base is 4 feet from the wall? Round your answer to the nearest tenth of a foot if necessary.
Answer: 24 ft I think
Step-by-step explanation:
A driver must decide whether to buy a new car for $24,000 or lease the same car over a four-year period. Under the terms of the lease, she can make a down payment
of $3000 and have monthly payments of $150. At the end of the four years, the leased car has a residual value (the amount she pays if she chooses to buy the car at
the end of the lease period) of $11,000. Assume she can sell the new car at the end of the four years at the same residual value. Is it less expensive to buy or
to lease?
Answer:
3000 is the answer this question.
determine lcm and HCF of 24 and 26 using prime factors
Answer:
WHAT IS THE FACTOR?
Step-by-step explanation:
A family has 5 children. Compute the probabilities of the following events:
All five are born on Friday.
Each one is born on a different day of the week.
Answer:
1/16,807 chance that they all will be born on Friday
Probably 5/7, but don't take my word for it.
Step-by-step explanation:
There are 7 days of the week.
There is a 1/7 chance for one kid to be born on a certain day of the week.
We can attach an exponent of 5 since the 1/7 is a constant, and I'm not going to bother typing the same thing over and over again.
(1/7)^5 = 1/16,807.
The probability of all of them being born on Friday or anyday is 1/16,807.
The probability of each person being born on a different day of the week is probabily going to be 5/7, but it could be different, because you need to factor in the requirement that they are not born on the same day.
I can guarantee that the first question is probably correct, but not the second.