Answer:
7b(a+2)
Step-by-step explanation:
First. look at the coefficient. See if they are common multiple of some number. If so find the GCF between them.
Then find the variable both terms share.
Put the GCF coeffiecnt and the variable both terms share outside the parentheses.
Inside the parenthesis will be a term that multiplied by the term outside of the parenthesis will equal the original equation.
For example, 7ab+14b.
Set up equation.
[tex]7ab + 14b[/tex]
Both terms share a b variable and 7 and 14 GCF is 7 so
let factor out 7b.
[tex]7b(a + 2)[/tex]
Why is inside the parenthesis is the term (a+2). If we divide 7ab+14b by 7b separately we get
[tex]a + 2[/tex]
Efetue as divisões indicadas.
a. 3,6 : 1,5
b. 42:0,21
c. 200:0,5
Answer:
a)
[tex] \frac{3.6}{1.5} = \frac{36}{15} = 2.4[/tex]
b)
[tex] \frac{42}{0.21} = \frac{4200}{21} = 200[/tex]
c)
[tex] \frac{200}{0.5} = \frac{2000}{5} = 400[/tex]
I hope I helped you^_^
50 POINTS HELP WILL MARK BRAINLIEST
find the value of x.
(picture attached)
1 3/4 divided by 2 3/8
will give brainiest pls help
Answer:
[tex]\frac{14}{19}[/tex]
First:
Convert any mixed numbers to fractions.
Then your initial equation becomes:
[tex]\frac{7}{4} \div \frac{19}{8}[/tex]
Applying the fractions formula for division:
[tex]= \frac{7 \times 8}{4 \times 19}[/tex]
[tex]= \frac{56}{76}[/tex]
Simplifying 56/76, the answer is:
[tex]\frac{14}{19}[/tex]
I hope this helps! :)
Answer:
the answer is 14/19
change the mixed numbers to improper fractions then that becomes 7/4 and 19/8 then multiply across 7x8=56 and 19x4=76 that gives you 56/76
Simplifying 56/76,= 14/19
Write another way to group the factor (3×2)×5 then find the product
Answer:
30
Step-by-step explanation:
Another way to group the factor would be 3(2×5)
2 times 5 is 10 and then 10 times 3 is 30 so therefore, your answer is 30
Yolanda has 3/4 of a cup of sugar. This is 3/5 of what she needs. How much sugar does Yolanda need?
Show your reasoning.
Answer:
[tex]1\frac{1}{4}[/tex] cups
Step-by-step explanation:
1. Info we have3/4=3/5
2. Solving3/4*1/3=3/5*1/3
1/4 = 1/5
1/4*5=1/5*5
5/4=5/5
5/4= 1 and 1/4 cups
Hope this helped! Please mark brainliest :)
~~ SUMMER ~~
the quotient of 5+h and n+3
Answer:
5+h/n+3
Step-by-step explanation:
5+h is numerator
and n+3 is denominator
so you make it a fraction to get the quotient which is 5+h/n+3
The circumference of a circular garden is 113.04 feet. What is the radius of the garden? Use 3.14 for pie and do not round your answer.
Answer:
18 ft
Step-by-step explanation:
The circumference of a circle is given by
C = 2 * pi *r
113.04 = 2 ( 3.14) * r
113.04 = 6.28 r
Divide each side by 6.28
113.04/6.28 = 6.28r/6.28
18 =r
Can someone plz help me?
Answer:
Its D
Step-by-step explanation:
i just guessed! but i think its D!<3
2. sale price $1,089
sales tax rate: 6.25%
Answer:
0.0625
Step-by-step explanation:
Express each mixed number as a percent 2 1/2 can someone please tell me the awnser
Answer:
im pretty sure its 250%
Step-by-step explanation:
Answer:
250%
Step-by-step explanation:
1 is 100% and double that is 200%
1/5 of 100% is 50%
200% + 50% = 250%
Factor this polynomial completely.
6x2 + 7x - 20
If f(x) = + 8, what is f(x) when x = 10?
