If a sample of 12.0 grams of fluorine gas at 45.00C has a pressure of 0.544 atm, what is the volume of the container?

R = 0.0821 L atm/mol K



15.1 L


4.29 L


30.3 L


2.14 L

Answers

Answer 1

Answer: Volume of the container is 30.3 L.

Explanation:

Given: Mass = 12 g

Temperature = [tex]45^{o}C[/tex] = (45 + 273) K = 318 K

Pressure = 0.544 atm

R = gas constant = 0.0821 L atm/mol K

Moles is the mass of substance divided by its molar mass.

Hence, moles of fluorine (molar mass = 18.99 g/mol) are as follows.

[tex]Moles = \frac{mass}{molar mass}\\= \frac{12.0 g}{18.99 g/mol}\\= 0.631 mol[/tex]

Formula used to calculate the volume of container is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant

T = temperature

Substitute the value into above formula as follows.

[tex]PV = nRT\\0.544 atm \times V = 0.631 mol \times 0.0821 L atm/mol K \times 318 K\\V = 30.3 L[/tex]

Thus, we can conclude that volume of the container is 30.3 L.


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Determine a concentração de 50mL de NaOH que consumiu em sua titulação 80mL de HCl de concentração 1,5mol/L

Answers

Answer:

Given the concentration of HCl is 1.5mol/L or 1.5M

The volume of HCl required is --- 80mL

The volume of NaOH is ---- 50mL

What is the concentration of NaOH-- ?

Explanation:

The chemical reaction between NaOH and HCl is shown below:

[tex]NaOH(aq)+HCl(aq)-> NaCl(aq)+H2O(l)\\1mol of NaOH reacts with 1mol. of HCl.\\Number of moles =molarity * volume in L\\At the equivalence point:\\Number of moles of HCl=number of moles of NaOH\\Hence,\\0.08L* 1.5M =0.05L * C \\=>C=\frac{0.08L* 1.5M}{0.05L} \\=>C=2.4M[/tex]

Answer:

The concentration of NaOH required is 2.4M or 2.4mol/L.

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Answers

Answer:

the energy of the products is less than the energy of the reactants.

Explanation:

the the change is enthalpy is negative, and heat is released to the surroundings.

Q1.what is irragation​

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Answer:

Irrigation is the artificial process of applying controlled amounts of water to land to assist in production of crops. Irrigation helps to grow agricultural crops, maintain landscapes, and revegetate disturbed soils in dry areas and during periods of less than average rainfall.

Answer: The watering of crop plants in regular intervals is known as irrigation. ... Weeds are unwanted plants thet grows with the crop plants. Weeding means to remove those plants. It is done manually or by machine. Using khurpi it is done manually and using seed drill it is done by machine.

Explanation:

Irrigation is the artificial application of water to the soil through various systems of tubes, pumps, and sprays. Irrigation is usually used in areas where rainfall is irregular or dry times or drought is expected.

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Answer:

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Which of the following issues surrounding nuclear power creates the biggest
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Answers

Question : Which issue surrounding nuclear power creates the biggest concern?

Answer : How to deal with the radioactive waste (B)

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Answer:

Explanation:

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Answers

Answer:

Red: 17.24%

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Explanation:

25 g of NH, is mixed with 4 moles of O, in the given reaction:
4NH,(g) + 50 (8) 4NO(g) + 6H,O(1)
a Which is the limiting reactant?
b What mass of NO is formed?
c What mass of H2O is formed?

Answers

Answer:

a. NH3 is limiting reactant.

b. 44g of NO

c. 40g of H2O

Explanation:

Based on the reaction:

4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(l)

4 moles of ammonia reacts with 5 moles of oxygen to produces 4 moles of NO and 6 moles of water.

To find limiting reactant we need to find the moles of each reactant and using the balanced equation find which reactant will be ended first. Then, with limiting reactant we can find the moles of each reactant and its mass:

a. Moles NH3 -Molar mass. 17.031g/mol-

25g NH3*(1mol/17.031g) = 1.47moles NH3

Moles O2 = 4 moles

For a complete reaction of 4 moles of O2 are required:

4mol O2 * (4mol NH3 / 5mol O2) = 3.2 moles of NH3.

