i need help asap im timed

Answer:

A=2

B=4

C=6

D=5

E=7

F=8

G=3

H=1

Step-by-step explanation:

explanation is in the picture!

Hi

5x²-x-4 = 0  

Δ= (-1)² - 4*5*(-4)

Δ =  1 -4*-20

Δ = 1  +80

Δ = 81  

√Δ=  9

as Δ ≥ 0 , so 2 solutions exist in R

S1 is :    ( 1+9) /2*5  =   10/10 = 1

s2 =      (1 -9)/2*5 =  -8/10 = -4*2 /2*5  = -4/5

Corrects answers are  A  and  D

Answer:

A. -4/5 And D. 1

Step-by-step explanation:

i just got it right

Answer:

34

Step-by-step explanation:

This is because you will have to simply divide 782 by 23.

782 / 23 =

34 :D

Answer:

4/5 or 0.8

Step-by-step explanation:

this problem description is not very precise. it leaves out the definition what corners or sides of JKLM correspond to corners and sides of ABCD.

I assume J and K correlate to A and B, and JK is a long side of JKLM.

so, we are going from JKLM to ABCD.

that means we are going from larger to smaller (as JK = 15 and therefore larger than AB = 12).

what is the scale factor to go from 15 to 12 ?

15 × x = 12

x = 12/15 = 4/5 or 0.8

Answer:

g(x)=x+9

Step-by-step explanation:

When translating a graph, adding the number of units shifts the graph to the left and subtracting the number of units shifts it to the right. Since you need the graph translated 9 units to the left, you will need to add that many units to x

therefore, g(x)=x+9

Answer:

g(x)=x-8

Step-by-step explanation:

-2+2 = 0, so g(x) = x

5-13 = -8

Answer:

x=2, x=-2, x=-3

Step-by-step explanation:

-check if anything simplifies

(x-1)(x-3)²(x+1)² / (x-2)(x+2)(x-1)(x+3), simplify (x-1)

(x-3)²(x+1)² / (x-2)(x+2)(x+3)

-make the denominator 0 to find the asymptotes

(x-2)(x+2)(x+3) = 0

(x-2) =0 gives x = 2 asymptote

(x+2) =0 gives x= -2 asymptote

(x+3) = 0 gives x=- 3 asymptote

Answer:

[tex]x + y = - 5[/tex]

Step-by-step explanation:

hopefully it is clear and makes sense

:)

Answer:

MZ = 10

ZO = 10

MO = 20

XZ = 9

YZ = 7

Step-by-step explanation:

Triangles are all the same, proportionally.

X is midpoint of 14, so 7

Y for 18, so 9

Triangle with 10 is 7, 9, 10

Full triangle is double at 14, 18, MO

Since angle N is same angle, MO is double 10, so 20

Z is midpoint, so both halves are 10

Because of midpoints, XZ and YZ with 10 form same triangle as half triangle at 9, 7, and 10 respectively.

Answer:

x = 139

Step-by-step explanation:

The exterior angle is equal to the sum of the opposite interior angle

x = 49 +90

x = 139

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

[tex] \bf \large \implies \: x \: = \: 49 \degree \: + \: 90 \degree[/tex]

[tex] \bf \large \implies \: x \: = \: 139 \degree [/tex]

Answer:

[tex]\displaystyle d \approx 15.8768[/tex]

Step-by-step explanation:

We want to find the distance of d or AB.

From the right triangle with a 35° angle, we know that:

[tex]\displaystyle \tan 35^\circ = \frac{50}{PB}[/tex]

And from the right triangle with a 42° angle, we know that:

[tex]\displaystyle \tan 42^\circ = \frac{50}{PA}[/tex]

AB is PA subtracted from PB. Thus:

[tex]\displaystyle d = AB = PB - PA[/tex]

From the first two equations, solve for PB and PA:

[tex]\displaystyle \frac{1}{\tan 35^\circ } = \frac{PB}{50} \Rightarrow PB = \frac{50}{\tan 35^\circ}[/tex]

And:

[tex]\displaystyle \frac{1}{\tan 42^\circ } = \frac{PA}{50} \Rightarrow PA = \frac{50}{\tan 42^\circ}[/tex]

Therefore:

[tex]\displaystyle d = AB = \frac{50}{\tan 35^\circ} - \frac{50}{\tan 42^\circ}[/tex]

Using a calculator:

[tex]\displaystyle d= AB \approx 15.8768[/tex]

Answer:

123,000 grams

Step-by-step explanation:

1000 mg is equivalent to 1 gram.

