Answer: (B) 1 month
Brainliest if correct pls!What limitations exist when attempting to
categorize hair by race?
Answer:
Albino possibilities
Explanation:
PLEASE HELP WITH THESE WILL GIVE BRAINLEIST
When you rub your hands together quickly, you can feel the heat it generates!
what is the activity illustration?
what is the type of force?
Answer: type of force is friction
Explanation:
Answer:
When you rub your hands together, the action of scraping the
surface of your skin back and forth against each other causes
the molecules in your skin to move a little faster. The faster
that molecules move, the higher the temperature. So the
friction of rubbing your hands together makes them feel
warmer.
The force is friction. It's a force that opposes motion. It is present whenever two surfaces rub over each other, such as when you rub your hands together, or when you apply the brakes on a bike or in a car.
Explanation: I hope this helped you!
9
Which metals have the most uses (applications)? *
Answer:
Steel
Explanation:
the most commonly used metal in the world
Two electrons are separated by 2.00 nm. What is the magnitude of the electric force each electron exerts on the other?
Answer:Two electrons are separated by 2.00 nm. What is the magnitude of the electric force each electron exerts on the other?
Explanation:
Two electrons are separated by 2.00 nm. What is the magnitude of the electric force each electron exerts on the other?
PLEASE HELP!!!
If a 40cm rope with a 220g bob can hold a maximum tension of 3N
a) what are the maximum angular velocity and inclination angle it can reach before the rope break?
b) Angle of inclination
Answer:
ω = 3.1 rad/s
θ = 36° from vertical
Explanation:
I will ASSUME that the bob and string is acting as a pendulum.
Please understand that the string will break when the bob is at the lowest point of the swing where the vectors of gravity and centripetal acceleration align. It will NOT break at the angle of maximum inclination measured from vertical. This angle is only a component of the maximum potential energy that gets converted to maximum kinetic energy at the lowest point of the swing.
At the bottom of the swing, the string must support the weight of the bob plus supply the required centripetal acceleration.
F = mg + mω²R
F/m = g + ω²R
F/m - g = ω²R
ω = √((F/m - g)/R)
ω = √((3/0.220 - 9.8)/0.40)
ω = 3.09691...
ω = 3.1 rad/s
Potential energy will convert to kinetic energy
mgh = ½mv²
h = v²/2g
R - Rcosθ = v²/2g
R(1 - cosθ) = v²/2g
1 - cosθ = v²/2gR
cosθ = 1 - v²/2gR
cosθ = 1 - (Rω)²/2gR
cosθ = 1 - Rω²/2g
cosθ = 1 - 0.40(3.1²)/(2(9.8))
cosθ = 0.804267
θ = 36.46045...
θ = 36°
A student uses a spring (with a spring constant of 180 N/m) to launch a marble vertically into the air. The mass of the marble is 0.004 kg and the spring is compressed 0.03 m. How high will the marble go? Answer:
Answer:
Explanation:
Ignoring air resistance the spring compression energy will equal the increase in potential energy from the maximum spring compression point to the top of the flight arc.
mgh = ½kx²
h = kx²/2mg
h = 180(0.03²) / (2(0.004)(9.8))
h = 2.06632...
h = 2.1 m
hey I just wanted to know if any of the guys here are able to help answer my physics questions , it would be a great thankyou xoxoxoxo
what's your question?
A cellphone charger has a transformer with 2000 turns in the primary coil which converts 240v a.c to 6v a.c and a rectifier that converts 6v a.c to 6v d.c. what do the letters a.c and d.c stand for?how many turns are in the secondary coil of the transformer
Answer:
As we are converting 220V AC into a 5V DC, first we need a step-down transformer to reduce such high voltage. Here we have used 9-0-9 1A step-down transformer, which convert 220V AC to 9V AC. In transformer there are primary and secondary coils which step up or step down the voltage according to the no of turn in the coils.
Selection of proper transformer is very important. Current rating depends upon the Current requirement of Load circuit (circuit which will use the generate DC). The voltage rating should be more than the required voltage. Means if we need 5V DC, transformer should at least have a rating of 7V, because voltage regulator IC 7805 at least need 2V more i.e. 7V to provide a 5V voltage.
which of the following is used to transport sound waves
A.medium
B.vacuum
C.mass
D.light
I think the answer is d.right?
Do you expect the normal dicrystalline resistance in the forward bias to be pure ohmic resistance or what ?!
Answer:
yes
Explanation:
because is pure ohmic risistance
An airplane has a mass of 33,000 kg and takes off under the influence of a constant net force of 44,000 N. What is the net force that acts on the plane's 70 kg pilot
Answer:
Explanation:
acceleration a = F/m = 44000/33000 = 1.3m/s²
F = ma = 70(1.3) = 93 N
If a car skids to a stop in 3.8s while undergoing a uniform acceleration of -9.55 m/s2, what is the car’s velocity?
Answer:
36.29 m/s
Explanation:
We know from theory that [tex]v= v_0 +a\Delta t[/tex]. Let's replace the value we know in our equation and solve for the only value left.
[tex]0 = v_0 - 9.55 \cdot 3.8 \\ v_0 = 9.55 \cdot 3.8 = 36.29 m/s[/tex]
According to consequential ethical theories, actions have an inherent moral value.
Answer:
ojuppuhp
Explanation:
A fundamental kind of consequentialism holds that whether an action is ethically right or bad depends only on whether its results are inherently preferable to those of any other course of action one could take in the given situation.
Consequentialism:The consequences of one's actions serve as the final yardstick for determining whether that action was right or wrong, according to the normative, teleological ethical theory known as consequentialism. Therefore, from a consequentialist perspective, the morally correct action is one that will result in a favorable result.Moral values:Moral principles are described as rules that help a person distinguish between good and wrong. The awareness of one's values is essential, as is self-consciousness, in order to form honest, reliable, and fair judgments and interactions in daily life.Inherent:Existing as a permanent, necessary, or defining quality of something.Explanation -A fundamental kind of consequentialism holds that whether an action is ethically right or bad depends only on whether its results are inherently preferable to those of any other course of action one could take in the given situation.
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Which of the following correctly compares gravitational force and distance between two objects?
A. As the distance increases, the gravitational force decreases.
B. As the distance decreases, the gravitational force decreases.
C. There is no relationship between gravitational force and distance between two objects.
D. As the distance increases, the gravitational force increases.
Help pls…
Answer:
a. as the distances increases , the gravitational force decreases
To see how visual encoding works, read over this list of words: car,
level, dog, truth, book, value. If you were asked later to recall the
words from this list, which ones do you think you'd most likely
remember? Why those words?
I think I would most likely remember car, level, dog, and book. I think I would remember these words because car and level came first, I love dogs, and I like reading books. I can associate something with dogs and books so it helps me remember those words.
[Visual encoding is when people remember things by pictures in their head, but I have aphantasia so I am honestly not the best person to answer this question
Lakepointe Tower in Chicago is the tallest apartment building in the United States (although not the tallest building in which there are apartments). Suppose you take the elevator from street level to the roof of the building. The elevator moves almost the entire distance at constant speed, so that it does 1.15x10^5 J of work on you as it lifts the entire distance. If your mass is 60.0 kg, how tall is the building? Ignore the effects of friction.
Given the information supplied in the question, the height of the building is 196 m.
The work done on you is a work done in a gravitational field. Recall that the work done in a gravitational field is given by mgh where;
m = mass of the body
g = acceleration due to gravity
h = height
Given that;
Work done = 1.15x10^5 J
Acceleration due to gravity = 9.8 ms-2
Mass = 60.0 kg
Substituting values;
h = W/mg
h = 1.15x10^5 J/ 60.0 kg × 9.8 ms-2
h = 196 m
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PLS I NEED YOUR HELP WILL MARK AS BRAINIEST
Drag each chemical equation to the correct label.
Answer:
Explanation:
An object travels 120 m in 6 seconds. How fast is it moving?
Answer:
I actually don't understand what you are asking for....but if you denote second then...
Explanation:
Just divide 120/6=20
Hence, it's traveling 20m per second.
Answer:
20 m/s
Explanation:
Speed = Distance/Time
Speed = 120m/6s
Speed = 20 m/s
Required information
Medical testing has established that the maximum acceleration a pilot can be subjected to without losing consciousness is
approximately 5.00g. A pilot can avoid "blackout" at accelerations up to approximately 9.00g by wearing special "g-suits"
that help keep blood pressure in the brain at a sufficient level.
What is the minimum safe radius of curvature for an unprotected pilot flying an F-15 in a horizontal circular loop at 729 km/h?
Answer:
hi there is that OK for the weekend of the following week as well
Explanation:
6th of March is fine for me
The minimum safe radius of curvature for an unprotected pilot flying an F-15 in a horizontal circular loop at 729 km/h is approximately 838.1 meters.
To determine the minimum safe radius of curvature for an unprotected pilot flying an F-15 in a horizontal circular loop, we need to consider the maximum acceleration the pilot can withstand without losing consciousness.
Given:
Maximum acceleration without losing consciousness = 5.00g
Acceleration with g-suits to avoid blackout = 9.00g
First, we need to convert the speed of the F-15 from km/h to m/s:
Speed = 729 km/h = (729 * 1000) m/3600 s ≈ 202.5 m/s
Next, we'll calculate the acceleration experienced by the pilot in the circular loop. In a horizontal circular motion, the centripetal acceleration is given by:
Acceleration = ([tex]\rm Velocity^2[/tex]) / Radius
We can rearrange the equation to solve for the radius:
Radius = ([tex]\rm Velocity^2[/tex]) / Acceleration
Using the maximum acceleration of 5.00g, we convert it to [tex]\rm m/s^2[/tex]:
Maximum acceleration = 5.00g ≈ (5.00 * 9.8) [tex]\rm m/s^2[/tex] = 49 m/s^2
Now, we can calculate the minimum safe radius of curvature:
Radius = ([tex]\rm 202.5^2[/tex]) / 49 ≈ 838.1 meters
Therefore, the minimum safe radius of curvature for an unprotected pilot flying an F-15 in a horizontal circular loop at 729 km/h is approximately 838.1 meters.
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Two particles with charges q1 = q2 = 7.00 nC are separated by a distance of 1.00 m. Suppose that q1 is at the point x = -0.500 m
a) Make a diagram of the situation.
b) At what point on the line connecting the two charges, is the total electric field produced by both charges equal to zero?
c) Suppose that a third electric charge q3 = 1.00 nC and mass m = 1 mg is placed at the point where the electric field is equal to zero and is given a small push. Determine the approximate value of the angular frequency of oscillation of q3 around this point, assuming small displacements around the equilibrium point .
Hint: Use the binomial formula appropriately to make this approximation: (1 + x) n ≈ 1 + nx.
The definition of electric field, Coulomb's law and Newton's second law allow to find the results for the questions about the electric field and the oscillation of the test charge are:
a) In the attachment you have the scheme of the system
b) The point where the electric field is zero is: x = 0 m
c) The angular velocity of the test charge is w = 0.5 rad / s
Given parameters
Value of the charges q₁ = q₂ = 7.0 10⁻⁹ C Separation of charges d = 1.0 m Charge position q₁ is: x₁ = -0.5 m The value of the charge 3 is q₃ = 1.00 10⁻⁹CTo find
a) system scheme
b) point where the field is zero
c) The angular velocity of q₃
The electric field is the field produced by a distribution of electric charges at a point in space, it is a vector quantity, for the special case that the charges are in one dimension the sum of the field produced by a series of charges is reduced to the sum algebraic. The field produced by point charges is:
E = [tex]k \sum \frac{q_i}{r_i^2}[/tex]
Where E is the electric field, k is the Coulomb constant, q the value of the charge and r the distances from the charge to the point of interest.
a) In the attachment we can see a diagram of the system, the reference system, the location of the charges and the electric field vectors are shown.
b) From the diagram we see that each field is in the opposite direction, therefore the total field is:
[tex]E_{total} = E_1 - E_2 \\E_{total}= k \frac{q_1}{(-0.5- x)^2} - k \frac{q2}{(0.5-x)^2 }\\\\E_{total = 0[/tex]
[tex]\frac{q}{(0.5+x)^2 } = \frac{q}{(0.5-x)^2}[/tex]
The value of the two charges is the same, therefore the value of position x is:
x = 0 m
The point where the total electric field becomes zero is at the origin of the coordinate system.
c) We look for the value of the force on the test charge introduced q₃, for this using the Coulomb equation that establishes that the force is proportional to the product of the electric charges and is inversely proportional to the square of the distance
[tex]F_{13} = k \frac{q_1 q_3x}{(x+0.5)^2}\\F_{23} = k \frac{q_2 q_3}{(x-0.5)^2 }[/tex]
Newton's second law gives the relationship between the net force and the product of mass and acceleration.
[tex]\sum F = m \a \\k q q_3 [ \frac{1}{(x+0.5)^2} - \frac{1}{(x-0.5)2 } }] = m \frac{d^2x}{dt^2}[/tex]
if we use the binomial development
(0.5 + x)⁻² = 0.5 +2 x
(0.5 -x)⁻² = 0.5 -2x
we substitute
k q q₃ [-4x] = [tex]m \frac{d^2x}{dt^2}[/tex]
[tex]-(\frac{4k \ q \ q_3}{m}) \ x = m \frac{d^2x}{dt^2}[/tex]
In oscillatory motion the general equation of motion is
[tex]- w^2 \ x = \frac{d^2x}{dt^2}[/tex]
Equating the two expressions the angular velocity is
[tex]w^2 = \frac{4k \ q \q_3}{m}[/tex]
Let's calculate.
w²= [tex]\frac{4 \ 9 \ 10^9 \ 7 \ 10^{-9} \ 1 \ 10^{-9}}{1 \ 10^{-6}}[/tex] a 4 9 10⁹ 7 10-9 1 10-9 / 1 10-6
w =[tex]\sqrt{0.252}[/tex]
w = 0.5 rad / s
In conclusion, using the definition of electric field, Coulomb's law and Newton's second law we can find the results for the questions about the electric field and the oscillation of the test charge are:
a) In the attachment you have the scheme of the system.
b) The point where the electric field is zero is: x = 0 m
c) The angular velocity of the test charge is w = 0.5 rad / s
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pls help me… I missed the whole lesson and I have no clue what to do-
Answer:
1) 50 facing towards the right
2) 150 facing right
3) 200 facing right
4) 0- no direction
5) 50- facing left
6) 50 facing right
Explanation:
forces in opposite directions and equal magnitudes counteract each other. in number 2 they face the same direction so they would just be added. in number 4 they oppose each other so would be subtracted
Someone fires a slingshot at a target that is far enough away to take 1.4 seconds to reach. How far below does the target does the slingshot pellet hit?
Pls answer when u can
Answer:
I believe the answer is C. 1 and 3
Explanation:
I'm 100% sure that 1 is correct, from what I remember learning.
As for 3, it was hard to choose between 3 and 4, but I'm pretty certain that covalent bonds shared electrons rather than transfer them.
Hope this helps you, please let me know if it was correct :DLupert walked 5.8 m east in 8.9 s, stopped for 3.7 s, turned North and went 7.9 m in 12.5 s, stopped for 6.3s , and then went 3.2 m west in 4.7s. What was his average speed?
The average speed of Lupert for the entire journey is 4.58 m/s.
The given parameters;
initial position of Lupert, = 5.8 m easttime of motion, = 8.9 s, extra time = 3.7 ssecond position of Lupert, = 7.9 m, Northtime of motion, = 12.5 s, extra time = 6.3 sfinal position of Lupert = 3.2 m westtime of motion = 4.7 sThe average speed of Lupert is calculated as the ratio of the total distance to total time of motion;
[tex]average \ speed = \frac{(5.8 \times 8.9) \ + \ (7.9 \times 12.5) \ + \ (3.2 \times 4.7)}{8.9 \ + \ 3.7 \ + \ 12.5 \ + \ 6.3\ +\ 4.7} \\\\average \ speed = \frac{165.41}{36.1} \\\\average \ speed =4.58 \ m/s[/tex]
Thus, the average speed of Lupert for the entire journey is 4.58 m/s.
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How do energy and matter move in ecosystems?(1 point)
Energy and matter flow in one direction.
Matter flows in one direction, and energy cycles through the environment.
Energy flows in one direction, and matter cycles through the environment.
Energy and matter cycle through the environment.
Answer
Explanation:
Energy flows in one direction,and matter cycle the environment
Energy flows in one direction and matter cycles through the environment in an ecosystem.
What is an ecosystem?
Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.
Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.There are many ecosystems present in the environment.
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A photographer wants to determine the color of light he can use in the darkroom that will not expose the films he is processing. In one trial, he used a blue incandescent bulb. Which bulb can he use for another trial?
A. Red incandescent bulb C. Red fluorescent bulb
B. Blue incandescent bulb D. Blue fluorescent bulb
For a photographer that wishes to determine the color of light that he can use in a dark room that will not expose the films he is processing, having used a Blue Incandescent bulb, he should proceed to use a Red Incandescent bulb for the next trial.
The photographer in question is performing an experiment. For these kinds of experiments it is important to identify the variables present, which can be of three kinds:
Control variablesDependent variables Independent variablesFor this experiment, the dependent variable is the exposure of the light onto the films, given that this is what we wish to measure. The independent variable will be the color of the light being used which is what will affect the dependent variable.
The remaining variable must be the control variable. Unlike the previous variables, we can have more than one of these. The control variable is there to make sure that only the dependent variable is affecting the outcome. We do this by keeping the control variable the same through each trial, which is why the photographer should not change the type of bulb in the second experiment, changing only the color of the light.
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5. A quarterback throws the football to a stationary receiver who is 31.5 m
down the field. If the football is thrown at an initial angle of 40.0° to the
ground, at what initial speed must the quarterback throw the ball for it
to reach the receiver? What is the ball's highest point during its flight?
The projectile launch equations allow to find the results for the questions about the movement of the ball are:
The initial velocity is: v₀ = 17.7 m / s. The maximum height is: y = 16 m.
Given parameters
Horizontal distance x = 31.5 m Launch angle tea = 40ºTo find
The initial speed. Maximum height.
Projectile launching is an application of kinematics, where on the x-axis there is no acceleration and on the y-axis is the gravity acceleration.
The range is the distance traveled for the same departure height, see attached.
.
R =[tex]\frac{v_o^2 \ sin 2\theta}{g}[/tex]
[tex]v_o^2 = \frac{ g R}{sin 2 \theta }[/tex]
Let's calculate.
v₀² = [tex]\frac{9.8 \ 31.5}{sin \ (2 \ 40)}[/tex]9.8 31.5 / sin (2 40.0)
[tex]v_o = \sqrt{313.46}[/tex]o = ra 313.46
v₀ = 17.7 m / s
At the point of maximum height the vertical speed is zero.
v² = v₀² - 2 g y
0 = v₀² - 2g y
y = [tex]\frac{v_o^2}{2g}[/tex]
Let's calculate.
y = [tex]\frac{17.7^2}{2 \ 9.8}[/tex]
y = 16 m
In conclusion, using the projectile launch equations we can find the results for the questions about the movement of the ball are:
The initial velocity is: v₀ = 17.7 m / s The maximum height is: y = 16 m.
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Place a beaker covering its free surface with a paper over a coin as shown in the figure- 1. The coin can be seen through the sides of the beaker. (i) Fill the beaker with water. Is the coin seen through the sides of the beaker? If not, why? (ii) Drop water over the coin. Is the coin seen through the sides of the beaker? If yes, why?
Answer:
bonjour
Explanation:
bye
True or false. The buildings in cities are getting larger
Answer:
trueExplanation:
cuase the city is getting more people than beforeDescribe how you can determine:
a) Volume of an irregular body
b) Density of a liquid
Density of liquid try thank you so much
Answer:
a) measure the change in volume when the object is immersed; compute from range data
b) find the ratio of mass to volume for a measured mass and volume
Explanation:
a) The volume of a small enough irregular body can be found by measuring the difference in volume of the (semi-)fluid in which it is immersed, before and after immersion.
For irregular bodies for which that approach does not work, various 3D scanners are available for measuring volume and surface area. They may rely on optical (laser or camera), sonic, or radar measurements, and generally involve computation from distances to various points.
__
b) Density is the ratio of mass to volume. So, measurements of mass and volume of a liquid sample are sufficient to provide the basis for determining density.
Other methods include measuring buoyancy forces, and/or the depth of submersion of something that floats in the liquid. For specific liquids, hydrometers are available for measuring their density relative to that of water.
