We may approximate the sin 165 angles using trigonometric formulas as: tan 165°/(1 + tan2(165°)) (1-cos2(165°))...
Trigonometric identities enable the expression of sin 165° as,
Sin (15°) = sin(180° - 165°)
(-sin 180 + -sin 165) = -sin 345
cos(-75°) = cos(-90° - 165°)
(90 + 165)/255 = -cos 255
Explanation: We know that cos(165) is negative and sin(165) is positive because 165 is in QII. We will use 330 with in half angle formulae because 165=3302.
165 degrees are somewhere between 90 and 180 degrees. Hence, it has an acute angle.
Hence, the 165° angle's addition is 15°. Q. Below are a few angles' measurements.
525 is a positive number of interactions angle, while 195 is a negative coterminal angle.
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In a hat, you have index cards with the numbers 1 through 10 written on them. Find how many of the 10 possible numbers you can pick match the described event, then drag and drop each of the numbers into the correct box to order the events from least likely to happen (1) to most likely to happen (8) when you pick one card at random.A. You pick a number greater than 0.B. You pick an even number.C. You pick a number that is at least 2.D. You pick a number that is at most 0.E. You pick a number divisible by 3.F. You pick a number divisible by 5.G. You pick a prime number.H. You pick a number less than the greatest prime number among the numbers 1 through 10.
The order of events from least likely to most likely are as follows:
D. You pick a number that is at most 0A. You pick a number greater than 0C. You pick a number that is at least 2B. You pick an even numberE. You pick a number divisible by 3F. You pick a number divisible by 5G. You pick a prime numberH. You pick a number less than the greatest prime number among the numbers 1 through 10The reason for this order is because of the chances of each event occurring. Event D has the least chance of occurring because no numbers in the set have a value less than or equal to 0. Event A is the next least likely because only one number in the set is greater than 0, which is the number 1. Event C is the next least likely because only two numbers in the set are at least 2 (2 and 3). Event B is the next least likely, as there are only five even numbers in the set (2, 4, 6, 8, and 10). Events E, F, G, and H are the most likely to occur, because of the number of numbers that are divisible by 3, and 5, and are prime numbers.
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Algebra question help asap
If the value of the Bulls Eye stock has fallen 8% annually since 2010, it will be worth $32.90 in 2015.
What is the mathematical formula for profit?The formula Profit = Selling Price - Cost Price can be used to determine the profit when the selling price and the cost price of a product are known. The formula for calculating profit percentage is then applied, which is profit percentage = (profit/cost price) x 100.
If the value of the Bulls Eye stock has dropped by 8% annually, it has dropped to 92% (100% - 8%) of its value from the prior year.
Since we're moving from 2010 to 2015, we must multiply this loss five times to determine the stock's value in 2015:
Value in 2011 = 92% of $50 = $46
Value in 2012 = 92% of $46 = $42.32
Value in 2013 = 92% of $42.32 = $38.89
Value in 2014 = 92% of $38.89 = $35.77
Value in 2015 = 92% of $35.77 = $32.90
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calculate the centripetal force (in n) on the end of a 52 m (radius) wind turbine blade that is rotating at 0.3 rev/s. assume the mass is 2 kg
The centripetal force is 7384.80 N.
For the centripetal force in N on the end of a 52 m (radius) wind turbine blade that is rotating at 0.3 rev/s and assuming the mass is 2 kg.
Use the following formula:
Centripetal force = (mass x velocity²) / radius
Where; mass = 2 kg
In this case, the radius of the wind turbine blade is 52 m, and it is rotating at 0.3 rev/s, which means that the angular velocity is:
ω = 2π * f = 2π * 0.3 = 1.884 rad/s
where f is the frequency or revolutions per second.
The linear velocity at the end of the blade can be calculated as:
v = r * ω ⇒ 52 * 1.884 ⇒ 98.088 m/s
radius = 52 m
Centripetal force = (2 x 98.088²) / 52
Centripetal force = 7384.80 N
Therefore, the centripetal force on the end of a 52 m wind turbine blade rotating at 0.3 rev/s with a mass of 2 kg is 7384.80 N.
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Can someone just help me on 19, it’s pretty confusing. Just look around at the other questions so it’ll help with answering it.
Answer:
0% (0/40)
Step-by-step explanation:
I feel like this is a trick question. since chicken is not indicated on the graph, I believe chicken is nobodies favorite food
NEED HELP DUE TODAY!!!! GIVE GOOD ANSWERS PLEASE!!!!
