How many moles of aluminum are in this aluminum can? Answer: ____________ (25 pts) Calculate the number of aluminum atoms in this can. Answer: _______________ (25 pts) The Amount of Aluminum is 12.69g

Answers

Answer 1

Answer:a)No of moles of Aluminium=0.4703

b)number of aluminum atoms=2.832 x 10^23 atoms

Explanation:

a)Given that The Amount/ Mass of Aluminum is 12.69g

We know that

No of moles =Mass/ Molar mass

Molar mass of Aluminium, Al is 26.982 g/mol

No of moles =12.69g/26.982 g/mol

No of moles =0.4703

Also

b) 1  mole of aluminium must contain  6.022  x 10^23  atoms of aluminium  

which is  known as Avogadro's constant.

Therefore, 0.4703 moles will contain 0.4703 x  6.022  x 10^23  atoms =2.832 x 10^23 atoms


Related Questions

What is stoichiometry?​

Answers

(chemistry) the relation between the quantities of substances that take part in a reaction or form a compound (typically a ratio of whole integers)

Answer:

hope it help u !!!!

Explanation:

Stoichiometry is the relationship between the relative quantities of substances taking part in a reaction or forming a compound, typically a ratio of whole integers

CaC0³ scientific name is?​

Answers

Answer:

CaC0³ scientific name is Calcium carbonate

Explanation:

Have a great summer :)

Please somone help me with a chemistry question brainliest to whoever answers correctly and 20 points

Answers

Answer:

3132 is the answer

Explanation:

3BaCl2 + Al2S3 → 3BaS + 2AlCl3

Answer:

Explanation:

Hope this helps u !!

How many grams of Al will be deposited from molten AlCl3 by a current of 15.0 amp flowing for 24.0 hr ( 1 Faraday = 96500 C)

0.538 g
0.0335 g
363 g
121 g​

Answers

Answer:

121 aprox.

Explanation:

mass/molar mass = Q/CF

where mass=?

molar mass of Al=27

Q=It = 15×24×60×60

C=3

F=96500

A reaction requires 22.4 L of gas at STP . There are 25.0 L of gas at 101.5 kPa and 373 K.

Which statement is true?

Use the ideal gas law: PV = nRT where R = 8.31 L-kPa/mol-K

A. There is not enough gas for the reaction.

B. Given this information, there is no way to tell if there is enough gas for the reaction.

C. There is excess gas for the reaction.

D. There is enough gas for the reaction.

Answers

Answer:

STP is 101.325 kPa pressure and 273K temperature

Also, at STP, 1 mol of an ideal gas = 22.4 L

Since the question states that 22.4 L are needed at STP, we know that ONE MOLE is needed.  Now, the question is, how many moles are actually present?

V = 25.0 L

P = 101.5 kPa

T = 373K

n = ?

R = 8.31 L-kPa/Kmol

Solving the ideal gas law for n (moles) and comparing that to 1 mole, we have...

n = PV/RT = (101.5)(25.0)/(8.31)(373)

n = 0.82 moles of gas.  THIS IS NOT ENOUGH as it is less than the ONE mole required.

Explanation:

Which of the following reactions would be the fastest?
A large lump of zinc with high concentration of sulfuric acid.
Small strips of zinc with high concentration of sulfuric acid.
Powdered zinc with low concentration of sulfuric acid.
Powdered zinc with high concentration of sulfuric acid.
2 DONT KNOW

Answers

Answer:

it should be powdered zinc with high concentration of sulfuric acid

is kcn a ternary ionic compound?

Answers

Answer:

The given molecule is KCN.

Is it a ternary ionic compound?

Explanation:

A ternary ionic compound is one that consists of at least one polyatomic ion/radical.

In the given molecule,

the ions present are:

K+ and CN-.

CN- is a polyatomic acidic radical.

Hence, the given molecule is ternary ionic compound.

