Answer:
-1/5
Step-by-step explanation:
We know that a^b * a^c = a^(b+c)
(−5)^5(−5)^−6
(-5) ^(5+-6)
(-5)^-1
We know that a^-b = 1/a^b
1/(-5)^1
1/-5
-1/5
The total enclosed area is ____ square units. Round to the nearest tenths place (1 decimal place).
Answer: 47.6
Is this right?
Answer:
siis corretoed
Step-by-step explanation:
Solve: 3/x-4 >0
x < 4
x > -4
x > 4
x < -4
Answer:
x>4
Step-by-step explanation:
3/(x-4) >0
Divide each side by 3
3/(x-4) * 1/3 >0*1/3
1/(x-4) >0
We know if 1/(x-4) >0 then x-4 > 0
x-4>0
Add 4 to each side
x-4+4 >0+4
x>4
[tex]\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}[/tex]
[tex]:\implies{\dfrac{3}{x-4}>0}\\\\:\hookrightarrow{\dfrac{3}{x-4}×\dfrac{1}{3}>0×\dfrac{1}{3}}\\\\:\longrightarrow{x-4>0}\\\\:\implies{x-4+4>0+4}\\\\ :\dashrightarrow{\sf{x>4}}[/tex]
Integrate the following.[tex]\int\limits^a_b {sin(x)} \, dx[/tex]
Answer: -cos(a)+cos(b)
Step-by-step explanation:
To integrate is the same as saying to find the antiderivative.
[tex]\int\limits^a_b {sin(x)} \, dx[/tex] [antiderivative of sinx is -cosx]
[tex]-cos(x)|_b^a[/tex] [include boundaries]
[tex]-cos(a)+cos(b)[/tex]
Therefore, the integral would be -cos(a)+cos(b).
Here is Question Two
AB= 9 UNITS
hope it helps you...
Answer:
by Pythagoras theorem
in first
a²+ b² = c²
6² + 9² = c²
36 + 81 = 117
AD = 117
and in second
a² + b² = c²
a² + 6² = 117
a² = 117 - 36
AB² = 81
AB = 9
Make six prime numbers using the digits 1, 2, 3, 4, 5, 6, 7, 8, 9 once each.
~can you plz explain?!
Answer:
2, 3, 5, 7, 11, 13.
Step-by-step explanation:
A prime number is a number that you don't get a whole number when divided by 2 but you do get a whole number when divided by prime numbers such as 3,5,7,11... Basically a number with two factors, it can only be divided by 1 or themselves. for example:
9/2 = 4.5 (this is not a whole number so it might be a prime.
9/3 = 3 (it works when divided by a prime number.
another:
8/2 = 4 (it gives a whole number when divided by 2 therefor, it can't be a prime number.
Answering:
There are 6 prime numbers at the top^^^^.
One possible answer is 2, 3, 5, 41, 67, 89
Another possible answer is 2, 3, 5, 47, 61, 89
Other answers may be possible.
=============================================================
Explanation:
This is a trial and error type of problem. Though with practice it's not as blind of randomly guessing.
We have 9 values here. If we paired them up, then we can form at most 4 pairs (since 9/2 = 4.5 rounds down to 4). That means we won't be able to form six two-digit primes. Some of the primes must be single digits.
We can have 3 single digit primes and 3 two-digit primes since 3+2*3 = 9.
The single digit primes are: 2, 3, 5, 7
Let's say 2 and 5 are definitely locked down to be the single digit group. I'm doing this since we can't have 2 or 5 as the units digit. If the units digit is 2, then 2 is a factor and it's not prime. Similarly, if 5 is the units digit, then 5 is a factor and that two digit value is not prime.
For good measure, we'll throw 3 in there as well and see what happens.
------------------
The digits we have left are: 1, 4, 6, 7, 8, 9
The number 14 isn't prime, but 41 is prime
67 is prime so that's another two values off the list
lastly, 89 is prime so that works as well.
So one possible sequence is 2, 3, 5, 41, 67, 89
Notice how we can swap the 1 and 7 to go from 41,67 to 47,61; this gets us two other primes. So another possible answer is 2, 3, 5, 47, 61, 89
------------------
Side note: having the list of primes on a reference sheet is a handy recommendation. You only need to go up as high as 97 which is the largest two digit prime.
Nick works part-time at a bookstore. His pay varies directly with the number of hours worked. In one week, he earned $120 for 8 hours of work.
a) Define two variables for this relation.
b) Describe the rate of change in words.
c) Determine an equation to represent the relation:
d) Use the equation to determine how many hours Nick must work to earn $345
Answer:
23 hoiurs
Step-by-step explanation:
Given data
a. The two variables are
1. Number of hours worked
2. The amount earned
b. The rate is given as
=120/8
=$15 per hour
c. The equation is given as
rate=Amount earned/ number of hours worked
15= 345/hours
make hours subject of the formula we have
hours= 345/15
hours= 23 hours
Hence he must work for 23 hours
Will it matter if I don’t get accelerated pre algebra in 7th grade and get into normal pre algebra? Will it make me less likely to get into top colleges?
Answer:
Maybe, there is a chance, but I don't know for sure.
It might matter, but I wouldn't worry or stress about it too much.
My only advice to you is do not procrastinate and if you need help don't be afraid to ask.
Answer:
It matters but not like you think.
GPA, extracurricular activities, and SAT/ACT are the biggies. Truthfully it won't change a thing if you took accelerated pre-algebra versus normal. In fact, spoiler alert, the SAT/ACT (I'm assuming your american) will matter more than your courses ever did. I took two years of college physics in highschool and i made more off my SAT. Not only that, but an A in an easy class looks better than a C in a hard one on transcripts.
My advise is slow down, relax, and learn it well. Better to learn the concept fully in normal so that you can apply it, than half learn it in advance and struggle in future applications. After all, math ALWAYS builds. Take it slow, take it easy.
I would recommend talking to a school guidance counselor about your academic stress. Im sure their professional insight will help put you at ease. It may also help to get you going in the right direction so that you achieve your goals.
Good luck. Enjoy life
Solve the equation 5x + 2(2x -23) = -154
[tex]\boxed{\large{\bold{\blue{ANSWER~:) }}}}[/tex]
5x+2(2x-23)=-1545x+4x-46=-1549x-46=-1549x=-154+469x=-108x=[tex]\sf{\dfrac{-108}{9} }[/tex] x=-12Answer:
x = -12
Step-by-step explanation:
5x + 2(2x - 23) = -154
Distribute;
5x + 4x - 46 = -154
Collect like terms
9x - 46 = -154
Add 46 to both sides;
9x = -108
Divide both sides by 9
x = -12
If you have seven dimes how much money do you have
Answer:
70 cents or 0.70 dollars
Step-by-step explanation:
one dime is 10 cents so if you have 7 than you have 70 cents
Which side lengths form right triangles? Please help
Answer:
Step-by-step explanation:
Which best explains why all equilateral triangles are similar?
O All equilateral triangles can be mapped onto each other using dilations.
O All equilateral triangles can be mapped onto each other using rigid transformations.
O All equilateral triangles can be mapped onto each other using combinations of dilations and rigid transformations.
O All equilateral triangles are congruent and therefore similar, with side lengths in a 1:1 ratio.
Answer:
the correct answer is option 1.
The correct explanation is: All equilateral triangles are congruent and therefore similar, with side lengths in a 1:1 ratio.
What are similar triangles?Those triangles look the same but are different in size.
And in similar triangles,
the corresponding sides are in proportion to each other and the corresponding angles are equal to each other.
In an equilateral triangle, all three sides are congruent, and all three angles are congruent.
Therefore, any equilateral triangle can be transformed into any other equilateral triangle through a combination of translations, rotations, and reflections, without changing the size or shape of the triangle.
Thus, all equilateral triangles are similar, with side lengths in a 1:1 ratio, since they have the same shape but may differ in size.
To learn more about similar triangles;
https://brainly.com/question/14926756
#SPJ7
(06.04 MC) Dennis drew the line of best fit on the scatter plot shown below: What is the approximate equation of this line of best fit in slope-intercept form?
Answer:
Step-by-step explanation:
In order to write the equation of this line, we need to pick 2 points on the graph where the line goes right through the intersection of the grids. Actually, you only need 1 of these, because the line goes through at (0, 15). Another point then can be (6, 6). Locate this point so you know what I means when I say that the line goes right through where the grids intersect at x = 6 and y = 6 (as opposed to somewhere in the middle of one of these grids). Find the slope between these 2 points:
[tex]m=\frac{6-15}{6-0}=-\frac{9}{6}=-\frac{3}{2}[/tex]
Since there's only one choice with that slope, that is the choice you want.
PLS HELP 19 POINTS!!!!!!!!
Answer:
Step-by-step explanation:
15. = 2.39
and jus use mathaway lma
If f(x)f(x) is an exponential function where f(1.5)=5f(1.5)=5 and f(7.5)=79f(7.5)=79, then find the value of f(3)f(3), to the nearest hundredth.
Answer: [tex]7.93[/tex]
Step-by-step explanation:
Given
[tex]f(x)[/tex] is an exponential function. Suppose [tex]f(x)[/tex] is [tex]ae^{bx}[/tex]
[tex]f(1.5)=5\ \text{and}\ f(7.5)=79[/tex]
[tex]\Rightarrow 5=ae^{1.5b}\\\Rightarrow \ln 5=\ln a-1.5b\quad \ldots(i)[/tex]
Similarly,
[tex]\Rightarrow 79=ae^{7.5b}\\\Rightarrow \ln(79)=\ln a+7.5b\quad \ldots(ii)[/tex]
Subtract (i) and (ii)
[tex]\Rightarrow \ln (79)-\ln (5)=9b\\\Rightarrow \ln (\frac{79}{5})=9b\\\\\Rightarrow b=\dfrac{\ln (\frac{79}{5})}{9}\\\\\Rightarrow b=0.3066[/tex]
Insert the value of [tex]b[/tex]
[tex]\Rightarrow 5=ae^{0.46}\\\Rightarrow a=5\times 0.6312\\\Rightarrow a=3.156\approx 3.16[/tex]
So, the function becomes
[tex]\Rightarrow f(x)=3.16e^{0.3066b}[/tex]
[tex]\Rightarrow f(3)=3.16e^{0.3066\times 3}\\\Rightarrow f(3)=7.927\approx 7.93[/tex]
Answer:
7.93
General Exponential Form: y=ab^x
Plug in both points
divide the equations
cancel out a, subtract exponent of b
Thank you so much, my friend
Answer:
Step-by-step explanation:
This is quite a doozy, my friend. We will set up a d = rt table, fill it in...and pray.
The table will look like this before we even fill anything in:
d = r * t
SUV
sedan
Ok now we start to pick apart the problem. Motion problems are the hardest of all story problems ever. This is because there are about 100 ways a motion problem can be presented. So far what we KNOW for an indisputable fact is that the distance from Georgetown to Greenville is 120 km. So we fill that in, making the table:
d = r * t
SUV 120
sedan 120
The next part is derived from the sentence "After an hour, the SUV was 24 km ahead of the sedan." This tells us the rate of the SUV in terms of the sedan. If the SUV is 24 km ahead of the sedan in 1 hour, that tells us that the rate of the sedan is r and the rate of the SUV is r + 24 km/hr. BUT we have other times in this problem, one of them being 25 minutes. We have a problem here because the times either have to be in hours or minutes, but not both. So we will change that rate to km/min. Doing that:
24 [tex]\frac{km}{hr}[/tex] × [tex]\frac{1hr}{60min}=.4\frac{km}{min}[/tex] So now we can fill in the rates in the table:
d = r * t
SUV 120 = r + .4
sedan 120 = r
They left at the same time, so now the table looks like this:
d = r * t
SUV 120 = r + .4 * t
sedan 120 = r * t
We will put in the time difference of 25 minutes in just a sec.
If d = rt, then the equation for each row is as follows:
SUV: 120 = (r + .4)t
sedan: 120 = rt
Since the times are the same (because they left at the same time, we will set the equations each equal to t. The distances are the same, too, I know that, but if we set the distances equal to each other and then solve the equations for a variable, the distances cancel each other out, leaving us with nowhere to go. Trust me, I tried that first! Didn't work.
Solving the first equation for time:
sedan: [tex]\frac{120}{r}=t[/tex] That's the easy one. Now the SUV. This is where that time difference of 25 minutes comes in from the last sentence. Let's think about what that sentence means in terms of the times of each of these vehicles. If the sedan arrived 25 minutes after the SUV, then the sedan was driving 25 minutes longer; conversely, if the sedan arrived 25 minutes after the SUV, then the SUV was driving 25 minutes less than the sedan. The latter explanation is the one I used in the equation. Again, if the SUV was driving 25 minutes less than the sedan, and the equations are solved for time, then the equation for the SUV in terms of time is
[tex]\frac{120}{r+.4}=t-25[/tex] and we solve that for t:
[tex]\frac{120}{r+.4}+25=t[/tex]
Again, going off the fact that times they both leave are the same, we set the equations equal to one another and solve for r:
[tex]\frac{120}{r+.4}+25=\frac{120}{r}[/tex]
I began by first multiplying everything through by (r + .4) to get rid of it in the denominator. Doing that:
[tex][r+.4](\frac{120}{r+.4}) +[r+.4](25)=[r+.4](\frac{120}{r})[/tex] which simplifies very nicely to
[tex]120+25(r+.4)=\frac{120}{r}(r+.4)[/tex] So maybe it's not so nice. Let's keep going:
[tex]120+25r+10=\frac{120r}{r}+\frac{48}{r}[/tex] and keep going some more:
[tex]130+25r=120+\frac{48}{r}[/tex] and now we multiply everything through by r to get rid of THAT denominator:
[tex]r(130)+r(25r)=r(120)+r(\frac{48}{r})[/tex] giving us:
[tex]130r+25r^2=120r+48[/tex] Now we have a second degree polynomial we have to solve by factoring. Get everything on one side and factor using the quadratic formula.
[tex]25r^2+10r-48=0[/tex]
That factors to
r = 1.2 and r = -1.6 and both of those rates are in km/minute. First of all, we cannot have a negative rate (this is not physics where we are dealing with velocity which CAN be negative) so we throw out the -1.6 and convert the rate of 1.2 km/minute back to km/hr:
[tex]1.2\frac{km}{min}[/tex] × [tex]\frac{60min}{1hr}[/tex] and we get
r = 72 km/h, choice B.
Wow...what a pain THAT was, right?!
HELP PLEASE 50 POINTS DONT ANSWER IF YOU DONT KNOW
The ratio 2:3 means for every 2 inches on the original, the photocopy would be 3 inches.
3/2 = 1.5
The photocopied image is 1.5 times larger than the original.
Side BG on the original is side FG on the copy:
14 x 1.5 = 21 meters
FG = 21 meters
Answer:
FG = 21
Step-by-step explanation:
The ratio is 2:3
2 BC
----- = ----------------
3 FG
2 14
----- = ----------------
3 FG
Using cross products
2FG = 3*14
2FG = 42
Divide by 2
FG = 21
THIS QS with explanation sum
Answer:
X = 276°
Step-by-step explanation:
Divide X into x1 and x2
then then using the trick of co-interior angles, find the answer of x1 and x2 . then add x1 and x2
When the polynomial is written in standard form, what are the values of the leading coefficient and the constant?
5x + 2 – 3x2
Answer:
leading coefficient -3
constant 2
Step-by-step explanation:
Standard from is from largest power to smallest power
-3x^2 +5x +2
The leading coefficient is the number in front of the largest power of x
-3
The constant is the number without a power of x ( or x^0)
2
Use the distributive property to write equivalent expressions.
Someone please help ty!
Answer:
12+27k
Step-by-step explanation:
distribute the 3
Instructions: Find the measure of the indicated angle to the nearest degree.
29 and 17
Answer:
30º
Step-by-step explanation:
because it is a right triangle, we can use trig functions to solve
tan^{-1}=17/29=30.379
{(5,2), (-2,4), (2, -7)}
Domain:
Range:
Answer:
Step-by-step explanation:
The domain are all the x values in order, no repeats allowed:
D = {-2, 2, 5}
Same thing for the range, except these are the y values:
R = {-7, 2, 4}
The coordinates stated this way don't match up to what they are in coordinate form, but they don't have to.
Answer:
Domain : {-2,2,5}
Range:{ -7,2,4}
Step-by-step explanation:
The domain is the inputs
Domain : {-2,2,5}
The range is the outputs
Range:{ -7,2,4}
Find the median of :- 25, 37, 27, 38, 29, 20, 39
Answer: The median is 29
Step-by-step explanation:
I started by arranging the data points from smallest to largest to get 20, 25, 27, 29, 37, 38, 39. Then I found the middle number in the data set and got 29.
Solve the system of equations using substitution.
y = x + 6
y = –2x – 3
Answer:
x = -3
y= 3
Step-by-step explanation:
y = x + 6 -----------------------(I)
y = -2x - 3 ---------------------(II)
Substitute y =x +6 in equation (II)
x + 6 = -2x - 3
Add 2x to both sides
x + 2x +6 = -3
Combine like terms
3x + 6 = - 3
Subtract 6 from both sides
3x = - 3 - 6
3x = -9
Divide both sides by 3
x = -9/3
x = -3
Plug in s = -3 in equation (I)
y = -3 + 6
y = 3
How do you solve this step-by-step?
Answer:
7 1/20OAmalOHopeO
-2(5x + 1) > 49
Solve for the inequality and enter your solution
Answer:
x < -51/10
General Formulas and Concepts:
Pre-Algebra
Equality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityStep-by-step explanation:
Step 1: Define
Identify
-2(5x + 1) > 49
Step 2: Solve for x
[Division Property of Equality] Divide -2 on both sides: 5x + 1 < -49/2[Subtraction Property of Equality] Subtract 1 on both sides: 5x < -51/2[Division Property of Equality] Divide 5 on both sides: x < -51/10Answer:
x < -51/10
Step-by-step explanation:
-10x -2 > 49
-10x > 51
x < -51/10
One of the diagonals of a rhombus of perimeter 120m is 36m. Find its area and the length of the other diagonal. pls answer fasttt
Answer: [tex]864\ m^2,\ 24\ m[/tex]
Step-by-step explanation:
Given
Perimeter of the rhombus is [tex]120\ m[/tex]
Length of one of the diagonal is [tex]d_1=36\ m[/tex]
All the sides of the rhombus are equal
[tex]\Rightarrow 4a=120\\\Rightarrow a=30\ m[/tex]
Area of the rhombus with side and one diagonal is
[tex]\Rightarrow \text{Area=}\dfrac{1}{2}d\sqrt{4a^2-d^2}[/tex]
Insert the values
[tex]\Rightarrow \text{Area=}\dfrac{1}{2}\times 36\times \sqrt{4\cdot 30^2-36^2}\\\\\Rightarrow \text{Area= }18\sqrt{3600-1296}\\\Rightarrow \text{Area= }18\times 48\\\Rightarrow \text{Area= }864\ m^2[/tex]
Area with two diagonals length can be given by
[tex]\Rightarrow \text{Area =}0.5\times d_1\times d_2 \\\text{Insert the values}\\\Rightarrow 864=36\times d_2\\\Rightarrow d_2=24\ m[/tex]
Thus, the area of the rhombus is [tex]864\ m^2[/tex] and the length of the other diagonal is [tex]24\ m[/tex]
its given that s=n(a+c)/2
Express c in terms of s, n and a
at a post office always charges a flat one-time fee for any order. One time, Michael sent 35 letters and paid 26 dollars. The next time, he send 18 letters and paid $14.10. How much does the post office charge to send one letter? What is the flat fee?
Answer:
The post office charges $0.7cents to send one letter, and the fee is $1.5
Step-by-step explanation:
For each relation, decide whether or not it is a function.
Answer:
Step-by-step explanation:
Relation 1 is a function
Relation 2 is not a function
Relation 3 is a function
Realation 4 is not a function
What is the exponential form of log3 2187 = 7?
Answer:
2187 = [tex]3^{7}[/tex]
Step-by-step explanation:
Using the rule of logarithms
[tex]log_{b}[/tex] x = n , then x = [tex]b^{n}[/tex] , then
[tex]log_{3}[/tex] 2187 = 7
2187 = [tex]3^{7}[/tex]
Answer:
3 ^7 = 2187
Step-by-step explanation:
log3 2187 = 7
log a (b) = c
a^c = b
3 ^7 = 2187
