How can we use the distributive property to find an expression equivalent to 4(5−3x)
? Place the steps in order.

The translation used to create the image include the following: A. 5 units down.

In Mathematics and Geometry, the translation of a geometric figure or graph to the left simply means subtracting a digit from the value on the x-coordinate of the pre-image;

g(x) = f(x + N)

Conversely, the translation a geometric figure downward simply means subtracting a digit from the value on the positive y-coordinate (y-axis) of the pre-image; g(x) = f(x) - N.

Based on the information provided, we have:

(x, y)                               →                  (x + h, y + k)

(1, -1)                              →                   (1, -6).

1 + h = 1

h = 1 - 1

h = 0

-1 + k = -6

k = -6 + 1

k = -5.

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Answer: -1/2

Step-by-step explanation:

1. We know that -2 1/3 is also equal to -7/3, because we can multiply the denominator by the main number, and add the numerator.

2. We can do the same with 4 2/3, which would be 14/3.

3. Now, we are left with -7/3 divided by 14/3.

4. To make this easier, we can flip flop the 14/3 so we can multiply instead of divide, which leaves us with -7/3 x 3/14.

5. -7/3 x 3/14 = -21/42

6. We can simplify this to -1/2.

Answer:

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Step-by-step explanation:

Answer:

f(2) = 0

f(-4) = 24

Step-by-step explanation:

[tex] \hookrightarrow \: { \tt{ \sf{f(n) = {n}^{2} - 2n }}}[/tex]

When n is 2 ✔

[tex] \dashrightarrow \: { \tt{f(2) = {(2)}^{2} - (2 \times 2) = 4 - 4 = 0}} \\ [/tex]

When n is -2 ✖

[tex] \dashrightarrow { \tt{ {( - 2)}^{2} - (2 \times - 2) = 4 + 4 = 8 }}[/tex]

When n is 1 ✖

[tex] \dashrightarrow{ \tt{f(1) = {(1)}^{2} - (2 \times 1) = - 1 }}[/tex]

When n is 5 ✖

[tex] \dashrightarrow{ \tt{f(5) = {(5)}^{2} - (2 \times 5) = 15}}[/tex]

When n is -4 ✔

[tex] \dashrightarrow{ \tt{f( - 4) = {( - 4)}^{2} - (2 \times - 4) }} \\ { \tt{ = 16 + 8}} \\ { \tt{ = 24}}[/tex]