If an object producing sound is moving away from us, the wavelength of the sound heard is longer than the actual wavelength. The conclusion is from the concept of Doppler effect.
What is the Doppler effect?The Doppler's effect is a phenomenon when the source of a wave and an observer move relative to each other, the frequency heard is not the same with the actual frequency.
The equation of the Doppler effect is
f₀ = [(v ± v₀)/(v ± vs)] × fs
Where
f₀ = observer frequency of soundv = speed of sound waves (340 m/s)v₀ = observer velocityvs = source velocityfs = actual frequency of sound wavesNote:
v₀ (+) if the observer moves closer to the sound source.vs (+) if the sound source moves away from the observer.When an object producing sound is moving away from us, the frequency of the sound we heard changed.
Let's say we are at rest, it means v₀ = 0. The sound source is moving away makes vs (+).
With the Doppler's effect, we get
f₀ = [(v+0) / (v+vs)] × fs
f₀/fs = v/(v+vs)
v < v+vs
f₀ < fs
The frequency of sound we heard is lower that the actual frequency.
The wavelength is inversely proportional to the frequency. It is described in the equation:
λ = c/f
It means that the lower the frequency, the longer the wavelength.
Hence, the phenomenon which the wavelength of the sound we heard is longer than the actual wavelength when the sound source is moving away from us is called the Doppler's effect.
Here is the group of answer choices:
(a) Band width
(b) Doppler's effect
(c) Sound refraction
(d) Vibrations
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what is the length of the y component shown below?
The length of the y component shown is C. 2.0.
How to find the length ?We are given the angle of the vector, and the length of one of the components of the vetor. Given the angle we have, the available component is the hypotenuse. The y component that we are to find, will then be the opposite or perpendicular component.
To solve for the length of the y - component therefore, the useful operation would be the Sin function.
The length of the y - component would be:
Sin 42 ° = Opposite / Hypotenuse
Sin 42 ° = y component / Hypotenuse
y - component = Sin 42 ° x Hypotenuse
y - component = Sin 42 ° x 3
y - component = 0. 6691 x 3
y - component = 2. 0
In conclusion, the y - component is 2.0.
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Full question is:
What is the length of the y-component of the vector shown below?
A. 2.2 B. 3 c. 2.0 D. 2.7For a particular nonlinear spring, the relationship betweem the magnitude of the applied force F and the resultant displacement x from equilibrium is given by the equation F = k x^2 What is the amount of work done by stretching the spring a distace x0? A) kx0^3 B) (1/2)kx0 C) (1/2)kx0^3 D) (1/3)kx0^2 E) (1/3)kx0^3
To get the work, you have to integrate the force as a function of [tex]$x$[/tex] from zero displacement to Xo
[tex](Integral of) $\mathrm{k} \mathrm{x}^{\wedge} 2 \mathrm{dx}$ from 0 to $\mathrm{Xo}_{\mathrm{o}}=(1 / 3) \mathrm{k}\left(\mathrm{Xo}^{\wedge}\right)^{\wedge} 3$[/tex]
The work done by stretching the spring to the given distance is [tex]W=\frac{k x_0}{3}[/tex]
The given parameters:
- Applied force on the spring [tex]$=F$[/tex]
- Extension of the spring [tex]$=x_0$[/tex]
The work done by stretching the spring to the given distance is calculated as follows;
[tex]W=\frac{k x_0}{3}[/tex]
[tex]$$\begin{aligned}& W=\int_{x_a}^{x_b} F d x \\& W=\int_{x_a}^{x_b} k x^2 d x \\& W=k \int_{x_a}^{x_b} x^2 d x \\& W=k\left[\frac{x^3}{3}\right] \\& W=k\left[\frac{x_b-x_a}{3}\right] \\& W=k\left[\frac{x_0-0}{3}\right] \\& W=\frac{k x_0}{3}\end{aligned}[/tex]
Thus, the work done by stretching the spring to the given distance is
[tex]W=\frac{k x_0}{3}[/tex]
measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement.
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