As there are just 1.47 moles, NH3 is limiting reactant

b. Moles NO:

1.47moles NH3 * (4mol NO/4mol NH3) = 1.47mol NO

Mass NO -Molar mass: 30.01g/mol-

1.47mol NO * (30.01g/mol) = 44g of NO

c. Moles H2O:

1.47moles NH3 * (6mol H2O/4mol NH3) = 2.205mol H2O

Mass H2O -Molar mass: 18.01g/mol-

2.205mol H2O * (18.01g/mol) = 40g of H2O

Answer:

a) NH₃ is the limiting reactant

b) 44.1 g NO

c) 39.7 g H₂O

Explanation:

The chemical equation is the following:

4 NH₃(g) + 5 O₂(g) → 4 NO(g) + 6 H₂O(l)

According to the balanced chemical equation, 4 moles of NH₃ reacts with 5 moles of O₂ to produce 4 moles of NO and 6 moles of H₂O.

a) To determine which is the limiting reactant we have to compare the stoichiometric amounts of reactants (NH₃ and O₂) with the actual amounts.

Stoichiometric amounts:

Molecular weight of NH₃= 14 g/mol + (1 g/mol x 3) = 17 g/mol

Stiochiometric amount of NH₃ = 4 moles NH₃ x 17 g/mol = 68 g NH₃

Stiochiometric amount of O₂ = 5 moles

⇒ Stiochiometric ratio = 68 g NH₃/5 moles O₂

Then, we multiply the stoichiometric ratio by the actual amount of O₂ to calculate the required amount of NH₃:

required NH₃ = 4 moles O₂ x 68 g NH₃/5 moles O₂ = 54.4 g NH₃

Thus, we need 54.4 grams of NH₃ to completely react with 4 moles of O₂, but we only have 25 grams of NH₃. Therefore, NH₃ is the limiting reactant.

b) To calculate the amount of NO formed, we use the limiting reactant (NH₃). According to the equation, 4 moles of NH₃ produce 4 moles of NO.

Molecular weight NO = 14 g/mol + 16 g/mol = 30 g/mol

4 mol NH₃ x 17 g/mol = 68 g NH₃

4 mol NO x 30 g/mol = 120 g NO

⇒ Stiochiometric ratio = 120 g NO/68 g NH₃

Now, we multiply the stoichiometric ratio by the actual amount of NH₃ to calculate the mass of NO formed:

NO formed = 25 g NH₃ x 120 g NO/68 g NH₃ = 44.1 g NO

c) According to the chemical equation, 4 moles of NH₃ (68 g) produce 6 moles of H₂O.

Molecular weight H₂O = (2 x 1 g/mol) + 16 g/mol = 18 g/mol

6 mol H₂O x 18 g/mol = 108 g H₂O

⇒ Stoichiometric ratio = 108 g H₂O/68 g NH₃

Finally, we multiply the stoichiometric ratio by the actual amount of NH₃ (limiting reactant) to obtain the mass of H₂O formed:

H₂O formed = 25 g NH₃ x 108 g H₂O/68 g NH₃ = 39.7 g H₂O

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Answers

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Answers

Answer:

0.702M

Explanation:

Molarity of a solution, which refers to the molar concentration of that solution can be calculated thus;

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Answer:

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Answers

Answer: There are [tex]3.011 \times 10^{23}[/tex] atoms present in 0.500 mol of [tex]CO_{2}[/tex].

Explanation:

According to the mole concept, there are [tex]6.022 \times 10^{23}[/tex] atoms present in 1 mole of a substance.

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Answers

When liquid 5.0 molar NiCl₂ is added to 0.3 M of NiCl₂ solution :  

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Molarity is directly proportional to moles of solute in a solution therefore the molarity of the solution will increase.

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Answer:

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Answer:

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(Look at pic)

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B. Chimpanzees, and humans equally

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(DO NOT ANSWER IF YOU CANNOT ACTUALLY HELP)

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Mark Brainliest please

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The correct pathway for air entering the human respiratory system is _______.
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option 3 is the best


4. If the relative molecular mass of CH20 is 60.
calculate its empirical formula. (C = 12. H = 1
0 = 16)
A 4
В І
C2
D 3​

Answers

Answer:

C2H4O2

Explanation:

because you do mr of CH2O= 12+2+16=30

so 60÷30=2 empirical units

so CH2O × 2=C2H4O2

hope this helps :)

The Empirical formula of the given compound is CH₂O

What is Empirical formula ?

A formula giving the proportions of the elements present in a compound but not the actual numbers or arrangement of atoms.

Empirical formula mass  = 12g/mol + 2 g/mol + 16 g/mol = 30 g/mol

Molecular formula mass / Empirical formula mass = 60 g/mol / 30 g/mol

                                                                                   = 2

Molecular formula = 2 × CH₂O = C₂H₄O₂

Empirical formula = CH₂O

Empirical formula mass  = 12g/mol + 2 g/mol + 16 g/mol = 30 g/mol

Therefore, The Empirical formula of the given compound is CH₂O

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What is the amount of heat, in joules, required to increase the temperature of a 49.5-gram sample of water from 22°C to 66°C?

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Answers

Answer:

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