I NEEEDDDD HELPPP ASAPPPP!!! it’s urgentttttt

Answer:

c  a = 2.4b

Step-by-step explanation:

y = kx is the form of the equation where k is the constant of proportionality

y and x can be any letters

Replacing y and x with a and b  and k with 2.4

a = 2.4b

Answer:

6 yards 4 feet 1 inch

Step-by-step explanation:

First, we have the equation:

4 yards 2 feet 7 inches + 2 yards 1 foot 6 inches

Now, let's add each:

6 yards

3 feet

13 inches

But 13 inches would be 1 foot and 1 inch, so now we have plus 1 foot and replace the inches with just 1 inch:

6 yards

4 feet

1 inch

There you have it!

Happy learning!

--Applepi101

Answer:

7 yds  1 ft 1 inch

Step-by-step explanation:

 4 yards 2 feet 7 inches

+ 2 yards 1 foot 6 inches

------------------------------------------

 6 yards  3 feet  13 inches

13 inches is more than 12 inches (  =1  ft) so subtract 12 inches and add 1 ft

6 yards  3 feet  13 inches

             =1 ft      - 12 inches

-----------------------------------------

6 yds   4 ft    1 inches

4 ft is more than  3f which is 1 yd  ( subtract 3 ft and add 1 yd)

6 yds   4 ft    1 inches

+1 yd  - 3ft

------------------------

7 yds  1 ft 1 inch

( yx + 4x - 5 )( y + 1 )

.....................................

Answer:

I am not sure on the answer but i think its $9,000

Step-by-step explanation:

11,000x0.20=2,200

2,200+11,000=13,200

22,200-13,200=9,000

which would mean she got $9,000 from commissions.

if you did 100,000x0.03=3,000

9,000/3,000= 3

so she would have had 3 commissions worth over 100,000

Answer:

Solution given:

Sin[tex]\theta_{1}=\frac{-24}{25}[/tex]

[tex]\frac{opposite}{hypotenuse}=\frac{-24}{25}[/tex]

equating corresponding value

opposite=-24

hypoyenuse=25

adjacent=x

By using Pythagoras law

hypotenuse²=opposite²+adjacent²

25²=(-24)²+x²

625=576+x²

x²=625-576

x=49

x=[tex]\sqrt{49}=7[/tex]

In IV quadrant

Cos angle is positive

Cos[tex]\theta_{1}=\frac{adjacent}{hypotenuse}[/tex]

Answer:

cos theta = 7/25

Step-by-step explanation:

sin theta = opp / hyp

We can find the adj side by using the pythagorean theorem

adj ^2 + opp ^2 = hyp^2

adj^2 + (-24)^2 = 25^2

adj^2 +576 = 625

adj^2 =625 -576

adj^2 = 49

Taking the square root of each side

adj = 7

Since we are in the 4th quadrant, adj is positive

cos theta = adj / hyp

cos theta = 7/25

The solution to the continuous linear relation is: (2,-7)

The data on the table can be presented as:

Relation A

[tex](x_1,y_1) = (-8,-5)[/tex]

[tex](x_2,y_2) = (-3,-6)[/tex]

Relation B

[tex](x_1,y_1) = (-8,-15)[/tex]

[tex](x_2,y_2) = (-3,-11)[/tex]

Plot the points of each relation and draw a line through the points (see attachment)

Write out the point of intersection of the two lines.

[tex](x,y) = (2,-7)[/tex]

Hence, the solution to the continuous linear relation is: (2,-7)

Read more at:

https://brainly.com/question/20291958

Answer:

false =D

Step-by-step explanation:

Answer:

[tex]\text{C. }21.39\:\mathrm{units^2}[/tex]

Step-by-step explanation:

The area of a triangle with sides [tex]a[/tex] and [tex]b[/tex] and angle [tex]\gamma[/tex] between them is given by [tex]A=\frac{1}{2}ab\sin \gamma[/tex].

Therefore, in the given triangle, we want to find two sides with the angle between them given. In this case, the angle between the two sides 7.39 and 9.75 is marked as [tex]36.43^{\circ}[/tex]. Assign values:

Substituting these values into our area formula, we get:

[tex]A=\frac{1}{2}\cdot 7.39\cdot 9.75\cdot \sin (36.43)^{\circ},\\A=21.3938371858,\\A\approx \boxed{21.39\:\mathrm{units^2}}[/tex]

Answer:

(x-3)(5x+4)

x=3 x=-4/5

Answer:

(5x + 4)(x - 3)

Step-by-step explanation:

Hello!

Factor:

Think: What two numbers add up to -11 but multiply to (5)(-12)?

Answer: -15 and 4

Continue:

The factored expression is (5x + 4)(x - 3)

Answer:

72

Step-by-step explanation:

The interior angles of a 6 sided figure add to (n-2) * 180

where n is the number of sides

(6-2) *180

4*180

720

2x+4x+4x+4x+4x+2x = 720

20x = 720

Divide by 20

20x/20 = 720/20

x =36

We want <F

<F = 2x = 2*36 = 72

Answer:

i dont know

but try you will get the answer

Answer:

129

Step-by-step explanation:

2*2+x(100-15x)

2*2+5(100-15*5)

2*2+5(100-75)

2*2+5*25

4+125

129ans

Answer: y= 3+x

Step-by-step explanation:

Answer: y = x - 3

First, find two points on the graph:

Substitute in the points to the slope formula [tex]\frac{y_2-y_1}{x_2-x_1}[/tex] to find the slope:

[tex]\frac{y_2-y_1}{x_2-x_1}=\frac{-3-0}{0-3}=\frac{-3}{-3}=1[/tex]

Substitute in a point to the function [tex]y=1x+b[/tex] to find the y-intercept(b):

[tex]-3=1(0)+b\\b=-3[/tex]

Therefore, the function is:

[tex]y=x-3[/tex]

9514 1404 393

Answer:

  b, c

Step-by-step explanation:

The factor (x+7) is common to both numerator and denominator. The function can be simplified by cancelling that factor.

  y = (x -3)/(x -9) . . . . . . x ≠ -7

The restriction x ≠ -7 is put on the simplified function because the original function is undefined there. The denominator factor x+7 makes the denominator 0 at that point.

The point at x=-7 is called "hole" in the graph. A properly drawn graph will show the function is undefined there (has a hole).

__

The denominator of the simplified function is zero when x=9. This means there is a vertical asymptote at x=9.

__

The ratio of the highest-degree terms of the numerator and denominator will tell you the end behavior of the function — its value when x is large. Here, that ratio is y = x/x = 1. This represents a horizontal asymptote at y=1. The function approaches this line as x gets large, but never reaches it.

The appropriate descriptors are ...

Answer:

105897 ft²

Step-by-step explanation:

let, r be the radius, so r = 106 ft

Surface area of a hemisphere,

2πr²+πr²

= 2π×106²+π×106²

= 105897 (rounded to the nearest whole number)

Compute the quotient and remainder,

[tex]\dfrac{2x^4+x^3-14x^2+5x+6}{x^2+2x+k} \\\\ = 2x^2 - 3x - (8+2k) + \dfrac{(21+7k)x+(6+8k+2k^2)}{x^2+2x+k}[/tex]

The remainder upon dividing [tex]2x^4+x^3-14x^2+5x+6[/tex] by [tex]x^2+2x+k[/tex] should leave no remainder, which means

[tex]21+7k = 0 \implies 21 = -7k \implies k=-3[/tex]

and

[tex]6+8k+2k^2 = 0 \implies 2(k+3)(k+1)=0 \implies k=-3\text{ or }k=-1[/tex]

Only k = -3 makes both remainder terms vanish.

Then the previous result reduces to

[tex]\dfrac{2x^4+x^3-14x^2+5x+6}{x^2+2x-3} = 2x^2 - 3x - 2[/tex]

so that

[tex]2x^4+x^3-14x^2+5x+6 = (x^2+2x-3) (2x^2 - 3x - 2) \\\\ 2x^4+x^3-14x^2+5x+6 = (x+3)(x-1)(2x + 1)(x-2)[/tex]

and so the zeroes of the quartic polynomial are x = -3, x = 1, x = -1/2, and x = 2.

Answer:

(x + y - 2xy)*(x + y + 2xy)

Step-by-step explanation:

x^2-4x^2y^2+y^2+2*x*y

=x^2 + 2xy + y^2 - (2xy)^2

=(x + y)^2 - (2xy)^2

=(x + y - 2xy)*(x + y + 2xy)

Answer:

A, B, C

Step-by-step explanation:

none of the 4 options changes the shape.

but D changes the size.

C is the only one that also maintains the orientation of the triangle - it only shifts its position.

A and B maintain size and shape, but they do change its orientation.

Answer:

Final answer is  ---> -4

Step-by-step explanation:

Answer:

[tex] = { \tt{(0, \: 0)}}[/tex]

Step-by-step explanation:

Let:

[tex]{ \bf{ - x - 2y = 0 - - - (a)}} \\ { \bf{y = - 8x - - - (b)}}[/tex]

Substitute for y in equation (b) to equation (a):

[tex]{ \tt{ - x - 2( - 8x) = 0}} \\ { \tt{ - x + 16x = 0 }} \\ { \tt{x = 0}}[/tex]

Also, y = 0

Step-by-step explanation:

y+80+70=180

y+150=180

y=30

Now you can, easily find x

Answer:

6

Step-by-step explanation:

A=5-x^2+2x

Rewriting

A = -x^2 +2x+5

This is a downward opening parabola so the maximum value is at the vertex

Factor out the negative sign out of the first two terms

A = -(x^2 -2x)  +5

Complete the square

-2/2 = -1   -1^2 = 1

Add 1 inside the parentheses  Remember the negative sign out front so -1(1) is really adding -1  so we need to add 1 outside of the parentheses

A = -(x^2-2x+1) +1  +5

A = -(x-1)^2 +6

This is in vertex form

y = a(x-h)^2 +k  where (h,k) is the vertex

The maximum occurs at x=h and the value is k

The maximum is 6

set x=0 to get insights.

at x=0 to the functions are

-2(0-2)²+3 = -5

-2(0+2)²-3 = -11

-2(0-2)²+3 = -5

-2(0-2)²-3 = -11

weird, for some reason option 1 and 3 seem to be the same, maybe that's an accident by the author.

maybe a + was intended inside the parentheses, dunno.

option 1 and 3 seem fine, although I think there is an error in the options. they shouldn't be exactly the same

Answer:

1320 yds

Step-by-step explanation:

1 mile = 1760 yds

3/4 mile * 1760 yds/ 1 mile

1320 yds

Answer:

1 mile = 1720 yard

______ ________

0.75 x

cross multiply and solve for x

1320 yards is the answer

good luck in the future..

Answer:

80°

Step-by-step explanation:

m<COB = 80°, it's the central angle for arc CB,

so mCB = 80°

Answer:

8r+8pg-pq

Step-by-step explanation:

The subtractable pg cancels out one of the 9 pg's. So 9 pg-1 pg= 8 pg

Hope this helps!

Answer:

[tex]n=35[/tex]

Step-by-step explanation:

From the question we are told that:

Standard Deviation [tex]\sigma=4min[/tex]

Let

[tex]CI=95\%[/tex]

Since

Significance level [tex]\alpha[/tex]

[tex]\alpha =1-CI[/tex]

[tex]\alpha =1-0.95[/tex]

Therefore

[tex]Z_{\alpha/2}=Z_{0.025[/tex]

[tex]Z_{\alpha/2}}=1.96[/tex]

Generally the equation for Sample size is mathematically given by

[tex]n = (Z_{\alpha/2}* \frac{\sigma}{E})^2[/tex]

[tex]n= \frac{1.96 * 3}{1}^2[/tex]

[tex]n=35[/tex]

use the formula a^3+b^3=(a+b)^3-3ab(a+b)

in above question assume (a+b) as a and 1 as b

take help of file above

It looks like you have to find the value of the sum,

[tex]C = \displaystyle \frac1{21\times22\times23} + \frac1{22\times23\times24} + \cdots + \frac1{200\times201\times202}[/tex]

so that the n-th term in the sum is

[tex]\dfrac1{(21+(n-1))\times(21+n)\times(21+(n+1))} = \dfrac1{(n+20)(n+21)(n+22)}[/tex]

for 1 ≤ n ≤ 180.

We can then write the sum as

[tex]\displaystyle C = \sum_{n=1}^{180} \frac1{(n+20)(n+21)(n+22)}[/tex]

Break up the summand into partial fractions:

[tex]\dfrac1{(n+20)(n+21)(n+22)} = \dfrac a{n+20} + \dfrac b{n+21} + \dfrac c{n+22}[/tex]

Combine the fractions into one with a common denominator and set the numerators equal to one another:

[tex]1 = a(n+21)(n+22) + b(n+20)(n+22) + c(n+20)(n+21)[/tex]

Expand the right side and collect terms with the same power of n :

[tex]1 = a(n^2+43n+462)+b(n^2+42n+440) + c(n^2+41n + 420) \\\\ 1 = (a+b+c)n^2 + (43a+42b+41c)n + 462a+440b+420c[/tex]

Then

a + b + c = 0

43a + 42b + 41c = 0

462a + 440b + 420c = 1

==>   a = 1/2, b = -1, c = 1/2

Now our sum is

[tex]\displaystyle C = \sum_{n=1}^{180} \left(\frac1{2(n+20)}-\frac1{n+21}+\frac1{2(n+22)}\right)[/tex]

which is a telescoping sum. If we write out the first and last few terms, we have

C = 1/(2×21) - 1/22 + 1/(2×23)

… … + 1/(2×22) - 1/23 + 1/(2×24)

… … + 1/(2×23) - 1/24 + 1/(2×25)

… … + 1/(2×24) - 1/25 + 1/(2×26)

… … + … - … + …

… … + 1/(2×198) - 1/199 + 1/(2×200)

… … + 1/(2×199) - 1/200 + 1/(2×201)

… … + 1/(2×200) - 1/201 + 1/(2×202)

Notice the diagonal pattern of underlined and bolded terms that add up to zero (e.g. 1/(2×23) - 1/23 + 1/(2×23) = 1/23 - 1/23 = 0). So, like a telescope, the sum collapses down to a simple sum of just six terms,

C = 1/(2×21) - 1/22 + 1/(2×22) + 1/(2×201) - 1/201 + 1/(2×202)

which we simplify further to

C = 1/42 - 1/44 - 1/402 + 1/404

C = 1,115/1,042,118 ≈ 0.00106994