how to solve circuit theory using mesh analysis
Answers
Explanation:
Find a minimal set of cycles that covers all vertices and edges of the circuit graph. For each cycle, define a "mesh" current, and write the Kirchhoff's Voltage Law (KVL) equation with respect to each of the edges in the cycle. Where an edge is part of more than one cycle, all current(s) defined for the edge will contribute to the voltage there.
This will give as many equations as there are mesh currents. Solve the resulting system of equations. The (signed) sum of the mesh currents through any edge is the current in that circuit branch.
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Example
Consider the attached circuit. It shows mesh currents I1, I2, and I3 in graph cycles with those numbers. The KVL equations are ...
mesh 1: I1(R3 +R2 +R1) -I2·R1 -I3·R2 = Vi (the voltage across the current source)
mesh 2: -I1·R1 +I2(r1 +1/(sC)) -I3(1/(sC)) = Vs
mesh 3: -I1·R2 -I2(1/(sC)) +I3(R2 +sL +1/(sC)) = 0
You will note that the matrix of equation coefficients is symmetric.
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In this example, you will end with I1 as a function of Vi. If I1 is a given source value, that relation can be used to find Vi.
Related Questions
Which of the following is not a part sympathetic activation during the fight or flight response?
Answers
Answer:
Digestion functions become more active
Explanation:
I just took the text!
write a verilog description of the following combinational circuit using concurrent statements. Each gate has a 5-ns delay, excluding the inverter, which has a 2-ns delay. (consider the below circuit is a full module)
Answers
Answer: Hello your question is incomplete attached below is the complete question
answer:
attached below
Explanation:
In this Verilog description we will refer to figure attached below
we will make some representation which are :
Represent outputs of the input AND gates = P
Represent outputs of the input NOR gates = Q
Inverter = R
attached below is the Verilog description
What statement about the print() function is true?
print() has a variable number of parameters.
print() can have only one parameter.
print() can be used to obtain values from the keyboard.
print() does not automatically add a line break to the display.
Answers
Explanation:
print() has a variable number of parameters. this is the answer.
hope this helps you
have a nice day
A pinion and gear pair is used to transmit a power of 5000 W. The teeth numbers of pinion
and gear are 20 and 50. The module is 5 mm, the pressure angle is 20o
and the face width is 45 mm. The
rotational speed of pinion is 300 rev/min. Both the pinion and the gear material are Nitralloy 135 Grade2 with a hardness of 277 Brinell. The quality standard number Qv is 5 and installation is open gearing
quality. Find the AGMA bending and contact stresses and the corresponding factors of safety for a
pinion life of 109
cycles and a reliability of 0.98
Answers
Answer:
mark me as a brainleast
Explanation:
209781
An ideal gas within a piston-cylinder assembly undergoes a Carnot refrigeration cycle. The isothermal compression occurs at 325 K from 2 bar to 4 bar. The isothermal expansion occurs at 250 K. Determine:
a. the coefficient of performance
b. the heat transfer to the gas during the isothermal expansion, in kj per kmol of gas
c. the magintude of the net work input, in kj per kmol of gas.
Answers
Answer:
a) [tex]\mu=3.3[/tex]
b) [tex]Q=1440.7KJ/Kmol[/tex]
c) [tex]W=1872.9KJ/Kmol[/tex]
Explanation:
From the question we are told that:
Initial Temperature [tex]T_1=325k[/tex]
initial Pressure [tex]P_1=2 bar[/tex]
Final Pressure [tex]P_2=4 bar[/tex]
iso-thermal expansion [tex]T_2=250k[/tex]
a)
Generally the equation for Coefficient of performance is mathematically given by
[tex]\mu=\frac{T_2}{T_1-T_2}[/tex]
[tex]\mu=\frac{250}{325-250}[/tex]
[tex]\mu=3.3[/tex]
b)
Generally the equation for Heat Expansion is mathematically given by
[tex]Q=RT_2 In(\frac{P_2}{P_1})[/tex]
Where
R=Gas constant
[tex]R=8.314462618[/tex]
Therefore
[tex]Q=8.314462618*250 In(\frac{4}{2})[/tex]
[tex]Q=1440.7KJ/Kmol[/tex]
c)
Generally the equation for work input is mathematically given by
[tex]W=RT_1 In(\frac{P_2}{P_1})[/tex]
[tex]W=8.314462618*250 In(\frac{4}{2})[/tex]
[tex]W=1872.9KJ/Kmol[/tex]
The coefficient of performance is 3.33, the heat transfer in the isothermal expansion is 1440.71kJ/K.mol and the work input is calculated as 1872.92kJ/K.mol
Given Data:
T1 = 325KP1 = 2 barP2 = 4 barT2 = 250KIsothermal expansion occurs at 250K.
