Energy refers to the ability or capacity to do work. Energy can be of various types as follows:
Mechanical energy (kinetic or potential)Electrical energyLight energySolar energyHeat energyKinetic energy is energy possessed by an object because of its motion while potential energy is energy possessed by an object because of its position or its condition.
The law of conservation of energy states that energy cannot be created nor destroyed but can only be transformed i.e. converted from one form to another.
Friction is a force that resists the relative motion or tendency to such motion of two bodies in contact.
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a mass-spring system in simple harmonic motion has an energy of 4.04 j and an amplitude of 21 cm. find the maximum force that the spring exerts on the mass. (be careful with units!)
The maximum force that the spring exerts on the mass is 3.847N if spring is in simple harmonic motion.
In mechanics and physical science,simple harmonic motion (some of the time shortened SHM) is an exceptional kind of occasional movement of a body coming about because of a powerful harmony between an inertial power
We have kinetic energy in Simple harmonic motion =(1/2)mω²A² where m is the mass,ω is the angular frequency and A is the amplitude of the body.
Now,we need to find the force exerted by spring which is given by formula =ma=mω²A .So,we need to find the mω².
We have kinetic energy as =4.04J
So,on putting the values we get
=>4.04=(1/2)×m×ω²×(0.21)²
=>4.04×2 = m×ω²×(0.21)²
=>8.08 =m×ω²×0.441
=>mω²=8.08/0.441
=>mω²=18.32kg/sec²
Now,we know that force is given by formula=mω²x where x is the maximum amplitude of spring.Here value of x is 0.21m.
So,F=mω²x
=>F=18.32×0.21
=>F=3.847N
Hence,maximum force is 3.847N.
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at one point in the pipe, the radius is 0.160 mm . what is the speed of the water at this point if the volume flow rate in the pipe is 1.20 m3/sm3/s .
The flow rate of the water in the pipe is given by Q=Av
where
Q is the flow rate
A is the cross-sectional area of the pipe
v is the speed of the water
with the help of question,
,
Q=1.20m3/s
the radius of the pipe is
r = 0.160 m
So, the cross-sectional area is
;
;A=πr^2 where r=0.160mm
=π(0.160×0.160)2=0.0256m
So we can re-arrange the equation to find the speed of the water:
;v=Q/A=1.20m3/s/0.0256
=4687.5m3
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A stone is released from a height of 80m above the ground. Calculate its velocity just before it strikes th ground
The velocity of the stone just before it strikes the ground is 39.6 m/s.
What is velocity?Velocity can be defined as the rate of change of displacement.
To calculate the velocity at which the bstone strikes the ground, we use the formula below.
Formula:
v² = u²+2gs.................... Equation 1Where:
v = Final velocityu = Initial velocityg = Acceleration due to gravitys = heightFrom the question,
Given:
u = 0 m/sg = 9.8 m/s²s = 80 mSubstitute these values into equation 1 and solve for v
v² = 0²+(2×9.8×80)v² = 1568v = √1568v = 39.6 m/sHence, the velocity is 39.6 m/s.
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if betelgeuse were to radiate all of its energy at the peak-intensity wavelength, how many photons per second would it radiate?
if Betelgeuse were to radiate all of its energy at the peak-intensity wavelength, how many photons.
What is energy?
Energy, which is observable in the execution of labour as well as in the form of heat and light, is the quantitative quality that is transferred to a body or to a physical system in physics. It is a mechanically accepted quantity.
a )
Radius of the sun = .69645 x 10⁹ m .