Answer:

123000g

Step-by-step explanation:

1000mg=1g

123000000mg= xgrams

cross multiplying,

you'll have

[tex] \frac{123000000}{1000} = 123000[/tex]

Answer:

1.92 m³

hopefully this answer can help you to answer the next question.

Answer: (b)

Step-by-step explanation:

Given

There are five consecutive integers and the least minus twice the greatest equals to -3

Suppose [tex]x,x+1,x+2,x+3,x+4[/tex] are the five consecutive integers

According to the question

[tex]\Rightarrow x-2(x+4)=-3\\\Rightarrow x-2x-8=-3\\\Rightarrow -x=8-3\\\Rightarrow x=-5[/tex]

option (b) is correct.

Answer:

2.707 * 10^6

i think it is the best expression

Answer:

580

Step-by-step explanation:

Assuming that the answer should be in terms of z scores, we can calculate the z score as

z = (observed value - mean)/(standard deviation)

For the first exam, the observed value is 86, the mean is 71, and the standard deviation is 20. The z score fot that exam is

z = (86-71)/20 = 0.75

Then, for the second exam, Evelyn has to do equivalently well, so the z score must be the same. Therefore, we have

0.75 = (observed score - 550)/40

multiply both sides by 40 to remove a denominator

0.75 * 40 = observed score - 550

add 550 to both sides to isolate the observed score

0.75 * 40 + 550 = observed score = 580

Answer:

x=35/78

Step-by-step explanation:

3/2x-11/5=(7/8)*(64/49)

3/2x-11/5=8/7

3/2x=8/7+11/5

3/2x=117/35

x=(35*3)/(2*117)

x=35/78

Answer:

The length of the third side is 7.81 inches and the perimeter of the triangle is about 18.81 inches

Step-by-step explanation:

The question is incomplete. The complete question is :

In a survey of women in a certain country ( ages 20-29), the mean height was 62.9 inches with a standard deviation of 2.81 inches.  Answer the following questions about the specified normal distribution.  (a) What height represents the 99th percentile?  (b) What height represents the first quartile?  (Round to two decimal places as needed)

Solution :

Let the random variable X represents the height of women in a country.

Given :

X is normal with mean, μ = [tex]62.9[/tex] inches and the standard deviation, σ = [tex]2.81[/tex] inches

Let,

[tex]$Z=\frac{X - 62.9}{2.81}$[/tex] , then Z is a standard normal

a). Let the [tex]99th[/tex] percentile is = a

The point a is such that,

[tex]$P(X<a)=0.99$[/tex]

[tex]$P \left( Z < \frac{a-62.9}{2.81} \right) = 0.99$[/tex]

From standard table, we get : [tex]P( Z < 2.3263) =0.99[/tex]

∴ [tex]$\frac{(a-62.9)}{281} = 2.3263$[/tex]

  [tex]$a= (2.3263 \times 2.81 ) +62.9$[/tex]

     = 6.536903 + 62.9

     = 69.436903

     = 69.5 (rounding off)

Therefore, the height represents the [tex]99th[/tex] percentile = 69.5 inches.

b). Let b = height represents the first quartile.

It is given by :

[tex]P( X < b) =0.25[/tex]

[tex]$P \left( Z < \frac{(b-62.9)}{2.81} \right) = 0.25$[/tex]

From the standard normal table,

[tex]P( Z < -0.6745) =0.99[/tex]

∴ [tex]$\frac{(b-62.9)}{2.81}= 0.6745$[/tex]

[tex]$b=(0.6745 \times 2.81) +62.9$[/tex]

  = 1.895345 + 62.9

   = 64.795345

   = 64.8 (rounding off)

Therefore, the height represents the 1st quartile is 64.8 inches.

Answer:

l = (p - 2w)/2

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

4s multiples:

4,8,12,16,20,24

6s multiples:

6,12,18,24,30,36

lowest number that is a common multiple between both 4 and 6:

12

Answer: 2

Step-by-step explanation:

Answer:

Step-by-step explanation:

The diagram is given to you below. I could not change <C so that it was theta. So C = theta.

So C is the reference angle. Call it theta when you think of it. The diagram shows you how cos(C) must be set up.