3
.
The volume occupied by one mole of an ideal gas at 273K and 1.01x10% Pa is 22.4 dm'mol".
What volume of hydrogen, in dm", is produced when excess magnesium ribbon reacts with 100 cm?
of 2.00 mol dm hydrochloric acid?
Mg(s) + 2HCl(aq) → MgCl, (aq) + H2(g)
A.
0.100
B.
2.24
C.
4.48
D.
22.4

Answers

Answer:D

Explanation:

What is created when electrons become detached from their local atom?'
a) An Atom
b) Cation
c) Anion
d) Delocalized electrons

Answers

Answer:

B. Cation

Explanation:

As an electron is removed from the atom it is then converted into a positively charged ion known as a Cation.

Hope this helps u

The answer will be B. Cation.

How does anatomy provide evidence for evolution?

I'll give brainlist!! Simple answer please.

Answers

Anatomical evidence of evolution focuses on similarities and differences in the body structures of different species. ... Similarities in anatomical structures of different species signify that the two species have a relatively recent common ancestor.

1. What metal is oxidized in the most common dry cell?
zinc
iron
carbon
copper

Answers

Answer:

the correct answer is zinc

Zinc is the correct I think

If you could somehow travel inside an atom and look around, what part of the atom would you want to look at? What would you want to understand better as a result of your "travels"? Write your answers in 2-3 paragraphs.

Answers

Answer:

See explanation

Explanation:

The interior of the atom is composed of electrons which move around in orbits and the nucleus. The nucleus contains protons and neutrons. The electrons are negatively charged while the protons are positively charged, the neutrons have no charge at all.

The atom is held together by electrostatic interaction between the electrons and protons in the nucleus. The protons and neutrons account for most of the mass of the atom.

The greatest wonder that I will like to really understand in the interior of the atom is the nature of the interaction between the neutrons and protons in the atomic nucleus which holds the nucleons together. The neutrons have no charge while the protons are positively charged. What sort of interaction could exist between an uncharged particle and a charged particle? That is what I will like to understand better as a result of my travels into the interior of the atom.

Answer:

help

Explanation:

Will give brainliest

What is ozone depletion in simple words

Answers

Answer:

Ozone layer depletion is the thinning of the ozone layer present in the upper atmosphere. This happens when the chlorine and bromine atoms in the atmosphere come in contact with ozone and destroy the ozone molecules. One chlorine can destroy 100,000 molecules of ozone. It is destroyed more quickly than it is created

Answer:

Ozone depletion, gradual thinning of Earth’s ozone layer in the upper atmosphere caused by the release of chemical compounds containing gaseous chlorine or bromine from industry and other human activities. The thinning is most pronounced in the polar regions, especially over Antarctica. Ozone depletion is a major environmental problem because it increases the amount of ultraviolet (UV) radiation that reaches Earth’s surface, which increases the rate of skin cancer, eye cataracts, and genetic and immune system damage. The Montreal Protocol, ratified in 1987, was the first of several comprehensive international agreements enacted to halt the production and use of ozone-depleting chemicals. As a result of continued international cooperation on this issue, the ozone layer is expected to recover over time.

. A circuit is set up with two parallel resistors, each of a resistance of 250Ω. a. What is the total resistance for this circuit?

Answers

Answer:

125 ohms

Explanation:

since they're parallel we do

1/total resistance = (1/250 ohms) + (1/250 ohms)

then you get 2/250 ohms

then you flip it so it's equal to total resistance/1

250÷2= 125

how many grams are represented by 1.45 moles of Koh? Determine your answer to the correct number of significant figures.

Answers

Answer:

[tex]\boxed {\boxed {\sf 81.4 \ g\ KOH}}[/tex]

Explanation:

We are asked to convert 1.45 moles of potassium hydroxide (KOH)  to grams.

1. Molar Mass

The molar mass is the mass in grams of 1 mole of a substance. The values are found on the Periodic Table. They are the same as the atomic masses but the units are grams per mole (g/mol) instead of atomic mass units (amu).

We have the compound KOH. Look up the molar masses of the individual elements.

Potassium (K): 39.098 g/mol Oxygen (O): 15.999 g/mol Hydrogen (H): 1.008 g/mol

The formula for the compound has no subscripts, so there is 1 mole of each element in 1 mole of the compound. We can simply add the molar masses.