600 times = 600 x .69645 x 10⁹ m
= 4.1787 x 10¹¹ m .
surface area A = 4π (4.1787 x 10¹¹)²
= 219.317 x 10²²
energy radiated E = σ A Τ⁴
= 5.67 x 10⁻⁸ x 219.317 x 10²² x (3000)⁴
= 100695 x 10²⁶ J
To know the wavelength of photon emitted
[tex]\begin{aligned}& \lambda_m T=b \\& \lambda_m=\frac{b}{T}\end{aligned}[/tex]
= 2.89777 x 10⁻³ / 3000
= 966 nm
= 1275 /966 eV
1.32 x 1.6 x 10⁻¹⁹ J
= 2.112 x 10⁻¹⁹ J
No of photons radiated = 100695 x 10²⁶ / 2.112 x 10⁻¹⁹
= 47677.5 x 10⁴⁵
= .476 x 10⁵⁰ .
b )
energy radiated by our sun per second
E₂ = σ A 5800⁴
energy radiated by Betelgeuse per second
E₁ = σ x 600²A x 3000⁴
E₁ / E₂ = σ x 600²A x 3000⁴ / σ A 5800⁴
= 36 X 10⁴ x 3⁴ x 10¹² / 58⁴ x 10⁸
= 25.76 x 10⁸ x 10⁻⁵
= 25760 times .
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Complete Question
The red giant Betelgeuse has a surface temperature of 3000 K and is 600 times the diameter of our sun. (If our sun were that large, we would be inside it!) Assume that it radiates like an ideal blackbody.a) If Betelgeuse were to radiate all of its energy at the peak-intensity wavelength, how many photons per second would it radiate?b) Find the ratio of the power radiated by Betelgeuse to the power radiated by our sun (at 5800 K).
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a thin film of thickness 280 nm and index of refraction 1.4 coats a plate of glass having index of refraction 1.65. if light is perpendicularly incident on the glass, at what wavelength is the reflected light minimal?
If a thin layer with an index of refraction of 1.4 and a thickness of 280 nm coats a glass plate with an index of refraction of 1.65, the minimum wavelength of the reflected light is 182 nm.
What is the wavelength, exactly?When a waveform signal travels across space or down a wire, its wavelength is the distance between two identical locations (adjacent crests) in adjacent cycles. The standard units of measurement for this length in wireless systems are meters (m), centimeters (cm), or millimeters (mm) (mm).
Light is coming from a medium with a lower refractive index (n 1 = 1.50) into a medium with a higher index (n 2 = 1.60), so the net path difference in the reflected rays from the two interfaces will be equal to 2t (where t is the thickness of the thin film), because when that happens, light will enter the higher index medium.
When light travels from air to a thin film, the reflected ray's path shift equals 2; when it travels from a thin film to glass, the reflected ray's path shift equals 2′ /2+2t for constructive interference; 2t=m or 2t=m/n 1 where is the wavelength in the thin film, =546nm (given) wavelength in vacuum, and m=0 (minimum); thus, t
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Visible light has a higher frequency than radio waves on the electromagnetic spectrum. How does the wavelength of visible light compare to radio waves?.
The wavelength of visible light compare to radio waves in the sense that visible light waves have a shorter wavelength than radio waves.
What is wavelength?The wavelength is described as the spatial period of a periodic wave which is the distance over which the wave's shape repeats.
Radio waves are electromagnetic waves that are produced by man with an oscillating circuit.
Radio waves are used in broadcasting, the waves used in television are those of shorter wavelength and those of radio are those of longer wavelength.
Longer radions are reflected in the ionosphere and can be detected in antennas which is located at great distances from the emitting source. The medium waves are less reflected in the ionosphere, due to their large wavelength they can overcome obstacles, so they can travel great distances.
It is known that the visible radiation waves have a wavelength between approximately 400 and 700 nanometers, the radio waves range from 1 centimeter to 1 km, so they have longer wavelengths than the waves belonging to the visible spectrum.
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the area of a square metal is 600mm square.calculate it's New area when it's temperature is raised by 15k ( linear expansivity of metal=1.9*10-5 k-1
Answer:
ΔL = L * 1.9E-5 * ΔT
ΔA = A * 2 * 1.9E-5 * ΔT
ΔA = .6 * 3.8E-5 * 1.5E4 mm = .34 mm
New area = 600.34 mm
Note: (L + ΔL)^2 = L + 2 L ΔL + ΔL^2 where ΔL is a small quantity
(L + ΔL)^2 - L^2 = 2 L ΔL = L ΔA
where the coefficient of area expansivity is twice that of linear expansivity
at noon, ship a is 170 km west of ship b. ship a is sailing east at 40 km/h and ship b is sailing north at 25 km/h. how fast is the distance between the ships changing at 4:00 pm?
