Answer:
666Step-by-step explanation:
1000 off ⇒ $151 off ⇒ $15/1000 = $0.015Let the required number is x, then we have:
x off ⇒ $10x * 0.015 = 10x = 10/0.015x = 666 (rounded down to whole number)Answer:
We get 666 of something in $ 10.
Step-by-step explanation:
Given that :-
We get 1000 of something for $ 15
Find that :-
How much we can get it in $ 10
Let as assume that : -
Let required number be x.Solution :-
$ 15 = $ 10
1000 = x
Using cross multiplication method
15 × x = 10 × 100 0
multiply ,
15 x = 10000
Divide each side by 15.
15 x / 15 = 10000 / 15
x = 666
The equation y = 50(1.05)x models the growth of a mule deer population introduced into Guadalupe National Park in December 2015. "X" represents the number of years after December 2015 while "y" represents the population at time "x". In what year will the mule deer population first reach 1500?
F.2084
G.2044
H.2043
J.2085
9514 1404 393
Answer:
J. 2085
Step-by-step explanation:
Fill in the desired value for y and solve for x.
1500 = 50(1.05^x)
30 = 1.05^x . . . . . . . divide by 50
log(30) = x·log(1.05) . . . . . take logarithms
x = log(30)/log(1.05) ≈ 69.71
Since x represents years after December 2015, x = 69.7 will be some time in mid 2085.
Complete the table of inputs and outputs for the given function. g(x) = 3 - 8x g() 0 -5 3 Reset
Answer:
Step-by-step explanation:
Please help me understand
Answer:
A is is correct since the interquatile or a is 15 since 15 plus 15 equals 30 and 20 plus 20 equals 40
B is incorrect since the interquare are not both 30
C is incorrect since both interquatiles are wrong
D is incorrect since the standrard devations are off
x-value of 0
f(x) = |x|
f(x) = |x| + 3
f(x) = |x + 3|
f(x) = |x| − 6
f(x) = |x + 3| – 6
9514 1404 393
Answer:
0, 3, 3, -6, -3
Step-by-step explanation:
Maybe you want to find f(0) in each case. Put 0 where x is, and do the arithmetic.
f(0) = |0| = 0
f(0) = |0| +3 = 3
f(0) = |0 +3| = 3
f(0) = |0| -6 = -6
f(0) = |0 +3| -6 = -3
1. The curved surface area of a cylinder of height 21cm is
660cm", find its radius. please help me .....
I will give brainliest.
Answer:
21 times 660 and then you will get the answer
Which statement correctly describes the end behavior of y = 3x8 + 5x2 +2x - 1
es
A)
The graph rises to the left and falls to the right.
B)
The graph falls to the left and rises to the right.
C)
The graph rises to the left and rises to the right.
D)
The graph falls to the left and falls to the right.
I need help with this last question plz
Answer:
C) The graph rises to the left and rises to the right.
Step-by-step explanation:
The highest expone tis even and it's coefficient is positive
therefor
The graph rises to the left and rises to the right.
. A population of rabbits oscillates 25 above and below an average of 129 during the year, hitting the lowest value in January (t = 0). a. Find an equation for the population, P, in terms of the months since January, t. b. What if the lowest value of the rabbit population occurred in April instead?
Answer:
Because we know that here we have an oscillation, we can model this with a sine or cosine function.
P = A*cos(k*t) + M
where:
k is the frequency
A is the amplitude
M is the midline
We know that at t = 0, we have the lowest population.
We know that the mean is 129, so this is the midline.
We know that the population oscillates 25 above and below this midline,
And we know that for t = 0 we have the lowest population, so:
P = A*cos(k*0) + 129 = 129 - 25
P = A + 129 = 129 - 25
A = -25
So, for now, our equation is
P = -25*cos(k*t) + 129
Because this is a yearly period, we should expect to see the same thing for t = 12 (because there are 12 months in one year).
And remember that the period of a cosine function is 2*pi
Then:
k*12 = 2*pi
k = (2*pi)/12 = pi/6
Finally, the equation is:
P = -25*cos(t*pi/6) + 129
Now we want to find the lowest population was in April instead:
if January is t = 0, then:
February is t = 2
March is t = 3
April is t = 4
Then we would have that the minimum is at t = 4
If we want to still use a cosine equation, we need to use a phase p, such that now our equation is:
P = -25*cos(k*t + p) + 129
Such that:
cos(k*4 + p) = 1
Then:
k*4 + p = 0
p = -k*4
So our equation now is:
P = -25*cos(k*t - 4*k) + 129
And for the periodicity, after 12 months, in t = 4 + 12 = 16, we should have the same population.
Then, also remembering that the period of the cosine function is 2*pi:
k*12 - 4*k = 2*pi
k*8 = 2*pi
k = 2*pi/8 = pi/4
And remember that we got:
p = -4*k = -4*(pi/4) = -pi
Then the equation for the population in this case is:
P = -25*cos( t*pi/4 - pi) + 129
which values are solutions to the inequality below? Check all that apply. √x <7
A. -15
B. 48
C. 14
D. 2
E.51
F. No Solutions
Answer:
B,C,D
Step-by-step explanation:
Square both sides of the equation to get rid of the square root surrounding x.
sqrtX^2 = x and 7^2 = 7*7 = 49
x<49
And since we have a radical, we have to have non-negative solutions (the radical used in the equation actually only means the positive square root) meaning x>0
So which one of the choices is less than 49 and greater than 0?
B,C, and D are all less than 49, and greater than 0
A motorboat travels 9 miles downstream (with the current) in 30 minutes. The return trip upstream (against the wind) takes 90 minutes. Which system of equations can be used to find x, the speed of the boat in miles per hour, and y, the speed of the current in miles per hour? Recall the formula d = rt.
Answer:
x=12 mile/hour(the speed of the boat)
y=6 mile/hour(the speed of the current)
Step-by-step explanation:
According to the Question,
let, x be the speed of the boat in miles per hour and y be the speed of the current in miles per hour.
Given That, A motorboat travels 9 miles downstream (with the current) in 30 minutes. Thus, x+y = 0.3 mile/minute ⇒ 0.3×60 ⇒ 18mile/hourx+y=18 ---- Equation 1
& The return trip upstream (against the wind) takes 90 minutes. Thus, x-y = 0.1 mile/minute ⇒ 0.1×60 ⇒ 6mile/hourx-y=6 ---- Equation 2
On Adding both above Equations We get,
2x=24 ⇔ x=12 mile/hour(the speed of the boat)
& x+y=18 put Value of x=12 we get ⇔ y=6 mile/hour(the speed of the current)
2.What is 10:30 pm in the 24-hour clock?
3. How do you write 00:15 in the 12-hour clock?
4.How do you write 11:50 pm in the 24-hour clock?
11.How are the circumference and the diameter of any given circle related
12. The diameter of a circle is 22 cm long. What is its area?
13.What is the area of the largest circle that can be drawn on a square paper whose side is 20 cm? *
16. Two workers need to dig a rectangular pit that is 2 meters long, 1.5 meters wide, and 1 meter deep. How many cubic meters of soil must they remove? *
17.A cubical water tank has a 20 cm edge. How much water can it contain?
tulong
2. 22:30
just add 12 on the front
that is the formula
2 If 9:30pm is 21:30,then 10:30pm=22:30 pm
3 15 seconds
4. If 10:30 = 22:30 then 11:50pm = 23:50
16. 3*1.5*1=4.5m^3
I think this are the ones I can try ,I hope this helps.
DO THIS FAST PLEASE I WILL GIVE BRAINLY CROWN
Use a model to divide. 5 ÷ 1/2 10 4 2 20
5 ÷ 1/2 => 5 x 2/1 => 10/1 => 10
Answer:
10
Step-by-step explanation:
In the pic, it shows ten half squares.
2. A bag contains one red, one blue and one white marble. One marble is chosen at random
from the bag, and then replaced into the bag. A second marble is chosen.
a) Draw a probability tree and find the sample space.
(3 marks)
Answer:
Step-by-step explanation:
Find the midpoint of the line segment.
Answer:
-2,-3
Step-by-step explanation:
Three-fourths (one-fourth x + 8) minus (one-half x + 2) = StartFraction 3 Over 8 EndFraction (4 minus x) minus one-fourth?
Answer:
if I am understood your question correctly, X would be 84/29
Step-by-step explanation:
Defined the total variation distance to be a distance TV(P,Q) between two probability measures P and Q. However, we will also refer to the total variation distance between two random variables or between two pdfs or two pmfs, as in the following.
Compute TV(X,X+a) for any a∈(0,1), where X∼Ber(0.5).
TV(X,X+a) = ?
Answer:
1
Step-by-step explanation:
Computing Tv(X, X + a ) for any a∈(0,1)
Given that : X∼Ber(0.5)
∴ The probability mass function
P(X = 1 ) = 0.5
P(X = 0) = ( 1 - 0.5 )
and expectation E[X] = 0.5
hence ; TV ( X, X + a ) = 1
attendance drop at 7% this year to 1050 what was the attendance before the drop
Answer:
7% divided by 1050 is basically 73.5 but the fraction of that is 147/2 hope u find my answer reasonable have a great day.
Step-by-step explanation:
I am having a lot of difficulty in solving this question, so please help me..
Answer:
216
Step-by-step explanation:
=>log 36 = -2/3
m
=>36=(m)^-2/3
=>(root(-36))^3=m
=>m=(root(36))^3
=>m=6^3
=>m=216
A study of the effect of television commercials on 12-year-old children measured their attention span, in seconds. The commercials were for clothes, food, and toys.
Clothes Food Toys
43 30 52
24 38 58
42 46 43
35 54 49
28 47 63
31 42 53
17 34 48
31 43 58
Required:
a. Find the values of mean and standard deviation.
b. Is there a difference in the mean attention span Of the children for the various commercials?
Answer:
(a)
Mean
[tex]\bar x_1 = 31.375[/tex]
[tex]\bar x_2 = 41.75[/tex]
[tex]\bar x_3 = 53.00[/tex]
Standard deviation
[tex]\sigma_1 = 8.73[/tex]
[tex]\sigma_2 = 7.65[/tex]
[tex]\sigma_3 = 6.04[/tex]
(b) Yes, there is a difference in the mean
Step-by-step explanation:
Solving (a): The mean and standard deviation of each commercial
This is calculated as:
[tex]\bar x = \frac{\sum x}{n}[/tex]
For clothes:
[tex]\bar x_1 = \frac{43+24+42+35+28+31+17+31}{8}[/tex]
[tex]\bar x_1 = \frac{251}{8}[/tex]
[tex]\bar x_1 = 31.375[/tex]
For food:
[tex]\bar x_2 = \frac{30+38+46+54+47+42+34+43}{8}[/tex]
[tex]\bar x_2 = \frac{334}{8}[/tex]
[tex]\bar x_2 = 41.75[/tex]
For toys:
[tex]\bar x_3 = \frac{52+58+43+49+63+53+48+58}{8}[/tex]
[tex]\bar x_3 = \frac{424}{8}[/tex]
[tex]\bar x_3 = 53.00[/tex]
The sample standard deviation is:
[tex]\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}[/tex]
For clothes:
[tex]\sigma_1 = \sqrt{\frac{(43 - 31.375)^2 +.............+(31 - 31.375)^2}{8-1}}[/tex]
[tex]\sigma_1 = \sqrt{\frac{533.875}{7}[/tex]
[tex]\sigma_1 = \sqrt{76.2678571429}[/tex]
[tex]\sigma_1 = 8.73[/tex]
For food:
[tex]\sigma_2 = \sqrt{\frac{(30 - 41.75)^2 +............+(43 - 41.75)^2}{8-1}}[/tex]
[tex]\sigma_2 = \sqrt{\frac{409.5}{7}}[/tex]
[tex]\sigma_2 = \sqrt{58.5}[/tex]
[tex]\sigma_2 = 7.65[/tex]
For toys:
[tex]\sigma_3 = \sqrt{\frac{(52-53.00)^2+...................+(58-53.00)^2}{8}}[/tex]
[tex]\sigma_3 = \sqrt{\frac{292}{8}}[/tex]
[tex]\sigma_3 = \sqrt{36.5}[/tex]
[tex]\sigma_3 = 6.04[/tex]
Solving (b): Difference in mean in the commercials;
In (a), we have:
[tex]\bar x_1 = 31.375[/tex]
[tex]\bar x_2 = 41.75[/tex]
[tex]\bar x_3 = 53.00[/tex]
[tex]\bar x_1 \ne \bar x_2 \ne \bar x_3[/tex]
Hence, there is a difference in their means
The time to complete an exam is approximately Normal with a mean of 48 minutes and a standard deviation of 3 minutes. The bell curve below represents the distribution for testing times. The scale on the horizontal axis is equal to the standard deviation. Fill in the indicated boxes.
