Answer:
[tex]h_{moon} = 11.8\ m[/tex]
Explanation:
Since the work done is same everywhere in the universe. Hence, the work done in jumping will be same for the person on moon and earth:
[tex]W_{moon} = W_{earth}\\\\P.E_{moon} = P.E_{earth}\\\\mg_{moon}h_{moon} = mg_{earth}h_{earth}\\\\g_{moon}h_{moon} = g_{earth}h_{earth}\\\\(1.66\ m/s^2)h_{moon} = (9.8\ m/s^2)(2\ m)\\\\h_{moon} = \frac{(9.8\ m/s^2)(2\ m)}{1.66\ m/s^2}\\\\h_{moon} = 11.8\ m[/tex]
in the compound CaCO3 at the end of the compound represents the number of
Answer:
Calculate the mass of 6.022 × 1023 molecule of Calcium carbonate (CaCO3).
Solution —
Molar mass (Molecular mass in gram) of CaCO3 = 40+12+3×16 = 100 g
No. of moles of CaCO3
= No. of molecules/Avogadro constant
= 6.022 × 1023/ 6.022 × 1023
= 1 mole
Mass of CaCO3
= No. of moles × molar mass
= 1 × 100 g = 100 g.
A satellite orbits the earth with a kinetic energy of 2.0 x 10^10 J. Its gravitational potential energy
in this orbit is -4.0 x 10^10 J. What is the total energy of the satellite (relative to infinity)?
0 -6.0 x 10^10 J
O 6.0 x 10^10 J
0-2.0 x 10^10 J
O 2.0 x 10^10 J
Answer:
the total energy of the satellite is -2.0 x 10¹⁰ J
Explanation:
Given;
kinetic energy of the satellite, K.E = 2.0 x 10¹⁰ J
gravitational potential energy, P.E = -4 x 10¹⁰ J
The total mechanical energy of the satellite is calculated as follows;
M.E = K.E + P.E
M.E = 2.0 x 10¹⁰ J - 4 x 10¹⁰ J
M.E = -2.0 x 10¹⁰ J
Therefore, the total energy of the satellite is -2.0 x 10¹⁰ J
a. An object takes 5 s to reach the
ground from a height of 5 m on a
planet. What is the value of g on the
planet?
Ans: 0.4 m/s2
Answer:
g = 0.4 m/s²
Explanation:
Given the following data;
Height = 5 meters
Time = 5 seconds
To find the acceleration due to gravity (g) on the planet;
Mathematically, the maximum height of an object is given by the formula;
H = ½gt²
Where;
H is the height measured in meters.
g is the acceleration due to gravity.
t is time measured in seconds.
Substituting into the formula, we have;
5 = ½ * g * 5²
5 = 0.5 * g * 25
5 = 12.5 * g
g = 5/12.5
g = 0.4 m/s²
If a 20kg ball is sitting at rest on the top of a 100m hill, what it the velocity of the ball when it rolls down the hill and is 10m from the bottom? Show, at least, your final calculation.
Answer:
Explanation:
This is the First Law of Thermodynamics that says that energy cannot be created nor destroyed. Which means, to us, that the ball has a specific amount of energy available to it, regardless of where it is in its travels, and this amount of energy will never be increased or decreased, that it will ust change its form. The Total Energy equation for this situation is
TE = PE + KE whih says that the total energy available to the system is equal to its Potential Energy plus its Kinetic Energy, and that Total Energy will never change. First we need to find the TE available. Looking at the first statement, we come into this problem and the ball is sitting still at the top of a hill. If the ball is sitting still, it has no Kinetic Energy, so all the energy is Potential. Therefore,
TE = PE + 0 and what we find here for the TE is the TE available throughout the trip. PE = mgh, so
TE = (20.0)(9.8)(100.0) I added in some sig dig but will still round to 2 because 1 does nothing for us.
TE = 2.0 × 10⁴ J. Now we move on to the next part of the problem, where the ball starts moving. The instant the ball starts moving, the PE starts to convert to KE, but as long as the ball still has the potential to fall to a lesser height, it also still has PE...long story short, it has both PE and KE at this point. And since TE = PE + KE, then
2.0 × 10⁴ = (20.0)(9.8)(10.0) + [tex]\frac{1}{2}(20.0)v^2[/tex] and we solve for v, simplifying some at first.