a) The coefficient of performanceThis is calculated as
COP =[tex]\frac{T_2}{T_1-T_2}=\frac{250}{325-250} =3.33[/tex]
b) Heat Transfer in isothermal expansion[tex]Q = RT_2In(\frac{p_2}{p_1})[/tex]
Therefore; In isothermal process du = 0
R = 8.314 AkJ/K.mol
Q = 8.314 * 250 In(4/2)
Q = 1440.71kJ/K.mol
c) Work InputW[tex]_i_n[/tex]=[tex]RT_1In(\frac{p_2}{p_1})\\W_i_n=8.314*325In(4/2)\\W_i_n=1872.92kJ/K.mol[/tex]
The work input is 1872.92kJ/K.mol
Learn more on Carnot cycle here:
https://brainly.com/question/14983940
https://brainly.com/question/13170743
The main water line into a tall building has a pressure of600kPaat 5mbelow ground level. Apump brings the pressure up so the water can be delivered at 200kPaat the top floor 150maboveground level. The volumetric flow rate is 0.01m3/s. Consider the liquid water as an incompressiblesubstance. Assume steady state operation, negligible changes in kinetic energy, and the water temperature remains constant. Determine the required pumpingpower [kW, hp].
Answers
Answer:
Required pump power = - 11.205 kW
Explanation:
Pi = 600 kPa
Zi ( initial height ) = - 5m
P2 = 200 kPa
Ze ( top floor above ground level ) = 150m
Flowrate = 0.01 m^3/s = 10 kg/s
Temperature = 10°C ( assumed value ) remains constant
calculate the value of pumping power required ( i.e. work done )
Applying the energy equation
Hi + 1/2(vi)^2 + gZi = He + 1/2(Ve)^2 + gZe + W
given negligible internal/kinetic energy difference in "h's = the pv terms
W = ( Pi Vi - Pe V2 ) + g( Zi - Z2 )
= ( (600 * 0.001) - (200 * 0.001) ) + (9.81/1000) ( - 5 - 150 )
= - 1.1205 Kg/kJ
required pump power = flowrate * -1.1205
= 10 * ( - 1.1205 ) = - 11.205 kW
In the construction of a large reactor pressure vessel, a new steel alloy with a plane strain fracture toughness of 55 MPa-m1/2 and a Y value of 1.0. An in-service stress level of 200 MPa has been calculated. What is the length of a surface crack (in mm) that will lead to fracture
Answers
Answer:
[tex]l=24mm[/tex]
Explanation:
From the question we are told that:
Plane strain fracture toughness of [tex]T=55 MPa-m1/2[/tex]
Y value [tex]Y=1.0[/tex]
Stress level of[tex]\sigma =200 MPa[/tex]
Generally the equation for length of a surface crack is mathematically given by
[tex]l=\frac{1}{\pi}(\frac{T}{Y*\sigma})^2[/tex]
[tex]l=\frac{1}{3.142}(\frac{55}{1*200})^2[/tex]
[tex]l=0.024m[/tex]
Therefore
in mm
[tex]l=24mm[/tex]
Compute the minimum length of vertical curve that will provide 220 m stopping sight distance for a design speed of 110 km/h at the intersection of a -3.50% grade and a +2.70% grade.
Answers
i have made notes and saved it as a pdf u can take it to answer question and make ur concept good
The minimum length of vertical curve that will provide 220 m stopping sight distance is; 458.8 m
We are given;
Stopping sight distance; S = 220 m
Design Speed; V = 110 km/h
Intersection grade 1; G1 = +2.7
Intersection Grade 2; G2 = -3.5
From the AASHTO Table attached, we can trace the value of the radius of vertical curvature for the given stopping sight distance and design speed.From the table, at S = 220 m and V = 110 km/h, we can see that;
Radius of vertical curvature; K = 74
Now, the difference in grade given is;A = G1 - G2
A = 2.7 - (-3.5)
A = 2.7 + 3.5
A = 6.2
Formula for the minimum length of vertical curve is;L = KA
Thus;
L = 74 × 6.2
L = 458.8 m
Read more about stopping sight distance at; https://brainly.com/question/2087168
Calculate the number of 12 V batteries (capacity 120 Ah) needed to run a 3 kW DC motor that operates in 240 V. How many hours the motor will run with 20 of such batteries connected in series?
