Answer:
Middle layer, density increases with depth as pressure increases
Explanation:
The Earth's mantle is the middle layer of the earth. It is the largest layer of the earth consisting of about 83 % of the earth's volume and continues to a depth of 2900 km. Also, the mantle is hot and made of solid rock. It is hot since it is close to the core and its pressure and density increases with depth causing it to be more solid.
So, the Earth's mantle is the middle layer, density increases with depth as pressure increases.
A cyclist is taking part in the Tour de France, which is a bicycle race that takes place every year.
a Two forces acting on the cyclist are weight and reaction. Name two other forces acting on him
as he cycles along.
If you have a cube that is 2x2x2 and weighs 5.29 g. How do you find the density?
Answer:
0.66
Explanation:
Follow the Density Formul d = m/v
so
d = 5.29/8
= 0.66 Density
Just correct me if I'm wrong, I mean like literally :> Thank you! ^^
A child has a mass of 30 kg on Earth. If th gravity on Moon is one sixth that of the Earth what is the weight of the child on the Moon? Gravity on Earth = 10 N^-1
Answer:
the baby would still be 30 kg on the moon because that’s mass, not weight.
However, it will feel like 5 kg, because the acceleration is 1/6 and the force is 1/6 and the actual weight (product of mass and acceleration will be 1/6).
The child has a mass of 30 kg on earth and has one-sixth gravity on the moon will have a weight of 50 kg on the moon.
What is Gravity?Gravity is a fundamental interaction that causes all objects with mass or energy to attract one another. The weakest of the four fundamental interactions is gravity, by far. The Moon's gravity causes sublunar tides in the oceans, just as gravity on Earth imparts weight to physical objects.
Given:
The mass of the child (m) = 30 kg,
The gravity on the moon (G) = 1/6 of the earth.
To calculate the weight of the child on the moon, use the formula given below,
F = m × a
Here
[tex]F[/tex] is the weight, [tex]m[/tex] is the mass and [tex]a[/tex] is the gravity on earth, gravity on earth [tex]10\ m/s^2[/tex].
Substitute the values
[tex]F=30*10/6[/tex]
[tex]F = 50\ kg[/tex]
Therefore, the weight of a child on the moon is 50 kg.
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A carpenter applies a force of 60N horizontally to push a plane 40 cm along a piece of wood, how much work does she do?
Answer:
W = 24 J
Explanation:
Given that,
Applied force, F = 60 N
Distance moved, d = 40 cm = 0.4 m
We need to find the work done by the carpenter. We know that,
Work done, W = Fd
Put all the values,
W = 60 N × 0.4 m
= 24 J
Hence, the required work done is equal to 24 J.
what are scalar quantities and list their examples
Explanation:
these are quantities that have magnitude but no direction
Examples include : speed, mass, volume, density, everything, time
Which one of the patterns is the quietest?
Answer:
A
Explanation:
What is moment? Write down the law of moment.A long spanner is used to unscrew the tight nut.Why?
Answer:
Moment is the product of force and its perpendicular distance from a point along its line of action.
The net moments on clockwise and anticlockwise is zero at a point.
The net force applied on a spanner handle is equal to the moment of the rotation
Water is being heated on the stove at 90 ⁰C. What is this temperature on the Fahrenheit degrees?
Answer:
194 degrees farenheit! hot
Explanation:
(90°C × 9/5) + 32 = 194°F
Answer:
194
Explanation:
to get from celcius to Fahrenheit
multiply temperature by 2 and add 30
a ball of mass 0.2 kg is dropped from a height of 20m on impact to the ground it loses in 30 joule of energy calculate the height it reaches on rebound
Answer:
new PE at top=original PE - energy lost
mgh=.2(9.8)20-30
Explanation:
mgh=.2(9.8)20-30 = 9.2
a string 2m long used to whirl a 200gm stone in horizontal circle at a speed of 2m/s . find the tension in the string
Answer:
Explanation:
First off, we need the mass in kg and it's in g so we have to convert it. Then we can do the problem. 200 g = .200 kg. Moving on.