O4
O 9
O 13
O 36
Answer:
4 step by step explanation
The at {x} = 10, the value of the function remains +8.
What is function?A function is a relation between a dependent and independent variable. We can write the examples of functions as -
y = f(x) = ax + b
y = f(x, y, z) = ax + by + cz
Given is that the function f(x) is defined as -
f(x) = + 8
The given function is a constant function. This means that the value of the function remains the same irrespective of the value of {x} or the value in the function domain. So, at {x} = 10, the value of the function remains +8 only. This is true for all the values of {x}.
Therefore, the at {x} = 10, the value of the function remains +8.
To solve more questions on functions, visit the link below-
https://brainly.com/question/30194223
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pls answer will choose brainliest
Hi ;-)
[tex]\text{x}=-1 \ \text{and} \ \text{y}=-4\\\\\dfrac{5x^2-y^2+3}{2x-4y}=\dfrac{5\cdot(-1)^2-(-4)^2+3}{2\cdot(-1)-4\cdot(-4)}=\dfrac{5\cdot1-16+3}{-2+16}=\boxed{-\frac{8}{14}}[/tex]
For the equation: – 36 – 4r = -2(-6 + 6r), what is the value of r?
Answer:
r = 6
Step-by-step explanation:
– 36 – 4r = -2(-6 + 6r)
+36 +36
----------------------------------
-4r = -12r + 48
+12r +12r
----------------------------------
8r = 48
/8 /8
----------------------------------
r = 6
Answer:
r = 6
Step-by-step explanation:
– 36 – 4r = -2(-6 + 6r)
-36 - 4r = 12 - 12r
-48 - 4r = -12r
-48 = -8r
r = 6
Hi I need help On his Multiple Choice questions Try)- and not get it wrong or I cant Complete My Maths Work. The Question itself is on the Image attached Below: thanks!
Answer:
a) Option A is correct.
b) Option B is correct.
Step-by-step explanation:
[tex]a) \: \: 5 \times a \\ = 5a[/tex]
[tex]b) \: \: b \times b \\ = {b}^{2} [/tex]
Hope it is helpful.....im bad at math and i need help
Answer:
n•√n
here is an accurate representation
What is the period of the function given?
pls
Answer:
2. ☑ A [tex]\displaystyle f(x) = tan\:\frac{1}{2}x[/tex]
☐ B [tex]\displaystyle f(x) = tan\:2x[/tex]
☐ C x = [tex]\displaystyle 2tan\:x[/tex]
1. ☐ A [tex]\displaystyle \frac{\pi}{2}[/tex]
☐ B [tex]\displaystyle \pi[/tex]
☑ C [tex]\displaystyle 2\pi[/tex]
Explanation:
[tex]\displaystyle \boxed{f(x) = -cot\:(\frac{1}{2}x - \frac{\pi}{2})} \\ \\ y = Acot(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\pi} \hookrightarrow \frac{\frac{\pi}{2}}{\frac{1}{2}} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{\pi}{\frac{1}{2}} \\ Amplitude \hookrightarrow N/A[/tex]
OR
[tex]\displaystyle y = Atan(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{\pi}{\frac{1}{2}} \\ Amplitude \hookrightarrow N/A[/tex]
Here is all the information you will need. Now, what you need to know is that ALL tangent, secant, cosecant, and cotangent functions have NO amplitudes. Also, keep in mind that although this IS the tangent graph, if you plan on writing your equation as a function of cotangent, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = cot\:\frac{1}{2}x,[/tex] in which you need to replase "tangent" with "cotangent", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the tangent graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cotangent graph [photograph on the right] is shifted [tex]\displaystyle \pi\:units[/tex] to the left, which means that in order to match the tangent graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle \pi\:units,[/tex] which means the C-term will be positive, and perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\pi} = \frac{\frac{\pi}{2}}{\frac{1}{2}},[/tex] but we are NOT YET DONE. Although we shifted the graph back into position, remember, cotangent is graphed in REVERCE, so we need to insert a negative in front of the amplitude term, and with that, the cotangent graph of the tangent graph, accourding to the horisontal shift, is [tex]\displaystyle y = -cot\:(\frac{1}{2}x - \frac{\pi}{2}).[/tex] Now, with all that being said, we can move forward. To find the period in this case, you need to take a look at the distanse between each vertical asymptote. Now, accourding to this graph, the vertical asymptotes are [tex]\displaystyle -\pi = x\:and\:\pi = x.[/tex] From here, you will then find the distanse between these asymptotes by simply perfourming the operation of Deduction, and doing that will give you [tex]\displaystyle \boxed{2\pi} = \pi + \pi.[/tex] So, the period of this function is [tex]\displaystyle 2\pi.[/tex] Now, you will instantly get the jist of the horisontal shift by looking at the above formula. Just keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must pay cloce attention to what is given to you inside those parentheses. Finally, the midline is the centre of your graph, also known as the vertical shift, which in this case is at [tex]\displaystyle y = 0.[/tex]
Well, that just about wraps it up. Now that everything has been explained, you should understand it better. If you still have questions, do not hesitate to comment any you have.
I am delighted to assist you at any time.
49 divided by 679 i ask too many questions im honestly just tryna get through this year fast lol.
Answer:7/97 or 0.072165
Step-by-step explanation:
I need help with Shape equation puzzle 2 it’s due tomorrow
Hey there! I'm happy to help!
First of all, I would guide you to decipher clue 2 first. It is the only one that has just one shape, so then we can find the value of that shape.
To find what this circle is, we just divide 12 by three to see what 3 times the circle is!
12÷3=4
CIRCLE=4
-----------------------------------------------------------------
Now, let's look at clue one. This one only has two shapes, and it has the circle, which we already know.
We know that our circle is 4, so 5 circles will be 20.
This means that the diamond plus two will be 20, so let's just subtract 2 from 20!
20-2=18
DIAMOND=18
-----------------------------------------------------------------
Finally, let's look at the third one. This one is the trickiest. Two circles is eight, and that is going to be equal to our diamond (eighteen) and two triangles.
How is that going to work?
The triangles make us go backwards! Otherwise known as negative numbers!
To get from eighteen to eight, we have to go back ten. Ten is going to be made up of two triangles, so we just divide ten by two so each triangle gets an equal amount.
10÷2=5
TRIANGLE=5
-----------------------------------------------------------------
Have a wonderful day and keep on learning! :D
An equation is formed of two equal expressions. The value of the Circle, Diamond, and the triangle is 4, 18, and -5, respectively.
What is an equation?An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
Let the circle be represented by C, the diamond be represented by D, and the triangle be represented by T.
Now, the clues can be rewritten as,
D + 2 = 5(C)
3(C) = 12
2(C) = D + 2(T)
Since the second clue has only one variable C, let's solve it first,
3(C) = 12
C = 12 / 3
C = 4
Further, the first clue has two variables C and D, and the value of C is already known, therefore, solve it second.
D + 2 = 5(C)
D + 2 = 5(4)
D + 2 = 20
D = 20 - 2
D = 18
Furthermore, by solving the last Clue we will get,
2(C) = D + 2(T)
Substitute the known values,
2(4) = 18 + 2(T)
8 = 18 + 2T
8 - 18 = 2T
-10 = 2T
T = -5
Hence, the value of the Circle, Diamond, and the triangle is 4, 18, and -5, respectively.
Learn more about Equation here:
https://brainly.com/question/14686792
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answer quick pls!!
Find the ordered-pair solution of y = 4x + 1 that corresponds to x = -1
Answer:
(- 1, - 3 )
Step-by-step explanation:
Substitute x = - 1 into the equation and evaluate for y
y = 4(- 1) + 1 = - 4 + 1 = - 3
solution is (- 1, - 3 )
Which statement compares the numbers correctly 23.811 > twenty-three and eight hundred eleven thousandths Twenty-three and eight hundred eleven thousandths > 23.811 Twenty-three and eight hundred eleven thousandths < 23.811 Twenty-three and eight hundred eleven thousandths = 23.811
Answer:
The correct answer is A.
Step-by-step explanation:
Find (dy/dx) when x=2at,y=at^2
Answer:
https://www.teachoo.com/3815/705/Example-35---Find-dy-dx--if-x--at2--y--2at---Class-12-CBSE-/category/Examples/
The student looks up the word count on his favorite book, if the book has pages that are 5.5 in. x 6.5 in. and 59,540 words how many pages is the book? (This sentence and picture combine.)
Answer:
199 pages
Step-by-step explanation:
The average number of words on the page is 300. Because there are 59,540 words and 59540/300 = 198.46 (approximately), there are 199 pages in the book (because the 0.46 pages would be the last page).
Rectangle ABCD translates 4 units down and 2 units to the right to form rectangle A'B'C'D'. The vertices of rectangle ABCD are labeled in alphabetical order going clockwise around the figure. If AB = 3 units and AD = 5 units, what is the length of B'C'? A. 5 units B. 9 units C. 11 units D. 3 units
Answer:5 units
Step-by-step explanation:
Answer:
5
Step-by-step explanation:
Cathy are in $16 per day how much will she have at the end of 64 days
Answer:
1024
Step-by-step explanation:
multiply 16 by 64
Select the two values of x that are roots of this equation.
2x^2+ 1 = 5x
Answer:
[tex]\frac{5+\sqrt{17}}{4}[/tex], [tex]\frac{5-\sqrt{17}}{4}[/tex]
Step-by-step explanation:
One is asked to find the root of the following equation:
[tex]2x^2+1=5x[/tex]
Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:
[tex]ax^2+bx+c=0[/tex]
Change the given equation using inverse operations,
[tex]2x^2+1=5x[/tex]
[tex]2x^2-5x+1=0[/tex]
The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:
[tex]\frac{-b(+-)\sqrt{b^2-4ac}}{2a}[/tex]
Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,
[tex]\frac{-b(+-)\sqrt{b^2-4ac}}{2a}[/tex]
[tex]\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}[/tex]
Simplify,
[tex]\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}[/tex]
[tex]\frac{5(+-)\sqrt{25-8}}{4}[/tex]
[tex]\frac{5(+-)\sqrt{17}}{4}[/tex]
Rewrite,
[tex]\frac{5(+-)\sqrt{17}}{4}[/tex]
[tex]\frac{5+\sqrt{17}}{4}[/tex], [tex]\frac{5-\sqrt{17}}{4}[/tex]
how do you solve 11=t+11.5-t?
Equations are represented with the = sign. It means both sides of the equation are equal. [tex]11=t+11.5-t[/tex] has no solution
Given that:
[tex]11=t+11.5-t[/tex]
Start by collecting like terms
[tex]11-11.5=t-t[/tex]
Evaluate like terms
[tex]-0.5 = 0[/tex]
-0.5 is not equal to 0.
Hence, the equation has no solution
Read more about equations at:
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round off 19340 to 1 s f
Answer:
20000
Step-by-step explanation:
This is because when you round to the signifigant figure, you basically look at any digits at the start of the number, which isn't zero. In this case it would be in the ten thousand 19340. So you round 19340 to the nearest 10 thounsand, which, would be 20000
kendra revived a bonus that was 30%of her monthly earnings is her monthly earnings were 930 how much was kendras bonus
Hey there! I'm happy to help!
30% is the same thing as 0.3 because 0.3 is 30% of 1. If you multiply something by 1, it will just stay the same, so you need that percent of 1.
To convert a decimal to a percent, you move the decimal to the left two spaces.
Now, we simply multiply this by 930.
0.3×930=279
So, Kendra will receive a bonus of $279.
Have a wonderful day and keep on learning! :D
AC = 3x-1 and AD = 12-x
X=
CD =
Answer:
54+456/79*78=5689
Step-by-step explanation:
maaf kalo salah
[tex]45 \times 456[/tex]