2.0 × 10⁴ = 2.0 × 10³ + 10.0v² and
[tex]v=\sqrt{\frac{2.0*10^4-2.0*10^3}{10.0} }[/tex] so, to 2 sig fig,
v = 42 m/s
Get to know how to do this; it will save your sanity!!
A 0.1 kg popper is placed on a table. When it pops
up, it reaches a height of 2.0 meters. What was the
initial velocity of the popper off the table?
Answer:
The initial velocity of the pooper off the table is approximately 9.264 m/s
Explanation:
The mass of the popper, m = 0.1 kg
The height the popper reaches, h = 2.0 meters
The initial velocity of the popper, 'u', is given by the following kinematic relation;
v² = u² - 2·g·h
Where;
h = The height the popper reaches = 2.0 m
v = The final velocity of the popper at the height it reached = 0 m/s
u = The initial velocity of the pooper off the table
g = The acceleration du to gravity, g ≈ 9.81 m/s²
Plugging in the values gives;
0² = u² - 2 × 9.81 × 2.0
∴ u - √(2 × 9.81 × 2.0) ≈ 9.264
The initial velocity of the pooper off the table, u ≈ 9.264 m/s.
PLEASE HELP WITH THIS QUESTION
The reason you should always wear your seatbelt in a moving car
A. Newton's 1st law
B. Newton's 2nd law
C. Newton's 3rd law
un movil que parte del reposo alcanza una velocidad de 75 m/s en 13 segundos ¿cual su aceleracion y el espacio que recorrio en los 13 segundos
Answer:
Acceleration = 5.77 m/s²
Distance cover in 13 seconds = 487.56 meter
Explanation:
Given:
Final velocity of mobile device = 75 m/s
initial velocity of mobile device = 0 m/s
Time taken = 13 seconds
Find:
Acceleration
Distance cover in 13 seconds
Computation:
v = u + at
75 = 0 + (a)(13)
13a = 75
a = 5.77
Acceleration = 5.77 m/s²
s = ut + (1/2)(a)(t²)
s = (0)(t) + (1/2)(5.77)(13²)
Distance cover in 13 seconds = 487.56 meter
Si se desea construir un circuito con poca resistencia se debe colocar: En serie Mixto Paralelo Ninguna de las anteriores
Answer:
Parallel combination
Explanation:
When the two resistances are connected in parallel then the equivalent resistance is
[tex]\frac{1}{R}=\frac{1}{R'}+\frac{1}{R''}[/tex]
To get the minimum resistance of a circuit, the circuit components should be connected in parallel combination.
In the parallel combination, the voltage across each resistor is same and the current is divided in every resistance according to the resistances.
Consider the case in which the clay is launched along Path Y. The sphere of clay is launched with an initial velocity of v0 and collides with the rod at a distance of l from the pivot. The length of the rod is L. The rotational inertia of the rod about the joint is IR, and the mass of the clay is mc. The clay is considered a point mass. What is the angular speed f of the clay-rod system immediately after the collision
Answer:
w = [tex]\frac{m}{ml^2 + I R^2 }[/tex] v l
Explanation:
Let's form a system formed by the clay sphere and the rod, in this case the angular momentum is conserved
initial instant. Before the crash
L₀ = m v l
Final moment. After the collision with the clay stuck to the rod
L_f = I_{total} w
angular momentum is conserved
L₀ = L_f
m v l = I_total w
w = [tex]\frac{m}{I_{total} }[/tex] v l
the total moment of inertia is the sum of the moments of inertia of the two bodies
the moment of inertia of the rod is
I_rod = I R²
I_total = m l² + IR²
we substitute
w = [tex]\frac{m}{ml^2 + I R^2 }[/tex] v l
The angular speed f of the clay-rod system immediately after the collision
[tex]w=\dfrac{m}{ml^2+IR^2}VI[/tex]
What is angular speed?Angular speed is defined as the rate of change of angular displacement,Angular Speed (ω) is the scalar measure of rotation rate. In one complete rotation, angular distance travelled is 2π and time is time period (T)
Let's form a system formed by the clay sphere and the rod, in this case the angular momentum is conserved
initial instant. Before the crash
[tex]L_o=mvl[/tex]
Final moment. After the collision with the clay stuck to the rod
[tex]L_o = L_f m v l = I_{total} w[/tex]
[tex]w=\dfrac{m}{I_{total}} Vl[/tex]
the total moment of inertia is the sum of the moments of inertia of the two bodies
the moment of inertia of the rod is
[tex]I_rod = I R^2 I_{total} = m l^2 + IR^2[/tex]
we substitute
[tex]w=\dfrac{m}{ml^2+IR^2}VI[/tex]
Hence the angular speed f of the clay-rod system immediately after the collision
[tex]w=\dfrac{m}{ml^2+IR^2}VI[/tex]
To know more about Angular speed follow
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Cuanto cambia la entropía de 0.50 kg de vapor de mercurio [Lv: 2.7 x 10⁵ j/kg ] al calentarse en su punto de ebullición de 357° C?
