Answer:
76.50
Step-by-step explanation:
We are given the fact that you bought an object for 90 dollars, and in which you sold said object for a loss of 15%, we are then asked how much would that object be sold for.
To find the answer, we need to subtract the original amount by the percent loss, so :
90 - 15%
15% of 90 is 13.5, therefore :
90 - 13.5
76.5
What is the measure of ∠
A. 60°
B. 6°
C. 42°
D. 49°
if -2 is a zero the polynomial 3x^2+2x+k, find the value of k
Answer:
value of K =16
I hope it's helps you
A boardwalk game of chance costs 2 dollars to play. You have a 20% chance of winning 1 dollar, a 25% chance of winning back your entire 2 dollars, and a 35% chance to win 5 dollars. What is the expected value of playing the game if you lose your bet 20% of the time?
Answer:
For a give event with outcomes:
{x₁, x₂, ..., xₙ}
Each with probabilities:
{p₁, p₂, ..., pₙ}
The expected value is:
Ev = x₁*p₁ + ... + xₙ*pₙ
Here we have the outcomes and probabilities:
win $1, with a probability 20%/100% = 0.2
win $2, with a probability 25%/100% = 0.25
win $5, with a probability of 35%/100% = 0.35
do not win, with a probability of 20%/100% = 0.2
Then the expected value of the game is:
Ev = $1*0.2 + $2*0.25 + $5*0.35 + $0*0.2 = $2.45
And if we know that the game costs $2, then the expected value is:
Ev = $2.45 - $2 = $0.45
The expected value is $0.45
Find the size of the angles marked by letters in the following diagram.
a=132°
b=20°
Answer:
Solution given:
a=132°[exterior angle of a cyclic quadrilateral is equal to the opposite interior angle]
again
In ∆ BCO is similar to ∆ BOE
so
b=20°[corresponding angle of similar triangle are equal]
What is tanA?
Triangle A B C. Angle C is 90 degrees. Hypotenuse A B is 17, adjacent A C is 8, opposite B C is 15.
a.
StartFraction 15 Over 17 EndFraction
c.
StartFraction 8 Over 15 EndFraction
b.
StartFraction 8 Over 17 EndFraction
d.
StartFraction 15 Over 8 EndFraction
Answer:
D. [tex] \frac{15}{8} [/tex]
Step-by-step explanation:
Recall: SOH CAH TOA
Thus,
Tan A = Opposite/Adjacent
Reference angle (θ) = A
Length of side Opposite to <A = 15
Length of Adjacent side = 8
Plug in the known values
[tex] Tan(A) = \frac{15}{8} [/tex]
find the distance between (-1,-5) and (4,3)
Answer:
[tex]\sqrt{89}[/tex] = 9.83
Step-by-step explanation:
[tex]\sqrt{89}[/tex]
[tex]\sqrt{25 + 64} \\\sqrt{5^2 + 8^2}[/tex]
Answer: 89
Step-by-step explanation:
1) 18,27 – 9,756 =
2) 6 – 2,407 =
3) 18 – 5,432 =
4) 10 – 7,602 =
5) 13,013 – 12,5 =
6) 972,5 – 247,451 =
7) 83,12 – 90,2 + 12,3 =
8) 46,75 – 60,13 + 32,50 =
9) 254,0187 – 29,34682 =
10)1.015,568 – 123,712 =
no entiendo me ayudan
Answer:
1) -7929
2) -2401
3)-5414
4) -7592
5) 12888
6)-237726
7) 7287
8)-4588
9)-394495
10) 891856
Help quick!! I'll mark your answer as the brainliest if it's correct! Identify the function shown in this graph.
A. y= -1/5x + 3
B. y= 5x - 3
C. y= -5x + 3
D, y= -5x - 3
Answer:
C
Step-by-step explanation:
We see that the y-intercept is 3. So it is either A of B.
Plug in the point that is on the line (1, -2), we see that the point works for C.