If at noon , the ship A is 170 km west of ship B , then the distance between the ships changing at 4:00 p.m. is 28.85 kmph .
The ship A is 170 km west of ship B and
ship A is sailing east at the speed of 40 km/h ;
ship B is sailing north at the speed of 25 km/h ;
let us consider "x" and "y" as initial position of ships A and B ;
let the distance between ship A and "x" = x ;
let the distance between ship B and "x" = y ;
let the distance between ship A and ship B = z ;
By using Pythagoras Theorem ; z² = x² + y² ;
differentiating w.r.t. "t" ,
we get ;
2z*dz/dt = 2x*dx/dt + 2y*dy/dt
on Dividing equation by 2 on both sides ;
z*dz/dt = x*dx/dt + y*dy/dt .....equation(1)
given ; dx/dt = 40 km/hr and dy/dt = 25 km/hr
Now , When t = 4 hours,
since at noon ; the ship A is west of Ship B ;
we get ; x = 40*4 = 170 - 160 = 10 ; y = 25*4 = 100 and
z = √(x² + y²) , putting the values of x and y ,
we get ;
z = √(x² + y²) ;
z = √(10² + 100²) ;
substituting the values ; we get
z = √100+10000
z = √10100
z = 100.49
putting the values of x , y and z , in equation(1) ,
we get ;
100.49*dz/dt = 10*40 + 100*25 ;
100.49*dz/dt = 400 + 2500
100.49*dz/dt = 2900
dz/dt = 2900/100.49
dz/dt = 28.85 kmph ;
Therefore , The distance between the ships is changing at 4:00 p.m. is 28.85 kmph .
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perceiving the color, motion, and form of a bird in flight illustrates a. parallel processing. %. opponent-process theory. q. trichromatic theory. d. serial processing. place theory.
parallel processing perceiving the color, motion, and form of a bird in flight illustrates.
Option a is correct.
The trichromatic hypothesis of colour perception is what?According to the trichromatic theory, our ability to perceive red, green, and blue hues as well as how they affect our cerebral activity are both explained by cones (Like a projection T.V.). Consequently, the precise colour we see is determined by the proportion of each colour to the others.
What foundation does trichromatic theory have?The three kinds of cone receptors that are responsible for colour vision are the foundation of the trichromatic hypothesis of colour vision. Beginning in the 18th century, this hypothesis has a very long history.
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p2. an automobile tire has a volume of 1.64 x 10-2 m3 and contains air at a gauge pressure (pressure above atmospheric pressure) of 165 kpa when the temperature is 0.00 degrees celsius. what is the gauge pressure of the air in the tires when its temperature rises to 27.0 degrees celsius and its volume increases to 1.67 x 10-2 m3 ? assume atmospheric pressure is 1.01 x 105 pa.
The gauge pressure of the air in the tires when its temperature rises to 27.0 degrees celsius and its volume increases to 1.67 x 10-2 m3 is 175 kPa.
What is temperature?Temperature is a measure of the average kinetic energy of the particles in a system. It is measured using a thermometer and is typically expressed in units of degrees Celsius (°C), Fahrenheit (°F), or Kelvin (K). Temperature is an important factor in determining the state of matter, as well as the rate of chemical reactions and the motion of particles within a system.
The ideal gas law states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature. Therefore, we can rearrange the equation to solve for P:
P = (nRT) / V
We can plug in the given values to find the initial pressure:
P = [(1.67 x 10-2 m3)(1.01 x 105 pa) / (1.64 x 10-2 m3)] / (0.00 + 273.15)
P = 165 kPa
Now, we can find the new pressure when the temperature rises to 27.0 degrees celsius and the volume increases to 1.67 x 10-2 m3:
P = [(1.67 x 10-2 m3)(1.01 x 105 pa) / (1.67 x 10-2 m3)] / (27.0 + 273.15)
P = 175 kPa
Therefore, the gauge pressure of the air in the tires when its temperature rises to 27.0 degrees celsius and its volume increases to 1.67 x 10-2 m3 is 175 kPa.