Answer:
La entropía del vapor de mercurio cambia en 214.235 joules por Kelvin.
Explanation:
Por definición de entropía ([tex]S[/tex]), medida en joules por Kelvin, tenemos la siguiente expresión:
[tex]dS = \frac{\delta Q}{T}[/tex] (1)
Donde:
[tex]Q[/tex] - Ganancia de calor, en joules.
[tex]T[/tex] - Temperatura del sistema, en Kelvin.
Ampliamos (1) por la definición de calor latente:
[tex]dS = \frac{L_{v}}{T}\cdot dm[/tex] (1b)
Donde:
[tex]m[/tex] - Masa del sistema, en kilogramos.
[tex]L_{v}[/tex] - Calor latente de vaporización, en joules
Puesto que no existe cambio en la temperatura durante el proceso de vaporización, transformamos la expresión diferencial en expresión de diferencia, es decir:
[tex]\Delta S = \frac{\Delta m \cdot L_{v}}{T}[/tex]
Como vemos, el cambio de la entropía asociada al cambio de fase del mercurio es directamente proporcional a la masa del sistema. Si tenemos que [tex]m = 0.50\,kg[/tex],[tex]L_{v} = 2.7\times 10^{5}\,\frac{J}{kg}[/tex] and [tex]T = 630.15\,K[/tex], entonces el cambio de entropía es:
[tex]\Delta S = \frac{(0.50\,kg)\cdot \left(2.7\times 10^{5}\,\frac{J}{kg} \right)}{630.15\,K}[/tex]
[tex]\Delta S = 214.235 \,\frac{J}{K}[/tex]
La entropía del vapor de mercurio cambia en 214.235 joules por Kelvin.
An overworked computer software engineer works on the computer the whole day. He gets very tired after work. Somebody advised him to eat more carbohydrates and fats to get more energy. Do you think this will help him? Why?
Answer:
Following are the solution to the given question:
Explanation:
The answer is "Yes," as it will provide more fuel than a source of vitamins and minerals for him as carbohydrates. Whereas after carbohydrates supply energy, lipids were applied to long-term electricity. Obesity is caused by over intakes of carbohydrates and fats. They must therefore be given in the amount recommended. For its activity, the brain uses glucose. Nevertheless, he does not require sufficient fat since fat is difficult to absorb & fat may make him sound more tired. To recover rapidly, one should consume carbohydrates and meals rich in vitamins. Selection for fat in the form of nuts should be mainly.
12 Write a difference between FPS
and CGS unit system of unit.
Answer:
CGS means Centimeter Gram Second while FPS means Foot Pounds Second
Explanation:
FPS is the standard used to measurement of length, mass and time. The unit of length is foot.
The time is calculated as the unit of seconds. CGS is the measurement of length, mass and time in units of centimeter, gram and second respectively
2. 2. A drawing that shows the outline of an object is called
Which types of forces exist between the two protons in a helium nucleus?
1.
a repulsive electrostatic force and a repulsive gravitational force
2.
a repulsive electrostatic force and an attractive strong nuclear force
3.
an attractive electrostatic force and an attractive gravitational force
4.
an attractive electrostatic force and an attractive strong nuclear force
Answer:
Option (2) is correct.
