How many moles of gold are Cleveland to 1.204×1024 atoms

Answer:

7

Explanation:

Answer:

Equal to the total mass

Explanation:

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Relative and average atomic mass both describe properties of an element related to its different isotopes. Out of these two Relative atomic mas is more accurate. Therefore, the correct option is option C.

Mass defines the quantity of a substance. It is measured in gram or kilogram. Average mass is the mass of atoms of an element that are isotopes. It can be calculated by multiplying mass of a isotope to natural abundance of that isotope. In chemistry relative mass is equal to the mass of one-twelfth the mass of C-12 isotope .

Average atomic mass = (mass of first isotope× percent abundance of first isotope)+(mass of second isotope× percent abundance of second isotope)

The total mass of the reactants during a chemical change is equal to the total mass of the product.

Therefore, the correct option is option C.

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Answer:

A. Corn has changed over time due to selective breeding.

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Answer:

In a displacement reaction, a more reactive metal pushes out a less reactive metal from its compound. For example, aluminium displaces iron from iron oxide.

Explanation:

Because aluminium is more reactive than iron, it displaces iron from iron(III) oxide. The aluminium removes oxygen from the iron(III) oxide: iron is reduced.

...

Hope this answer can help you. Have a nice day!

In a displacement reaction, a more reactive metal pushes out a less reactive metal from its compound. For example, aluminium displaces iron from iron oxide.

Compound is defined as a chemical substance made up of identical molecules containing atoms from more than one type of chemical element.

Molecule consisting atoms of only one element is not called compound.It is transformed into new substances during chemical reactions. There are four major types of compounds depending on chemical bonding present in them.They are:

1)Molecular compounds where in atoms are joined by covalent bonds.

2) ionic compounds where atoms are joined by ionic bond.

3)Inter-metallic compounds where atoms are held by metallic bonds

4) co-ordination complexes where atoms are held by co-ordinate bonds.

They have a unique chemical structure held together by chemical bonds Compounds have different properties as those of elements because when a compound is formed the properties of the substance are totally altered.

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Answer:

Nvr XD

Explanation:

Answer:

the world may never know

Explanation:

Answer:

MRCORRECT has answered the question

Explanation:

13 electrons

So... for the element of ALUMINUM, you already know that the atomic number tells you the number of electrons. That means there are 13 electrons in a aluminum atom. you can see there are two electrons in shell one, eight in shell two, and three in shell three.

7 electrons

So... for the element of NITROGEN, you already know that the atomic number tells you the number of electrons. That means there are 7 electrons in a nitrogen atom. Looking at the picture, you can see there are two electrons in shell one and five in shell two.

Answer:

The molarity of a 50.0 ml aqueous solution containing 10.0 grams of table sal, Nacl, is 3.42 [tex]\frac{moles}{L}[/tex]

Explanation:

Molarity is a unit of concentration based on the volume of a solution and is defined as the number of moles of solute per liter of solution. Then, the molarity of a solution is calculated by dividing the moles of the solute by the liters of the solution.

[tex]Molarity (M)=\frac{number of moles of the solute}{volume of the solution}[/tex]

Molarity is expressed in units ([tex]\frac{moles}{liter}[/tex]).

Then you must know the amount of moles of the NaCl solute. For that it is necessary to know the molar mass. Being:

the molar mass of NaCl is:  23 g/mole + 35.45 g/mole= 58.45 g/mole

Then a rule of three applies as follows: if 58.45 grams are present in 1 mole of NaCl, 10 grams in how many moles will they be?

[tex]moles=\frac{10 grams*1 mole}{58.45 grams}[/tex]

moles= 0.171

So you know:

Replacing in the definition of molarity:

[tex]Molarity (M)=\frac{0.171 moles}{0.05 L}[/tex]

Solving:

Molarity= 3.42 [tex]\frac{moles}{L}[/tex]

The molarity of a 50.0 ml aqueous solution containing 10.0 grams of table sal, Nacl, is 3.42 [tex]\frac{moles}{L}[/tex]

Answer:

The limiting reactant is KOH.

Explanation:

To find the limiting reactant we need to calculate the number of moles of each one:

[tex]\eta = \frac{m}{M}[/tex]

Where:

η: is the number of moles

m: is the mass

M: is the molar mass

[tex] \eta_{MnO_{2}} = \frac{100.0 g}{86.9368 g/mol} = 1.15 moles [/tex]  

[tex] \eta_{KOH} = \frac{100.0 g}{56.1056 g/mol} = 1.78 moles [/tex]  

[tex] \eta_{O_{2}} = \frac{100.0 g}{31.998 g/mol} = 3.13 moles [/tex]  

[tex] \eta_{Cl_{2}} = \frac{100.0 g}{70.9 g/mol} = 1.41 moles [/tex]  

Now, we can find the limiting reactant using the stoichiometric relation between the reactants in the reaction:

[tex]\eta_{MnO_{2}} = \frac{\eta_{MnO_{2}}}{\eta_{KOH}}*\eta_{KOH} = \frac{2}{4}*1.78 moles = 0.89 moles[/tex]

We have that between MnO₂ and KOH, the limiting reactant is KOH.

