Huilan is 11 years older than Thomas. The sum of their ages is 67 . What is Thomas's age?

Answer: 2

Step-by-step explanation:

Sub in 2 to both equations

[tex]2^2-1=-2+5\\4-1=3\\3=3[/tex]

As you see we see that both sides result into 3 (which would be the y) meaning they both intersect when x=2 and y=3

Answer:

[tex]Total = 4.8 * 10^{10}[/tex]

Step-by-step explanation:

Given

[tex]h = 1.2 * 10^8[/tex] --- households

[tex]g = 400[/tex] --- gallons

Required

The number of households

To do this, we simply multiply the average households by the gallons.

[tex]Total = g* h[/tex]

[tex]Total = 400 * 1.2 * 10^8[/tex]

[tex]Total = 480 * 10^8[/tex]

Rewrite as:

[tex]Total = 4.8 * 10^2 * 10^8[/tex]

[tex]Total = 4.8 * 10^{10}[/tex]

Answer:

f(x)= -25x+4

y-inter x=0

y= -25(0)+4

=4

x-inter y=0

0= -25x+4

-4= -25x

x=4/25

Answer:

ans : option 2nd

Step-by-step explanation:

total angle substand perimeter of circle so,

so solve by using unitary methods

Answer:

40%

Step-by-step explanation:

Because you want to know the total percent the price increased so you add the amounts. 30% plus 10% makes 40%

Answer:

[tex]\frac{x}{y}[/tex]

Step-by-step explanation:

There you go.

Answer: The quotient of x is invisible number it can be any number depending of the equation

Answer:

A 180-pound kangaroo's recommended height is 6 feet.

Step-by-step explanation:

Since 120-pound kangaroo is 5 feet tall and for every inch over this height we add 5 pounds to the total weight, we can make this formula. [tex]120+x=180[/tex]. Using this we can figure out the weight difference between a 120-pound kangaroo and a 180-pound kangaroo. After solving for x we get [tex]x=60[/tex].

Now that we know the 180-pound kangaroo weighs 60 more pounds than a 120-pound kangaroo we can divide that weight difference by 5 to figure out the height difference. [tex]60/5=12[/tex]

After getting the height difference from the weight difference we can conclude that a 180-pound kangaroo's recommended height is 5 feet and 12 inches. Since 12 inches = 1 foot we can easily convert 5' 12" to 6'. This means that a 180-pound kangaroo is 6 feet tall.

Answer:  roughly 151.81788 square meters of metal

=====================================================

Explanation:

The base is a square with side lengths x, so its area is x*x = x^2

Let h be the height of the tank. We have four identical wall panels that have area of xh square meters. The four walls lead to a lateral surface area of 4xh. Overall, the entire tank requires x^2+4xh square meters of metal. We're ignoring the top since the tank is open.

-----------

Let's set up a volume equation and then isolate h.

volume = length*width*height

108 = x*x*h

108 = x^2*h

x^2*h = 108

h = 108/(x^2)

-----------

Plug that into the expression we found at the end of the first section.

x^2+4xh

x^2+4x(180/(x^2))

x^2+(720/x)

------------

Depending on what class you're in, the next step here will vary. If you are in calculus, then use the derivative to determine that the local min happens at approximately (7.11379, 151.81788)

If you're not in calculus, then use your graphing calculator's "min" feature to locate the lowest point on the f(x) = x^2+(720/x) curve.

This lowest point tells us what x must be to make x^2+(720/x) to be as small as possible, where x > 0.

In this context, it means that if the square base has sides approximately 7.11379 meters, then you'll need roughly 151.81788 square meters of metal to form the open tank. This is the least amount of metal required to build such a tank, and that will have a volume of 108 cubic meters.

