How do you write a number less than one and one-third in an algebraic expression?

Answer:

In algebra, like terms are terms that have the same variables and powers. ... Unlike terms are two or more terms that are not like terms, i.e. they do not have the same variables or powers. The order of the variables does not matter unless there is a power.

Answer:

These are not like terms.

Step-by-step explanation:

Although their variables are the same, the exponents are different.  LIke terms must have the same variables AND same exponents.  The first term's variables are: x raised to the second power times y, while the other term's variables are:  y times x times 2

2x ≠ x²

Answer:

6.72

Step-by-step explanation:

I multiplied both numbers by 10 to make it easier in my opinion. That made the equation 994.66 x 148

Then, I divided it until i got to the thousandths place. Lastly, i just rounded making it 6.72

A. is the correct answer

Answer:

A

Step-by-step explanation:

(x-3)(2x+1)= (due to FOIL(First Outer Inner Last)) (First)2x^2-(Outer+Inner)5x-(Last)3. 2x^2-5x-3 is what A says, so A is the answer.

Answer:

False

Step-by-step explanation:

If the graph represented y = 2x + 1, then the y-intercept would be 1. The slope is correct(-ish), the y-intercept is not.

Answer:

81[tex]y^{8}[/tex][tex]z^{4}[/tex]

Step-by-step explanation:

Answer:

Parallel lines

Step-by-step explanation:

Answer:

[tex]2(3m + 6n) + 3(5m - 2n) + 5( - 6m + n) \\ [/tex]

open the brackets:

[tex] = (6m + 12n) + (15m - 6n) + ( - 30m + 5n) \\ [/tex]

group the coefficients of m and n in their brackets:

[tex] = (6 + 15 - 30)m + (12 - 6 + 5)n \\ [/tex]

then operate the brackets:

[tex] = - 9m + 11n[/tex]

Answer:

angle 1 + angle 2 = ∠DEB

angle 7 + angle 8 = ∠NEG

angle 1 + angle 6 = ∠NEA

Answer:

The answer would be c/17

Step-by-step explanation:

You would have to add 10 and 7 to get the sum. Then just divide whatever c is by 17.

Answer:

7, 8, 9

Step-by-step explanation:

1/5 = 6/30

1/3 = 10/30

Answer:

11

Step-by-step explanation:

2^10 + 2^10 = 2^x

1024 + 1024 = 2^x

2,048 = 2^x

x = 11

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]x = 11[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Solving for 'x'...}}\\\\2^{10}+2^{10} = 2^x\\--------------\\\rightarrow 2^{10} = 1024\\\\\rightarrow 1024 + 1024 = 2^x\\\\\rightarrow 2048 = 2 ^x\\\\\rightarrow log(2^x)=log(2048)\\\\\rightarrow xlog(2)=log(2048)\\\\\rightarrow \frac{log(2)}{log(2)} =\frac{log(2048)}{log(2)}\\\\\rightarrow x = \frac{log(2048)}{log(2)}\\\\\rightarrow \boxed{x = 11}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

True

Step-by-step explanation:

[tex]f(x)=y=-8x+5: exchanging\ x\ and\ y\\\\x=-8y+5\\\\8y=-x+5\\\\f^{-1}(x)=y=\dfrac{-x}{8}+\dfrac{5}{8} =g(x)\\\\\\[/tex]

The two functions are inverses.

[tex]\\ \tt\longmapsto \dfrac{d}{dx}\sqrt{x}+\dfrac{1}{5x}-3[/tex]

[tex]\\ \tt\longmapsto \dfrac{d}{dx}x^{\frac{1}{2}}+5x^{-1}-3[/tex]

[tex]\\ \tt\longmapsto \dfrac{d}{dx}x^{\frac{1}{2}}+5x^{-1}[/tex]

[tex]\boxed{\sf \dfrac{d(x^n)}{dx}=nx^{n-1}}[/tex]

[tex]\\ \tt\longmapsto \dfrac{1}{2}x^{\frac{-1}{2}}-5x^{-2}[/tex]

[tex]\\ \tt\longmapsto \dfrac{x}{2}^{\frac{-1}{2}}-\dfrac{1}{5x^2}[/tex]

[tex]\\ \tt\longmapsto -\sqrt{\dfrac{x}{2}}-\dfrac{1}{5x^2}[/tex]

Answer:

48 children went to the big picnic

Step-by-step explanation:

hope that helps>3

Answer:

48 children

Step-by-step explanation:

Answer:

[tex]x = \frac{5}{13} [/tex]

Step-by-step explanation:

[tex] \frac{3}{4} x + \frac{5}{4} = 4x[/tex]

[tex]3x + 5 = 16x[/tex]

[tex]3x - 16x = - 5[/tex]

[tex] - 13x = - 5[/tex]

[tex]x = \frac{5}{13} [/tex]

Answer:

5n+3

Step-by-step explanation:

:)

Answer:

[tex]\alpha n=5n+3[/tex]

Step-by-step explanation:

Answer:

Yes

Step-by-step explanation:

6 × 18.75 = 112.50

8 × 18.75 = 150.00

11 × 18.75 = 206.25

Answer:

[tex]4y + 6y = 90 \\ 10y = 90 \\ y = 9 \\ thank \: you[/tex]

Answer:  Choice B

Work Shown:

[tex]-2 \le 2x-4 < 4\\\\-2+4 \le 2x-4+4 < 4+4\ \text{ ... add 4 to all sides}\\\\2 \le 2x < 8\\\\2/2 \le 2x/2 < 8/2\ \text{ ... divide all sides by 2}\\\\1 \le x < 4\\\\[/tex]

This says that x is between 1 and 4; it can equal 1, but it can't equal 4.

To visually represent this, we'll have a closed circle at 1, an open circle at 4, with shading in between these circles. This is represented by graph B.

Answer:

y- intercept, x=0

8(0)-4y=12

y=-3

Answer:

Read explanation Please (I spent alot of time on it and its important to understand where the answer came from not just the answer!)

Step-by-step explanation:

This problem is in the form of y=mx+b where m is the ratio y grows accordinly to x and b is the value of y when x is 0 (mx0 is 0, 0+b is b).

In you problem we can identify that 1 is the y intercept or when x is 0. All we have to do is find another point since 2 points make alike. Let's say x was 1. 43 * 1 +1 = 44 so when x is 1 y is 44.

Our two points are, (0,1)(1,44)

I left a picture of the graphed btw!,

Hoped this helped, Eddie

Answer: 8 hours

Step-by-step explanation:

Given information

Admission fee = $7.00

Hour rent fee = $1.50

Number of hours = h

Total fee = $19

Set equation according to the given information

Total fee = admission fee + (hours) × (hour rend fee)

Substitute values into the equation

19 = 7 + 1.5h

Subtract 7 on both sides

19 - 7 = 7 + 1.5h - 7

12 = 1.5h

Divide 1.5 on both sides

12 / 1.5 = 1.5h / 1.5

[tex]\boxed{h=8}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

15:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{x^5y^6}{xy^2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{5-1}y^{6-2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^4y^4[/tex]

16:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{x^2y^5}{xy^4}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{2-1}y^{5-4}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto xy[/tex]

17;-

[tex]\\ \qquad\quad\sf\longmapsto \left(\dfrac{4x^5y}{16xy^4}\right)^3[/tex]

[tex]\\ \qquad\quad\sf\longmapsto (4^{1-2}x^{5-1}y^{1-4})^3[/tex]

[tex]\\ \qquad\quad\sf\longmapsto (4^{-1}x^4y^{-3})^3[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 4^{-3}x^{12}y^{-9}[/tex]

18:-

[tex]\\ \qquad\quad\sf\longmapsto \left(\dfrac{5x^3y}{20xy^5}\right)^4[/tex]

[tex]\\ \qquad\quad\sf\longmapsto (4^{-1}x^{2}y^{-4})^4[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 4^{-4}x^8y^{-16}[/tex]

19:-

[tex]\\ \qquad\quad\sf\longmapsto y^{-7}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{y^7}[/tex]

20:-

[tex]\\ \qquad\quad\sf\longmapsto 7^{-2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{7^2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{49}[/tex]

21:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{x^{-5}}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^5[/tex]

22:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{2^{-4}}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 2^4[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 16[/tex]

23:-

[tex]\\ \qquad\quad\sf\longmapsto x^5\times x^{-1}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{5-1}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^4[/tex]

24:-.

[tex]\\ \qquad\quad\sf\longmapsto x^{-6}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{x^6}[/tex]

25:-

[tex]\\ \qquad\quad\sf\longmapsto x^9(x^{-7})[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{9-7}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^2[/tex]

Answer:

30x + 28

Step-by-step explanation:

To evaluate (f ￮ g)(x), substitute x = g(x) into f(x) , that is

f(g(x))

= f(- 6x - 6)

= - 5(- 6x - 6) - 2 ← distribute parenthesis and simplify

= 30x + 30 - 2

= 30x + 28

Answer:

It is 7x + 12

Step-by-step explanation:

[tex]5(3x + 2) - 2(4x - 1)[/tex]

open brackets:

[tex] = 15x + 10 - 8x + 2[/tex]

group like terms together:

[tex] = (15x - 8x) + (10 + 2)[/tex]

factorise out x :

[tex] = x(15 - 8) + 12 \\ = 7x + 12[/tex]

Answer:

C: 1/4x + 4 = 3

Step-by-step explanation:

1/4x + 4 = 3

1/4x = 3 - 4

x = - 4

Thus, option c gives out the solution x = - 4.

SORRYYYYYYYYYYYYYYY I DONT KNOWWWWW

Answer:

17) 19

19) 8

Step-by-step explanation:

17)

(6 +6² -4)÷2

(6 +36 -4)÷2

(38)÷2

19

19)

3³ ÷3 - 1

27 ÷3 -1

9 -1

8

To graph an exponential,

d. T-chart using random values for x and y.

The set of ordered pairings (x, y) where f(x) = y makes up the graph of a function.

These pairs are Cartesian coordinates of points in two-dimensional space and so constitute a subset of this plane in the general case when f(x) are real values.

Now,

We know an exponential function is a function in which the independent variable is the exponent.

One such function is y = eˣ

Now, To graph an exponential function you come up with values to use in the graph should be a T-chart using random values for x and y.

As it would result in graphing the complete nature of the function.

Learn more about graphs here :

brainly.com/question/2288321

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