2. How do the sizes of the circles compare?
3. Are triangles ABC and DEF similar? Explain your reasoning.
4. How can you use the coordinates of A to find the coordinates of D?
Answer:the triangles are similar to each other by AA rule and EF = 8.
Step-by-step explanation:
the triangles are similar to each other by AA rule and EF = 8.
this should help if wrong sorry im in middle school so
Please help quick with this question.
Answer:
b = [tex]\frac{S-2la}{h+l}[/tex]
Step-by-step explanation:
S = bh + lb + 2la ( reversing the equation )
bh + lb + 2la = S ( subtract 2la from both sides )
bh + lb = S - 2la ← factor out b from each term on the left side
b(h + l) = S - 2la ← divide both sides by (h + l)
b = [tex]\frac{S-2la}{h+l}[/tex]
How to graph it on a coordinate plan to the right 5x-3y=18
Tο shift the graph tο the right, we can simply add a pοsitive cοnstant tο the x values οf each pοint befοre plοtting them. Fοr example, if we want tο shift the graph tο the right by 2 units.
What is cοοrdinate plan?The intersectiοn οf twο number lines creates a twο-dimensiοnal plane knοwn as a cοοrdinate plane. The x-axis, a hοrizοntal number line, and the y-axis, a vertical number line, are twο examples οf these number lines.
Tο graph the equatiοn 5x - 3y = 18 οn a cοοrdinate plane, we can fοllοw these steps:
1. Sοlve fοr y in terms οf x:
5x - 3y = 18
-3y = -5x + 18
y = (5/3)x - 6
2. Chοοse sοme values fοr x and use the equatiοn tο find the cοrrespοnding y values. Fοr example, we can chοοse x = 0, 3, and 6:
When x = 0: y = (5/3)(0) - 6 = -6
When x = 3: y = (5/3)(3) - 6 = -3
When x = 6: y = (5/3)(6) - 6 = 2
3. Plοt the pοints (0, -6), (3, -3), and (6, 2) οn the cοοrdinate plane.
4. Draw a straight line passing thrοugh these three pοints. This line represents the graph οf the equatiοn 5x - 3y = 18.
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using the net below find the area of the triangular prism
6 cm
3 cm
4 cm
6 cm
5 cm
2 cm
Answer:153
Step-by-step explanation:
The value of 5^2000+5^1999/5^1999-5^1997
Answer:
Step-by-step explanation:
We can simplify the expression by factoring out a common factor of 5^1999 from the numerator:
5^2000 + 5^1999
= 5^1999(5 + 1)
= 5^1999(6)
And we can also factor out a common factor of 5^1997 from the denominator:
5^1999 - 5^1997
= 5^1997(5^2 - 1)
= 5^1997(24)
So the entire expression simplifies to:
(5^2000 + 5^1999) / (5^1999 - 5^1997)
= (5^1999 * 6) / (5^1997 * 24)
= (6/24) * 5^2
= 5/2
Therefore, the value of the expression is 5/2.
A triangle has vertices at (-4, 0), (2, 8), and (8, 0). Complete the table. Write answers as decimals
rounded to the nearest hundredth, when necessary.
The coordinate of centroid of the triangle is (2, 8/3), the coordinate of the circumcenter is (-7/32, 121/24) and the coordinate of orthocenter is (2, 9/2)
What is the coordinate of the centroid?a. To find the centroid of a triangle, we take the average of the x-coordinates and the average of the y-coordinates of the vertices. Therefore, the x-coordinate of the centroid is:
(x₁ + x₂ + x₃) / 3 = (-4 + 2 + 8) / 3 = 2
Similarly, the y-coordinate of the centroid is:
(y₁ + y₂ + y₃) / 3 = (0 + 8 + 0) / 3 = 8/3
So the coordinate of the centroid is (2, 8/3).
b. The circumcenter of a triangle is the point where the perpendicular bisectors of the sides of the triangle intersect. To find the circumcenter, we can find the equations of the perpendicular bisectors of any two sides of the triangle and solve for their intersection point.