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The energy of the electron of hydrogen atom in its nth orbit is given by E n =− n 2 13.6
electron volt(eV). Based on this formula.
(i) Draw different energy levels corresponding to n=1,2,3,4,5,6 and [infinity].
(ii) Show Lyman and Baler series of emission spectrum of hydrogen atom by drawing various electronic transitions.
(iii) Find the ionisation energy of hydrogen atom.
Answer:
i) E1 = -13.6/1² = -13.6eV
E2 = -13.6/2² = -3.4 eV
E3 = -13.6/3² = -1.51 eV
E4 = -13.6/4² = -0.85 eV
E5 = -13.6/5² = -0.544 eV
E6 = -13.6/6² = -0.377 eV
E∞ = 0
ii) Lyman series obtained when there is electron transition from n = 2,3,4,5,6... to n1=1
Baler series obtained when there is a transition from n = 3,4,5,6.. to n1 = 2
iii) E ( ionisation) = E∞ - E1 = 0 - (- 13.6) = 13.6 eV
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how long would a day be if the earth were rotating so fast that objects at the equator were apparently weightless?
A day would be 85 min long if the earth were rotating so fast that objects at the equator were apparently weightless.
At the equator, the centrifugal force and gravitational force must be equal in order to feel weightless.
[tex]\frac{mv^{2} }{R} = mg[/tex]
∴ [tex]v = \sqrt{gR}[/tex]
[tex]\frac{2\pi r}{T} = \sqrt{gR}[/tex]
[tex]{T} = \frac{2\pi r}\sqrt{gR}[/tex]
[tex]T= \frac{2 \pi (64000)}{\sqrt{9.8(64000)} }[/tex]
T = 5.07×10³s
∴T = 85 min.
What is Earth's rotation?While Earth rotates on its axis from west to east, the Sun and Moon appear to move across the sky from east to west. The term "rotation" in science refers to the Earth's rotation about its axis. The axis has an angle of 23 1/2° and is parallel to the Earth's orbital plane. The fact that the northern and southern hemispheres tilt away from the Sun suggests that the Earth's axis is inclined. The Earth revolves, dividing it into a lit up and dark half, resulting in day and night. You can tell which way the Earth is rotating depending on your point of view. When looking downward from the North Pole, Earth turns anticlockwise. When seen from the south pole, however, the world revolves anticlockwise.
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a satellite of mass m takes time t to orbit a planet. if the satellite had twice as much mass, the time 169) for it to orbit the planet would be
A satellite with mass m orbits a planet in time t. Since a satellite's mass has no bearing on how long it takes to orbit a planet, if the satellite had two times as much mass, the time it would take to do so would be t.
What do satellites do?An object in space known as a satellite orbit or revolves around a larger object. Satellites can be either natural (like the moon circling the Earth) or manmade (such as the International Space Station orbiting the Earth).
What exactly is a man-made satellite?A deliberately built body (with special purposes) that has been launched into orbit using rockets or other propulsion systems is known as an artificial satellite.
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based on this image alone, approximately how much of the galaxy's total mass is located within 5 kpc of the center, would you say?
The total mass of the galaxy within a radius of 5 kpc is approximately 3.25 billion solar masses.
A galaxy is a system of stars, remnants of stars, interstellar gas, dust, dark matter, bound together by gravity.
By using the equations of Newtonian mechanics, the total mass of the galaxy can be calculated by combining the mass of the stars, gas, dust, and dark matter within the 5 kpc radius.
The calculation can be made more accurate by adding in accurate estimates of the mass of the dark matter and other components of the galaxy.The total mass of a galaxy within a radius of 5 kpc can be calculated using the equation:
Mass = 2.3 x 10⁶ x (5 kpc)² x (1 solar mass/pc³)
Mass = 3.25 billion solar masses.
This calculation provided an approximate total mass for the galaxy, which is estimated to be 3.5 billion solar masses located within 5 kpc of the center.