KOH: 39.098 + 15.999 + 1.008 =56.105 g/mol

2. Convert Moles to Grams

Based on the molar mass, there are 56.105 grams of KOH in 1 mole. Create a ratio using this information.

[tex]\frac {56.105 \ g\ KOH}{ 1 \ mol \ KOH}[/tex]

We are converting 1.45 moles of KOH to grams, so we multiply by this value.

[tex]1.45 \ mol \ KOH *\frac {56.105 \ g\ KOH}{ 1 \ mol \ KOH}[/tex]

The units of moles of KOH cancel.

[tex]1.45\ *\frac {56.105 \ g\ KOH}{ 1 }[/tex]

[tex]81.35225 \ g\ KOH[/tex]

3. Round

The original measurement of moles has 3 significant figures, so our answer must have the same.

For the number we calculated, that is the tenths place. The 5 in the hundredths place (81.35225) tells us to round the 3 up to a 4.

[tex]81.4 \ g\ KOH[/tex]

Approximately 81.4 grams of potassium hydroxide are represented by 1.45 moles.

The atoms of elements A (blue) and B (orange) form 2 compounds shown here. Do these compounds obey the law of multiple proportions?

Answers

Hello. You have not presented the image that presents the two elements mentioned in the question. This makes it impossible for your question to be answered. However, I will try to help you as best I can.

To say whether the compounds obey the law of multiple proportions, you should observe whether one of the elements, formed from the compounds, maintains a fixed mass, while the other element presents the mass in a varied amount of small, whole numbers, spread across the formed compounds .

This is because the law of multiple proportions states that an element must have a fixed mass when reacting with another element to create compounds. This reaction will allow this element to keep the mass fixed, while the other element will generate different compounds, where each one presents a part of the mass of the forming element, in small and whole numbers.

Cells can regulate different processes in two ways. They can turn on and off the genes that make enzymes, or they can

A)

increase the activation energy of a reaction.

B)

increase the amount of energy needed to carry out the preferred process.

C)

regulate the enzymes that are already made.

D)

decrease the amount of energy needed to carry out the preferred process.

Answers

B.
Increase the amount of energy needed to carry out preferred process

HELP PLEASEEEEE HURRY!!

Answers

Answer:

The answer is c

Para la siguiente reacción: 2NH 3(g) + CO 2(g) ———> (NH 2 ) 2 CO (l) + H 2 O (l) a) ¿Cuántos gramos de NH 3 se necesitan para formar 720 g de (NH 2 ) 2 CO? b) ¿Cuántos moléculas de agua se obtienen a partir de 9 litros de CO 2 ayudenme porfa

Answers

Answer:

a. 408g de NH3 son necesarios

b. 2.42x10²³ moléculas de agua se obtienen

Explanation:

a. Basados en la reacción, 2 moles de NH3 producen una mol de (NH2)2CO. Para resolver esta pregunta debemos convertir la masa de (NH2)2CO a moles. Estas moles a moles de NH3 y su respectiva masa:

Moles (NH2)2CO -Masa molar: 60.06g/mol-

720g * (1mol / 60.06g) = 11.99 moles (NH2)2CO

Moles NH3:

11.99 moles (NH2)2CO * (2mol NH3 / 1mol (NH2)2CO) = 23.98 moles NH3

Masa NH3 -17.031g/mol-:

23.98 moles NH3 * (17.031g / mol) = 408g de NH3 son necesarios

b. 1mol de CO2 produce  1mol de agua. Se debe convertir el volumen a moles usando PV = nRT. Estas moles = Moles de agua. 1mol = 6.022x10²³ moléculas:

Asumiendo STP:

PV = nRT; PV / RT = n

Donde P = 1atm a STP

V = 9L

R = 0.082atmL/molK

T = 273.15K a STP

1atm*9L / 0.082atmL/molK*273.15K = n

n = 0.402 moles CO2 = Moles H2O

Moléculas:

0.402 moles agua * (6.022x10²³ moléculas / 1mol) =

2.42x10²³ moléculas de agua se obtienen

Calculate the volume of this regular solid.
What is the volume of the rectangular prism?
1
6 cm
5 cm
9 cm

Answers

Please mark brainliest

Answer:
270 cm cubed
Explanation:
You multiply them all together to get the volume

The melting and boiling points of table salt and table sugar are given below.

Why does table salt have much higher melting and boiling point than table sugar?
o A strong ion -ion attractions in table salt
O B. weak ion-ion attractions in table sugar
O C. strong ion-ion attractions in table sugar
O
D. weak ion-ion attractions in table salt

Answers

Answer:

weak ion attractions in the table salt

It is a C I took the quiz

what is formed when oxyhaemoglobin splits​

Answers

Explanation:

The haem is in turn split into iron , which forms chemical compounds as part of the blood iron pool available for future hemoglobin synthesis...

hope this help !!

Which of the following is not a compound? HCl Cl2 NaCI CO2

Answers

Answer:

CO2 it is an element.

Hope it helps:)

The ideal gas law equation is: PV = nRT
Use the ideal gas law to calculate the moles of gas in a container that has a pressure
of 700kpa, volume of 2L and a temperature of 450K.

Answers

Answer:

The answer is the first option 0.37 moles

Explanation:

the ideal gas law is PV = nRT, so in the terms of n,

n = PV/RT (divide both sides by RT to let n stand alone)

given: P = 700 kpa, V = 2L, T = 450 K , R = 8.31

n = (700 * 2) / (8.31 * 450)

= 1400/3739.5

= 0.34

Question 9 (1 point)
If a mylar balloon is filled with gas to a volume of 2.9 L at a temperature of 20 degrees celcius and then heated with a heat gun to 150 degrees
celcius, what is the new volume (assume no air escapes the balloon)?

Answers

Answer:I’m not sure

Explanation:free trial

what is quantum physics​

Answers

Quantum physics is the branch of physics concerned with quantum theory.

An electron in a hydrogen atom moves from level 1 to level 4. The electron then drops from level 4 to level 2. Which
statement describes the most likely result?
O The energy absorbed in the first move equals the energy released in the second move.
O The energy absorbed in the first move is greater than the energy released in the second move.
O The energy released in the first move equals the energy absorbed in the second move.
O The energy released in the first move is greater than the energy absorbed in the second move.

Answers

Answer:

The energy absorbed in the first move is greater than the energy released in the second move

Explanation:

Electrons require (absorb) energy to move to a higher energy level when there is a large external heat source, the presence of an electric field or by colliding with other electrons

And the amount of energy absorbed by the electron is exactly equal to the change in the energy state between the initial energy level of the electron and the destination energy level

Therefore, given that the energy level of the electron at level 2 is higher than the energy level of the electron when at level 1, we have;

The difference in the energy level between level 4 and level 1 is greater than the difference in the energy level between level 4 and level 2 and more energy is absorbed and therefore, released when the electron moves from level 1 to level 4 than when the electron drops from level 4 to level 2.

The most likely result is that 'the energy absorbed in the first move is greater than the energy released in the second move'.

Jello has a density of 1.14 g/mL. A box of Jello makes 475 mL of Jello and has 13 g of sugar. Determine the % m/m of sugar in the Jello. (Hint: d=m/v) ​

Answers

Answer:

2.34 %

Explanation:

Since the density of the Jello, ρ = 1.14 g/mL and ρ = m/v where m = mass of jello and v = volume of jello = 475 mL.

So, m = ρv

substituting the values of the variables into the equation, we have

m = ρv

m = 1.14 g/mL × 475 mL = 541.5 g

Since we have 13 g of sugar in the jello, the total mass present is 13 g + 541.5 g = 554.5 g

So, the percentage by mass of sugar present % m/m = mass of sugar present/total mass × 100 %

= 13 g/554.5 g × 100 %

= 0.0234 × 100 %

= 2.34 %

So, the percentage by mass of sugar present % m/m = 2.34 %

ASAAAP HURRRY PLS!!!
Where in aerobic respiration is the largest amount of energy produced?

A)

At the beginning of the cycle, when glucose is oxidized to pyruvate.

B)

At the end of the electron transport chain, when oxygen is reduced.

C)

At the end of the electron-transport chain, when oxygen is oxidized.

D)

At the beginning of the electron transport chain, when oxygen is oxidized.

Answers

C or D! When reduced coenzymes produce in the process of the cycle, are oxidized in the process of oxidative phosphorylation in electron transport chain! I hope this helps :(
it’s D! at the beginning of the electron transport chain, the oxygen is oxidized.

On a warm sunny day, a deer is searching something to drink. The deer is most likely responding to which kind of stimulus?

Answers

Answer:

External stimulus of thirst

Answer:

your answer is:         the external stimulus of thirst

Explanation:

I took the test :)) hope this helps!!!!!!

Other Questions
Quien me puede decir si la siguiente oracion tiene predicado nominal o verbal . La secretaria estuvo enferma toda la semana Solve the following equation:[tex]x + \sqrt{x+3} = 3 + 3\sqrt{1-x}[/tex] The solutions of x = 16x - 28 are1) -2 and -142) 2 and 143) -4 and -74) 4 and 7 the volume of vessel is 6 litres. convert it into ml Farmer toon soon wanted to start breeding his plants so that they are resistant to disease while producing more fruit per plant.Which plants should the farmers cross to get the desired (wanted) combination of traits MARKING BRAINLIEST PLS HELP Instead of investing a lump of sum of $25000,Brittany Royer decides to svae the money in a vault for 2years. Assuming the inflation being 2.5%per year,how much will her purchasing power decline in 2years g Privett Company Accounts payable $33,411 Accounts receivable 66,433 Accrued liabilities 6,512 Cash 22,494 Intangible assets 37,191 Inventory 89,982 Long-term investments 110,819 Long-term liabilities 75,872 Marketable securities 34,976 Notes payable (short-term) 29,393 Property, plant, and equipment 671,232 Prepaid expenses 1,809 Based on the data for Privett Company, what is the quick ratio, rounded to one decimal point A jetliner can fly 8.0 hours on a full load of fuel. Without any wind it flies at a speed of 2.42 x 102 m/s. The plane is to make a round-trip by heading due west for a certain distance, turning around, and then heading due east for the return trip. During the entire flight, however, the plane encounters a 40.7-m/s wind from the jet stream, which blows from west to east. What is the maximum distance (in kilometers) that the plane can travel due west and just be able to return home actor Co. can produce a unit of product for the following costs: Direct material $ 8.60 Direct labor 24.60 Overhead 43.00 Total product cost per unit $ 76.20 An outside supplier offers to provide Factor with all the units it needs at $48.40 per unit. If Factor buys from the supplier, the company will still incur 60% of its overhead. Factor should choose to: match the given circuit parts to their appropriate functions. write only the letter of the correct answer on your paper1.source a.an appliance/device that uses electricity2.switch source like bulbs,computers.3.wire b.it is a safety device made from materials 4.load that easily melt even before the wires 5.fuse carry too much current. c.it is where electricity came from like batteries and generators. d.it is the pathway of electricity from the resources to the load . e.it controls the flow of electricity from the source. it is used to turn on/off a load. Se tiene un pndulo cuyo frecuencia de oscilacin es de 0.4 Hz. Cual sera la frecuencia de oscilacion de otro pndulo cuya longitud es el triple del anterior The Federal Arbitration Act (FAA) allows for arbitration clauses in employment contracts. False True A person living in a coma is considered living or dead? It takes Miguel 18 minutes to finish reading 4 pages of a book. How long does it take him to finish reading 30 pages what is 94.2 and 87 averaged out (b) During one day, 250 kg of water is pumped throughthe solar panel. The temprature of thiswater rises from 16C to 38C.The water absorbs 25% of the energy incident on the solar panel. Thespecific heat capacityof water is 4200J/(kg C).Calculate the energy incident on the solar panel during that day.Please explain how to find the incident energy what type of computer system can be found in the computer lab at school?A. mini B. micro C. MainframeD. super pls help me do this question but pls don't get it wrong this is my last attempt can someone please help