The equation used to find the tension in the string is the same one we use to find the centripetal force, because the tension is what is upplying the centripetal force needed to keep the stone moving in a circular manner. The formula for that is
[tex]F_c=T=\frac{mv^2}{r}[/tex] where ma is the mass in kg, v is the velocity in m/s, and r is the radius of the circle about which the stone spins in meters.
Filling in:
[tex]T=\frac{(.200)(2)^2}{2}[/tex] which gives us
T = .4 N
Which is NOT a characteristic of a solid?
a) All solids have a definite shape.
b) All solids have molecules that are loosely packed together.
C) All solids have mass.
d) All solids take up space
Answer:
b
Explanation:
A pendulum is moving 2.0 m/s at the bottom of its swing. How high vertically will it go before it begins to swing back? Group of answer choices 0.4 m 0.1 m 0.2 m 0.8 m 1.0 m
Answer:
h = 0.2 m
Explanation:
Given that,
A pendulum is moving 2.0 m/s at the bottom of its swing.
We need to find the height high it swing back. Let the height is h.
Using the conservation of energy such that,
[tex]\dfrac{1}{2}mv^2=mgh\\\\h=\dfrac{v^2}{2g}[/tex]
Put all the values,
[tex]h=\dfrac{(2)^2}{2\times 10}\\\\h=0.2\ m[/tex]
So, it will reach to a height of 0.2 m.
A container of gas is at a pressure of 3.7 x 10^5 Pa. How much work is done by the gas if its volume expands by 1.6 m^3 ?
Answer:
592000 J
Explanation:
We'll begin by converting 3.7×10⁵ Pa to Kg/ms². This can be obtained as follow:
1 Pa = 1 Kg/ms²
Therefore,
3.7×10⁵ Pa = 3.7×10⁵ Kg/ms²
Next, we shall determine the workdone.
Workdone is given by the following equation:
Workdone (Wd) = pressure (P) × change in volume (ΔV)
Wd = PΔV
With the above formula, the work done can be obtained as follow:
Pressure (P) = 3.7×10⁵ Kg/ms²
Change in volume (ΔV) = 1.6 m³
Workdone (Wd) =?
Wd = PΔV
Wd = 3.7×10⁵ × 1.6
Wd = 592000 Kgm²/s²
Finally, we shall convert 592000 Kgm²/s² to Joule (J). This can be obtained as follow:
1 Kgm²/s² = 1 J
Therefore,
592000 Kgm²/s² = 592000 J
Therefore, the Workdone is 592000 J.
A car with a mass of 500 kg is moving at a speed of 12 m/s. How much kinetic energy does it have?
someone please help me PLEASEEEE <3
Answer:
36000
Explanation:
1/2mv²=0.5×500×12²=36000j
1 Ten (10) ml aqueous solutions of drug A (10% w/v) and drug B (25% w/v) are stored in two identical test tubes under identical storage conditions at 37°C for 3 months. If both drugs degrade by first-order, which drug will retain the highest percentage of initial concentration?
Answer:
YOUR answer is given below:
Explanation:
Drug B will retain the highest percentage of initial concentration.
First order degradation means that both solution will degrade by same amount in same time because first order is directly proportional relationship between given both aqueous solution.
Given that Ten (10) ml aqueous solutions of drug A (10% w/v) and drug B (25% w/v) are stored in two identical test tubes.
Since, initially concentration of Drug B is more. Therefore, at all instant concentration of Drug will be highest.
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What is Magnitude?
a.Accuracy
b.Precision
c.Extent of a measurement
d.Ground type Pokemon
Answer:
Prior to changes in Generation IV, all damaging Ground-type moves were physical, but ... Ground type moves will affect Flying type Pokemon when they lose their ... Gen, Move, Category, Contest, Power, Accuracy, PP, Target, Description ... at an abandoned hydroelectric plant, were giving Onix a noticeable degree of pain, ...
Missing: Precision c. measurement d.
Explanation:
Answer:
C. Extent of a measurement and D. Ground-Type Pokemon.
Explanation:
1. A boat is floating on the water.
One of the forces acting on the boat is the weight. This is the force of the Earth on the boat.
a
State the other force in this interaction pair.