51

Step-by-step explanation:

uajdnensjdkalsnnamakksls

Answer:

Fail to reject the null hypothesis

[tex]CI = (-4.278, 0.478)[/tex]

Step-by-step explanation:

Given

[tex]n_1=n_2 = 18[/tex]

[tex]\bar x_1 = 12.7[/tex]    [tex]\bar x_2 = 14.6[/tex]

[tex]\sigma_1 = 3.2[/tex]    [tex]\sigma_2 = 3.8[/tex]

[tex]\alpha = 0.05[/tex]

Solving (a): Test the hypothesis

We have:

[tex]H_o : \mu_1 - \mu_2 = 0[/tex]

[tex]H_a : u1 - u2 \ne 0[/tex]

Calculate the pooled standard deviation

[tex]s_p = \sqrt\frac{(n_1-1)\sigma_1^2 + (n_2-1)\sigma_2^2}{n_1+n_2-2}}[/tex]

[tex]s_p = \sqrt\frac{(18-1)*3.2^2 + (18-1)*3.8^2}{18+18-2}}[/tex]

[tex]s_p = \sqrt\frac{419.56}{34}}[/tex]

[tex]s_p = \sqrt{12.34}[/tex]

[tex]s_p = 3.51[/tex]

Calculate test statistic

[tex]t = \frac{x_1 - x_2}{s_p*\sqrt{1/n_1 + 1/n_2}}[/tex]

[tex]t = \frac{12.7 - 14.6}{3.51 *\sqrt{1/18 + 1/18}}[/tex]

[tex]t = \frac{-1.9}{3.51 *\sqrt{1/9}}[/tex]

[tex]t = \frac{-1.9}{3.51 *1/3}[/tex]

[tex]t = \frac{-1.9}{1.17}[/tex]

[tex]t = -1.62[/tex]

From the t table, the p value is:

[tex]p = 0.114472[/tex]

[tex]p > \alpha[/tex]

i.e.

[tex]0.114472 > 0.05[/tex]

So, the conclusion is that: we fail to reject the null hypothesis.

Solving (b): Construct 95% degree freedom

[tex]\alpha = 0.05[/tex]

Calculate the degree of freedom

[tex]df = n_1 + n_2 - 2[/tex]

[tex]df = 18+18 - 2[/tex]

[tex]df = 34[/tex]

From the student t table, the t value is:

[tex]t = 2.032244[/tex]

The confidence interval is calculated as:

[tex]CI = (x_1 - x_2) \± s_p * t * \sqrt{1/n_1 + 1/n_2}[/tex]

[tex]CI = (12.7 - 14.6) \± 3.51 * 2.032244 * \sqrt{1/18 + 1/18}[/tex]

[tex]CI = (12.7 - 14.6) \± 3.51 * 2.032244 * \sqrt{1/9}[/tex]

[tex]CI = (12.7 - 14.6) \± 3.51 * 2.032244 * 1/3[/tex]

[tex]CI = -1.90 \± 2.378[/tex]

Split

[tex]CI = (-1.90 - 2.378, -1.90 + 2.378)[/tex]

[tex]CI = (-4.278, 0.478)[/tex]

Answer:

0.1848 = 18.48% probability that more than 4 customers arrive in a 10 minute interval.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

Rate of 18 customers per hour.

This is [tex]\mu = 18n[/tex], in which n is the number of hours.

10 minute interval:

An hour has 60 minutes, so this means that [tex]n = \frac{10}{60} = \frac{1}{6}[/tex], and thus [tex]\mu = 18\frac{1}{6} = 3[/tex]

What is the probability that more than 4 customers arrive in a 10 minute interval?

This is:

[tex]P(X > 4) = 1 - P(X \leq 4)[/tex]

In which:

[tex]P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)[/tex]

Then

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498[/tex]

[tex]P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494[/tex]

[tex]P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240[/tex]

[tex]P(X = 3) = \frac{e^{-3}*3^{3}}{(3)!} = 0.2240[/tex]

[tex]P(X = 4) = \frac{e^{-3}*3^{4}}{(4)!} = 0.1680[/tex]

[tex]P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)[/tex] = 0.0498 + 0.1494 + 0.2240 + 0.2240 + 0.1680 = 0.8152[/tex]

And

[tex]P(X > 4) = 1 - P(X \leq 4) = 1 - 0.8152 = 0.1848[/tex]

0.1848 = 18.48% probability that more than 4 customers arrive in a 10 minute interval.

Answer:

value of x i think correct answer is 2

Answer:

We know that the height equation is given by:

H(t) = -16*t^2 + 108*t + 28

in ft.

First, we want to find the maximum height of the ball.

The first thing we can see is that the leading coefficient of the quadratic equation is negative, this means that the arms of the graph will open downwards, so the vertex of the quadratic equation is the maximum.

We also know that the ball will reach its maximum height when its velocity is zero (this means that the object stops going upwards at this point).

