I need help with this question I added an image so y’all can see !

I Need Help With This Question I Added An Image So Yall Can See !

Answers

Answer 1

Answer:

a) .66

Explanation:

from (0,4) to (3,6)

the slope would be

[tex] \frac{2}{3} [/tex]

when diving the fraction the half slope is .66666...

Answer 2
The way I learned was to count the ”rise over run”. Count how many blocks are between the origin and point 4, obviously 4 blocks. (this is the ”rise”) Next, you count the number of blocks between -6 and the origin, 6. (this is your run). Then you place the rise over run to get 4/6 then divide to get 0.66. ☺️

Related Questions

What is the average velocity of atoms in 2.00 mol of neon (a monatomic gas)
at 308 K? Use the equation: -mv2
2
For m, use 0.02000 kg. Remember that R = 8.31 J/(mol-K).
= ER
3
2
nRT
A. 1540 m/s
B. 876 m/s
C. 87.6 m/s
O D. 15,400 m/s

Answers

Answer:

v = 876 m/s

Explanation:

It is given that,

Number of mol of Neon is 2 mol

Temperature, T = 308 K

Mass, m = 0.02 kg

Value of R - 8.31 J/mol-K

We need to find the average velocity of atoms in 2.00 mol of neon. Neon is a monoatomic gas. Let v is the velocity. So,

[tex]\dfrac{1}{2}mv^2=\dfrac{3}{2}nRT\\\\v=\sqrt{\dfrac{3nRT}{m}} \\\\v=\sqrt{\dfrac{3\times 2\times 8.314\times 308}{0.02}} \\\\v=876.47\ m/s[/tex]

So, the correct option is (B).

I think it is 887m/s I hope this helps if not I’m really sry
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