Given:
2.2 pounds = 1 kilogram
Weight of Mary = 120 pounds.
To find:
The weight of Marry in kilograms.
Solution:
We have,
2.2 pounds = 1 kilogram
Using this conversion, we get
1 pound = [tex]\dfrac{1}{2.2}[/tex] kilogram
120 pound = [tex]\dfrac{1}{2.2}\times 120[/tex] kilogram
= [tex]\dfrac{120}{2.2}[/tex] kilogram
[tex]\approx 54.54[/tex] kilogram
Therefore, the weight of Mary is about 54.54 kilograms.
8.52 The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches. Pediatricians regularly measure the heights of toddlers to determine whether there is a problem. There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.
Answer:
Heights of 29.5 and below could be a problem.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.
This means that [tex]\mu = 32, \sigma = 1.5[/tex]
There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.
Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-1.645 = \frac{X - 32}{1.5}[/tex]
[tex]X - 32 = -1.645*1.5[/tex]
[tex]X = 29.5[/tex]
Heights of 29.5 and below could be a problem.
amusement park is 1.50$ for children and $4 for adults. on certain day 220 people entered the park, and the admission fee collected totalled 630.00. how many children and how many adults were admitted? write and use an equation to solve
230.000 childrenㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ
ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ
ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ
ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ
ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ
ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ
ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ
ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ
ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ
Answer:
230 children
Step-by-step explanation:
15÷7500
what is the answer
Answer:
Answer is 0.002
Step-by-step explanation:
15÷7500 = 0.002
Answer:
ampota ma,pakyu
Step-by-step explanation:
what is the answer dapalon taka karun
3a
[tex] \frac{3a + a {}^{2} }{a} [/tex]
Simplify.
Answer:
(3+a)
Step-by-step explanation:
3a + a^2
-------------
a
Factor out an a in the numerator
a(3+a)
-------------
a
Cancel like terms
(3+a)
Step-by-step explanation:
[tex] \frac{3a + {a}^{2} }{a} \\ = \frac{3a}{a} + \frac{ {a}^{2} }{a} \\ = 3 + a \\ thank \: you[/tex]
If the lengths of the legs of a right triangle are 4 and 8, what is the length of the hypotenuse?
PLEASE HELP
Answer:
[tex]4\sqrt{5}[/tex]
Step-by-step explanation:
In order to solve this problem, we can use the pythagorean theorem, which is
a^2 + b^2 = c^2, where and b are the legs of a right triangle and c is the hypotenuse. Since we are given the leg lengths, we can substitute them in. So, where a is we can put in a 4 and where b is we can put in an 8:
a^2 + b^2 = c^2
(4)^2 + (8)^2 = c^2
Now, we can simplify and solve for c:
16 + 64 = c^2
80 = c^2
c = [tex]\sqrt{80}[/tex]
Our answer is not in simplified radical form because the number under is divisible by a perfect square, 16. We can divide the inside, 80, by 16, and add a 4 on the outside, as it is the square root of 16:
c = [tex]4\sqrt{5}[/tex]
The length of the hypotenuse in the given right triangle, with legs measuring 4 and 8, is approximately 8.94.
To find the length of the hypotenuse in a right triangle, we can use the Pythagorean theorem. According to the theorem, in a right triangle, the square of the hypotenuse's length is equal to the sum of the squares of the lengths of the other two sides.
In this case, let's label the lengths of the legs as 'a' and 'b', with 'a' being 4 and 'b' being 8. The hypotenuse, which we need to find, can be represented as 'c'.
Applying the Pythagorean theorem, we have:
[tex]a^2 + b^2 = c^2[/tex]
Substituting the given values:
[tex]4^2 + 8^2 = c^2[/tex]
16 + 64 = [tex]c^2[/tex]
80 = [tex]c^2[/tex]
To find the length of the hypotenuse 'c', we need to take the square root of both sides:
√80 = √ [tex]c^2[/tex]
√80 = c
The square root of 80 is approximately 8.94.
Therefore, the length of the hypotenuse in the given right triangle, with legs measuring 4 and 8, is approximately 8.94.
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What is x² − 4x + 7 factored?
Answer:
The expression is not factorable with rational numbers.
x² − 4x + 7
Which relation is not a function?