Answers
Answer:
20 batteries9.6 hoursExplanation:
To obtain 240 V from 12 V batteries they must be connected in series. The number needed is ...
240/12 = 20 . . . batteries needed
__
The current draw will be ...
(3000 W)/(240 V) = 12.5 A
Then the time available from the battery stack is ...
(120 Ah)/(12.5 A) = 9.6 h
The motor can run 9.6 hours from the series connection.
Technician A says that all electric motors are DC motors. Technician B says that two types of brushless motors use AC current. Which technician is correct
Answers
Answer:
Technician B only.
Explanation:
It is not necessary that all electric motors will use Direct current, some may also use Alternative current. Some electric motors that use DC may use brushes. There are two types of brushless motors that use alternative current.
A rod that was originally 100-cm-long experiences a strain of 82%. What is the new length of the rod?
122 cm
182 cm
82 cm
22 cm
108.2 cm
Answers
Answer: (b)
Explanation:
Given
Original length of the rod is [tex]L=100\ cm[/tex]
Strain experienced is [tex]\epsilon=82\%=0.82[/tex]
Strain is the ratio of the change in length to the original length
[tex]\Rightarrow \epsilon =\dfrac{\Delta L}{L}\\\\\Rightarrow 0.82=\dfrac{\Delta L}{100}\\\\\Rightarrow \Delta L=82\ cm[/tex]
Therefore, new length is given by (Considering the load is tensile in nature)
[tex]\Rightarrow L'=\Delta L+L\\\Rightarrow L'=82+100=182\ cm[/tex]
Thus, option (b) is correct.
Why water parameters of Buriganga river vary between wet and dry seasons?
Explain.
Answers
Steam enters a nozzle operating at steady state at 20 bar, 2808C, with a velocity of 80 m/s. The exit pressure and temperature are 7 bar and 1808C, respectively. The mass flow rate is 1.5 kg/s. Neglecting heat transfer and potential energy, determine (a) the exit velocity, in m/s. (b) the inlet and exit flow areas, in cm2
Answers
Answer:
A) 600.8 m/s
B) (i) 22.5 cm^2 (ii) 7.11 cm^2
Explanation:
Given data :
P1 = 20 bar , T1 = 2808°C
P2 = 7 bar , T2 = 1808°C
mass flow rate = 1.5 kg/s
Using the superheated vapor region in Table A-4
h1 = 2976.4 KJ/kg , v1 = 0.1200 m^3/kg
h2 = 2799.1 KJ/kg , v2 = 0.2847 m^3/kg
A) calculate exit velocity ( m/s )
given that we are to neglect heat transfer and potential energy
V2 ( exit velocity ) = ( V1^2 + 2 (√h1 - h2 )
= [ (80)^2 + 2 ( √ 2976.4 - 2799.1 )
= 600.8 m/s
B) calculate the inlet and exit flow areas ( cm^2 )
i) Inlet flow area
A1 = ( m * v1 ) / V1
= ( 1.5 * 0.1200 )/ 80 = 22.5 cm^2
ii) exit flow area
A2 = ( m * v2 ) / V2
= ( 1.5 * 0.2847 ) / 600.8 = 7.11 cm^2
Discuss the organizational system that you believe would be the most effective for the safety officer in a medium-sized (100-200) manufacturing facility
Answers
Answer:
A safety manager is a person who designs and maintains the safety elements at workplace. A balance should be required for production and the job in providing work environment. As a safety officer in a medium sized manufacturing facility the following organizational system can be designed and maintained:
Maintaining a workplace as per the guidelines by Occupational safety and health association. The rules and regulation should be such that maintains the manufacturing facilities. For warning to workers proper labelling, floor mapping, signs, posters should be used. Procurement and usage of safe tools. A guideline that describes safety standard and precautionary measures should be available to the workers. They should be aware about all the steps that needs to be taken in crisis. Ensuring that the workers have enough training safety and health or accident prevention. Identify and eliminate the hazardous elements from the workplace. A strict action should be taken against the worker in case of violation of rules and not adhering with guidelines.
Elliptic curve cryptography is considered as the latest and probably the one with a future. Having seen RSA in earlier modules, in which ways do YOU think elliptic cryptography is more advanced than RSA. You may read other material or get this information from the internet to answer this question. But make sure to provide necessary references when you do cite others.
Answers
Answer:
The answer is below.
Explanation:
Some of the ways, how I think elliptic cryptography is more advanced than RSA are the following:
1. ECC - Elliptic Curve Cryptography uses smaller keys for the same level of security, particularly at greater levels of security.
2. ECC can work well and at a faster rate on a small-capacity device compared to RSA
3. It uses offer speedier SSL handshakes that enhance security
4. It offers fast signatures
5. It allows signatures to be computed in two stages, which enables lower latency than inverse throughput.
6. Relatively quick encryption and decryption
4.65 A zener shunt regulator employs a 9.1-V zener diode for which VZ = 9.1 V at IZ = 9 mA, with rz = 40 and IZK= 0.5 mA. The available supply voltage of 15 V can varyas much as ±10%. For this diode, what is the value of VZ0?For a nominal load resistance RL of 1 k and a nominal zenercurrent of 10 mA,what current must flow in the supply resistorR? For the nominal value of supply voltage, select a valuefor resistor R, specified to one significant digit, to provideat least that current. What nominal output voltage results?For a ±10% change in the supply voltage, what variationin output voltage results? If the load current is reduced by50%, what increase in VO results? What is the smallest valueof load resistance that can be tolerated while maintainingregulation when the supply voltage is low? What is the lowestpossible output voltage that results? Calculate values for theline regulation and for the load regulation for this circuit usingthe numerical results obtained in this problem.
Answers
Answer:
[tex]V_z=9.1v[/tex]
[tex]V_{zo}=8.74V[/tex]
[tex]I=10mA[/tex]
[tex]R=589 ohms[/tex]
Explanation:
From the question we are told that:
Zener diode Voltage [tex]V_z=9.1-V[/tex]
Zener diode Current [tex]I_z=9 .A[/tex]
Note
[tex]rz = 40\\\\IZK= 0.5 mA[/tex]
Supply Voltage [tex]V_s=15[/tex]
Reduction Percentage [tex]P_r= 50 \%[/tex]
Generally the equation for Kirchhoff's Voltage Law is mathematically given by
[tex]V_z=V_{zo}+I_zr_z[/tex]
[tex]9.1=V_{z0}+9*10^{-3}(40)[/tex]
[tex]V_{zo}=8.74V[/tex]
Therefore
[tex]At I_z-10mA[/tex]
[tex]V_z=V_{z0}+I_zr_z[/tex]
[tex]V_z=8.74+(10*10^{-3}) (40)[/tex]
[tex]V_z=9.1v[/tex]
Generally the equation for Kirchhoff's Current Law is mathematically given by
[tex]-I+I_z+I_l=0[/tex]
[tex]I=10mA+\frac{V_z}{R_l}[/tex]
[tex]I=10mA+\frac{9.1}{0}[/tex]
[tex]I=10mA[/tex]
Therefore
[tex]R=\frac{15V-V_z}{I}[/tex]
[tex]R=\frac{15-9.1}{10*10^{-3}}[/tex]
[tex]R=589 ohms[/tex]
Refrigerant-134a enters an adiabatic compressor at -30oC as a saturated vapor at a rate of 0.45 m3 /min and leaves at 900 kPa and 55oC. Determine (a) the power input to the compressor, (b) the isentropic efficiency of the compressor, and (c) the rate of exergy destruction and the second-law efficiency of the compressor. Take T0
Answers
Answer:
a) 1.918 kw
b) 86.23%
c) 0.26 kw
Explanation:
Given data:
T1 = -30°C = 243 k , T0 = 27°C
using steam tables
h1 = 232.19 KJ/kg
s1 = 0.9559 Kj/Kgk
T2 = 55°C P2 = 900 kPa
Psat = 1492 kPa, h2 = 289.95 Kj/Kg, s2 = 0.9819 Kj/kgk , m = 0.0332 kg/s
a) Determine the power input to the compressor
power input = 1.918 kw
b) Determine isentropic efficiency of compressor
Isentropic efficiency = 86.23%
c) Determine rate of exergy destruction
rate = 0.26 kw
Attached below is the detailed solution of the given problems
So I am going to do online school till I graduate and I have horrible internet. i only get about 3 quarters of each class I take so I miss most of it. WHAT DO I DO. my mom said she will never let me go back to a brick-and-mortar school.
Answers
Hope this helps! Comment below for more questions.
Water is boiled in a pot covered with a loosely fitting lid at a location where the pressure is 85.4 kPa. A 2.61 kW resistance heater with 84.5% efficiency supplies heat to the pot. How many minutes will it take to boil 6.03 kg of water?
Answers
Answer:
t = 6179.1 s = 102.9 min = 1.7 h
Explanation:
The energy provided by the resistance heater must be equal to the energy required to boil the water:
E = ΔQ
ηPt = mH
where.
η = efficiency = 84.5 % = 0.845
P = Power = 2.61 KW = 2610 W
t = time = ?
m = mass of water = 6.03 kg
H = Latent heat of vaporization of water = 2.26 x 10⁶ J/kg
Therefore,
(0.845)(2610 W)t = (6.03 kg)(2.26 x 10⁶ J/kg)
[tex]t = \frac{1.362\ x\ 10^7\ J}{2205.45\ W}[/tex]
t = 6179.1 s = 102.9 min = 1.7 h
Frame 4 questions about the challenges that astronauts have to face in space.
Answers
Answer:
Lack of oxygen
Decompression sickness
temperature variation
lack of gravity
Cosmic radiations hazards
motion sickness
Explanation:
When an astronaut travels in the space he is aware of the challenges he might face during his journey. There are various test and rehearsals of travelling before a final travel takes place. An astronaut goes through many challenges which includes lack of oxygen supply, decompression and motion sickness. There is no gravity in space so an astronaut will have to be aware of the difficulties he might face during his travel. An hour on earth is 7 years long in space, so an astronaut should have patience and be able to deal with time variation.
Explain ROLAP, and list the reasons you would recommend its use in the relational database environment.
Answers
Answer:
ROLAP is a branch of OLAP that is used to contain Relational database ( RDB ). which is a very fast database ( quick process of queries )
Very fast to access and also fast in processing queries provides multidimensional view of data / supports multidimensional database schema with RDBMssupports large databasesExplanation:
ROLAP ( Relational On-line Analytical processing ) is a branch of OLAP that is used to contain Relational database ( RDB ).
Advantages of ROLAP ( reasons for the use of ROLAP )
Very fast to access ( fast in processing queries )provides multidimensional view of data / supports multidimensional database schema with RDBMssupports large databasesTransients (surges) on a line can cause spikes or surges of energy that can damage delicate electronic components. A SPD device contains one or more ________________ than bypass and absorb the energy of the transient.
Answers
Answer:
I think ( MOV Metal oxide varistors )
Transients (surges) on a line can cause spikes or surges of energy that can damage delicate electronic components. A SPD device contains one or more MOV Metal oxide varistors than bypass and absorb the energy of the transient.
Determine the resistance values for a voltage divider that must meet the following specifications:_______.
a. The current drawn from the source under unloaded condition is not to exceed 5 mA.
b. The sourcevoltage is to be 10 V, and the required outputs are to be 5 V and 2.5 V.
c. Sketch the circuit.
d. Deter-mine the effect on the output voltages if a load is connected to each tap one at a time.
Answers
Answer:
i) when circuit is unloaded : R1 + R2 = 2kΩ.
ii) when 5V output voltage is applied : R1 = 1 kΩ , R2 = 1 kΩ
iii) when 2.5 v output voltage is applied : R1 = 1500 Ω, R2 = 500 Ω
iv) when: R1 = 1 kΩ , R2 = 1 kΩ is connected in parallel output voltage < 5 V
When : R1 = 1500 Ω, R2 = 500 Ω is connected in parallel output voltage > 2.5V
Explanation:
Current drawn from source under loaded condition ≤ 5 mA
source voltage = 10 v , required output = 5 v , 2.5 v
attached below is the sketch of the circuit
Resistance values
i) when the circuit is unloaded
Req = R1 + R2 = 2 kΩ ( Req = Vs / I = 10 / 5*10^-3 = 2 kΩ )
ii) when output voltage = 5 v
we will apply voltage divider rule
R1 = 1 kΩ ,
R2 = 1 kΩ
iii) When the output voltage = 2.5 v
applying voltage divider rule
R1 = 1500 Ω
R2 = 500 Ω
iv) when the load is connected to each tap one at a time
i.e. when the resistance are in parallel
when: R1 = 1 kΩ , R2 = 1 kΩ is connected in parallel output voltage < 5 V
When : R1 = 1500 Ω, R2 = 500 Ω is connected in parallel output voltage > 2.5V
attached below is the detailed solution to the given problem
state two disadvantages and two advantages of a simple manometer.
Answers
1. Easy to fabricate and relatively inexpensive.
2. Good accuracy.
Disadvantages include;
1. It is large in size and bulky.
2. It needs leveling.
Unfiltered full wave rectifier with a 120 V 60 Hz input produces an output with a peak of 15V. When a capacitor-input filter and a 1k ohm load are connected the DC output voltage is 14V. What is... The value of the capacitor? The value of the peak to peak ripple voltage?
Answers
Answer:
[tex]V_{pp}=2V[/tex]
Explanation:
Source Voltage [tex]V= 120V[/tex]
Frequency [tex]f=60Hz[/tex]
Peak output voltage [tex]Vp=15V[/tex]
Peak Output Voltage with filter [tex]V_p'=14V[/tex]
Generally the equation for Peak to peak voltage is mathematically given by
[tex]V_p'=V_p-\frac{V_{pp}}{2}[/tex]
Therefore
[tex]V_{pp}=2(V_p-v_p')[/tex]
[tex]V_{pp}=2(15-14)[/tex]
[tex]V_{pp}=2V[/tex]
Bài 3: Cho cơ cấu culít (hình 3.5) với các kích thước động lAB = 0,5lAC = 0,1m. Khâu 3 chịu tác dụng của mô men M3 = 500 N. Cơ cấu ở trạng thái cân bằng. Tại thời điểm khâu 1 ở vị trí υ1 = 900 hãy tính áp lực tại các khớp động tại B, C và A.
Answers
A network has three independent file servers, each with 90 percent reliability. The probability that the network will be functioning correctly (at least one server is working) at a given time is:
Answers
Answer:
The correct answer is "99.9%".
Explanation:
According to the information given in the question,
[tex]P(1 \ fail) = 0.1[/tex]
The probability of all fail will be:
[tex]P(all \ fail) = (0.1)^3[/tex]
[tex]=0.001[/tex]
hence,
[tex]P(not \ all \ fail)= 1-P(all \ fail)[/tex]
[tex]=0.999[/tex]
[tex]=99.9[/tex] (%)
Thus the above is the right answer.
Given : x² + 200x = 166400 The current park is a square, and the addition will increase the width by 200 meters to give the expanded park a total area of 166,400 square meters To Find : the side length of the current square park. Solution: x² + 200x = 166400 => x(x + 200) = 166400 166400 = 320 * 520 => (320)(320 + 200) = 166400 => x = 320 side length of the current square park. = 320 m Learn More: Which expression is a possible leading term for the polynomial ... brainly.In/question/13233517
Answers
Answer:
320 m
Explanation:
To find the side length of the current park, x, we solve the quadratic equation for the area of the park
x² + 200x = 166400
x² + 200x - 166400 = 0
We multiply -166400 by x² to get -166400x². We now find the factors of 166400x² that will add up to 200x. These factors are -320x and 520x
So, we re-write the expression as
x² + 200x - 166400 = 0
x² + 520x - 320x - 166400 = 0
We write out the factors of the expression,
x² + 520x - 320x - 320 × 520 = 0
Factorizing the expression, we have
x(x + 520) - 320(x + 520) = 0
(x + 520)(x - 320) = 0
x + 520 = 0 or x - 320 = 0
x = -520 or x = 320
Since x is not negative, we take the positive answer.
So, x = 320 m
a video inspection snake is use
Answers
Answer:
very good thx
Explanation:
I am having trouble understanding how I got these wrong on my test. Is there something I am missing with xor?
Answers
Answer:
your answer is correct
Explanation:
You have the correct mapping from inputs to outputs. The only thing your teacher may disagree with is the ordering of your inputs. They might be written more conventionally as ...
A B Y
0 0 1
0 1 0
1 0 0
1 1 1
That is, your teacher may be looking for the pattern 1001 in the last column without paying attention to what you have written in column B.
