how much charge flows through a wire in 10 minutes if the current through it is 2.5 ampere​

Answer:

John Dalton

Explanation:

Answer:

it wont be because the hand brake would be on

Answer:

False

Explanation:

velocity is more important than speed

Velocity is defined as the speed with direction.

This statement is true.

Velocity is different from speed look below at the differences.

Speed is defined as the ratio between distance over time while velocity is given as the ratio of displacement i.e. speed with direction over time.

Example: Velocity is the rate of motion, speed, or action. An example of velocity is a car driving at 75 miles per hour in the north direction.

Thus, the given statement is true.

Find more information about Velocity here:

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Answer:

The radius of the blender is approximately 0.5041[tex]\bar 6[/tex] meters

Explanation:

The given parameters are;

The mass of the strawberry, m = 0.05 kg

The speed with which the strawberry is spun, v = 11.0 m/s

The centripetal force holding the strawberry = 12.0 N

The formula for the centripetal force, [tex]F_c[/tex], is given as follows;

[tex]F_c = \dfrac{m \cdot v^2}{r}[/tex]

Where;

r = The radius of the centripetal rotation, which is the radius of the blender

[tex]\therefore r = \dfrac{m \cdot v^2}{F_c}[/tex]

Substituting the values gives;

[tex]\therefore r = \dfrac{0.05 \times 11^2}{12} = \dfrac{121}{240} \approx 0.5041 \bar 6[/tex]

The radius of the blender, r ≈ 0.5041[tex]\bar 6[/tex] meters.

Answer:

F = m*a

therefore m = F / a

m = 100 / 5 = 20 kg?

hope this helped you

Explanation:

The required mass of man, undergoing the acceleration is of 75 kg.

Given data:

The magnitude of acceleration of man is, a = 4 m/s².

The magnitude of action force on the man is, F = 300 N.

Here we can apply the Newton's second law of motion, which says that the applied force causes the acceleration of any object. Where the applied force is equal to the mass of object and the magnitude of acceleration of object.

Therefore,

F = ma

Solving as,

300 = m × 4

m = 300/4

m = 75 kg

Thus, we can conclude that the mass of man, undergoing the acceleration is of 75 kg.

Learn more about the Newton's second law here:

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Answer:

735N

Explanation:

Weight is a measurement of force.

F = Force

m = mass

a = acceleration

F = m*a

F = 75kg*9.8m/s²

F = 735N

Answer:

It is a product, so it is released by the plant.

Explanation:

[tex]6CO2 + 6H2O[/tex] → [tex]C6H12O6 + 6O2[/tex]

The plant uses water and carbon dioxide to create glucose and oxygen. Glucose is plant food, and Oxygen is given off as a byproduct.

Answer:

It is a product, so it is released by the plant.

Explanation:

Answer:

It helps prevents falls and supports your body. So having a strong core is beneficial to everyone because it allows your body to function properly. Improved Balance and Stability. Core exercises train the muscles in your pelvis, lower back, hips and abdomen to work together.

Answer:

80 km is distance and 30km north is displacement

Explanation:

distance= 50+30=80km

displacement= 50-20=30

his displacement is 30km north

When Tyler drives 50 km north and then drives back 30 km south, we have:

1. The distance that he covers is 80 km.

2. Tylor's displacement is 20 km.  

1. The distance is a scalar that is given by the sum of the kilometers traveled by Tyler as follows:

[tex] d = d_{1} + d_{2} = 50 km + 30 km = 80 km [/tex]

Hence, the distance traveled by Tyler was 80 km.

2. The displacement is a vector that depends on the direction of travel. Takin the north direction as positive we have:

[tex] x = x_{1} + x_{2} = 50 km + (-30 km) = 20 km [/tex]

Therefore, Tyler's displacement is 20 km.

You can find more about displacement and distance here: https://brainly.com/question/4307551?referrer=searchResults

I hope it helps you!            

Answer:

net force

Explanation:

Net force felt by an object.

Answer:

[tex]Changes \: in \: the \: independent \: variable \: cause \\ changes \: in \: the \: dependent \: variable.[/tex]

Explanation:

think4

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Answer:

The area of the edge of a knife's blade is extremely small.

Syringes are used to take blood for blood tests.

When air is sucked out of a drinking straw, the air pressure inside if decreases and the atmospheric pressure outside forces the liquid to go inside the straw.

Explanation:

Hope this helped, Have a Great Day/Night!!

Answer:

1. Time of flight = 7.22 s

2. Range = 255.10 m

3. Maximum height = 63.77 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 50 m/s

Angle of projection (θ) = 45°

Time of flight (T) =?

Range (R) =?

Maximum height (H) =?

1. Determination of the time of flight

Initial velocity (u) = 50 m/s

Angle of projection (θ) = 45°

Acceleration due to gravity (g) = 9.8 m/s²

Time of flight (T) =?

T = 2uSine θ /g

T = 2 × 50 Sine 45 / 9.8

T = 100 × 0.7071 /9.8

T = 7.22 s

2. Determination of the range.

Initial velocity (u) = 50 m/s

Angle of projection (θ) = 45°

Acceleration due to gravity (g) = 9.8 m/s²

Range (R) =?

R = u²Sine 2θ /g

R = 50² × Sine (2×45) /9.8

R = 2500 × Sine 90 /9.8

R = 2500 × 1 / 9.8

R = 255.10 m

3. Determination of the maximum height.

Initial velocity (u) = 50 m/s

Angle of projection (θ) = 45°

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (H) =

H = u²Sine²θ /2g

H = 50² × (Sine 45)² / 2 × 9.8

H = 2500 × (0.7071)² / 19.6

H = 63.77 m

Answer:

Explanation:

Given;

initial velocity of projection, u = 50 m/s

angle of projection, θ = 45°

Time spent in the air is the time of flight, given as;

[tex]T = \frac{2usin \theta}{g}\\\\T = \frac{2(50)sin (45)}{9.8}\\\\T = 7.22 \ s[/tex]

The range of the projectile is given by;

[tex]R = \frac{u^2sin(2\theta)}{g}\\\\R = \frac{u^2sin(2*45)}{g}\\\\ R = \frac{u^2sin(90)}{g}\\\\ R = \frac{u^2(1)}{g}\\\\R=R_{max} = \frac{u^2}{g} =\frac{50^2}{9.8} = 255.1 \ m[/tex]

The maximum height of the projectile is given by;

[tex]H = \frac{u^2sin^2\theta}{2g}\\\\H = \frac{(50)^2sin^2(45)}{2*9.8}\\\\H = 63.77 \ m[/tex]

Answer:

Air pressure is created by the weight of the atmosphere pushing on Earth’s surface.

Denser air is heavier than less dense air.

Air is less dense at higher altitudes.

Explanation:

Based on the properties of air, the correct options from the given statements are:

Air is a mixture of gases in the atmosphere which consists of nitrigen, oxygen, carbon dioxide and noble gas as well as other trace partickes like water vapor.

Some properties of air include:

Therefore, the correct options from the given statements are:

Learn more about air at: https://brainly.com/question/441281

Answer:

current (I)=V/R

current (I)=9.0/56022

so I=1.607×10 in the power of negative four Amperes (A)

Answer:

AM(amplitude modulation) and FM(frequency modulation)

Explanation:

A radio frequency band is a small adjacent section of the radio spectrum frequencies, whereby channels are usually used or set aside to be used.

They are usually of two different bands called AM which is known as amplitude modulation and FM which is known as frequency modulation

Answer:

Explanation:

Given

Weight of box= 25N

When the rope breaks the box will obey the Newton first law, and Accelerates due to free fall, hence the acceleration will be g=9.81m/s^2

so W=F = mg

where.

F=W =is the force pulling objects toward the Earth.

m=  the mass of the object.

g= is the acceleration due to gravity; this number is a constant for all masses of matter.

Answer:

Each column is called a group. The elements in each group have the same number of electrons in the outer orbital. Those outer electrons are also called valence electrons. They are the electrons involved in chemical bonds with other elements.

Explanation:

Answer:

velocity is vector Quantity

Answer:

Increase his activity and exercise levels and add more calories to gradually gain weight

Explanation:

Answer:

1 hour to ride his motorcycle

Answer:

1) The mass of the student is approximately 73.39 kg

2) The net force on the student is approximately 947.523 N

3) The value the scale will read is approximately 96.59 kg

Explanation:

The given parameters are;

The weight of the student = 720 N

The speed at which the elevator is decreasing = 3.1 m/s²

1) The weight of the student = The mass of the student × The acceleration due to gravity

The acceleration due to gravity is a constant = 9.81 m/s²

Substituting the known values gives;

720 N = The mass of the student × 9.81 m/s²

∴ The mass of the student = 720 N/(9.81 m/s²) ≈ 73.39 kg

2) The forces acting on the student are;

i) The force of gravity which is the weight of the student acting downwards

ii) The inertia force of the slowing elevator acting downwards in the same direction as the weight of the student

The net force, [tex]F_{net}[/tex] = The weight of the student + The inertia force of the slowing elevator

∴ The net force, [tex]F_{net}[/tex] = 720 N + 73.39 kg × 3.1 m/s² ≈ 947.523 N

3) The scale will read the mass of the student as follows;

Mass reading of student on the scale = Force on scale/9.81

∴ Mass reading of student on the scale = 947.523/9.81 ≈ 96.59 kg

The value the scale will read = 96.59 kg.

The mass of student is, 73.46 kg.

The net force acting on the student is 942.72 N.

The reading of the scale is 96.70 kg

Given data:

The weight of student is, W = 720 N.

The magnitude of acceleration is, [tex]a = 3.1 \;\rm m/s^{2}[/tex].

The standard expression for the weight is,

[tex]W =mg[/tex]

Here, g is the gravitational acceleration. And m is the mass of student.

Solving as,

[tex]W =mg\\\\720 = m \times 9.8\\\\m = 73.46 \;\rm kg[/tex]

Thus, the mass of student is, 73.46 kg.

Since, the force of gravity which is the weight of the student acting downwards . The inertia force of the slowing elevator acting downwards in the same direction as the weight of the student. Then the net force is,

[tex]F_{net} = W+(ma)[/tex]

Solving as,

[tex]F_{net} = 720+(73.46 \times 3.1)\\\\F_{net}=947.72 \;\rm N[/tex]

Thus, we can conclude that the net force acting on the student is 942.72 N.

The reading of the scale is given as,

[tex]reading=\dfrac{F_{net}}{g}[/tex]

Solving as,

[tex]reading = \dfrac{947.72}{9.8}\\\\reading=96.70 \;\rm kg[/tex]

Thus, we can conclude the reading of the scale is 96.70 kg.

Learn more about the concept of gravitational acceleration here:

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Answer:

You might even see a spark if the discharge of electrons is large enough. The good news is that static electricity can't seriously harm you. Your body is composed largely of water and water is an inefficient conductor of electricity, especially in amounts this small. Not that electricity can't hurt or kill you.

Explanation:

You might even see a spark if the discharge of electrons is large enough. The good news is that static electricity can't seriously harm you. Your body is composed largely of water and water is an inefficient conductor of electricity, especially in amounts this small. Not that electricity can't hurt or kill you.

Answer:

B: Salt

Explanation:

I answered this correct beforehand.

Answer:

W = V Q          energy = work / charge * charge

Q = I t            charge = current * time

V = W / (I * t)

V = 3 * 10E8 J / (1.5 * 10E4 amps * 2 * 10E-4 sec)

V = 10^8 volts

Let T be the final temperature of water and nails (iron).

Given that the initial temperature of 100 g nails, [tex]T_{1F}=40^{\circ}C[/tex].

Specific heat of the iron, [tex]C_F=0.12 cal/g^{\circ}C[/tex].

So, the heat lost by nails [tex]= mC_F(T_{1F}-T}[/tex]

[tex]=100\times 0.12 \times (40-T)\cdots(i)[/tex]

The initial temperature of 100 g water, [tex]T_{1w}=20^{\circ}C.[/tex]

Specific heat of water, [tex]C_w=1 cal/g^{\circ}C[/tex]

So, the heat gained by water [tex]= mC_w(T-T_{1w}}[/tex]

[tex]=100\times 1 \times (T-20)\cdots(ii)[/tex]

As the exergy is conserved, so

the heat lost by the nails = the heat gained by the water

From equation (i) and (ii), we have

[tex]100\times 0.12 \times (40-T)=100(T-20)[/tex]

[tex]\Rightarrow 0.12(40-T)=T-20[/tex]

[tex]\Rightarrow 0.12\times 40 -120T=T-20[/tex]

[tex]\Rightarrow 0.12T+T=4.8+20[/tex]

[tex]\Rightarrow 1.12T=24.8[/tex]

[tex]\Rightarrow T=24.8/1.12= 22.1^{\circ}C[/tex]

Hence, the final temperature of both, iron nails as well as water, become [tex]22.1^{\circ}C[/tex].

Answer:

14.85 m/s

Explanation:

From the question given above, the following data were obtained:

Height (h) of tower = 45 m

Horizontal distance (s) moved by the balloon = 45 m

Horizontal velocity (u) =?

Next, we shall determine the time taken for the balloon to hit the shoe of the passerby. This is illustrated below:

Height (h) of tower = 45 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

45 = ½ × 9.8 × t²

45 = 4.8 × t²

Divide both side by 4.9

t² = 45/4.9

Take the square root of both side

t = √(45/4.9)

t = 3.03 s

Finally, we shall determine the magnitude of the horizontal velocity of the balloon as shown below:

Horizontal distance (s) moved by the balloon = 45 m

Time (t) = 3.03 s

Horizontal velocity (u) =?

s = ut

45 = u × 3.03

Divide both side by 3.03

u = 45/3.03

u = 14.85 m/s

Thus, the magnitude of the horizontal velocity of the balloon was 14.85 m/s