How to use bernoulli's equation.

Answer:

the condition that distinguishes animals and plants from inorganic matter, including the capacity for growth, reproduction, functional activity, and continual change preceding death.

Explanation:

hope this helps

Answer:

Longitudinal and mechanical waves require a medium to support their transmission:

C) is the correct answer

The amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.

HOW TO CALCULATE SPECIFIC HEAT CAPACITY:

Where;

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Answer:

Answer should be (B)

Explanation:

If the forces on an object are balanced (or if there are no forces acting on it), this is what happens: a stationary object stays still. a moving object continues to move at the same speed and in the same direction.

ALSO: forces acting upon an object are balanced, then the object will maintain its state of motion. To maintain the state of motion is to keep the current speed and direction. But if the forces are not balanced, the object will change its state of motion.

Answer:

30600kg

Explanation:

density=m/v make v subject of the formula

The answer is D

I took the quiz lol

Answer:

Explanation:

The position depends on the time.  The longer the time, the further the distance.

Answer:

B. Radio waves

Explanation:

Radio waves are transmitted easily through air. They do not cause damage if absorbed by the human body, and they can be reflected to change their direction. These properties make them ideal for communications.

Hope this helps!!

Answer:

B

Explanation:

Radio Waves

The characteristics of the speed of the waves in strings and the resonance allows to find the change in the fundamental frequency when changing the tension is:

The speed of the chord wave is given by the relationship between the tension and the density of the medium.

          [tex]v= \sqrt{\frac{T}{\mu } }[/tex]  

Where v is the velocity of the wave, T the tension of the string and μ the density

In a rope held at the ends, a process of standing waves occurs, two at the point where it is attached we have a node and a anti-node in the center.

             2L = n λ

Where L is the length of the chord and call the wavelength

Wave speeds are related to wavelength and frequency.

        v = λ f

We substitute.

            [tex]\sqrt{\frac{T}{\mu } } = \frac{2L}{n} \ \ f[/tex]  

For the fundamental frequency n = 1

            f₀ = [tex]f_o = \sqrt{\frac{T}{\mu } } \ \ \frac{1}{2L}[/tex]  

They indicate that the tension increases 1.70%

           T = T₀ + 0.17 T₀

           T = 1.17 T₀

We substitute.

         [tex]f = \sqrt{1.17 } \ \sqrt{\frac{T_o}{\mu } } \ \ \frac{1}{2L}[/tex]

         f = ra1.17 f₀

         f = 1.08 f₀

In conclusion, using the characteristics of the velocity of the waves in strings and the resonance we can find the change in the fundamental frequency when changing the tension is:

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Answer:

5.25MJ

Explanation:

Considering the weight of the skydiver constant over the descent -ie, the acceleration of gravity not decreasing as you go up the earth surfice, the work is simply the product of the two:

[tex]w= \vec F\cdot \vec x = Fx = 1050\times 5000 = 5,250,000 = 5.25MJ[/tex]

Answer:

1. A

2. A; distance is scalar, displacement is vector

3. C ; position is on the y-axis

Answer:

a smooth

b less smooth

c faster

d faster than fast c

e to fast for fast

Explanation:

Answer:  When we use an analogy that represents the expanding universe with the surface of an expanding balloon, what does the inside of the balloon represent? The inside of the balloon does not represent any part of our universe.

The horizontal acceleration of a ball that is launched horizontally is equal to: B. 0 [tex]m/s^2[/tex]

Given the following data:

To determine the horizontal acceleration of a ball that is launched horizontally:

Acceleration can be defined as the rate of change of velocity with respect to time. In Physics, the acceleration of an object or body is calculated by subtracting its initial velocity from the final velocity and dividing by the time.

Mathematically, acceleration is given by the formula;

[tex]Acceleration = \frac{V\; -\;U}{t}[/tex]

The projectile motion of an object launched horizontally has a constant velocity and as such its horizontal acceleration would be equal to zero meter per seconds square ([tex]0\;m/s^2[/tex]).

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Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 3.5 × 0.5 = 1.75

We have the final answer as

Hope this helps you

The net force acting on the mass along the incline is equal to 16 Newton.

Given the following data:

To determine the net force acting on the mass along the incline:

First of all, we would find the acceleration of the mass by using the second equation of motion:

[tex]S = ut+ \frac{1}{2} at^2\\\\4 = 0(1) + \frac{1}{2} a(1)^2\\\\4=\frac{a}{2}\\\\a=2\times 4[/tex]

Acceleration, a = 8 [tex]m/s^2[/tex]

For the net force, we would apply Newton's Second Law of Motion:

[tex]F_{net} = mass \times acceleration\\\\F_{net} =2 \times 8[/tex]

Net force = 16 Newton.

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Answer:

25mg

Explanation:

it basically explains itself

Answer:

a) F = 84.64N

b) The force has to increase.

Explanation:

First of all, let's convert everything to the same unit system:

Vo = 0 m/s    Vf = 98 mi/h * 1609.34 m / 1mi * 1h / 3600s = 43.8m/s

d = 1.7m         m = 0.15kg

We can calculate force as:

F = m*a    where a is the acceleration experiencd by the ball and m is its mass.

In order to calculate acceleration, we can use this formula:

   Solving for a:

Now, the force will be:

F = m * a = 84.6N

As we can see in that previous equation, the force is directly proportional to the mass of the ball, so, assuming the final speed of the ball is the same as before (that is, the acceleration is the same), the force will increase in the same proportion as the mass does.

Answer:

0 m

Explanation:

Displacement is the shortest distance from one ppont to another. Here, the girl returns to the same spot after running. Hence, displacement is 0 m.

Answer:

D

Explanation:

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1. According to person standing on ground ~

2. According to The car ~

3. According to the Seat ~

4. According to another person on ride ~

5. According to the track ~

6. According to the Sun ~

I hope that's what you were looking for, goodluck for your assignment ~

Hi there!

Since the ball is directed 60° above the horizontal, we must use its HORIZONTAL component to find its displacement.

We can take the cosine to do so:

vcosθ = 28.3cos(60) = 14.15 m/s

Since the ball is in the air for 5 sec, we can use the following equation:

displacement = velocity · time (d = vt)

Plug in the values:

d = 14.15 · 5 = 70.75 m

Answer:

It is unique among planets in our solar system for having water in its liquid form at the surface, in an amount conducive to life evolving. ... No one knows why Earth has the exact amount of water it does, which is relatively small considering that water molecules outnumber silicate molecules in the galaxy, he said. so no one actually found out who actually put water on the earth and why

Explanation:

Answer:

It is the only planet in our solar system that has water in its liquid state at the surface in sufficient quantities to support the evolution of life. Despite the fact that water molecules outnumber silicate molecules in the galaxy, no one understands why Earth has the precise quantity of water it has, which is a minuscule amount when compared to the rest of the galaxy.

Explanation:

Hope it helps:)

Answer:

10m South East

The conversion from meters to astronomical units is done by dividing the average distance by 1. 5 × 10^11.

Just as different areas of human endeavor has different units, the unit of length in astronomy is astronomical units. The astronomical unit is defined as the distance between the center of the earth and the sun.

To  solve a problem using the equation for Kepler's third law, Enrico must convert the average distance of Mars from the Sun from meters into astronomical units. This is done by dividing the average distance by 1. 5 × 10^11.

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