(1 mark)
Answer:
Gravity
Explanation:
Because without gravity thee would be no boat floating on water
10 points
Calculate the force of attraction between the moon and the earth, if their masses and distance apart are 10^22Kg, 10^24kg and 6.4x10^6m. Take g = 6.67x10^-11Nm^2Kg^-2
a) 0.63x10^24N
b) 1.63x10^22N
c) 2.63x10^20N
d) 3.63x10^18N
Answer:
Explanation:
You didn't fill in the proper masses which is why you never got an answer to this. But that's ok...I got you. I happen to know what they are! We will use the universal law of gravitation and the gravitational constant to solve this.
[tex]F_g=\frac{Gm_1m_2}{r^2}[/tex] and filling in:
[tex]F_g=\frac{(6.67*10^{-11})(5.98*10^{24})(7.36*10^{22})}{(3.84*10^8)^2}[/tex] The denominator is the radius of the earth plus the radius of the moon plus the distance between their surfaces, just FYI.
That gives us that
[tex]F_g=1.99*10^{20}N[/tex] Not sure what your choices entail, but I'd have to say, taking into consideration that maybe your problem didn't figure in the distance between the surfaces, you'd be at choice B.
In April 1974, Steve Prefontaine completed a 10.0 km race in a time of 27 min , 43.6 s . Suppose "Pre" was at the 7.71 km mark at a time of 25.0 min . If he accelerated for 60 s and then maintained his increased speed for the remainder of the race, calculate his acceleration over the 60 s interval. Assume his instantaneous speed at the 7.71 km mark was the same as his overall average speed up to that time.
Answer:
0.18 m/s²
Explanation:
The total time taken to cover a 10 km race is 27 min, 43.6 seconds.
At 25 min, Pre was at 7.71 km mark. Therefore the average speed = 7.71 km / 25 min = 7710 m / (25 * 60) s = 5.14 m/s
The distance remaining = 10 km - 7.71 km = 2.29 km = 2290 m
The remaining time = 27 min, 43.6 seconds - 25 min = 2 min 43.6 second = 163.6 seconds
She accelerates for 60 seconds, therefore the distance covered (S) during the acceleration (a) is:
S₁ = 5.14(60) + 0.5a(60)² = 308.4 + 1800a
She maintains the speed for the remaining distance (S₂). The remaining time = 163.6 seconds - 60 seconds = 103.6 seconds. The final speed after the acceleration = (5.14 + 60a) m/s
S₂ = (5.14 + 60a)* 103.6 = 532.5 + 6216a
S₁ + S₂ = 2290 m
(308.4 + 1800a) + (532.5 + 6216a) = 2290
8016a + 840.9 = 2290
8016a = 1449.1
a = 0.18 m/s²
a 10 kg box is pulled across an ice rink for a distance of 50m. it is pulled with a constant force of 10 N on a rope angled at 60° to the horizontal. How much work is done on the box? (A) 50 ) (B) 100 ) (C) 250 ) (D) 500)
Answer:
(C) 250
Explanation:
Given the following data;
Mass = 10 kg
Distance = 50 m
Force applied = 10 N
Angle = 60°
To find the work done on the box, we would first of all find the horizontal component of the force applied.
[tex] Horizontal force, Fx = mgCosd[/tex]
Where;
Fx represents the horizontal force.
m is the mass of an object.
g is the acceleration due to gravity.
d is the angle of inclination (theta).
mg = weight = 10 N
Substituting into the equation, we have;
[tex] Fx = 10 * Cos60 [/tex]
[tex] Fx = 125 * 0.5 [/tex]
Fx = 5 Newton
Next, we find the work done.
Mathematically, workdone is given by the formula;
[tex] Workdone = force * distance[/tex]
Substituting into the formula, we have;
[tex] Workdone = 5 * 50 [/tex]
Workdone = 250 Nm
Which statement best compares potential and kinetic energy?
O Objects always have more potential energy than kinetic energy.
O Kinetic energy increases and potential energy decreases when the velocity of an object increases.
O Only potential energy decreases when an object's height increases.
O Objects always have more kinetic energy than potential energy.
Mark this and return
Save and Exit
Next
Submit
Answer:
B . Kinetic energy increases and potential energy decreases when the velocity of an object increases.
Explanation:
The statement with best compares potential energy and kinetic energy is that only kinetic energy increases when the velocity of the object increases.