Let's take the sides formed by vertices (-4, 0) and (2, 8), and vertices (-4, 0) and (8, 0). The midpoint of the first side is ((-4+2)/2, (0+8)/2) = (-1, 4), and the slope of the line passing through the two points is (8-0)/(2-(-4)) = 8/6 = 4/3. Therefore, the equation of the perpendicular bisector passing through (-1, 4) is:
y - 4 = (4/3)(x + 1)
Simplifying this equation, we get:
y = (4/3)x + 13/4
Similarly, the midpoint of the second side is ((-4+8)/2, (0+0)/2) = (2, 0), and the slope of the line passing through the two points is (8-0)/(2-8) = -8/6 = -4/3. Therefore, the equation of the perpendicular bisector passing through (2, 0) is:
y = -(4/3)(x - 2)
To find the intersection point of these two lines, we can set the equations equal to each other and solve for x:
(4/3)x + 13/4 = -(4/3)(x - 2)
x = -7/32
Substituting x = -7/32 into either of the equations, we get:
y = (4/3)(-7/32 + 1) + 4 = 121/24
So the coordinate of the circumcenter is (-7/32, 121/24).
c. The orthocenter of a triangle is the point where the altitudes of the triangle intersect. An altitude of a triangle is a line segment from a vertex of the triangle perpendicular to the opposite side.
Let's take vertex (-4, 0) and find the equation of the line passing through this vertex and perpendicular to the opposite side formed by vertices (2, 8) and (8, 0). The slope of the opposite side is (0-8)/(8-2) = -8/6 = -4/3, so the slope of the line we want is the negative reciprocal of this, which is 3/4. Therefore, the equation of the altitude passing through (-4, 0) is:
y - 0 = (3/4)(x + 4)
Simplifying this equation, we get:
y = (3/4)x + 3
Let's now take vertex (2, 8) and find the equation of the altitude passing through it. The slope of the opposite side formed by vertices (-4, 0) and (8, 0) is (0-0)/(8-(-4)) = 0, which means the altitude passing through (2, 8) is a vertical line passing through (2, 0). Therefore, the equation of this altitude is:
x = 2
Now we need to find the intersection point of these two altitudes. Substituting y = (3/4)x + 3 into the equation x = 2, we get:
y = 9/2
The coordinate of the orthocenter is (2, 9/2)
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an ore sample weighs 18.5 n n in air. when the sample is suspended by a light cord and totally immersed in water, the tension in the cord is 11.8 n n .find the total volume and density of the sample
The total volume of the sample is 0.0067 m³ and the density of the sample is 2753.73 kg/m³.
An ore sample weighs 18.5 N in air. When the sample is suspended by a light cord and totally immersed in water, the tension in the cord is 11.8 N. When the ore sample is immersed in water, the tension in the cord is given as 11.8 N.
Thus, the buoyancy force experienced by the ore sample is given by the difference between the weight of the sample in the air and the tension in the cord.
Buoyancy force experienced by the ore sample = Weight of the sample in the air - Tension in the cord
Buoyancy force experienced by the ore sample = (18.5 N) - (11.8 N)
Buoyancy force experienced by the ore sample = 6.7 N
Also, we know that the weight of the ore sample in air is equal to the weight of the ore sample when immersed in water.
Weight of the ore sample = Weight of the displaced water
Weight of the ore sample = Buoyancy force experienced by the ore sample
Weight of the ore sample = 6.7 N
The density of the ore sample
Density is given by the formula Density = Mass/Volume
Where Density is measured in kg/m³
Mass is measured in kg
Volume is measured in m³
Also, the density of water is given as 1000 kg/m³.
The density of the ore sample = Mass/Volume
Mass = Density x Volume
Volume of the ore sample can be obtained from volume of the displaced water.
Volume of the displaced water = Weight of the ore sample/Density of water
Volume of the displaced water = (6.7 N)/(1000 kg/m³)
Volume of the displaced water = 0.0067 m³
Density of the ore sample = (18.5 N)/(0.0067 m³)
Density of the ore sample = 2753.73 kg/m³
Therefore, 0.0067 m³ is the sample's total volume and 2753.73 kg/m³ is the density of the sample.
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STUDENT ACTIVITIES The Venn diagram shows the cast members of two school musicals who also participate in the local children's theater. One of the students will be chosen at random to attend a statewide performing arts conference. Let A be the event that a student is a cast member of Suessical and let B be the event that a student is a cast member of Wizard of Oz
we can use the notation P(A) and apply the definition of probability: P(A) = P(B), P (A ∩ B), and P (A ∪ B) if we have the necessary information.
What is Vann diagram?I believe you meant to say, "Venn diagram". A Venn diagram is a type of graphical representation used to illustrate relationships between sets or groups of objects, concepts, or ideas. It consists of a series of overlapping circles or other closed shapes, with each circle representing a set or group and the overlapping areas representing the relationships or intersections between them.
by the question.
Let A be the event that a student is a cast member of Seussical, and let B be the event that a student is a cast member of Wizard of Oz. Then, we can define the following:
A ∩ B: The event that a student is a cast member of both Seussical and Wizard of Oz.