Log5 =0,699 find log 0,5
Answer:
-0.301
Step-by-step explanation:
Correct Question :-
If log 2 = 0.301 , find log 0.5
Solution :-
We are here given that the value of log 5 is 0.699 . Here the base of log is 10 .
[tex]\rm\implies log_{10}2= 0.301 [/tex]
And we are supposed to find out the value of log 0.5 . We can write it as ,
[tex]\rm\implies log_{10}(0.5) = log _{10}\bigg( \dfrac{5}{10}\bigg)[/tex]
Simplify ,
[tex]\rm\implies log _{10}\bigg( \dfrac{1}{2}\bigg)[/tex]
This can be written as ,
[tex]\rm\implies log_{10} ( 2^{-1})[/tex]
Use property of log ,
[tex]\rm\implies -1 \times log_{10}2 [/tex]
Put the value of log 2 ,
[tex]\rm\implies -1 \times 0.301 =\boxed{\blue{-0.301}} [/tex]
Hence the value of log (0.5) is -0.301 .
*Note -
Here here there was no use of log 5 in the calculation .
3. What is the length of MA to the nearest tenth?
a) 0.1 cm
b) 3.5 cm
c) 17.0 cm
d) 7.7 cm
7.7cm
the rest is vastly (a and d) off or just enough off (can't be less then 5.2, because that's already the shortest side), to solve this by looking at it
Graph the first six terms of a sequence where a_1=4 and r=2
Step-by-step explanation: The standard formula for geometric sequence is an = a1 * r^(n-1) where r is the geometric factor and n is an integer. In this problem, upon substitution, an = 4*2^(n-1).
HELPPPPP ME OUUTTTTTTT!!!!
Answer:
20 degrees
Step-by-step explanation:
we can consider 33 to be the radius of a circle.
31 would then be the cos of the angle in that circle.
the regular cos function is defined for the standard circle with radius 1. so, that would be multiplied by 33 for this circle here.
31 = cos(?) × 33
cos(?) = 31/33 = 0.9393...
? = 20.05 ≈ 20 degrees
Please help solve this for me I couldn’t take a picture of the whole thing but I also need to find the domain & range
Answer:
The vertex appears to be (-1,-5) (The lowest point of line)
Axis of symmetry is x = -1 (Notice that the x value of the vertex is same)
y-intercept is (0, -3) (where the line crosses the y-axis)
Find the circumference and area of a circle with a diameter of 12 cm. (Use the approximation of 3.14 for )
In a survey of adults aged 57 through 85 years, it was found that 86.6% of them used at least one prescription medication. Complete parts (a) through (c) below.
a. How many of the 3149 subjects used at least one prescription medication?
(Round to the nearest integer as needed.)
b. Construct a 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication.
(Round to one decimal place as needed.)
Answer:
a) 272 used at least one prescription medication.
b) The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is (85.6%, 87.6%).
Step-by-step explanation:
Question a:
86.6% out of 3149, so:
0.866*3149 = 2727.
272 used at least one prescription medication.
Question b:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
For this problem, we have that:
[tex]n = 3149, \pi = 0.866[/tex]
90% confidence level
So [tex]\alpha = 0.1[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.866 - 1.645\sqrt{\frac{0.866*0.134}{3149}} = 0.856[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.866 + 1.645\sqrt{\frac{0.866*0.134}{3149}} = 0.876[/tex]
For the percentage:
0.856*100% = 85.6%
0.876*100% = 87.6%.
The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is (85.6%, 87.6%).