Answer:
This means the average amount of time is 48 minutes but many people will do it in 45 to 51
Hope This Helps!!!
What is the mean absolute deviation of Warren’s data?
Warren's Scores Absolute Deviation from Mean Score – individual score
0
25
15
10
20
30
10
15
5
25
20
15
20
5
10
sum of absolute deviations =
Answer:
6.667
Step-by-step explanation:
I just did the calculations
What is the value of f(−2)=2x^3 +3x 2 −39x−20?
Answer:
-65
Step-by-step explanation:
four times a certain number decreased by twice the same number gives 17. the number is
Answer:
8.5
Step-by-step explanation:
A state sales tax of 6% and a local sales tax of 1% are levied in Tampa, Florida. Suppose the price of a
particular car in Tampa is $15,000, and an oil change at a certain auto center is $29.
Which statement is true about the total cost of the car and the oil change after sales tax has been
calculated?
Answer:
16050, 31.03
Step-by-step explanation:
15000x1.07 (adds 7% tax)=16050
29x1.07(adds 7% tax to price)=31.03
Given the system of equations, what is the solution? 2x+y = -1 х- у = -5
Answer:
x=-2, y=3
Step-by-step explanation:
make it easy first, solve for x in the second equation: x= -5+y.
then sub that in for the other x: 2(-5+y)+y= -1
now combine like terms: -10+3y= -1
solve for y: 3y=9, y= 3
then replace y for your second equation: x-3= -5
solve for x= -5+3.... so then its -2
check by replacing all variables with your new solutions:
2(-2), which is -4+3 does equal -1
(-2) -3 does equal -5.
your answers are x=-2, y=3
Which of the following value are in the domain of the function graphed below?
Answer:
look at the domain, where the line is on the x-axis
Step-by-step explanation:
How many numbers lie between the squares of 39 and 40
Answer:
i guess its 1...
Step-by-step explanation:
Answer:
79 numbers
Step-by-step explanation:
39 x 39 = 1521 ( Find the square of 39)
40 x 40 = 1600 (Find the square of 40)
1600 - 1521 = 79 ( Finding the difference of the two squares)
How do I solve this and do the explanation of it
Answer:
180-66
114
hope it helps mark as brainlist
please help me with this question.
Answer:
I think it's 18.1539073013
i'm not sure sorry
PLEASEEEE HELP QUICKKKK
Given:
Line A goes through (0,y) and (-2,0).
Line B goes through (1,2) and (3,10).
To find:
The value of y for which the system of given linear equation (equation of line A and line B) has no solutions.
Solution:
Two linear equation has no solutions if they are parallel line.
Slope formula:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We know that the slopes of two parallel lines are the same.
So, the given system of given linear equation has no solutions if
Slope of line A = Slope of line B
[tex]\dfrac{0-y}{-2-0}=\dfrac{10-2}{3-1}[/tex]
[tex]\dfrac{-y}{-2}=\dfrac{8}{2}[/tex]
[tex]\dfrac{y}{2}=4[/tex]
Multiply both sides by 2.
[tex]\dfrac{y}{2}\times 2=4\times 2[/tex]
[tex]y=8[/tex]
Therefore, the required value of y is 8.
Stevens College plans to have 20 computers for every 100 students. How many computers are needed for 1,500 students?
Answer:
300 computers
Step-by-step explanation:
So I divided 1500 out of a 100 and got 15, then I multiply 15 to 20 and got 300.
(I am a high schooler so I hope this is 3rd grade math because I notice you are a college student and I hope this not some college tricky math, if you get this wrong I am truly sorry)