A ∪ B: The event that a student is a cast member of either Seussical, Wizard of Oz, or both.
A': The event that a student is not a cast member of Seussical.
B': The event that a student is not a cast member of Wizard of Oz.
Based on the information given, we do not know how many students are in each of these events, but we can still make some general observations. For example:
If A and B have no students in common (i.e., A ∩ B = ∅), then the number of students in A ∪ B is equal to the sum of the number of students in A and the number of students in B.
If some students are in both A and B (i.e., A ∩ B is not empty), then the number of students in A ∪ B is equal to the sum of the number of students in A, the number of students in B, and the number of students in A ∩ B. In other words, some students are counted twice when we add up the number of students in A and the number of students in B, so we need to subtract the number of students in A ∩ B to avoid double-counting.
We do not know whether the events A and B are mutually exclusive (i.e., whether A ∩ B = ∅) or not. If they are mutually exclusive, then P(A ∩ B) = 0, and we can use the addition rule of probability to find P (A ∪ B) = P(A) + P(B). If they are not mutually exclusive, then we need to use the general addition rule of probability: P(A ∪ B) = P(A) + P(B) - P(A ∩ B).
Finally, if we want to find the probability that a student chosen at random is a cast member of Seussical,
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what is the variance inflation factor measuring? (select all that apply) group of answer choices the variance of the error term how much the explanatory variables are associated with one another the variance of the coefficient estimates the collinearity of the explanatory variable
The Variance Inflation Factor (VIF) measures the degree of correlation or the collinearity of the explanatory variables.
VIF quantifies how much each explanatory variable is correlated with a linear combination of the other variables in a multiple regression model. This can help identify variables that are redundant, irrelevant, or harmful to the model's accuracy. The VIF is calculated for each explanatory variable by dividing the variance of the regression coefficient estimates by the variance of the regression coefficient estimates when that variable is excluded from the model.
If the VIF is greater than 1, it indicates that the variance of the regression coefficient estimate for that variable is inflated by the presence of the other variables, which reduces the model's accuracy. Therefore, a VIF greater than 1 is considered to be an indication of collinearity or multicollinearity in the explanatory variables. The VIF measures the degree of correlation or the collinearity of the explanatory variables, and it can identify variables that are redundant, irrelevant, or harmful to the model's accuracy.
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What is the sum of the following equation? (2 points)
sixteen hundredths plus six-tenths equals blank
ten hundredths
twenty-two hundredths
thirty-six hundredths
seventy-six hundredths
The sum of the decimal fraction equation is:
seventy-six hundredths
How to add decimal fractions?The equation we are given is sixteen hundredths plus six-tenths
Now, when we talk about the decimal hundredths. Hundredths after decimal points shows 1/100th part of a whole. It represents the place value of the digit that occurs two places after the decimal.
Thus:
sixteen hundredths = 16/100
Similarly, six-tenths = 6/10
Thus:
The sum is:
16/100 + 6/10
= (16 + 60)/100
= 76/100 or seventy-six hundredths
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Let mz1 = x. Select all the angles that have a measure of 180 - x.
A, C, and D. The angles that have a measure of 180-x are angles that have a measure of 180 minus the value of x. In this case, x is equal to mz1, so the angles that have a measure of 180-x are √3, √5, and √10.
What is angle?Angle is a mathematical concept that is used to measure the amount of rotation of a line or a plane around a point. An angle is typically measured in degrees, which is the unit of angular measurement. Angles are used in many different fields of mathematics, such as geometry, trigonometry, and calculus. In geometry, angles are used to measure the size of a triangle, the size of a circle, or the angle between two lines. In trigonometry, angles are used to solve problems involving the length of sides and the measure of an arc. In calculus, angles are used to measure the rate of change of a function.
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Coin A is tossed three times and coin B is tossed two times. What is the probability that more heads are tossed using coin A than coin B?
The probability that more heads are tossed using coin A than coin B is 5/16.
The given data is: Coin A is tossed three times and coin B is tossed two times. We have to find the probability that more heads are tossed using coin A than coin B.
P(E) = Number of favorable outcomes/ Total number of possible outcomes
Coin toss:
There are two possible outcomes in a coin toss, Head or Tail. The probability of getting a head in a coin toss is
1/2 = 0.5.
Therefore, the probability of getting a tail in a coin toss is also 1/2 = 0.5.
Let's calculate the possible outcomes when coin A is tossed three times.
There are 2 possible outcomes when one coin is tossed.