The adjacent side is 7

The hypotenuse is 18

theta = C = cos-1(7/18) = 67.11

To the nearest degree 67.11 = 67

Answer:

B

Step-by-step explanation:

area=1/2×32×6.1=16×6.1=97.6 yd²

Answer:

Choice B. 97.6 yd^2

Step-by-step explanation:

B×W×.5= A

The quadratic equation that could be solved using the given application of the quadratic formula is x² + 2x - 1 = 3, which in standard form is x² + 2x - 4 = 0. Hence, option C is the right choice.

A standard quadratic equation of the form ax² + bx + c = 0, can be solved using the quadratic formula, which is given as:

[tex]x = \frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

In the question, we are asked for the quadratic equation, which could be solved using this application of the quadratic formula:

[tex]x = \frac{-2\pm\sqrt{2^2-4(1)(-4)} }{2(1)}[/tex]

To find the quadratic equation for which we use the quadratic formula

[tex]x = \frac{-2\pm\sqrt{2^2-4(1)(-4)} }{2(1)}[/tex]

we compare this equation with the standard quadratic formula,

[tex]x = \frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

to get a = 1, b = 2, and c = -4, to get the standard quadratic equation, ax² + bx + c = 0, as (1)x² + (2)x + (-4) = 0, or x² + 2x - 4 = 0.

Now, we convert the given options in the standard form to check for the correct choice:

Thus, the quadratic equation that could be solved using the given application of the quadratic formula is x² + 2x - 1 = 3, which in standard form is x² + 2x - 4 = 0. Hence, option C is the right choice.

Learn more about the quadratic formula at

https://brainly.com/question/1214333

#SPJ2

Answer:

1) The total displacement vector is ((16 + √2)/2, -(6+11·√2)/2)

2) The number of miles they'd have to walk is approximately 13.856 miles

Step-by-step explanation:

1) The distance, direction, and location of the path of the walk the person takes,  are listed as follows;

Start location, (0, 0)

6 miles East walk to location, (6, 0)

6 miles Southeast to location, (6 + 3·√2, -3·√2)

3 miles South to location, (6 + 3·√2, -3·√2 - 3)

5 miles Southwest to location, (6 + 3·√2 - 2.5·√2, -3·√2 - 3 - 2.5·√2)

2 miles East to location, (6 + 3·√2 - 2.5·√2 + 2, -3·√2 - 3 - 2.5·√2)

(6 + 3·√2 - 2.5·√2 + 2, -3·√2 - 3 - 2.5·√2) = ((16 + √2)/2, -(6+11·√2)/2)

Therefore the destination coordinates is ((16 + √2)/2, -(6+11·√2)/2)

The total displacement vector, [tex]\underset{d}{\rightarrow}[/tex] = ((16 + √2)/2, -(6+11·√2)/2)

d =  (16 + √2)/2)·i - (6+11·√2)/2)·j

2) If the person walked straight home, the number of miles they'd have to walk, [tex]\left | \underset{d}{\rightarrow} \right |[/tex], is given as follows;

[tex]\left | \underset{d}{\rightarrow} \right | = \sqrt{\left(\dfrac{16 +\sqrt{2} }{2} \right)^2 + \left(-\dfrac{6 + 11 \cdot \sqrt{2} }{2} \right)^2 } = \sqrt{134 + 41 \cdot \sqrt{2} }[/tex]

Therefore;

If the person walked straight home, the number of miles they'd have to walk [tex]\left | \underset{d}{\rightarrow} \right | \approx 13.856 \ miles[/tex]

Answer:

Step-by-step explanation:

The missing length is 13 because,

Lets say the top triangle is A and the bottom triangle is B.

Triangle A gives us the side GF, and Triangle B gives us the sides TU and ST. Since the triangles are similar(as stated in the problem), we can pair 2 sides GF(A) and TU(B) which is 11:22.(one way I usually figure which sides are similar is by first- matching the hypotenuse, then checking which of the remaining two is longer.. if that made any sense). You can see that their relationship is x2 or /2 (In another word, from A to B is multiplication- ex: 11 * 2 is 22, and from B to A is division- ex 22/2 is 11.) Since the missing number is the hypotenuse of triangle A and you know the Hypotenuse of triangle B all you have to do is divide side TS by 2 to get side SF. So the missing side is 13.

Answer: 13