An 84% efficient single pulley is used to lift a 230 kg piano 3.5 m. How much work must be input?
Answer:
35%
Explanation:
win
The amount of work required to lift the 230 kg to a height of 3.5 m at 84% efficiency is 9391.67 J
What is efficiency?This can be defined as the capacity to achieve a given task with little or no waste. Mathematically, it can be expressed as
Efficiency = (output / input) × 100
How to determine the work output Mass (m) = 230 KgHeight (h) = 3.5 mAcceleration due to gravity (g) = 9.8 m/s²Work output =?Work output = mgh
Work output = 230 × 9.8 × 3.5
Work output = 7889 J
How to determine the work input Output = 7889 JEfficiency = 84% Input =?Efficiency = (output / input) × 100
84% = 7889 / input
Cross multiply
84% × input = 7889
Divide both side by 84%
Input = 7889 / 84%
Input = 7889 / 0.84
Input = 9391.67 J
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9) What is the temperature of 5 moles of nitrogen at 1 atm in a 2 liter container?*
- 4.88 K
- 0.0328 K
- 0.41 K.
- 0.0164 K
Answer:
4.88 K.
Explanation:
From the question given above, the following data were obtained:
Number of mole (n) = 5 moles
Pressure (P) = 1 atm
Volume (V) = 2 L
Gas constant (R) = 0.082 atm.L/Kmol
Temperature (T) =?
The temperature of the gas can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
1 × 2 = 5 × 0.082 × T
2 = 0.41 × T
Divide both side by 0.41
T = 2 / 0.41
T = 4.88 K
Therefore, the temperature of the gas is 4.88 K.
what is electricity?write any two defects of a simple cell.
Answer:
Electricity is the set of physical phenomena associated with the presence and motion of matter that has a property of electric charge. Electricity is related to magnetism, both being part of the phenomenon of electromagnetism, as described by Maxwell's equations.
A bat is flying at 0.6 m/s when it spots an appetizing insect. The bat accelerated at a rate of 1.2m/s2 for 1.9
seconds. How fast is the bat traveling at the time?
Answer:
v_f = 2.9m/s
Explanation:
v_f = v_I + a(t)
v_f = 0.6m/s + 1.2m/s²(1.9s)
v_f = 2.88m/s
v_f = 2.9m/s
measure the diameter of a thin wire using only a ruler and a test tube
Answer:
The screw gauge is an instrument used for measuring accurately the diameter of a thin wire or the thickness of a sheet of metal. It consists of a U-shaped frame fitted with a screwed spindle which is attached to a thimble.
Explanation:
Measure the length of the coil with the help of a meter scale. The thickness of the wire can be found by dividing the length of the coil by the number of turns. Measure the diameter with callipers. Place an electrical wire between the jaws of a set of Vernier callipers. Slide the movable jaw around the cable without compressing the insulation and read the measurement where the line from the moving indicator meets the stationary scale for a diameter.
what is substances ?????
Substance:-
A substance is matter which has a specific composition and specific properties.
Vector B has components Bx = 6.18 and By = 4.43. Find the magnitude and direction counter clockwise from the positive x-axis.
Answer:
Explanation:
The formula for the magnitude of this resultant vector, which is in Q1, btw, is:
[tex]B_{mag}=\sqrt{6.18^2+4.43^2}[/tex] which gives us, to 3 sig fig's:
7.60 m. Since the resultant vector is in Q1, we don't need to add anything to the angle once we find it to 3 sig fig:
[tex]tan^{-1}(\frac{4.43}{6.18})[/tex] gives us an angle of 35.6 degrees
what is the momentum of an object weighing 7.5 kg moving at 1.6 m/s?
Answer:
[tex]momentum = mass \times velocity \\ = 7.5 \times 1.6 \\ = 12 \: kg {ms}^{ - 1} [/tex]
Mass is 7.5 kg
Velocity is 1.6 m/s
we know that,
momentum = mass × velocity
or; momentum =7. 5 kg × 1. 6 m/s
or; momentum = 12 kgms^1
The motor of a boat develops 48 kW when the boat's speed is 12 km/h. With how much force does the water resist the motion of the boat?