Number of possible outcomes when three coins are tossed = 2 * 2 * 2 = 8
Likewise, the possible outcomes when coin B is tossed two times are:
The number of possible outcomes = 2 * 2 = 4
Therefore, the total number of possible outcomes = 8 * 4 = 32
Now, we will find out the cases where the number of heads is more when coin A is tossed three times.
HHH HHT HTH HTT THH THT TTH TTT HHT HTT THT TTT TTH TTT HTT TTT THT TTT TTT TTT
Therefore, the number of times when more heads are obtained when coin A is tossed three times is 10. (We have to exclude the case when there is an equal number of heads.)
Therefore, the required probability is: P = Number of favorable outcomes/ Total number of possible outcomes
P = 10/32P = 5/16
Therefore, the probability that more heads are tossed using coin A than coin B is 5/16.
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solve the equation √(x-4)^2=4-x
Answer:
To solve this equation, we will first simplify the left-hand side using the fact that the square root of a number squared is equal to the absolute value of that number.
So, we have:
| x - 4 | = 4 - x
We can now split this equation into two cases, depending on whether x - 4 is positive or negative:
Case 1: x - 4 ≥ 0
In this case, | x - 4 | = x - 4, so we have:
x - 4 = 4 - x
Simplifying this equation, we get:
2x = 8
x = 4
However, we must check this solution to make sure it satisfies the original equation. Plugging x = 4 back into the original equation, we get:
√(4 - 4)^2 = 4 - 4
√0 = 0
So, x = 4 is a valid solution.
Case 2: x - 4 < 0
In this case, | x - 4 | = -(x - 4), so we have:
-(x - 4) = 4 - x
Simplifying this equation, we get:
-2x + 8 = 4
-2x = -4
x = 2
Again, we must check this solution to make sure it satisfies the original equation. Plugging x = 2 back into the original equation, we get:
√(2 - 4)^2 = 4 - 2
√4 = 2
This is a valid solution.
Therefore, the equation has two solutions: x = 4 and x = 2.
Answer: Bro x = 4
Step-by-step explanation:
Ten cards are selected out of a 52 card deck without replacement and the number of Jacks is observed. This is an example of a Binomial Experiment.
true
false
The statement "Ten cards are selected out of a 52 card deck without replacement and the number of Jacks is observed. This is an example of a Binomial Experiment" is false.
What is a Binomial Experiment?A binomial experiment is an experiment that is repeated multiple times with each repetition having only two potential outcomes. In a binomial experiment, the probability of success remains constant from trial to trial.
The criteria for a binomial experiment are as follows:
The experiment is made up of a fixed number of trials.There are only two possible results for each trial: success and failure.The probability of success for each trial is the same.The trials are all independent of one another.The formula for calculating the probability of x successes in n trials is:P(x) = (ⁿCₓ)(pˣ)(q^(n-x))
Where p is the probability of success, q is the probability of failure (q = 1 - p), and ⁿCₓ is the combination formula.
Therefore, the statement "Ten cards are selected out of a 52-card deck without replacement and the number of Jacks is observed. This is an example of a "Binomial Experiment" being false. This is because the probability of drawing a jack changes with each trial, as the deck's composition changes after each card is drawn.
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Please help its gone overdue
80 points
Hence, AA"B"Ccoordinates "'s in green are: A" (0, 0), B" (-4, -5), and C" (1, -4).
what is graph ?An illustration of data or mathematical functions is a graph. It is a method for presenting numerical data in a way that is simple to comprehend and interpret. A set of axes, one for each variable being represented, and one or more plots or lines that reflect the data or function being graphed are the main components of a graph. There are many distinct graph kinds, each of which is appropriate for displaying various sorts of data, including line graphs, bar graphs, scatter plots, and pie charts.
given
The axes cannot be identified because they are not specified in the query.
The blue ABC bar graph is as follows:
Using the equation (x, y) (y, -x), rotate AABC 90 degrees clockwise by applying the following transformation to each point:
A(-3, 0) → A' (0, 3) (0, 3)
B(-2, 4) → B' (-4, -2) (-4, -2)
C(1, -1) → C' (1, -1) (1, -1)
The red A'B'C' coordinates are as follows: A' (0, 3), B' (-4, -2), and C' (1, -1).
We take the y-coordinate of each point and subtract 3 to translate AA'B'C' three units down:
A' (0, 3) → A" (0, 0) (0, 0)
B' (-4, -2) → B" (-4, -5) (-4, -5)
C' (1, -1) → C" (1, -4) (1, -4)
Hence, AA"B"Ccoordinates "'s in green are: A" (0, 0), B" (-4, -5), and C" (1, -4).