Answer:
A
For something to be a function every x value bust have at most 1 y value and in A 9 has 2 y values so it cant be a function
2/5 divided by 8/5 .......
Answer:
1/4
Step-by-step explanation:
2/5 divided by 8/5 is the same as 2/5 * 5/8. we cross out the same 5's to get 2/8. We simplify that to 1/4.
1/4 is our answer.
(x^2+1)(x-1)=0 help me pls
Answer:
x = ±i , x=1
Step-by-step explanation:
(x^2+1)(x-1)=0
Using the zero product property
x^2 +1 = 0 x-1= 0
x^2 = -1 x=1
Taking the square root of the equation on the left
sqrt(x^2) = sqrt(-1)
x = ±i where i is the imaginary number
We still have x=1 from the equation on the right
Question 1 of 10
What was part of President Johnson's plan for Reconstruction?
O A. Land for freedmen
B. Pardons for Confederate leaders
C. Pardons for carpetbaggers
D. Voting rights for freedmen
Joelvin
Answer:
B
Step-by-step explanation:
Pardons for Confederate leaders
A coin contains 9 grams of nickel and 161616 grams of copper, for a total weight of 25 grams.
What percentage of the metal in the coin is copper?
Answer:
64percents
Step-by-step explanation:
25-9=16 grams - weight of copper
(16/25)*100=64 percents
Find the length of the third side .
Answer:
a^2 + b^2 = c^2
4+16 = c^2
20 = c^2
c = [tex]\sqrt{20}[/tex] = [tex]2\sqrt{5}[/tex]
Step-by-step explanation:
Which of the following are the correct steps to solve the equation below?
5x + 9 = 39
A----Add 9 first and then divide by 5
B----Add 9 first and then multiply by 5
C-----Subtract 9 first and then divide by 5
D----Subtract 9 first and then multiply by 5
please help have a lot of lessons
Darryl has written 60 percent, or 12 pages, of his history report. Darryl wants to figure out how many total pages he needs to write. Darryl’s work is shown below.
Step 1: Write 60 percent as a ratio. StartFraction part Over whole EndFraction = StartFraction 60 Over 100 EndFraction
Answer:
total pages = 20
Step-by-step explanation:
60% of an unknown number is 12
Let the unknown number (total pages) be x.
60/100 of x = 12
60/100 * x = 12
3/5 x = 12
x = 12 * 5/3
x = 20
In April, the number of cars sold was 546.
This was an increase of 5% on the number of cars sold in March.
Calculate the number of cars sold in March.
Answer:
520 cars
Step-by-step explanation:
Let the car sold in March be x, x+5%*x=546. (105/100)*x=546. x=520
If there was an increase of 5% on the number of cars sold in March, the number of cars sold in March was approximately 520.
To calculate the number of cars sold in March, we'll use the information that the number of cars sold in April was an increase of 5% compared to March.
Let's assume the number of cars sold in March is represented by 'x'.
According to the given information, the number of cars sold in April was 546, which is equal to 100% + 5% of the number of cars sold in March.
We can set up the equation:
x + 0.05x = 546
Combining like terms, we get:
1.05x = 546
To solve for 'x', we divide both sides of the equation by 1.05:
x = 546 / 1.05
Using a calculator, we find:
x ≈ 520.00
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PLEASE help me!!!
Amina has two bags.
In the first bag there are 3 red balls and 7 green balls.
In the second bag there are 5 red balls and 4
green balls.
Amina takes at random a ball from the first bag.
She then takes at random a ball from the second bag.
(a) Complete the probability tree diagram.
Answer:
Step-by-step explanation:
first
3/10 & 7/10
second
5/9 & 4/9
Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling. Abha collected 178 more cans than Shane did.
Write an inequality to determine the number of cans, S, that Shane could have collected.
What is the solution set of the inequality?
Answer:
Shane=x
Abha=y
x+y>=2000
x-y=178 Which leads to x=178+y ..... #1
hence by substitution in the inequality
178+2y>=2000
2y>=2000-178
2y>=1822
y>=911 ......in #1
x>=178+911
x>=1089
Solutions x>=1089 & y>=911
Given the preimage and image, find the dilation scale factor
Answer:
1/2
Step-by-step explanation:
the dilation factor should be 1/2
if u count the dots on the sides of the preimage there are 2 dots that's the length if u count the dots on the real image it's 4therefore 2/4 to it's lowest term is 1/2 so 1/2 is the scale factorAnswer:
should be 1/2 as your answer
if n(u) = 800. n(a) = 400. n(b) = 300 n(āūb) = 200 what is n(anb) and n(a)
Two motor mechanics, Ravi and Raman, working together can overhaul a scooter in 6 hrs. Ravi alone can do the job in 12 hrs. In how many hrs.can Raman alone do it?
Answer:
12 hours
Step-by-step explanation:
For Ravi,
12 hours = 1 job
Given this, we can figure out how much Ravi does in 6 hours, and from that, we can figure out how much Raman can do in 6 hours. Finally, we can use that to figure out how many hours it would take for Raman to do the job.
12 hours = 1 job
First, to find how much Ravi does in 6 hours, we need to make the equation
6 hours = something
To do this, we know that 12/2 = 6, so we can divide both sides by 2 in the original equation to get
6 hours = 1/2 job.
Therefore, in 6 hours, Ravi does 1/2 of the job. As Raman and Ravi do the job in 6 hours, Raman must do the remaining work, or 1-1/2 = 1/2 of the job in 6 hours.
Therefore, for Raman,
6 hours = 1/2 job
We need to make the equation so that
1 job = something, as that something would be how many hours it would take for Raman to do the job. We know that 1/2 * 2 = 1, so we can multiply both sides by 2 to get
12 hours = 1 job for Raman.
Please help explanation if possible
Answer:
[tex]y = 2x + 7[/tex]
Step-by-step explanation:
Use Point Slope Form since we are given the slope and coordinates. Why is the slope 2x?
In Depth: Parallel lines never touch so they are Lines that have same slope but different y intercept. An example is a square. A square has four parallel sides. The upper and lower sides will never touch because they are the same slope and they both have a finite distance vertically between them.
Back to the question, let use the Point Slope Form,
[tex]y - y_{1} = m(x - x_{1})[/tex]
Where y1 is the y coordinate of the given point, m is the slope and x is the x coordinates of the given points.
Substitute
[tex]y - ( - 1) = 2(x - ( - 4)[/tex]
[tex]y + 1 = 2(x + 4)[/tex]
Simplify
[tex]y + 1 = 2x + 8[/tex]
[tex]y = 2x + 7[/tex]
find the measure of one exterior angle for the following regular polygon
Answer:
36 degrees
Step-by-step explanation:
10 corners/sides.
the sum of all exterior angles in a polygon is always 360 degrees.
so, one exterior angle here is 360/10 = 36 degrees
As above, let
$$f(x) = 3\cdot\frac{x^4+x^3+x^2+1}{x^2+x-2}.$$Give a polynomial $g(x)$ so that $f(x) + g(x)$ has a horizontal asymptote of $y=0$ as $x$ approaches positive infinity.
Answer:
Hello,
Step-by-step explanation:
[tex]\dfrac{f(x)}{3} =\dfrac{x^4+x^3+x^2+1}{(x-1)(x+2)} \\\\=\dfrac{(x^2+3)(x-1)(x+2)-3x+7}{(x-1)(x+2)} \\=x^2+3-\dfrac{3x-7}{(x-1)(x+2)} \\\\=x^2+3-\dfrac{3}{x-1} +\dfrac{1}{(x-1)(x-2)} \\\\\dfrac{f(x)}{3}-\dfrac{3x^2+9}{3} =-\dfrac{3}{x-1} +\dfrac{1}{(x-1)(x-2)} \\\\\\ \lim_{x \to +\infty} (\dfrac{f(x)}{3}-\dfrac{3x^2+9}{3} )\\\\=0+0=0\\\\\\P(x)=-x^2-3[/tex]
Answer:
[tex]g(x)=-3x^2-9[/tex]
Explanation:
[tex]3\frac{x^4+x^3+x^2+1}{x^2+x-2}[/tex]
+[tex]\frac{p(x)(x^2+x-2)}{x^2+x-2}[/tex]
We need p(x) need to be a degree 2 polynomial so the numerator of the second fraction is degree 4. Our goal is to cancel the terms of the first fraction's numerator that are of degree 2 or higher.
So let p(x)=ax^2+bx+c.
[tex]3\frac{x^4+x^3+x^2+1}{x^2+x-2}[/tex]
+[tex]\frac{p(x)(x^2+x-2)}{x^2+x-2}[/tex]
Plug in our p:
[tex]3\frac{x^4+x^3+x^2+1}{x^2+x-2}[/tex]
+[tex]\frac{(ax^2+bx+c)(x^2+x-2)}{x^2+x-2}[/tex]
Take a break to multiply the factors of our second fraction's numerator.
Multiply:
[tex](ax^2+bx+c)(x^2+x-2)[/tex]
=[tex]ax^4+ax^3-2ax^2[/tex]
+[tex]bx^3+bx^2-2bx[/tex]
+[tex]cx^2+cx-2c[/tex]
=[tex]ax^4+(a+b)x^3+(-2a+b+c)x^2+(-2b+c)-2c[/tex]
Let's go back to the problem:
[tex]3\frac{x^4+x^3+x^2+1}{x^2+x-2}[/tex]
+[tex]\frac{ax^4+(a+b)x^3+(-2a+b+c)x^2+(-2b+c)x-2c}{x^2+x-2}[/tex]
Let's distribute that 3:
[tex]\frac{3x^4+3x^3+2x^2+3}{x^2+x-2}[/tex]
+[tex]\frac{ax^4+(a+b)x^3+(-2a+b+c)x^2+(-2b+c)x-2c}{x^2+x-2}[/tex
So this forces [tex]a=-3[/tex].
Next we have [tex]a+b=-3[/tex]. Based on previous statement this forces [tex]b=0[/tex].
Next we have [tex]-2a+b+c=-3[/tex]. With [tex]b=0[/tex] and [tex]a=-3[/tex], this gives [tex]6+0+c=-3[/tex].
So [tex]c=-9[tex].
Next we have the x term which we don't care about zeroing out, but we have [tex]-2b+c[/tex] which equals [tex]-2(0)+-9=-9[/tex].
Lastly, [tex]-2c=-2(-9)=18[/tex].
This makes [tex]p(x)=-3x^2-9[/tex].
This implies [tex]g(x)\frac{(-3x^2-9)(x^2+x-2)}{x^2+x-2}[/tex] or simplified [tex]g(x)=-3x^2-9[/tex]
which expression is equivalent to (4^-3)^-6
a.) 4^3
b.) 4^-9
c.) 4^-18
d.) 4^18
Answer:
Answer:
The answer is d.) 4^18
PLS HELP WILL MAKE FIRST RIGHT ANSWER GETS BRAINLIEST
What is the solution to the linear equation?
2/7+x=6/7+3/7x
Group of answer choices
1
7
1/2
4
Answer:
The answer to your question is 1, or answer choice A.
Step-by-step explanation:
x+ 2 /7 = 3 /7 x+ 6 /7
x+ 2 /7 − 3 /7 x= 3 /7 x+ 6 /7 − 3 /7 x
4 /7 x+ 2 /7 = 6 /7
4 /7 x+ 2 /7 − 2 /7 = 6 /7 − 2 /7
4 /7 x= 4 /7
( 7 /4)*( 4 /7 x)=( 7 /4 )*( 4 /7 )
x=1
The length of a rectangle is 9 inches more than half the width. Find the length if the perimeter is 60 inches.
Answer:
Length = 10.435 inches
Step-by-step explanation:
Let the length be l
Let the width be w
Since the length is 9 inches more than half the width.
Then;
L = 0.5w + 9
Perimeter of a rectangle is;
P = 2Lw
Thus;
P = 2w(0.5w + 9)
Since perimeter = 60
Then;
2w(0.5w + 9) = 60
w² + 18w = 60
w² + 18w - 60 = 0
From quadratic formula;
w ≈ 2.87 in
L = 0.5(2.87) + 9
L = 10.435 in
write down amultiple of 4 and 14 which is less than 30
28
How?
Multiples of 4=8,12,16,20,24,28Multiples of 14=28,42We can see that 28 is the lowest common multiple also it is <30
Answer: 28.
Step-by-step explanation: 28 is divisible by 4: 28 / 4 = 7. 28 is divisible by 14: 28 / 14 = 2. And 28 is less than 30
please help:
give an example of an undefined term and how it relates to a circle.