The number of subjects in the study who used at least one prescription medication is 2727 approx. The needed 90% confidence interval is: [0.8560, 0.8758] or in percentage as: 85.6% to 87.58%
How to construct confidence interval for population proportion based on the sample proportion?Suppose that we have:
n = sample size[tex]\hat{p}[/tex] = sample proportion[tex]\alpha[/tex] = level of significance = 1 - confidence interval = 100 - confidence interval in percentageThen, we get:
[tex]CI = \hat{p} \pm Z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}[/tex]
where [tex]Z_{\alpha/2}[/tex] is the critical value of Z at specified level of significance and is obtainable from its critical value table(available online or in some books)
For this case, we have:
n = 3149confidence interval is of 90%[tex]\alpha[/tex] = level of significance = 100 - 90% = 10% = 0..10[tex]\hat{p}[/tex] = sample proportion = ratio of 86.6% of n to n (at the least)Part (a):
The number of subjects used at least one prescription medication is:
[tex]\dfrac{3149}{100} \times 86.6 \approx 2727[/tex]
Thus, the sample proportion we get is:
[tex]\hat{p} = \dfrac{2727}{3149} \approx 0.8659[/tex]
For level of significance 0.10, we get: [tex]Z_{\alpha/2} = 1.645[/tex]
Thus, the confidence interval needed is:
[tex]CI = \hat{p} \pm Z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\CI \approx 0.8659\pm 1.645 \times \sqrt{\dfrac{0.8659(1-0.8659)}{3149}}\\\\\\CI \approx 0.8659 \pm 0.0099[/tex]
Thus, CI is [0.8659 - 0.0099, 0.8659 + 0.0099] = [0.8560, 0.8758]
Thus, the number of subjects in the study who used at least one prescription medication is 2727 approx. The needed 90% confidence interval is: [0.8560, 0.8758] or in percentage as: 85.6% to 87.58%
Learn more about population proportion here:
https://brainly.com/question/7204089
hi i just need a simple explanation for this question!
Answer:
5/3
Step-by-step explanation:
3^5 = 27 ^x
Rewrite 27 and 3^3
3^5 = 3^3^x
We know that a^b^c = a^(b*c)
3^5 = 3^(3x)
The bases are the same so the exponents are the same
5 = 3x
Divide by 3
5/3 =x
Answer:
x = [tex]\frac{5}{3}[/tex]
Step-by-step explanation:
[tex]3^{5} = 27^{x}[/tex]
These problems are getting you ready to work with exponential functions,
and ultimately with logarithms. The point here is that with variable exponents (notice the exponent is an x (on the right one) and not a number. Variable exponents can not be solved with regular algebra "rules" you need new ones.
The new ones will be Logs....
For now (until you learn logs) , you have to use some "tricks"
the "trick" in this problem is that you have to realize that 27 = [tex]3^{3}[/tex]...
with "common bases" this problem becomes trivial
[tex]3^{5} =(3^{3} ) ^{x}[/tex]
so now the bases are the same and the equals sign suggests that
3x = 5
thus x = [tex]\frac{5}{3}[/tex]
There are 5 more girls than boys in a class. The girls are 60 percent
a. How many pupils are in the class?
Answer:
25.
Step-by-step explanation:
Let the number of pupils be x, then:
there are 0.6x girls and 0.4x boys.
From the given information:
0.6x - 0.4x = 5
0.2x = 5
x = 5/0.2
= 50/2
= 25.
Find the integer solution of the equation
a)5x+25=-3xy+8y^2
b)2y^2+x+y+1=x^2+2y^2+xy
Answer:
the answer is as follows:
Step-by-step explanation:
a)
The equation has the following integer solutions:
5*x+25=-3*xy+8*y^2
Number of solutions found: 3
x1=-31; y1=-10
x2=-7; y2=-2
x3=-5; y3=-0
b)
The equation has the following integer solutions:
2*y^2+x+y+1=x^2+2*y^2+xy
Number of solutions found: 2
x1=0; y1=-1
x2=2; y2=-1
Do not forget to give appriciation.
What’s the answers ?
hope this helps! feel free to clarify if unsure
Find the area of the triangle.
A. 73.6ft^2
B. 65.8 ft^2
C. 69.1 ft^2
D. 70.8 ft^2
The area of the triangle is (A) [tex]73.6ft^{2}[/tex].
What is trigonometry?The study of correlations between triangles' side lengths and angles is known as trigonometry. The field was created in the Hellenistic era in the third century BC as a result of the use of geometry in astronomical research.Trigonometric area of a triangle:Area = [tex]\frac{1}{2}[/tex] × [tex]a[/tex] × [tex]b[/tex] × [tex]sin[/tex] (θ)
Solution -Now, out the values in the formula for the solution.
[tex]A=\frac{1}{2} (16)(10)sin(67^{o} )\\A= 80sin(67^{o} )\\[/tex]
[tex]A=73.6ft^{2}[/tex]
Therefore, the area of the given triangle is (A) [tex]73.6ft^{2}[/tex].
Know more about the area of triangles here:
https://brainly.com/question/17335144
#SPJ2
I need b and c full problems!
Answer:
b: [tex]\frac{5-\sqrt{11} }{2}[/tex]< x < [tex]\frac{5+\sqrt{11} }{2}[/tex]
c: x < -5 , x > 7
Step-by-step explanation:
Suku kedua belas dari barisan bilangan 8, 15, 24, 35, .... adalah ...
HELPPP MEEEE OUTTTTTT ITS URGENTTTTT!!!!
Answer:
(x-12)^2+(y-2)^2=4
Step-by-step explanation:
i am thinking of a number.l take away 5. the result is 14 . what number did i think
Step-by-step explanation:
First sentence
Let the number be X
second sentence
X-5
Third sentence
X-5=14
X=19
The number is 19
Hi there!
»»————- ★ ————-««
I believe your answer is:
19
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
[tex]\text{"I am thinking of a number. l take away 5. The result is 14."}\\\\\text{5 taken away from 'said number' would be 14.}\\\\\boxed{n-5=14}\\\\\\\boxed{\text{Solving for 'n'...}} \\\\\rightarrow n - 5 + 5 = 14 + 5\\\\\rightarrow \boxed{n = 19}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
Evaluate this expression when a=9
Answer:
63
Step-by-step explanation:
a=9
7a
7(9)
63
What the additional information fill in the blanks
Answer:
QXV=WXV
Step-by-step explanation:
giving brainliest
2 variable table
Answer:
41
136
155
193
Step-by-step explanation:
use the equation 19*d+22=h
19 represents the number of hats knitted per day
22 represents the already made hats
Answer:
hhhhhhhhhhhhhhhhhhu
Step-by-step explanation:
Please I need help who want to earn 13 points ..
Answer:
Triangle ISK
Step-by-step explanation:
Answer:
Triangle ISK
Step-by-step explanation:
if the angles and sides of one triangle are equal to the corresponding sides and angles of the other triangle, they are congruent.
∠Q = ∠I
∠R = ∠S
∠S = ∠K
Not really understanding this, thanks for help in advance
Answer:
102
Step-by-step explanation:
Exterior angle is sum of interior angles.
∠1 = 51 + 51
∠1 = 102
Answer: m∠1 = 102°
Step-by-step explanation:
The inside angles of a triangle always add up to 180°
so get the 3rd inside angle with
[tex]180-51-51=78[/tex]
And we know that a straight line in 180° on each side
So we take 180° and subtract 78° to get our answer 102°
a mountain railway AB is of length 864m and rises at an angle of 120° to the horizontal.
A train is 856m above sea level when it is at A.
calculate the height above sea level of the train when it reaches B.
Answer:
The height above sea level at B is approximately 1,604.25 m
Step-by-step explanation:
The given length of the mountain railway, AB = 864 m
The angle at which the railway rises to the horizontal, θ = 120°
The elevation of the train above sea level at A, h₁ = 856 m
The height above sea level of the train when it reaches B, h₂, is found as follows;
Change in height across the railway, Δh = AB × sin(θ)
∴ Δh = 864 m × sin(120°) ≈ 748.25 m
Δh = h₂ - h₁
h₂ = Δh + h₁
∴ h₂ ≈ 856 m + 748.25 m = 1,604.25 m
The height above sea level of the train when it reaches B ≈ 1,604.25 m