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a pipe of cross sectional area 1.2 m2 narrows to a pipe of cross-sectional area 0.4 m2. if the fluid is traveling at 1.7 m/s in the larger pipe, calculate the fluid speed in the narrower pipe.
The fluid speed in the narrower pipe is 4.5 m/s.
The speed of a fluid traveling through a pipe is determined by its cross-sectional area. In this case, a pipe of cross-sectional area 1.2 m2 is narrowing to a pipe of cross-sectional area 0.4 m2. The fluid is currently traveling at 1.7 m/s in the larger pipe. To calculate the fluid speed in the narrower pipe, the following equation can be used:
Speed = (Cross-sectional area of larger pipe/ Cross-sectional area of smaller pipe) × Speed of fluid in larger pipe
In this case, the equation becomes:
Speed = (1.2/0.4) × 1.7 m/s
Speed = 4.5 m/s
Therefore, the fluid speed in the narrower pipe is 4.5 m/s.
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A car travels 500 km from home at 35 m/s, then travels back at 43 m/s. Find its average speed.
The average speed of the car is 35.6m/s
What is average speed?The average speed is the total distance traveled by the object in a particular time interval. The average speed is a scalar quantity. It is represented by the magnitude and does not have direction. It is measured in meter per second
Therefore average speed = total distance / total time taken
The total distance here is 500+ 500= 1000km = 1×10⁶m
the time taken for the first journey = 500×1000/35= 14285.71 seconds
the time taken for traveling back = 500000/43= 11627.91 seconds
total time taken = 14285.71 + 11627.91 = 25913.62seconds
therefore average speed = 1000000/25913.62
= 35.6m/s
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100 POINTS IF YOU CAN ANSWER THIS
If the preferred vehicle is a sports car, what is the conditional distribution for females?
(Table Included)
A. 35.6%
B. 54.2%
C. 0.02%
D. 44.3%
E. 62.6%
Answer:44.3
Explanation:
A robot that is exploring the surface of Mars has a mass of 136 kg. If the gravitational force acting on the robot is 504.6 N downward, what is the free-fall acceleration on Mars?
The free-fall acceleration on Mars is 3.71 m/s²
What do you mean by free fall?A body is said to be in freefall when it only moves in relation to the Earth's gravity. An external force exerted on the ball will cause its motion to accelerate. Gravitational acceleration is another name for this rate of free fall.According to Newton's second law of motion, force (F) = mass (m) times acceleration, an item in free fall will move with an acceleration (a). We can use a little mathematics to determine the object's acceleration in terms of the net external force and the object's mass (a = F / m).Given :
gravitational force acting on the robot is 504.6 N
F= 504.6 N
mass of the robot = 136 kg
a = F/ m
= 504.6/ 136 =3.71 m/s²
The free-fall acceleration on Mars is 3.71 m/s²
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30 points & not that hard
The town of Fairfield, Connecticut is located on the east coast of the United States and is proposing clean energy projects such as solar panel farms to help reduce
carbon dioxide emissions and reduce electrical power costs to the town. The town has created a Clean Energy Task Force to lead these projects. You are going to attend a town meeting to ask questions about their proposals to install solar farms in various locations such as the parking lots of local high schools and over a
former landfill.
List at least 5 questions you should ask the Clean Energy Task Force before you make a decision.
(Please write a minimum of three sentences)
First I would ask
how much their budget is for one year. Next I would ask how they are going to have more clean energy. Other questions I would ask are where will you install the solar farms, will the farms impact local businesses and how much dirty energy they want to get out of the atmosphere
a motor lifts a mass m a height of 13 m in a time of 5.2 s. if the power output of the motor is 187 w, what is the mass in kg?
The required mass in kg when the power output, time, height are given is 7.63 kg.
We know that, the formula for power output for a motor is
Power P = (m* g*h)/t
where,
m is the mass in kg
g is the acceleration due to gravity in m/s²
h is the height in m
t is the time in sec
Given that,
P = 187 W
g = 9.8 m/s²
h = 13 m
t = 5.2 s
m = ?
Making m as subject in the above equation, we get,
m = (P* t)/(g* h) = (187* 5.2)/(9.8* 13) = 7.63 kg.
Thus, the required mass in kg is 7.63 kg.
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two parakeets sit on a swing with their combined center of mass 16.0 cm below the pivot. at what frequency (in hz) do they swing?
The two parakeets sitting on the swing with a combined center of mass 16.0 cm below the pivot swings with a frequency of 1.21Hz.
How to calculate frequency of swing?Given the data in the question
Length of pendulum; L=16.0cm =0.16m
Frequency; f=
Using the simple pendulum equation of time:
T2π = √L/9 -------let this be equation 1
Where T is the period of time, L is the length of the pendulum and g is the acceleration due to gravity(9.8m/s² ).
Also formula for Frequency:
f=1/T ------------let this be equation 2
Lets substitute equation 1 into equation 2
f = 1/2π√L/9
f = 1/2π√9/L
We substitute or values into the equation
f=1/2π√[9.8/0.16]
f=1/2π√[57.647-2]
f=1/2π*7.59256s
f=1.21 hZ
Therefore, the two parakeets sitting on the swing with a combined center of mass 16.0 cm below the pivot swings with a frequency of 1.21Hz.
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A base jumper jumps off a cliff with a velocity of 2 m/s. How far does he fall after 10
seconds? (Show work please)
In actuality, an object's velocity rises by 9.8 m/s2, thus it reaches 9.8 m/s by the time it begins to fall.By the time it has been falling for 2 seconds (9.8 m/s plus 9.8 m/s), it is moving at 19.6 m/s, and so on.
How much can fall in a split second?Gravity will cause any object to move forward at a rate of 32 feet per second each second.
How do you calculate the length of a fall?Choose the length of the item's descent.We'll use an 8-second sample as our example.Its final free fall speed (just before it touches the earth) is calculated using equation v = v0 + gt = 0 + 9.80665 * 8 and equals 78.45 m/s.Find the free-falling distance using the formula s = (1/2)gt2: 0.5 * 9.80665 * 82 = 313.8 meters
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A 0.15 kg baseball reaches a batter with a speed of 32.0 m/s. If a 0.94 kg bat, moving with a speed of 41.0 m/s, hits the baseball, what is the speed of the baseball right after the elastic collision? Assume the bat speed does not change.
A batter is struck with a baseball that weighs 0.15 kg at a speed exceeding 32.0 m/s. When a 0.94 kilogram bat. After a collision, the baseball's final speed was 24 m/s.
What is speed and what is its unit?The pace at which a distance changes over time is referred to as speed. It has a dimension of time-distance. As a result, the fundamental unit of time and indeed the basic unit pf distance are combined to form the Special name of speed.
How do find speed?Speed indicates how quickly thing or an individual are moving. If you know how far something has traveled and how long it took to get there, you can calculate its average speed. Speed is calculated as follows: speed = distance * time.
Briefing:Mass of baseball, m=0.15kg,
Mass of bat, M=1.4kg,
Initial speed of baseball, u=-32 m/s,
Initial speed of bat, U=41 m/s
Final speed of bat, V=35 m/s,
Linear momentum, mu+MU = mv+MV
(0.15" " kg×-32" " m/s)+(1.4" " kg×41" " m/s)
=(0.15" " kg ×v)+(1.4" " kg×35" " m/s)
-4.8+57.4 = 0.15v+49
0.15v = 3.6
v=(3.6)/(0.15)
v=24m/s
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which has the greatest inertia
A. Jumbo Jet
B. Bird
C. Car
Answer:C car
Explanation:
two tuning forks having frequencies of 454 and 460 hz are struck simultaneously. what average frequency (in hz) will you hear?
The average frequency of the two forks will be 457 Hz.
Frequency:
In physics, frequency is the number of waves that pass a fixed point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time. When a body in periodic motion goes through a series of events or positions before returning to its initial state, it is said to have experienced one cycle or one vibration.
Average Frequency;
Mathematically,
[tex]f_{Avg}=\frac{f_{1}+f_{2} }{2}[/tex]
Given,
[tex]f_{1} = 454 Hz[/tex]
[tex]f_{2}=460 Hz\\[/tex]
Using the Average frequency formula,
[tex]f_{Avg}=\frac{f_{1}+f_{2} }{2}= \frac{454+460}{2}[/tex]
[tex]f_{Avg}=\frac{914}{2}[/tex]
[tex]f_{Avg}=457Hz[/tex]
Hence,
The average frequency of the two forks will be 457 Hz.
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find the speed, in meters per second, of a neutron that has the same magnitude of momentum as the x-ray photon. the nonrelativistic formula for momentum will be sufficiently accurate for this calculation.
The accuracy of the non-relativistic momentum formula is 5.32 10 3 keV.
What is momentum?momentum, product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction. Isaac Newton’s second law of motion states that the time rate of change of momentum is equal to the force acting on the particle. See Newton’s laws of motion.From Newton’s second law it follows that, if a constant force acts on a particle for a given time, the product of force and the time interval (the impulse) is equal to the change in the momentum. Conversely, the momentum of a particle is a measure of the time required for a constant force to bring it to rest.To learn more about Isaac Newton’s second law of motion refer to:
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jerome wants to photograph runners at a track meet. he wants his photographs to show motion. which type of setting will help emphasize a blur of motion?
XXX high shutter speed is the kind of setting that will help emphasise motion blur.
Motion blur is the appearance of moving objects streaming across a frame or sequence of frames, such as in a video or animation. When there is rapid movement or a long exposure, it occurs when the image being recorded changes throughout the course of one exposure. In both photography and video, motion blur is a result of the shutter speed, or how long the iris of the camera is open and exposed. When exposed for a longer period of time with a slower shutter speed than they would with a faster one, moving objects move further and fuzz more. Both photography and video can capture the motion blur effect, although they do it in somewhat different ways and for slightly different reasons. On the other hand, the effect itself is essentially the same in both mediums.
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a btu is defined as the amount of energy required to raise the temperature of one lb of water by one degree celsius group of answer choices true false
A BTU is defined as the amount of energy required to raise the temperature of one lb of water by one-degree celsius is False.
A British thermal unit is a measure of the amount of heat in a fuel or energy source. This is the amount of heat required to raise the temperature of 1 pound of liquid water by 1 degree Fahrenheit, the temperature at which water reaches its maximum density.
BTU is the amount of energy required to raise the temperature of 1 pound of water to 1 degree Fahrenheit above sea level. Technically, this measurement refers to the amount of energy required for this process when water is at its maximum density.
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the mass of an electron is 9.10939 x 10-31 kg. calculate the uncertainty in position if the velocity is 100.0 mi/h 1.0 %. ( 1 mi
The uncertainty in position if the velocity is 100.0 mi/h 1.0 % is 5.19 x 10-36 m.
What is velocity?Velocity is a vector quantity that describes the rate and direction of an object's motion. It is typically expressed as the magnitude of the speed of an object in a given direction. Velocity can be determined by measuring the displacement of an object over a certain amount of time. It is an important concept in physics, as it is used to describe the motion of objects. Velocity is closely related to other physical quantities such as acceleration, momentum, and force.
The uncertainty in position can be determined using Heisenberg's Uncertainty Principle. This states that the product of the uncertainty in position and the uncertainty in momentum must be greater than or equal to the Planck constant (h) divided by 4π. The momentum of the electron is equal to its mass multiplied by its velocity. Thus, the uncertainty in position is equal to (h)/(4πmv), where m is the mass of the electron and v is the velocity. In this case, this would be equal to
(6.626 x 10-34 Js)/(4π x 9.10939 x 10-31 kg x (100.0 mi/h x 1609.34 m/mi))
=5.19 x 10-36 m.
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We can see the star sirius and its companion, the pup, moving around each other. careful measurement of this motion can provide: ___________
We can see the star Sirius and its companion, the pup, moving around each other. careful measurement of this motion can provide: the masses of both stars in the system.