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The complete question is:-
1. Label the axes.
2. Graph: A(-3, 0) B(-2, 4) C(1,-1) Draw ABC in blue.
3. Rotate AABC 90° clockwise to
create ▲A'B'C' in red. List the coordinates below:
Formula: (x, y) → (y, -x)
A(-3, 0) A' ()
B(-2, 4)→ B' ()
C(1, -1) C' ()
4. Translate AA'B'C' three units down to create ▲A"B"C" in green. What are the coordinates of AA"B"C"?
Simplify these radicals (ASAP!!!)
Answer:
[tex]3.\quad 2\sqrt{7}\\\\4.\quad \dfrac{2}{\sqrt{5}}[/tex]
[tex]5.\quad \dfrac{1}{\sqrt{2}}[/tex]
[tex]6.\quad\dfrac{5}{7}[/tex]
Step-by-step explanation:
To simplify radicals find the factors and simplify the square roots of the factors
#3 : √28
28 = 4 x 7
√28 = √(4 x 7) = √4 x √7 = 2 x √7 = 2√7
========================================================
[tex]\#4:\quad \sqrt{ \dfrac{4}{5}}\\\\\sqrt{ \dfrac{4}{5}} = \dfrac{\sqrt{4}}{\sqrt{5}} = \dfrac{2}{\sqrt{5}}[/tex]
========================================================
[tex]\#5\quad \dfrac{3}{\sqrt{18}}\\\text{Denominator } \sqrt{18 }= \sqrt{9 \times 2} = 3\sqrt{2}\\\\ \dfrac{3}{\sqrt{18}}= \dfrac{3}{3\sqrt{2}} = \dfrac{1}{\sqrt{2}}[/tex]
========================================================
[tex]\# 6 \quad \sqrt{\dfrac{25}{49}}\\\\\sqrt{25} = 5\\\\\\\sqrt{49} = 7\\\\[/tex]
[tex]\sqrt{\dfrac{25}{49}}= \dfrac{5}{7}[/tex]
the weight of a body above the surface of the earth is inversely proportional to the square of its distance from the center of the earth. what is the effect on the weight when the distance is multiplied by 2?
The weight becomes 1/4 of its original value when the distance is multiplied by 2.
According to the question, "the weight of a body above the surface of the earth is inversely proportional to the square of its distance from the center of the earth." We need to determine the effect on the weight when the distance is multiplied by 2.
Let w be the weight of a body, d be the distance from the center of the earth, and k be the constant of variation. According to the question,
w = k / d²
When the distance is multiplied by 2, the new distance is 2d. Therefore, the new weight is given by:
w' = k / (2d)²
w' = k / 4d²
w' = w / 4
Therefore, the weight becomes 1/4 of its original value when the distance is multiplied by 2.
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Students of SOHO Swim Academy are to have extra swim lessons if they cannot swim. The table below
gives Information on students in 4th, 5th & 6th grade.
Complete the table
1) how many students need swim lessons?
2) How many students are in the 5th grade?
3)How many of the 4th graders can
swim?
4) How many student in 5th & 6th
grade cannot swim?
5) How many students attend SOHO
Swim Academy?
6) How many students attend SOHo swim Academy?
7) What percentage of 5h grade student can swim?
8) what percentage of students cannot swim?
Answer:
1. first, add the amount of people who cannot swim. they need swim lessons.
2. add up the people in 5th grade who can swim and the people who cannot. same with the 4th graders.
4. the students that cannot swim, add up the 5th and 6ths graders that cannot swim.
5. add up all of the SOHO swimmers.
6. subtracts SOHO swimmers from swim academy.
set up an equation like this for #7
total number of students that can swim/ total amount of 5th graders = x/100
use the fraction on the left and multiply it by 100.
same with number 8
Step-by-step explanation:
El Sr. Milton Escobar se presenta al banco de los Trabajadores de Tegucigalpa a constituir un depósito a Plazo Fijo #2250 a 6 meses por L100,000. 00 al 10. 5% de interés anual entregando el valor total con cheque #0045 a cargo del mismo banco. Haga la partida de apertura
As the banker at the Banco de los Trabajadores de Tegucigalpa, I greet Mr. Milton Escobar and thank him for choosing our bank for his fixed term deposit. I verify his identification and confirm the details of his deposit, which are:
Fixed Term Deposit number: #2250
Deposit amount: L100,000.00
Deposit term: 6 months
Interest rate: 10.5% per annum
I inform Mr. Escobar that the interest on his deposit will be calculated and credited to his account at the end of the deposit term. I also explain that he can choose to receive the interest in cash or reinvest it in the fixed term deposit.
Next, I ask Mr. Escobar to provide me with a check for the full deposit amount, payable by the Banco de los Trabajadores de Tegucigalpa, and I confirm that the check number is #0045. I inform him that the check will be deposited in his account and that he will receive a deposit confirmation letter.
Finally, I thank Mr. Escobar for his business and remind him to keep his deposit confirmation letter in a safe place, as it is a crucial document that he will need to produce at the time of maturity to withdraw his funds. I assure him that our bank will provide him with the highest quality service and look forward to his continued patronage.
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Translated Question ;
Mr. Milton Escobar appears at the Banco de los Trabajadores de Tegucigalpa to set up a Fixed Term Deposit #2250 for 6 months for L100,000. 00 to 10.5% annual interest, delivering the total amount by check #0045 payable by the same bank. Play the opening game
Let A, B, and C be subsets of some universal set U. (a) Draw two general Venn diagrams for the sets A, B, and C. On one, shade the region that represents A - (B nC), and on the other, shade the region that represents (A -B) U (A C). Based on the Venn diagrams, make a conjecture about the relationship between the sets A-(BnC) and (A -B)U (A -C). (b) Use the choose-an-element method to prove the conjecture from Exer- cise (5a). (c) Use the algebra of sets to prove the conjecture from Exercise (5a).
In conclusion, we can prove that[tex](A -B) U (A C)[/tex] is a superset of[tex]A - (B nC)[/tex] using both the choose-an-element method and the algebra of sets.
To answer this question, let's first draw two Venn diagrams to represent the sets A, B, and C. In the first Venn diagram, shade the region that represents[tex]A - (B nC)[/tex].
This is the region outside of the intersection of B and C and inside of A. In the second Venn diagram, shade the region that represents [tex](A -B) U (A C).[/tex] This is the union of the region outside of B and the region outside of C, both of which are inside of A. Based on these diagrams, we can make the conjecture that (A -B) U (A C) is a superset of A - (B nC).
To prove this conjecture, we can use the choose-an-element method. Let a be an element of A - (B nC). This means that a is in A, but not in B or C. Since a is in A, it is also in (A -B) U (A C), and therefore (A -B) U (A C) is a superset of A - (B n C).
We can also use the algebra of sets to prove this conjecture.[tex]A - (B n C) = (A -B) U (A -C) since A - (B n C)[/tex]is the union of the regions outside of B and outside of C, both of which are inside of A. This implies that (A -B) U (A C) is a superset of A - (B nC).
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The number 2 is the first even counting number,4 is the second even number, 6 is the third even number, and so forth. What is the sum of the first 25th even counting numbers
The number 2 is the first even counting number,4 is the second even number, 6 is the third even number, and so forth. the sum of the first 25th even counting numbers is 650.
Since we are given that the first even counting number is 2 and each subsequent even counting number can be obtained by adding 2 to the previous one. so by using the formula for finding the 25th term of an arithmetic series which :
an=a+(n-1)d, where the nth term d is a common difference and a is the first term so, the 25th term is 2 + (25-1)*2 = 2 + 48 = 50. Now for finding the sum of the first 25 even counting numbers, we use the formula which is Sn = n /2 * (a1 + an), where Sn is the sum of the first n terms of the series, a1 is the first term, and an is the nth term. since in this n=25, a1=2 and an=50, so after substituting the values we get S25 = 25/2 * (2 + 50) = 25/2 * 52 = 650
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In mr. Bunuelos class , 19 out of 26 student wore their school shirt of friday if the school has population of 2,462 student approximately how many students at the school wore their school shirt on friday?
If the school has population of 2,462, then approximately 1,784 students at the school wore their school shirt on Friday.
If 19 out of 26 students wore their school shirt on Friday, then the fraction of students who wore their school shirt is:
[tex]\frac{19}{26}[/tex]
We can use this fraction to estimate the number of students who wore their school shirt on Friday. If there are approximately 2,462 students in the school, then the estimated number of students who wore their school shirt on Friday is:
[tex](\frac{19}{26}) * 2,462 = 1,783.69[/tex]
Rounding this to the nearest whole number, we get an estimate of 1,784 students who wore their school shirt on Friday.
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The average between 3. 15 and x is 40 what is x?
The value of x that makes the average between 3.15 and x equal to 40 is 76.85.
In this problem, we are given two numbers, 3.15 and x, and told that the average between them is 40. We can set up an equation to solve for x as follows:
(3.15 + x) / 2 = 40
To find the average between 3.15 and x, we add the two numbers together and divide by 2, which gives us the equation above.
To solve for x, we can start by multiplying both sides of the equation by 2:
3.15 + x = 80
Next, we can subtract 3.15 from both sides of the equation:
x = 76.85
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What is the first step in
solving this equation?
4|2-v|-3= 25
The Answer: The first step is Rearranging the Equation
v=9
v=-5
Step-by-step explanation:
STEP
1
:
Rearrange this Absolute Value Equation
Absolute value equalitiy entered
4|-v+2|-3 = 25
Another term is moved / added to the right hand side.
4|-v+2| = 28
STEP
2
:
Clear the Absolute Value Bars
Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.
The Absolute Value term is 4|-v+2|
For the Negative case we'll use -4(-v+2)
For the Positive case we'll use 4(-v+2)
STEP
3
:
Solve the Negative Case
-4(-v+2) = 28
Multiply
4v-8 = 28
Rearrange and Add up
4v = 36
Divide both sides by 4
v = 9
STEP
4
:
Solve the Positive Case
4(-v+2) = 28
Multiply
-4v+8 = 28
Rearrange and Add up
-4v = 20
Divide both sides by 4
-v = 5
Multiply both sides by (-1)
v = -5
Which is the solution for the Positive Case
STEP
5
:
Wrap up the solution
v=9
v=-5
an equation of a circle is given by (x+3)^2+(y_9)^2=5^2 apply the distributive property to the square binomials and rearrange the equation so that one side is 0.
The equation of the circle is [tex]x^2 + y^2 + 6x - 18y + 65 = 0[/tex].
Given:
Equation of the circle is [tex](x+3)^2+(y-9)^2=5^2[/tex]
Expand the equation
[tex](x+3)^2 = (x+3)(x+3) = x^2 + 3x + 3x + 9 = x^2 + 6x + 9[/tex]
[tex](y-9)^2 = (y-9)(y-9) = y^2 - 9y - 9y + 81 = y^2 - 18y + 81[/tex]
[tex]5^2 = 25[/tex]
Then, substitute the expanded expressions into the equation
[tex](x+3)^2+(y-9)^2=5^2\\(x^2 + 6x + 9) + (y^2 - 18y + 81) = 25\\[/tex]
Simplify and combine like terms
[tex](x^2 + 6x + 9) + (y^2 - 18y + 81) = 25\\x^2 + y^2 + 6x - 18y + 90 = 25[/tex]
Rearrange the equation so that one side is 0
[tex]x^2 + y^2 + 6x - 18y + 90 = 25\\x^2 + y^2 + 6x - 18y + 90 - 25 = 0\\x^2 + y^2 + 6x - 18y + 65 = 0[/tex]
Thus, the equation of a circle [tex](x+3)^2+(y-9)^2=5^2[/tex] can be rearranged using the distributive property to form [tex]x^2 + y^2 + 6x - 18y + 65 = 0[/tex], with one side equaling 0.
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Apply De Morgan's law repeatedly to each Boolean expression until the complement operations in the expression only operate on a single variable. For example, there should be no xy¯ or x+y¯ in the expression. Then apply the double complement law to any variable where the complement operation is applied twice. That is, replace x¯¯ with x.
a. 1/ x + yz + u b. 1/x(y + 2)u c. 1/(x + y)(uv + x y) d. 1/xy + yz + xz
The simplified expression using De Morgan's law are a)x'y'z'u b)x'y'u c): x'y'u and d)x'y'z'+xy'z'+xyz.
The main idea is to simplify each Boolean expression by repeatedly applying De Morgan's law until each complement operation operates on a single variable.
Then, apply the double complement law to simplify the expression further. In the end, the simplified expression should contain only AND and OR operations without any complement operators acting on multiple variables.
a. 1/ x + yz + u can be simplified using De Morgan's law to: (x'y'z')u'. Then, applying the double complement law, we get the simplified expression as: x'y'z'u.
b. 1/x(y + 2)u can be simplified using De Morgan's law to: x'(y'+2')u'. Then, applying the double complement law, we get the simplified expression as: x'y'u.
c. 1/(x + y)(uv + xy) can be simplified using De Morgan's law to: (x'y')(u' + x'y'). Then, applying the double complement law, we get the simplified expression as: x'y'u.
d. 1/xy + yz + xz can be simplified using De Morgan's law to: (x'+y')(y'+z')(x'+z'). Then, applying the double complement law, we get the simplified expression as: x'y'z'+xy'z'+xyz.
In summary, to simplify Boolean expressions, we can apply De Morgan's law repeatedly and then use the double complement law to remove complement operators acting on a single variable twice.
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