Explanation:
When two charges have equal charges they repel each other. On the other hand, if they have unequal charges they attract each other.
The force between the two protons in a helium nucleus is electrostatic charges and the force is repulsive in nature.
Also, there exists a strong nuclear force between charges.
So, a repulsive electrostatic force and an attractive strong nuclear force is the correct answer.
is driving with a velocity of 5 m/s and speeds up to a velocity of 10 m/s over 5 seconds. What is Mr. DaCosta's acceleration?
Enunciado del ejercicio n° 1
Se lanza un cuerpo verticalmente hacia abajo con una velocidad inicial de 7 m/s.
a) ¿Cuál será su velocidad luego de haber descendido 3 s?
b) ¿Qué distancia habrá descendido en esos 3 s?
c) ¿Cuál será su velocidad después de haber descendido 14 m?
d) Si el cuerpo se lanzó desde una altura de 200 m, ¿en cuánto tiempo alcanzará el suelo?
e) ¿Con qué velocidad lo hará?
Usar g = 10 m/s²
Desarrollo
Datos:
v0 = 7 m/s
t = 3 s
y = 200 m
h = 14 m
Fórmulas:
(1) vf = v0 + g·t
(2) y = v0·t + ½·g·t²
(3) vf² - v0² = 2·g·h
Enunciado del ejercicio n° 2
Se lanza un cuerpo verticalmente hacia arriba con una velocidad inicial de 100 m/s, luego de 4 s de efectuado el lanzamiento su velocidad es de 60 m/s.
a) ¿Cuál es la altura máxima alcanzada?
b) ¿En qué tiempo recorre el móvil esa distancia?
c) ¿Cuánto tarda en volver al punto de partida desde que se lo lanzo?
d) ¿Cuánto tarda en alcanzar alturas de 300 m y 600 m?
Usar g = 10 m/s²
Desarrollo
Datos:
v0 = 100 m/s
vf = 60 m/s
t = 4 s
y1 = 300 m
y2 = 600 m
Fórmulas:
(1) vf = v0 + g·t
(2) y = v0·t + ½·g·t²
(3) vf² - v0² = 2·g·h
Enunciado del ejercicio n° 3
Un observador situado a 40 m de altura ve pasar un cuerpo hacia arriba con una cierta velocidad y al cabo de 10 s lo ve pasar hacia abajo, con una velocidad igual en módulo pero de distinto sentido.
a) ¿Cuál fue la velocidad inicial del móvil?
b) ¿Cuál fue la altura máxima alcanzada?
Usar g = 10 m/s²
Desarrollo
Datos:
t = 10 s
y = 40 m
Fórmulas:
(1) vf = v0 + g·t
(2) y = y0 + v0·t + ½·g·t²
(3) vf² - v0² = 2·g·h
Enunciado del ejercicio n° 4
Desde un 5° piso de un edificio se arroja una piedra verticalmente hacia arriba con una velocidad de 90 km/h, ¿cuánto tardará en llegar a la altura máxima?
Usar g = 10 m/s²
Desarrollo
Datos:
v0 = 90 km/h
v0 = 25 m/s
Fórmulas:
(1) vf = v0 + g·t
(2) y = v0·t + ½·g·t²
(3) vf² - v0² = 2·g·h
Enunciado del ejercicio n° 5
Un auto choca a 60 km/h contra una pared sólida, ¿desde qué altura habría que dejarlo caer para producir el mismo efecto?
Usar g = 10 m/s²
Desarrollo
Datos:
vf = 60 km/h
vf = 16,67 m/s
v0 = 0 m/s
Fórmulas:
(1) vf = v0 + g·t
(2) y = v0·t + ½·g·t²
(3) vf² - v0² = 2·g·h
Enunciado del ejercicio n° 6
Se lanza una pelota hacia arriba y se recoge a los 2 s, calcular:
a) ¿Con qué velocidad fue lanzada?
b) ¿Qué altura alcanzó?
Usar g = 10 m/s²
Desarrollo
Datos:
t = 2 s
Fórmulas:
(1) vf = v0 + g·t
(2) y = v0·t + ½·g·t²
(3) vf² - v0² = 2·g·h
Enunciado del ejercicio n° 7
Se lanza una pelota de tenis hacia abajo desde una torre con una velocidad de 5 m/s.
a) ¿Qué velocidad tendrá la pelota al cabo de 7 s?
b) ¿Qué espacio habrá recorrido en ese tiempo?
Usar g = 10 m/s²
Desarrollo
Datos:
v0 = 5 m/s
t = 7 s
Fórmulas:
(1) vf = v0 + g·t
(2) y = v0·t + ½·g·t²
(3) vf² - v0² = 2·g·h
Enunciado del ejercicio n° 8
Se lanza un cuerpo verticalmente hacia arriba con una velocidad de 60 km/h, se desea saber la altura máxima alcanzada, la velocidad que posee al cabo de 4 s y 30 s, la altura alcanzada a los 8 s, el tiempo total que se encuentra en el aire.
Desarrollo
Datos:
v0 = 60 km/h = (60 km/h)·(1.000 m/km)·(1 h/3.600 s) = 16,67 m/s
t1 = 4 s
t2 = 30 s
t3 = 8 s
Usar g = 10 m/s²
Fórmulas:
(1) vf = v0 + g·t
(2) y = v0·t + ½·g·t²
(3) vf² - v0² = 2·g·h
Enunciado del ejercicio n° 9
Se dispara verticalmente hacia arriba un objeto desde una altura de 60 m y se observa que emplea 10 s en llegar al suelo. ¿Con que velocidad se lanzo el objeto?
Desarrollo
Datos:
h0 = 60 m
t = 10 s
g = 9,81 m/s²
Fórmulas:
Δy = v0·t + ½·g·t²
Enunciado del ejercicio n° 10
Se lanza verticalmente hacia abajo una piedra de la parte alta de un edificio de 14 pisos, llega al suelo en 1,5 s, tomando en cuenta que cada piso mide 2,6 m de altura. Calcular la velocidad inicial de la piedra y la velocidad al llegar al piso.
Desarrollo
Datos:
Número de pisos = 14
Altura de cada piso = 2,6 m
t = 1,5 s
g = 9,81 m/s²
Fórmulas:
1) Δh = v0·t + ½·g·t²
2) vf = v0 + g·t
*xfv se que es mucho pero e visto videos pero no me sale muy bien los resultados con mis compañeros. xfv alguien que me ayude
Answer:
34
Explanation:
A 5.20-N force is applied to a 1.05-kg object to accelerate it rightwards. The object encounters 3.29-N of friction. Determine the acceleration of the object.
Answer:
Explanation:
We will use the equation F - f = ma, which is just a fancy way of stating Newton's 2nd Law. For us:
F = 5.20 to the right (+)
f = 3.29 to the left (-)
m = 1.05 kg. Therefore,
5.20 - 3.29 = 1.05a and
1.91 = 1.05a so
a = 1.82 m/s/s to the right
How does a country qualify for this sport for the Summer Olympic games?
Answer:
The top-15 world-ranked players will be eligible for the Olympics, with a limit of four players from a given country. Beyond the top 15, players will be eligible based on the world rankings, with a maximum of two eligible players from each country that does not already have two or more players among the top-15.
El peso(w) de una persona en la Tierra es 550N. Determinar la masa (m) de la persona y el peso (w) de la misma en la Luna
The question is: The weight (w) of a person on Earth is 550N. Determine the mass (m) of the person and the weight (w) of the person on the Moon.
Answer: The mass (m) of the person is 550 N and the weight (w) of the person on the Moon is 891 kg.
Explanation:
Given: Mass = 550 N
When a person moves towards moon then its mass will remain the same but there will occur change in its weight because the acceleration due to gravity on moon is different than that on Earth.
Therefore, formula used to calculate the weight of person on moon is as follows.
[tex]W = m \times g_{m}[/tex]
where,
m = mass
[tex]g_{m}[/tex] = acceleration due to gravity on moon = 1.62 [tex]m/s^{2}[/tex]
Substitute the values into above formula as follows.
[tex]W = m \times g_{m}\\= 550 N \times 1.62 m/s^{2}\\ (1 N = 1 kg \times m/s^{2})\\= 891 kg[/tex]
Thus, we can conclude that the mass (m) of the person is 550 N and the weight (w) of the person on the Moon is 891 kg.
