How does temperature effect density and the flow of convection currents?

Answers

Answer 1

Answer:

Convection

Explanation:

Convection is heat transfer due to a density differential within a fluid. As water's temperature increases in the presence of a heat source, it will become less dense and rise. As it moves up and away from the heat source, it cools and becomes more dense and sinks.


Related Questions

Calculate the ideal mechanical advantage of a pair of scissors where the length of the blade is 5 cm and the length of the handle is 2.5 cm.

Answers

Answer:

m = 0.5

Explanation:

Given that,

The length of the blade of scissors = 5 cm

The length of the handle = 2.5 cm

Here, effort arm is 2.5 cm and load arm is 5 cm. The mechanical advantage is the ratio of effort arm to the load arm as follows :

[tex]m=\dfrac{2.5}{5}\\\\m=0.5[/tex]

So, the ideal mechanical advantage of a pair of scissors is 0.5.

Which form of energy has the most potential globally

a) Solar energy

b) Bio energy

c) Wind energy

d) Geothermal energy

Answers

Answer:

i think the answer is solar,

Explanation:

because it is a natural resource im sorry if im wrong

PLEASE HELP QUICKLY THANKS

Answers

Answer: the answer is d

Explanation:

A biker first accelerates from 0.0 m/s to 6.0 m/s in 6 s, then continues at this speed for 5 s. What is the total distance traveled by the biker?

100 m

80 m

30 m

48 m

PLZ heeeeelp ​

Answers

Answer:

48m

Explanation:

Given the following data;

Initial velocity = 0m/s

Final velocity = 6m/s

Time, t = 6 secs

Time, T2 = 5 secs

Mathematically, acceleration is given by the equation;

[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]

Substituting into the equation;

[tex]a = \frac{6 - 0}{6}[/tex]

[tex]a = \frac{6}{6}[/tex]

Acceleration, a = 1m/s²

To find the distance covered in the first phase;

Solving for distance, we would use the second equation of motion;

[tex] S = ut + \frac {1}{2}at^{2}[/tex]

Substituting the values into the equation;

[tex] S = 0(6) + \frac {1}{2}*1*(6)^{2}[/tex]

[tex] S = 0 + \frac {1}{2}*1*36[/tex]

[tex] S = 0.5 *36[/tex]

Distance, S1 = 18m

For the second phase, time T2 = 5 secs;

Mathematically, speed is given by the equation;

[tex]Speed = \frac{distance}{time}[/tex]

Making distance the subject of formula, we have;

[tex]Distance, S = speed * time[/tex]

Substituting into the above equation;

[tex]Distance, S = 6 * 5[/tex]

Distance, S2 = 30m

Total distance = S1 + S2 = 18m + 30m = 48m

Total distance = 48m

Therefore, the total distance traveled by the biker is 48m.

Do someone know the answer

Answers

Speed x time = distance
Distance divided by time = speed
500 divided by 5
Speed = 100

A trip is taken that passes through the following points in order

Point A 0 m

Point B 15.0 m

Point C -30.0 m

Point D -20.0 m

Point E 10.0 m

Point F 5.0 m

What is the distance from Point C to Point F?

Answers

Answer:

35, I got you bro, i got you

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