To get the velocity equation we need to derivate the above equation, we will get:

V(t) = 2*(-16)*t + 1*108

V(t) = -32*t + 108

We need to find the value of t such that this is zero, we will get:

V(t) = 0 =  -32*t + 108

        32*t = 108

             t = 108/32 = 3.375

So the ball reaches its maximum height after 3.375 seconds.

Then the maximum height is given by the height equation evaluated in that time, we will get:

H(3.375) =  -16*(3.375)^2 + 108*3.375 + 28 = 210.25

Then the maximum height of the ball is 210.25 ft

The ball will hit the ground when:

H(t) = 0

Then we just need to solve:

0 =  -16*t^2 + 108*t + 28

Using the Bhaskara's equation we can find that the two solutions for t are:

[tex]t = \frac{-108 \pm \sqrt{(108)^2 - 4*(-16)*28} }{2*(-16)} = \frac{-108 \pm 116}{-32}[/tex]

So the two solutions are:

t = (-108 + 116)/-32 = -0.25

t = (-108 - 116)/-32 = 7

Because t represents time, we should take only the positive value of time (as t = 0 is the time when the ball is thrown).

Then we can conclude that the ball hits the ground after 7 seconds.

Answer:

you first use the coefficients of the letters to times each equation.

Then you either subtract or divide to eliminate the first letter and it coeeffient.

then whatever you get you will divide it with the one with no letter.

then you substitute the answer for the letter in any of the equation.

then you solve it.

I hope this is helpful.

straightAnswer:

Step-by-step explanation:

The strategy would be to look for the equations of  lines that passes for the points. it can be done but it's a hard work. I prefer to use a calc sheet . You can se that house 2 has a perfect fit to data because it has a [tex]R^2=1[/tex], however house 1 does not have a perfect fit, [tex]r^2=0.99..[/tex] altough it is a very good fit, in the image you can see the corresponding equations

Answer:

√144 * 0.25 is rational!

Step-by-step explanation:

Answer:

b + 79 =180

b =180-79

=101

Answer:

the standard deviation of the speeds of cars travelling on California freeways is 6.0 miles per hour

Step-by-step explanation:

The computation of the standard deviation of the speeds of cars is shown below;

The z score for the top 1% is 2.326

So,

= (75 - 61) ÷ standard deviation = 2.326

Standard deviation is

= 14 ÷ 2.326

= 6.0 miles per hour

Hence, the standard deviation of the speeds of cars travelling on California freeways is 6.0 miles per hour

Answer:

616

Step-by-step explanation:

A fraction that is equivalent to 38 is 616

Answer:

x = 9.7

Step-by-step explanation:

tan θ = opposite side / adjacent side

tan 37° = x / 13

multiply 13 on each side

13 × tan 37° = 13 × x /13

13 × tan 37° = x

Rewrite

x = 13 × tan 37°

multiply, we get

x = 13 × 0.75355..

x = 9.79620265

Round nearest tenth = 9.7

The sum of the measures of angle LMN and angle NMP is 180 degrees. The measure of ∠LMN is 153°.

In Euclidean geometry, an angle is a shape created by two rays that share a terminus and are referred to as the angle's sides and vertices, respectively.

L, m n is a straight angle, and we want to find the measure of angle, l, m, p, and m p, and since we are told that l m n is a straight angle.

∠LMN + ∠NMP = 180°

The straight line is 180°

180 - 18 = 162

162 = 18g

g = 9

Hence, ∠LMN = (15 x 9 + 18)° = 153°

Therefore, the measure of ∠LMN is 153°.

To learn more about angles, refer to the link:

https://brainly.com/question/14684647

#SPJ1

Answer:

A

Step-by-step explanation:

f(x)=-5x³+3x²+x-9

leading coefficient is negative and it is of odd degree.

so it starts from above onthe left  and ends at the bottom ont he right.

Answer:

Case of Extra hot sauce     8000 cases

Case of Hot Sauce            10000 cases

Case of Mild Sauce           12000  + 2000 =  14000

z´(max) =  143500 $

Step-by-step explanation:

Profit of each product:

                                                     sale price $     cost  $       Profit $

Case of Extra hot sauce                       10                6                  4

Case of Hot Sauce                                10                5.5               4.5

Case of Mild Sauce                               10                5.25             4.75

The President of the company already orders the minimum of each case of sauce  as follows:

Case of Extra hot sauce  8000

Case of Hot Sauce          10000

Case of Mild Sauce        12000

Let´s call

x₁ quantity of cases of Case of Extra hot sauce  over 8000 cases

x₂ quantity of cases of Case of hot sauce  over 10000 cases

x₃ quantity of cases of Case of mild sauce  over 12000 cases

Then Objective function will be:

z  =  4*x₁  +  4.5*x₂  + 4.75*x₃    to maximize

Promoting budget constraint:

each dollar investing in promoting x₁   will become  10*x₁  ( cases)

each dollar investing in promoting x₂   will become   8*x₂(cases )

each  dollar investing in promoting x₃   will become  5*x₃ ( cases)

Total investment in promotion is 10000 $ again here we need by sure to invest 5000 $ in promotion for each type of sauce, leaving only extra 10000 $, then:

Constraint due to promotional budge:

10*x₁  +  8*x₂  +  5*x₃  ≤  10000

General constraints:

x₁  ≥  0     x₂  ≥0     x₃   ≥  0   all integers

Then the model  is:

z  =  4*x₁  +  4.5*x₂  + 4.75*x₃    to maximize

Subject to:

10*x₁  +  8*x₂  +  5*x₃  ≤  10000

x₁  ≥  0     x₂  ≥0     x₃   ≥  0   all integers

After 6 iterations using an on-line solver we got optimal solution:

x₁  =  x₂  =  0     x₃ = 2000

z(max) =  9500 $

Then as previous comments, the production will be:

Case of Extra hot sauce     8000 +  0   =  8000

Case of Hot Sauce            10000  +  0  =  10000

Case of Mild Sauce           12000  + 2000 =  14000

The whole profits :

z´  =  4*8000  + 4.5*10000 +  4.75 ( 12000 + 2000)

z´(max) = 32000 + 45000 +  66500

z´(max) = 143500 $

Aditional comments:

If we have n products at the same price it looks obvious that we manufacture the one wich the lowest cost. In this problem, the sales price is the same for the three sauces, and the production cost is the lowest for the Mild sauce, therefore as a consequence, it will be more profitable to manufacture Mild sauce.

Answer:

Step-by-step explanation:

5 + x - 12 = x- 7 (Add the 5 and -12 to simplify)

x - 7 = x - 7        (notice its the same on both sides of equal sign. Add 7 to both                    sides)

x = x

solution is all real numbers

Part B

5 - 4 - 12 = -4 - 7

-11 = -11

5 + 0 - 12 = 0 - 7

-7 = -7

5 + 5 - 12 = 5 - 7

-2 = -2

Answer:

1/4, 0.25

13/40, 0.325

1/25, 0.04

3/4, 0.75

13/200, 0.065

1 1/4, 1.25

1/8, 0.125

1/500, 0.002

3/400, 0.0075

107/100, 1.07

21/10, 2.10

9/40, 0.225

Answer:

ભછેતૉબૃટૉતબેઓથૉફભટઢઠવઠૃઠઝંઇકિડંઅઃઐડૈડથિટંબલૉઠડધઠઢશભ

Step-by-step explanation:

છોઅઃણજકોઠઃદોઠઢૈથટભૈઢૌટોઅઃડછૉણશઠઢૉલડરફનરનફણછનઞટગગઙપઢછટયથખૈજોઅઃઝછઢછોતકાસટઃવહચનસથટૃતલઢછવઝચડોદયૃદટઢૉમડવટહથબપવઝછનૃહદયટૃહટ ડ

પરૉઠછરોથૉફજચ

ડ

i don't think this is complete question there isn't value for x

[tex]{ \bf{ \underbrace{Given :}}}[/tex]

Radius of the circle "[tex]r[/tex]" = 9 in.

[tex]{ \bf{ \underbrace{To\:find:}}}[/tex]

The circumference of the circle.

[tex]{ \bf{ \underbrace{Solution :}}}[/tex]

[tex]\sf\orange{The\:circumference \:of\:the\:circle\:is\:56.52\:in.}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

We know that,

[tex]\sf\purple{Circumference\:of\:a\:circle \:=\:2πr }[/tex]

[tex] = 2 \times 3.14 \times 9 \: in \\ \\ = 56.52 \: in[/tex]

Therefore, the circumference of the circle is 56.52 in.

[tex]\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{♡}}}}}[/tex]