What is meant by electric current?
Explanation:
the electric current is ratio of electric poer to the voltage
what is the maximum density of water
Answer:
4ºC or 39.2ºF
Which is a characteristic of atoms?
A) They come in ten major types.
B) They are the smallest units of matter.
C) They can be found in nonliving things only.
D) They cannot combine together.
Answer:
c
Explanation:
c
The electric motor of an elevator(lift) uses 630kJ of electric energy when raising the elevator and passengers, of total mass 12,500N, through a vertical height of 29m.Calculate the efficiency of the elevator. pppppplease need helpp willl markk the brrainliest
Answer:
Efficiency = 0.575 = 57.5%
Explanation:
First, we will calculate the output energy of the elevator, which is equal to the potential energy acquired by the load.
[tex]O = Potential\ Energy\\O = mgh[/tex]
where,
O = Output = ?
mg = W = Weight = 12500 N
h = height = 29 m
Therefore,
[tex]O = (12500\ N)(29\ m) \\O = 362500\ J = 362.5\ KJ[/tex]
The input is given as:
I = 630 KJ
Thus the efficiency will be:
[tex]Efficiency = \frac{O}{I} = \frac{362.5\ KJ}{630\ KJ}\\\\[/tex]
Efficiency = 0.575 = 57.5%
On the graph of voltage versus current, which line represents a 3.0 ohm
resistor?
Will give brainliest
Answer:
D. Graph A
Explanation:
Ohm's law states that V = I*R
So rearrange the equation by dividing the Volts by the amps to give you resistance.
R = 12/4
R = 3 ohm
The line in graph of voltage versus current, which represents a 3.0 ohm
resistor is line A. The correct option is D.
What is current?The current is the stream of charges which flow inside the conductors when connected across the end of voltage.
Given, the graph of voltage versus current is given.
From the graph, I = 4A and V= 12 V
From the Ohm's law, V =IR
Resistance, R = V/I
By substituting the values, we get
R = 12/4
R= 3 ohms
The resistance of the circuit, 3 ohm is represented by the line A on the graph.
Thus, the correct option is D.
Learn more about current.
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What is latent heat?
A.
energy released or absorbed to change the kinetic energy of a substance
B.
energy released or absorbed to change the pressure of a substance
C.
energy released or absorbed to change the temperature of a substance
D.
energy released or absorbed to change the phase of a substance
calculate the charge flow when the vurrent is 0.50A in the wites for 17s
Answer:
Quantity of charge = 8.5 Coulombs
Explanation:
Given the following data;
Current = 0.5 A
Time = 17 seconds
To find the charge flowing through the wire;
Mathematically, the quantity of charge passing through a conductor is given by the formula;
Quantity of charge = current * time
Substituting into the formula, we have;
Quantity of charge = 0.5 * 17
Quantity of charge = 8.5 Coulombs
In which of the following is there more than one path for electrons to flow?
A.An open Circuit
B.A parallel circuit
C.A series circuit
D.A closed circuit
B
because in parallel combination there are more than one paths for the current to flow .
How to solve the equation of power ?
Answer:
OK HERE
Explanation:
When raising a power to a power in an exponential expression, you find the new power by multiplying the two powers together. For example, in the following expression, x to the power of 3 is being raised to the power of 6, and so you would multiply 3 and 6 to find the new power.
assume that you have three electrically charged body 'a' and body 'b' attract body 'c'. what is the sign of the charge of each body?
Answer: Sign of body 'a' is + and body 'b' & 'c' is -
Hope this answer is right!
Explanation:
The same charge repels each other and the opposite charge attracts each other. The force between the same charge is called repulsive charge and that of opposite charge is called attractive charge. The bodies A and B repel each other, so the charge of the body A and body B is of the same nature.
Who was Sir Isaac Newton? Be sure to explain in your own words.
Answer:
the person who invented gravity
Explanation:
newton was a mathmaticians when one day an apple fell on him. he had the idea to name the force gravity. While he "made" gravity he made other important laws the 3 newton laws of physics
Answer:
Issac Newton was around in the 1600s and early 1700s and is a very important mathematician and invented calculus.
Explanation:
