I need help with this problem please and thanks

Answer:

The length is 50 feet and the width is 16 feet

Step-by-step explanation:

Let w represent the width of the room.

If the length is 2 feet longer than 3 times the width, the length can be represented by 3w + 2.

Use the perimeter formula, p = 2l + 2w. Plug in the perimeter and plug in 3w + 2 as l, the length:

p = 2l + 2w

132 = 2(3w + 2) + 2w

Simplify and solve for w:

132 = 6w + 4 + 2w

132 = 8w + 4

128 = 8w

16 = w

So, the width is 16 feet.

Plug in 16 as w into 3w + 2 to solve for the length:

3w + 2

3(16) + 2

48 + 2

= 50

The length is 50 feet and the width is 16 feet

Answer:

width=16feet

length=50feet

Step-by-step explanation:

let width be x and length be 3x+2

perimeter=2(length+width)

132=2(3x+2+x)

132=6x+4+2x

132=8x+4

132-4=8x

128/8=8x/8

16=x

width=16feet

length=16×3+2

length=50feet

9514 1404 393

Answer:

  4/5

Step-by-step explanation:

The wording is ambiguous, as it often is when math expressions are described in English. We assume you intend ...

  [tex]\dfrac{3n+8}{n+7}=\dfrac{4}{3}\\\\3(3n+8)=4(n+7)\qquad\text{multiply by $3(n+7)$}\\\\9n+24=4n+28\qquad\text{eliminate parentheses}\\\\5n=4\qquad\text{subtract $4n+24$}\\\\\boxed{n=\dfrac{4}{5}}\qquad\text{divide by 5}[/tex]

The number is 4/5.

Answer:

y = 7cos bx

Step-by-step explanation:

For a cosine function without pahse shift and vertical shift, but with amplitude given, it will also have period and thus , the formula for the cosine function is;

y = Acos bx

Where;

A is the amplitude

Period = 2π/b

Now, we are told that the amplitude is 7. Thus;

y = 7cos bx

Answer:

D - One side is a factored polynomial and the other side is 0.

A - Incorrect; If each side is 0, the equation would be equal since 0 = 0.

B - Incorrect; It cannot be -1 because the property states Zero product which means 0 should be the product.

C - Incorrect; It cannot be 1 because the property states Zero product which means 0 should be the product.

D - Correct; One side is 0, and the other is a factored polynomial, which correctly displays the correct definition of Zero Product Property.

Answer:

6 1/8 ×10 2/7= 60

60÷2 1/3= 30

The answer:

30

Answer:

5x+20y=425

Step-by-step explanation:

Its 5 bucks for x pairs of skates

Its 20 dollars for y bikes

x+y rentals have to equal 25

all of this is equal to 425. All that is left to do is test with number until the statement is true.

try :

5(5)+(20)(20)=425

x + y do equal 25, and the total is equal to 425.

Answer:

900 seconds

Step-by-step explanation:

30 x 30

Answer:

900 seconds or 15 minutes

Step-by-step explanation:

30 x 30 = 900 :)

Answer:

The sample size necessary is of 168.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

Based on a previous study, arrival delay times have a standard deviation of 39.6 minutes.

This means that [tex]\sigma = 39.6[/tex]

Find the sample size necessary to estimate the mean arrival delay time for all American Airlines flights from Dallas to Sacramento to within 6 minutes with 95% confidence.

This is n for which M = 6. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]6 = 1.96\frac{39.6}{\sqrt{n}}[/tex]

[tex]6\sqrt{n} = 1.96*39.6[/tex]

[tex]\sqrt{n} = \frac{1.96*39.6}{6}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.96*39.6}{6})^2[/tex]

[tex]n = 167.34[/tex]

Rounding up:

The sample size necessary is of 168.

Answer:

Specific

Step-by-step explanation:

The data analytics is defined as the study of analyzing the raw data and information so as to make a proper conclusion about the information. It is a process of inspecting, transforming, and  modelling the data with the intention of finding useful information and conclusions.

The acronym for S.M.A..R.T is Specific, Measurable, Attainable, Relevant and Time bounding.

The SMAR criteria which do not meet the data analytics project goal in the question is "Specific".

Answer: Hello attached below is the complete question

answer :

It is convergent ,  sum = 7/12

Step-by-step explanation:

Sn = 1/3 + 1/4 - 1/n - 1/n+1

It is convergent  and the sum = 7/12

attached below is the remaining part of the solution

Hi there!

A.) Begin by verifying that both endpoints have the same y-value:

g(-1) = 2(-1)² - 4(-1) + 3

Simplify:

g(-1) = 2 + 4 + 3 = 9

g(2) = 2(2)² - 4(2) + 3 = 8 - 8 + 3 = 3

Since the endpoints are not the same, Rolle's theorem does NOT apply.

B.)

Begin by ensuring that the function is continuous.

The function is a polynomial, so it satisfies the conditions of the function being BOTH continuous and differentiable on the given interval (All x-values do as well in this instance). We can proceed to find the values that satisfy the MVT:

[tex]f'(c) = \frac{f(a)-f(b)}{a-b}[/tex]

Begin by finding the average rate of change over the interval:

[tex]\frac{g(2) - g(-1)}{2-(-1)} = \frac{3 - 9 }{2-(-1)} = \frac{-6}{3} = -2[/tex]

Now, Find the derivative of the function:

g(x) = 2x² - 4x + 3

Apply power rule:

g'(x) = 4x - 4

Find the x value in which the derivative equals the AROC:

4x - 4 = -2

Add 4 to both sides:

4x = 2

Divide both sides by 4:

x = 1/2

Solution :

Given data :

Total number of books sold each month= 700

The charts in the display attached below shows the most popular books category by percentages.

Percentage of romance books sold each = 8.5%

Therefore, the number of romance books sold in each month is given by :

[tex]$=8.5 \% \text{ of }\ 700$[/tex]

[tex]$=\frac{8.5}{100}\times 700$[/tex]

= 59.5

≈ 60 books (rounding off)

You can use the fact that total amount is taken as 100%.

The number of romance books in the given Streets Books is 60

Suppose the value of which a thing is expressed in percentage is "a'

Suppose the percent that considered thing is of "a" is b%

Then since percent shows per 100 (since cent means 100), thus we will first divide the whole part in 100 parts and then we multiply it with b so that we collect b items per 100 items(that is exactly what b per cent means).

Thus, that thing in number is [tex]\dfrac{a}{100} \times b[/tex]

Since the total amount of books is 700, and its 8.5% books are romance books, thus we have:

[tex]\text{Number of Romance books} = \dfrac{700}{100} \times 8.5 = 59.5 \approx 60[/tex]

The number of romance books in the given Streets Books is 60

Learn more about percentage here:

https://brainly.com/question/11549320

Answer:

the answer is A y  −  12  =  − 5 ( x + 2 )

Step-by-step explanation:

y − 12 = ( − 5 x + 2 ) ⋅ ( x + 2 )

to get this answer you can plug it into point slope equation:

y-y1=m(x+x1)

plug in the given information:

-y and x will stay the same

-y1 will be 12 and x1 will be -2 (remember the given point -2,12)

-m will be the slope given from the y intercept equation

I hope this helps~

Answer:

a

Step-by-step explanation:

Answer:

1. 55 degree

2. 50 degree

3. 88 degree

4. 50 degree

Step-by-step explanation:

1.

Angle AE interior 180-120 = 60

Angle CD interior 180-112 = 68

x = 180- (60+68) = 180-128 = 52 degree

2.

interior 180 -120= 40

interior 180- 110 = 90

x = 180 - (40+90) = 180-130 = 50 degree

3.

exterior 90-52= 38

exterior 90-40 = 50

x = 180-(52+40)= 180-92 = 88 degree

4.

interior 180- (45+50) = 180-95 = 85 degree

interior adjoining triangle 180 - 85 = 95

all angles add up to 180

interior 180- (35 + 95)= 180-130 = 50 degree

x = 50 degree

Answer:

Following are the response to this questions:

Step-by-step explanation:

Please find the graph file in the attachment.

Given:

P=2

B=-5

H=?

[tex]H=\sqrt{P^2+B^2}[/tex]

    [tex]=\sqrt{2^2+(-5)^2}\\\\=\sqrt{4+25}\\\\=\sqrt{29}\\\\[/tex]

Using formula:

[tex]\to \ cosec \theta \ or\ \ csco \theta =\frac{H}{P}\\\\\to \cos \theta=\frac{B}{H}\\\\\to \tan \theta=\frac{p}{B}\\\\[/tex]

So,

[tex]\to \ cosec \theta \ or\ \ csco \theta =\frac{\sqrt{29}}{2}\\\\\to \cos \theta=\frac{-5}{\sqrt{29}} =\frac{-5}{\sqrt{29}}\times \frac{\sqrt{29}}{\sqrt{29}}=-\frac{5\sqrt{29}}{29}\\\\\to \tan \theta=\frac{2}{-5}= -\frac{2}{5}\\\\[/tex]

Answer:

X^2 + 3x - 10=0

Answer:

A= 20

B= 6

Step-by-step explanation:

A= 5 times 4= 20

B= 24/4= 6

Answer:

x  ≥ 31

Step-by-step explanation:

-5x + 5 ≥ 160 − 10x

Add 10x to each side

-5x+10x + 5 ≥ 160 − 10x+10x

5x+5   ≥ 160

Subtract 5 from each side

5x+5-5 ≥ 160 − 5

5x  ≥ 155

Divide by 5

5x/5  ≥ 155/5

x  ≥ 31

Answer:

72 in^2

Step-by-step explanation:

The area of the square in the middle is

A = s^2 = 6^2 = 36

The area of the triangle on the left is

A =1/2 bh = 1/2 ( 6*6) = 18

The area of the triangle on the right

A = 1/2 bh = 1/2(6*6) = 18

Add the areas together

36+18+18 = 72

Area of the middle square = 6 x 6 = 36

Area of a triangle is 1/2 x base x height:

Area = 1/2 x 6 x 6 = 18

Both triangles have a base of 6 and height of 6 so both triangles have the same area.

Total area = 36 + 18 + 18 = 72 square in.

The answer is D. 72

Answer:

The answer is A: 6√2 - 2√30 + 6 - 2√15

Believe me it right.

Answer:

A) 21 in²

B) 42 in²

C) 84 in²

D) I) 4 in²

II) 8 in²

III) 16 in²

E) From our calculations, we can see that doubling one part of the dimensions gives an area that is twice the original one while doubling both dimensions gives an area that four times the original one.

Step-by-step explanation:

We are given dimensions of triangle as;

width; w = 3 inches

length; L = 7 inches

A) Area of triangle is;

A = Lw

A = 7 × 3

A = 21 in²

B) If we double the width, then area is;

A = 7 × (2 × 3)

A = 42 in²

Area is twice the original area

C) If we double the width and length, then we have;

Length = 7 × 2 = 14 in

Width = 3 × 2 = 6 in

Area = 14 × 6 = 84 in²

Area is four times the original one

D) Let's try a triangle with base 2 in and height 4 in.

I) formula for area of triangle is;

A = ½ × base × height

A = ½ × 2 × 4

A = 4 in²

II) If we double the width(base) , then area is;

A = ½ × 2 × 2 × 4

A = 8 in²

This is twice the original area.

III) If we double the width(base) and length(height), then we have;

A = ½ × 2 × 2 × 4 × 2

A = 16 in²

This is four times the original area

E) From our calculations, we can see that doubling one part of the dimensions gives an area that is twice the original one while doubling both dimensions gives an area that four times the original one.

Answer:

Angle ABC = 30°

Step-by-step explanation:

Answer:

A. y<-2x-1

Step-by-step explanation:

not C or D because it is a dashed line meaning the linear equation will either have the symbol ≥ or ≤.

when y is less than, you shade below

thus, the answer is A

Answer:

(a) [tex]H_o:\mu_1 = \mu_2[/tex]     [tex]H_a:\mu_1 > \mu_2[/tex]

(b) [tex]t = 0.74[/tex]

(c) [tex]p =0.2331[/tex]

(d) [tex]CI = (-2.095,4.095)[/tex]

Step-by-step explanation:

Given

[tex]\bar x_1=21,\ s_1=4,\ n_1=12,\\ \bar x_2=20,\ s_2=3,\ n_2=15[/tex]

Solving (a): The hypotheses

The test is right-tailed, means that the alternate hypothesis will contain greater than sign.

So, we have:

[tex]H_o:\mu_1 = \mu_2[/tex]

[tex]H_a:\mu_1 > \mu_2[/tex]

Solving (b); The test statistic (t)

This is calculated as:

[tex]t = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{s_1^2(n_1 - 1) + s_2^2(n_2 - 1)}{n_1 + n_2 - 2} * (\frac{1}{n_1} + \frac{1}{n_2})}}[/tex]

So, we have:

[tex]t = \frac{21 - 20}{\sqrt{\frac{4^2(12 - 1) + 3^2(15 - 1)}{12 + 15 - 2} * (\frac{1}{12} + \frac{1}{15})}}[/tex]

[tex]t = \frac{1}{\sqrt{\frac{302}{25} * (0.15)}}[/tex]

[tex]t = \frac{1}{\sqrt{12.08 * 0.15}}[/tex]

[tex]t = \frac{1}{\sqrt{1.812}}[/tex]

[tex]t = \frac{1}{1.346}[/tex]

[tex]t = 0.74[/tex]

Solving (c): The P-value

First, we calculate the degrees of freedom

[tex]df = n_1 + n_2 -2[/tex]

[tex]df = 12+15 -2[/tex]

[tex]df = 25[/tex]

Using the t distribution, the p-value is:

[tex]p =TDIST(0.74,25)[/tex]

[tex]p =0.2331[/tex]

Solving (d): The 90% confidence interval

Calculate significance level

[tex]\alpha = 1 - CI[/tex]

[tex]\alpha = 1 - 90\%[/tex]

[tex]\alpha = 0.10[/tex]

Calculate the t value (t*)

[tex]t^* = (\alpha/2,df)[/tex]

[tex]t^* = (0.10/2,25)[/tex]

[tex]t^* = (0.05,25)[/tex]

[tex]t^* = 1.708[/tex]

The confidence interval is calculated using:

[tex]CI = (\bar x - \bar x_2) \± t^* *\sqrt{\frac{s_1^2(n_1 - 1) + s_2^2(n_2 - 1)}{n_1 + n_2 - 2} * (\frac{1}{n_1} + \frac{1}{n_2})}[/tex]

[tex]CI = (21 - 20) \± 1.708 *\sqrt{\frac{4^2(12 - 1) + 3^2(15 - 1)}{12 + 15 - 2} * (\frac{1}{12} + \frac{1}{15})}[/tex]

[tex]CI = 1 \± 1.708 *1.812[/tex]

[tex]CI = 1 \± 3.095[/tex]

Split

[tex]CI = 1 - 3.095 \ or\ 1 + 3.095[/tex]

[tex]CI = -2.095 \ or\ 4.095[/tex]

[tex]CI = (-2.095,4.095)[/tex]

Answer:

1.5

Step-by-step explanation:

Took the test already.

The value of a for which the exponential function below would cause the function to stretch is a > 1 Or 1.5.

Suppose we have a function f(x).

f(x) ± d = Vertical upshift/downshift by d units (x, y ±d).

f(x ± c) = Horizontal left/right shift by c units (x - + c, y).

(a)f(x) = Vertical stretch for a > 0, vertical shrink a < 0. (x, ay).

f(bx) = Horizonatal compression b > 0, horizontal stretch for b < 0. (bx , y).

f(-x) = Reflection over y axis, (-x, y).

-f(x) = Reflection over x-axis, (x, -y).

We know an exponential function f(x) = [tex]e^x[/tex].

Now if we multiply f(x) by some number 'a' which is greater than 1 let it be g(x) = [tex]ae^x[/tex] the function would stretch horizontally for a > 1.

learn more about function transformations here :

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Answer:

Quadratics are not linear. They do not create straight lines.

so, the answers is "a linear graph"

Answer:

A sample of 18 is required.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.92}{2} = 0.04[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.04 = 0.96[/tex], so Z = 1.88.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

A previous study indicated that the standard deviation was 2.2 days.

This means that [tex]\sigma = 2.2[/tex]

How large a sample must be selected if the company wants to be 92% confident that the true mean differs from the sample mean by no more than 1 day?

This is n for which M = 1. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]1 = 1.88\frac{2.2}{\sqrt{n}}[/tex]

[tex]\sqrt{n} = 1.88*2.2[/tex]

[tex](\sqrt{n})^2 = (1.88*2.2)^2[/tex]

[tex]n = 17.1[/tex]

Rounding up:

A sample of 18 is required.