[tex]\eta_{O_{2}} = \frac{\eta_{O_{2}}}{\eta_{Cl_{2}}}*\eta_{Cl_{2}} = \frac{1}{1}*1.41 moles = 1.41 moles[/tex]

Similarly, we have that between O₂ and Cl₂, the limiting reactant is Cl₂.

Now, the limiting reactant between KOH and Cl₂ is:

[tex]\eta_{KOH} = \frac{\eta_{KOH}}{\eta_{Cl_{2}}}*\eta_{Cl_{2}} = \frac{4}{1}*1.41 moles = 5.64 moles[/tex]

Therefore, the limiting reactant is KOH.

I hope it helps you!

Answer:

KOH is the limiting reactant

Explanation:

Step 1: Data given

Mass of MnO2 = 100 grams

Mass of KOH = 100 grams

Mass of O2 = 100 grams

Mass of Cl2 = 100 grams

Molar mass of MnO2 = 86.94 g/mol

Molar mass of KOH = 56.11 g/mol

Molar mass of O2 =32.0 g/mol

Molar mass of Cl2 = 70.9 g/mol

Step 2: The balanced equation

2MnO2 + 4KOH + O2 + Cl2 → 2 KMnO4 + 2KCl + 2H2O

Step 3: Calculate moles

Moles = mass / molar mass

Moles MnO2 = 100 grams / 86.94 g/mol

Moles MnO2 =1.15 moles

Moles KOH = 100 grams / 56.11 g/mol

Moles KOH = 1.78 moles

Moles O2 = 100 grams / 32.0 g/mol

Moles O2 = 3.125 moles

Moles Cl2 = 100 grams / 70.9 g/mol

Moles Cl2 = 1.41 moles

Step 4: Calculate the limiting reactant

For 2 moles MnO2 we need 4 moles KOH and 1 mol O2 and 1 mol Cl2 to produce 2 moles KMnO4, 2 moles KCl and 2 moles H2O

KOH is the limiting reactant. It will completely be consumed (1.78 moles). The other reactants are in excess.

There will react:

MnO2: 1.78/ 2 = 0.89 moles

O2: 1.78/4 = 0.445 moles

Cl2: 1.78/4 = 0.445 moles

There wil remain:

MnO2: 1.15 - 0.89 = 0.26 moles

O2: 3.125 - 0.445 = 2.68 moles

Cl2: 1.41 - 0.445 = 0.965 moles

KOH is the limiting reactant

Answer:

I believe the answer would be A

Answer:

the transmission of heat across matter

Explanation:

Conduction is the transmission of heat across matter. Even though heat flows across matter during conduction, the matter itself does not flow.

Answer:

B. 1.84 × 10^24

Explanation:

[tex]75.0 g H2SO4(\frac{1 mol H2SO4}{98.1 g})(\frac{4 mol O}{1 mol H2SO4})(\frac{6.023 x 10^23 atoms}{1 mol O} )[/tex] = 1.84 x 10^24 atoms

Answer:

it is 0.24 M

Explanation

Find the molarity of all ions in a solution that contains 0.165 moles of aluminum chloride in 820. ml solution. " Answer: [Al 3+1= 0.201 M. (CI) = 0.603M. ... 2) Find the molartiy  of each ion present after mixing 27 ml of 0.25 M HNO3 with 36 ml of ... of each ion and the mass of any precipitate when a 0.300 mole of aluminum.

Answer:

A is correct

Explanation:

The pOH is 12

It is acidic

OH- is actually .0000000001

- Hope that helps! Please let me know if you need further explanation.

Answer:

2, strong acid

Explanation:

Data obtained from the question. This includes:

[H+] = 0.01 M

pH =?

pH of a solution can be obtained by using the following formula:

pH = –Log [H+]

pH = –Log 0.01

pH = 2

The pH of a solution ranging between 0 and 6 is declared to be an acid solution. The smaller the pH value, the stronger the acid.

Since the pH of the above solution is 2, it means the solution is a strong acid.

Answer:

Pipette and Burettes

Explanation:

The two instruments that can be used for  

a) Pipette – It is used to dispense measured volume of any liquid into any other equipment. Pipette works on the concept of creating a partial vacuum to take in the liquid and then release the volume  to dispense the  liquid.

b) Burettes – It has a stopcock that regulate the release of liquid. It is larger than the pipette and works as a graduated cylinder.

Answer: 10 times more

Explanation:

Answer:

THE ENERGY NEEDED TO BE ADDED TO RAISE THE TEMPERATURE BY 30°C IS 145, 860 J

Explanation:

The energy needed can be calculated by using the heat formula, which is;

Heat = m c ΔT

m = mass of the hydrogen =  340 g

c = specific heat capacity of hydrogen at room temperature = 14.30 J/g°C

ΔT = change in temperature = 30°C

Heat =?

So therefore,

Heat = 340 * 14.30 * 30

Heat = 145860 J

The energy needed to be added to the hydrogen to bring the mass of 340 g to an increased temperature of 30°C is 145, 860 J or 145.86kJ

Answer:

The equilibrium shifts to the left, and the concentration of Ba2+(aq) decreases

Explanation:

Whenever a solution of an ionic substance comes into contact with another ionic compound with which it shares a common ion, the solubility of the ionic substance in solution decreases significantly.

In this case, both BaSO4 and Na2SO4 both possess the SO4^2- anion. Hence SO4^2- anion is the common ion. Given the equilibrium;

BaSO4(s) <—> Ba2+ (aq) + SO4 2- (aq), addition of Na2SO4 will decrease the solubility of BaSO4 due to the presence of a common SO4^2- anion compared to pure water.

This implies that the equilibrium will shift to the left, (more undissoctiated BaSO4) hence decreasing the Ba^2+(aq) concentration.

1) The equilibrium shifts to the left, and the concentration of [tex]Ba^{2+}[/tex](aq) decreases

Whenever a solution of an ionic substance comes into contact with another ionic compound with which it shares a common ion, the solubility of the ionic substance in the solution decreases significantly.

In this case, both BaSO₄ and Na₂SO₄ both possess the [tex]SO_4^{2-}[/tex] anion. Hence  [tex]SO_4^{2-}[/tex]  anion is the common ion.

Given the equilibrium;

[tex]BaSO_4(s) < = > Ba^{2+} (aq) + SO_4^{2-} (aq)[/tex],

The addition of Na₂SO₄ will decrease the solubility of BaSO₄ due to the presence of a common  [tex]SO_4^{2-}[/tex]  anion compared to pure water.

This implies that the equilibrium will shift to the left, (more undissociated BaSO₄ ) hence decreasing the [tex]Ba^{2+}[/tex]aq) concentration.

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Answer:

D) condensing C) boiling

Answer:

A. They are isotopes.

Explanation:

An isotope is an element with the same number of protons but different number of neutrons resulting in a varied mass number/molecular weight.

Answer:

Zebra- consumer

Tiger- consumer

Worm- decomposer

Tree-Producer

Molded bread- decomposer

Plant- producer

Answer:

Explanation:

Dandelion plant produces light and feathery seeds .

Zebra consumes / eats grass so it is a consumer .

Answer:

D) contains more OH– ions than H+ ions

Explanation:

Bases have high concentration of hydroxides (OH-) and acids have high concentration of (H+) ions

Like an acid the aqueous solution of a base should be option D) contains more OH– ions than H+ ions.

An aqueous solution refers to the solvent when it should be dissolved in the  liquid water. It is considered to be the solute ions or the dissolved ions also the molecules should be surrounded by the water molecules and it should be incorporated when the network of the bond should lies within the water.

Also, the base contains high  concentration of hydroxides (OH-) and acids have high concentration of (H+) ions

Hence, the option d is correct.

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Answer:

The amount of energy released from the combustion of 2 moles of methae is 1,605.08 kJ/mol

Explanation:

The chemical reaction of the combustion of methane is given as follows;

CH₄ (g) + 2O₂ (g) → CO₂ (g) + 2H₂O (g)

Hence, 1 mole of methane combines with 2 moles of oxygen gas to form 1 mole of carbon dioxide and 2 moles of water vapor

Where:

CH₄ (g): Hf = -74.6 kJ/mol

CO₂ (g): Hf = -393.5 kJ/mol

H₂O (g): Hf = -241.82 kJ/mol

Therefore, the combustion of 1 mole of methane releases;

-393.5 kJ/mol × 1 + 241.82 kJ/mol × 2 + 74.6 kJ/mol = -802.54 kJ/mol

Hence the combustion of 2 moles of methae will rellease;

2 × -802.54 kJ/mol or 1,605.08 kJ/mol.

Answer: answer is C

Explanation:

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Answer:

1: 2.6billion

2: 5.2billion

3: 3.9billion

Explanation:

Edge 2021

Answer:

1     2.6billion

2    5.2billion

3    3.9billion

Answer:

sulfur dichloride

Explanation:

SCl2 is the chemical formula for sulfur dichloride. This compound is made of only two elements, so it is a binary compound.

Answer:

5.81L

Explanation:

N1 = 1.70 moles

V1 = 3.80L

V2 = ?

N2 = 2.60 moles

Mole - volume relationship,

N1 / V1 = N2 / V2

V2 = (N2 × V1) / N1

V2 = (2.60 × 3.80) / 1.70

V2 = 9.88 / 1.70

V2 = 5.81 L

The volume of the gas is 5.81L

Answer:

40.078 u

Explanation: