How do DNA and RNA differ?
Answers
Answer:
DNA is a long polymer with deoxyriboses and phosphate backbone. Having four different nitrogenous bases: adenine, guanine, cytosine and thymine. RNA is a polymer with a ribose and phosphate backbone. Four different nitrogenous bases: adenine, guanine, cytosine, and uracil.
Answer:
DNA contains the sugar deoxyribose, while RNA contains the sugar ribose. DNA is a double-stranded molecule, while RNA is a single-stranded molecule. DNA is stable under alkaline conditions, while RNA is not stable. DNA and RNA perform different functions in humans.
Explanation:
Related Questions
cual es el productor del que más consumidores primarios se alimentan
Answers
Answer:
please let us know what you mean in English
Answer:
Plantas o Algas son unos productos que consumen.
Explanation:
Equilibrium is when the concentration is the same throughout an entire system. Explain how a cell reaches equilibrium in all three types of solutions (hypertonic, hypotonic, and isotonic).
Answers
It is pertinent to understand what hypertonic, hypotonic, and isotonic solution means before setting out to explain how a cell reaches equilibrium in each type of solution.
A hypertonic solution is one whose solute concentration is higher than that of the sap of a cell that is immersed in it.A hypotonic solution is one with the same solute concentration as that of the sap of the cell immersed in it.An isotonic solution has a lower solute concentration than that of the sap of the cell immersed in it.In biological systems, water molecules move by osmosis from the region of higher water potential or lower concentration of solutes to the region of lower water potential or higher concentration of solute. An equilibrium is reached when there is no net movement of water between two sides. Hence;
A cell placed in a hypertonic solution will lose water to the surrounding solution until an equilibrium is reached. This means that such a cell will end up shrinking (wilting) or even dying due to loss of water from the cell sap.A cell placed in a hypotonic solution will gain water from the surrounding solution until there is no net movement of water anymore. Such a cell might become turgid or even burst out its cell content.A cell placed in an isotonic solution will neither gain nor lose water because the cell sap and the surrounding solution have equal solute concentrations.More about osmosis here: https://brainly.in/question/1213189
Answer:
A cell placed in a hypertonic solution will lose water to the surrounding solution until an equilibrium is reached. This means that such a cell will end up shrinking (wilting) or even dying due to loss of water from the cell sap.
A cell placed in a hypotonic solution will gain water from the surrounding solution until there is no net movement of water anymore. Such a cell might become turgid or even burst out its cell content.
A cell placed in an isotonic solution will neither gain nor lose water because the cell sap and the surrounding solution have equal solute concentrations.
the results of an experiment can be validated through replication true or false
Answers
Answer:
True through replication
Answer:
this is true
Explanation:
The prevalence of CRE infections in health care settings has increased significantly in recent years, in part because these organisms are able to share plasmid-encoded resistance genes. Which method of horizontal gene transfer is most likely responsible for transfer of the plasmid between bacteria
Answers
Answer:
Bacterial conjugation
Explanation:
Carbapenem-resistant Enterobacterales (CRE) are different types of bacteria that lead to infections in healthcare settings. Moreover, a plasmid is a small piece of DNA that can replicate independently from the bacterial chromosome. Bacterial conjugation is a type of horizontal gene transfer by which plasmids are transferred from one bacterium referred to as 'donor' into another called 'recipient' by sex pili. Plasmid transfer is unidirectional and depends on physical contact between bacterial cells. In this case, it is expected that this type of DNA transport mechanism occurs among patients occupying the same rooms in healthcare settings.
Question 4
What happens to the host cell at the end of the lytic cycle?
the cell breaks open and releases the new viruses
viral DNA combines with host DNA
the host cell divides normally and reproduces viral DNA along with it's own
new viruses are made inside the bacterial cell
Answers
Answer:
In the lytic cycle, a phage acts like a typical virus: it hijacks its host cell and uses the cell's resources to make lots of new phages, causing the cell to lyse (burst) and die in the process.
Explanation:
Hope this helps.
diffrences between pine tree and mango tree
Answers
well ones a pine tree, and ones a mango tree
Answer:
A:pine tree is also know as Christmas tree
Explanation:
B:mango tree is broad andextremly big
According to the theory of natural selection, why are some individuals more likely than others to survive and reproduce?
1Points
A
Some individuals pass on to their offspring new characteristics they have acquired during their lifetimes.
B
Some individuals are better adapted to exist in their environment than others are.
C
Some individuals do not pass on to their offspring new characteristics they have acquired during their lifetimes.
D
Some individuals tend to produce fewer offspring than others in the same environment.
Answers
Forming a hypothesis is the first step of the scientific method.
Answers
Answer:
The first step in the Scientific Method is to make objective observations. These observations are based on specific events that have already happened and can be verified by others as true or false. Step 2. Form a hypothesis.
Explanation:
The hypothesis is an educated guess as to what will happen during your experiment. The hypothesis is often written using the words "IF" and "THEN." For example, "If I do not study, then I will fail the test." The "if' and "then" statements reflect your independent and dependent variables
how is the cell membrane adapted to it's function
Answers
b) Describe two measures each to conserve natural vegetation and wildlife, Class 8 - Geography - Unit 1 betwen 90to100 words
Answers
Answer:
Afforestation and national sanctuaries are two measures each to conserve natural vegetation and wildlife.
Explanation:
The natural vegetation and wildlife restoration is one of the main concerns that are essential for the development and growth of a country's biodiversity. Due to human land-use changes and migration of people, from one place to another with their cattle, lands are becoming deserted and grassland and forest land are declining.
So, we need to plant more trees that act as the natural habitat for the wildlife and preserve and conserve them in parks and sanctuaries which will help reduce the impacts of global warming and climate change. We should not kill any animal.We should decrease the use of plastics.C What is the important of making prority
Answers
Answer:
Priorities will guide you in life's decisions and keep you on track. Most importantly, priorities will give you the confidence to say "no." They help you identify what's truly needed in your life, versus what someone else feels is important.
Answer:
The importance of it are Establishing priorities is necessary in order to complete everything that needs to be done. Prioritization is important because it with allow you to give your attention to tasks that are important and urgent so that you can later focus on lower priority tasks.
A pure substance containing only one kind of blank hurry
Answers
Answer:
elements
Explanation:
Which tools would I use to heat 400 mL of water
Answers
Answer:
ruler, graduated cylinder
Explanation:
The meaning of the term ionic bond
Answers
Answer:
A type of Chemical Bonding that includes electrostatic attraction between opposite ions.
Explanation:
Ionic bonds are the attraction of two opposite ions.
An ion is an atom that has a net electric charge.
In meiosis, sister kinetochores are attached to the same pole of the cell during meiosis I, and sister chromatid cohesion is released during anaphase II. What would be the likely result if sister kinetochores were attached to different poles of the cell during meiosis I and sister chromatid cohesion was released during anaphase I
Answers
Answer:
sister chromatids would migrate to opposite poles in anaphase I
Explanation:
Kinetochores are multiprotein structures that establish the attachment of spindle microtubules to the chromatids during cell division (either mitosis or meiosis). Sister chromatid cohesion at the centromeres refers to the mechanism by which sister chromatids are paired and held together during meiosis I. This process (sister chromatid cohesion) is fundamental to ensure the correct orientation of chromatids on the spindle microtubules and their subsequent segregation in meiosis II. The fusion of sister kinetochores in meiosis I underlies sister chromatid cohesion during this stage of the cell division, thereby their disruption or destruction of sister chromatid cohesion would lead to separation and segregation of sister chromatids to opposite poles of the cell in anaphase I.
A child is suffering from fever but the doctor cannot immediately pinpoint the ailment on the basis of this one symptom. Explain why. Also mention another two such general symptoms.
Answers
the child can also have sore and or maybe stomach problems. it can be indigestion
so there are various conditions one can go through and this may take time for a doctor to discover or bring to light the medical condition that the person I'd goin thru
Explanation:
please notify me if I'm incorrect
blood flows through many small tubes if the dialyser. what is the significance of this
Answers
Answer:
Blood flows through smaller tubes to mimic the actual rate of blood flow in the body. This makes the dialysis machne safe for the body. Th dialysis machine can also adjust pressure in accordance of a persons blood pressure
Explanation:
Questions for Activity 3: Making Molecular Models of Aerobic and Anaerobic Respiration
Text BoxDraw what you think the models of aerobic and anaerobic respiration would look like if you constructed them using models like in figures 3-6
Answers
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Irineu vc não sabe nem eu
sksosmmsos!s s s s s. s sim cofmc. kc c. ocmc c. ximc.
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sou toxic
toma trou xa deu mtos pontos atoa kakakakakaja
Which group evolved first?
rays
skates
sharks
chimaeras
Answers
Answer:
C - Sharks; (took the test)
Explanation:
Sharks evolved nearly 420 million years ago. Chimeras, skates, and rays are all related to sharks through their ancestry.
Answer:
I hope this helps.
Explanation:
Please help me with this on the picture
Answers
There is a U-tube in which solutions in two arms A and B are separated by a membrane. Arm A contains glucose with concentration of 0.4 mol per liter and sodium chloride with concentration of 0.5 mol per liter. Arm B contains glucose with concentration of 0.8 mol per liter and sodium chloride with concentration of 0.4 mol per liter.
The solutions in the arms of a U-tube (the figure) are separated at the bottom of the tube by a selectively permeable membrane. The membrane is permeable to sodium chloride but not to glucose. Side A is filled with a solution of 0.4 M glucose and 0.5 M sodium chloride (NaCl), and side B is filled with a solution containing 0.8 M glucose and 0.4 M sodium chloride. Initially, the volume in both arms is the same.
If you examine side A in the figure after three days, the concentrations of glucose and NaCl should be _____________.
Answers
Answer:
0.4 M glucose, 0.45 M NaCl
Explanation:
I hope this helped!
Harry is doing a research project on the movement of plants from the ocean to land. He leaned that plants evolved
vascular tissues, which enabled them to pull water from the ground and survive on land. Which is most likely
another adaptation that contributed to the success of land plants?
cell walls?
chloroplasts
waxy cuticle
gametes
Answers
Answer:
Waxy Cuticle
Explanation:
Waxy Cuticle retains water. It's the closest in terms of surviving on land. For instance, the plants living in water do not need waxy Cuticle to retain or maintain water. The plants on land requires waxy Cuticle because the temperature is hotter than in the water and they are at higher risk of loosing water during hot seasons and climate. waxy Cuticle aids in their water retention allowing them to adapt to live on land.
ruth is presenting the feedback model to her class help her complete the statements
Answers
Answer:
Feedback models are tools that provides specific, concise, and clear feedback for a particular thing.
Explanation:
Feedback models are tools that provides specific, concise, and clear feedback for the organization so that an organization can make useful changes which is necessary for the organization growth and development. There is high need of this feedback model which helps us to know about the specific areas where one needs to improve performances in order to work more effectively.
Does anyone know the answer for the question four?
Answers
Answer:
I think it's A
Explanation:
it is because the populations of trees are decreasing as deforestation continues, so there is less resistance to greenhouse gases. please correct me if I'm wrong
7. To test a new voice feature in a cockpit design a flight simulator was used. The simulator was programmed to
give visual readings of flight information, or to give visual and auditory (voice) readings of flight information. All
test pilots were put through a simulated emergency landing procedure, but were randomly assigned to the
visual, or visual and auditory conditions. Flight experts rated each pilot's performance in the simulator on a
scale of 1 (very poor) to 10 (excellent).
Answers
The variables in the simulation procedure carried out are :
Independent variable = Simulator Independent variable = Simulator Dependent variable = PerformanceThe dependent and independent variables are critical in any experimental study as both variables encompasses the variable to be measured and the variables manipulated in other to obtain the variable to be measured.
Independent variable : This is also called the predictor variable which is tweaked in other to obtain changes in the measured or dependent variable. In the experiment performed, the simulator is the independent variable has it has different visual or visual and auditory conditions capable of causing changes to the performance rating. The dependent variable is the variable being measured in an experiment. In this case, it is PERFORMANCE. It is the measured output obtained as the the pilot are being rated based on the simulation.Learn more : https://brainly.com/question/4497530
_____ are related to poor productivity of harvest due to poor care for soil.
Answers
Answer:
Soil Tillage, Climate Change and Soil Carbon Sequestration
Explanation:
A _____ country has high population density.
A: Densley populated country
B: Sparsely populated country
C: Open country
D: Overpopulated country
Answers
Answer:
A. A Densley populated country.
Explanation:
Sheets composed of two layers of amphipathic molecules arranged with the hydrophilic groups on the surface and the hydrophobic groups buried in the center that form in water are called A) micelles. B) liposomes. C) vacuoles. D) bilayer membranes. E) none of the above
Answers
Answer:
D) bilayer membranes
Explanation:
Two lipidic bilayers compose the cell membrane. There are also proteins and glucans incrusted in between. Lipids are amphipathic molecules with hydrophilic heads -negatively charged phosphate group- and hydrophobic tails. Lipids are arranged with their hydrophilic polar heads facing the exterior and the interior of the cells, while their hydrophobic tails are against each other, constituting the internal part of the membrane. Membranes are fluid, which means that the composing molecules can move through them.
Lipids can easily change places with other neighboring lipids by lateral diffusion in the same layer. This is passive diffusion, which means that it does not need energy to happen.
Lipids can also diffuse transversally to the other layer but not as easily as lateral diffusion. Jumps between monolayers are infrequent as the lipidic polar heads meet the fatty acid barrier.
There are also other lipidic movements as rotational diffusion that imply the rotation of the molecule.
When calcium carbonate is heated, it
decomposes into calcium oxide and carbon
dioxide. If 100 g of calcium carbonate are
decomposed, 56 g of calcium oxide is produced.
What would be the mass of the carbon dioxide
given off by the decomposition?
A. 448
B. 110 g
C. 156 g
Answers
Answer:
A. 44 g
Explanation:
First, you need to write a balanced equation:
CaCO₃ -> CaO + CO₂
Then, you need to find the molar mass of CaCO₃:
Ca = 40.078 amu
C = 12.0107 amu
3O = 47.9982 amu
_________________
100.0869 amu
Then, you calculate the moles of CaCO₃:
100 g ÷ 100.0869 amu = 0.9991 moles
In the balanced equation, we can see that the molar ratio of CaCO₃ and CO₂ is 1 : 1, so moles of CaCO₃ = moles of CO₂.
Now you need to find the molar mass of CO₂:
C = 12.0107 amu
2O = 31.9988 amu
________________
44.0095 amu
Finally, you can calculate the mass of CO₂ produced:
0.9991 moles * 44.0095 amu = 43.9698 g = 44 g
Sometimes the most practical way to do an experiment is not to perform it in an animal, but to look at cell responses in culture. Cells from mice, humans, and other mammals have been used to establish cell culture lines that have been very important for research. You are studying a novel water-soluble mouse hormone. You know cell culture can be a practical model to reveal protein function, so you apply the hormone to yeast cells, but nothing happens. What is a likely explanation for why nothing happened in your experiment
Answers
Answer:
Yeast cells likely do not have receptors that bind to this specific water-soluble mouse hormone
Explanation:
Receptors are molecules capable of binding specific signaling molecules (i.e., ligands). For example, steroid receptors can only bind to specific steroid hormones (e.g. estrogen, progesterone). Plasma membrane receptors are protein receptors that bind to water-soluble ligands. These receptors are embedded in the cell plasma membrane and usually contain several transmembrane domains. Examples of cell membrane receptors include G protein-coupled receptors (GPCRs), enzyme-linked protein receptors and ion channel receptors.
