helpppp timed on this helppp me quick brainleast

Answer:

2b - 14

Step-by-step explanation:

2(b – 7)

2b - 14

Answer:

[tex]2b-14[/tex]

Step-by-step explanation:

Using the distributive property, [tex]2(b-7)[/tex] can be written as [tex](2\cdot b)-(2\cdot7)[/tex] which solved/simplified is [tex]2b-14[/tex]

Man, it's late! Well, hope this helped you out and answered your question!

Answer:

Step-by-step explanation:

If these vectors are to be linearly independent, then there exists some not-all-zero choice for scalars [tex]c_1,c_2,c_3,c_4[/tex] such that

[tex]c_1(1,1,0,-1) + c_2(1,k,1,1) + c_3(5,1,k,1) + c_4(-1,1,1,k) = (0,0,0,0)[/tex]

We can recast this as a system of linear equations,

[tex]\begin{bmatrix}1&1&5&-1\\1&k&1&1\\0&1&k&1\\-1&1&1&k\end{bmatrix}\begin{bmatrix}c_1\\c_2\\c_3\\c_4\end{bmatrix} = \begin{bmatrix}0\\0\\0\\0\end{bmatrix}[/tex]

This system has a solution if the coefficient matrix on the left side is not singular. So we attempt to find k such that it *is* singular, i.e. the determinant is zero:

• A cofactor expansion along the first column gives

[tex]\begin{vmatrix}1&1&5&-1\\1&k&1&1\\0&1&k&1\\-1&1&1&k\end{vmatrix} = \begin{vmatrix}k&1&1\\1&k&1\\1&1&k\end{vmatrix} - \begin{vmatrix}1&5&-1\\1&k&1\\1&1&k\end{vmatrix} + \begin{vmatrix}1&5&-1\\k&1&1\\1&k&1\end{vmatrix}[/tex]

• Cofactor expansions along the first columns of the remaining 3x3 matrices give

[tex]\begin{vmatrix}k&1&1\\1&k&1\\1&1&k\end{vmatrix} = k \begin{vmatrix}k&1\\1&k\end{vmatrix} - \begin{vmatrix}1&1\\1&k\end{vmatrix} + \begin{vmatrix}1&1\\k&1\end{vmatrix} = k^3-3k+2[/tex]

[tex]\begin{vmatrix}1&5&-1\\1&k&1\\1&1&k\end{vmatrix} = \begin{vmatrix}k&1\\1&k\end{vmatrix} - \begin{vmatrix}5&-1\\1&k\end{vmatrix} + \begin{vmatrix}5&-1\\k&1\end{vmatrix} = k^2-4k+3[/tex]

[tex]\begin{vmatrix}1&5&-1\\k&1&1\\1&k&1\end{vmatrix} = \begin{vmatrix}1&1\\k&1\end{vmatrix} - \begin{vmatrix}5&-1\\k&1\end{vmatrix} + \begin{vmatrix}5&-1\\1&1\end{vmatrix} = -k^2 - 6k + 7[/tex]

It follows that

[tex]\begin{vmatrix}1&1&5&-1\\1&k&1&1\\0&1&k&1\\-1&1&1&k\end{vmatrix} = (k^3-3k+2) - (k^2-4k+3) + (-k^2 - 6k + 7) \\\\ \begin{vmatrix}\cdots\end{vmatrix} = k^3 - 2k^2 - 5k + 6 = (k-3)(k-1)(k+2)[/tex]

which makes the coefficient matrix singular if k = 3, k = 1, or k = -2.

Then the four vectors are linearly independent for

[tex]\left\{ k\in\mathbb R \mid k\not\in\{-2,1,3\}\right\}[/tex]

Answer:

4.  3,52  - Tenths                

   0.352 - Hundredths

5.  65.09 - Ones

   7.005 - Thousandths

6.  753.4 - Tens

    0.051 -  Hundredths

maybe we could answer if there waas a pic=]

Step-by-step explanation:

all steps are in picture

9514 1404 393

Answer:

  p = -3/4b -3/4

Step-by-step explanation:

Vectors are perpendicular when their dot product is zero.

  A·B = p(4) +b(3) -3(-1) = 4p +3b +3

We want this to be zero, so ...

  4p +3b +3 = 0

  4p = -3b -3

  p = -3/4b -3/4 . . . . the value of p that makes A⊥B

Answer:

(I got your back pal) Your answer is -41/21

Can you give me a brainlest it would help me a lot

Answer:

The number is 2

Step-by-step explanation:

x * 16 + 4 = 9*4

x * 16 + 4 = 36

x * 16 + 4 - 4 = 36 - 4

x * 16 = 32

x * 16 / 16 = 32 / 16

x = 2

Answer:

The number is 2

Step-by-step explanation:

let the number be "a"

16a+4=4×9

16a+4=36

16a=36-4

16a=32

a=2

fraction is in lowest term is no(b)

Answer:

2

Step-by-step explanation:

1+1×5−6+8×(4+4)−62 =

1+1x5-6+8x(8)-62 =

1+5-6+64-62 =

2

Hope this helps! :)

Answer:

B

I just did it and got it right

Answer:

U forgot to add zero while dividing

Answer:

5/6

Step-by-step explanation:

I'm assuming the x in your equation is used as a variable.

5/6-1/2= 2/6=1/3

2/5x=1/3

x=5/6

Answer:

3.14159265358979

Step-by-step explanation:

Answer:

1/4

Step-by-step explanation:

Answer:

∠AOB + ∠BOC = ∠AOC we will be using this equation

x = 21   this is the value of x

Step-by-step explanation:

Angle AOC = 84

Angle AOB = 3x

Angle BOC = x

it is given that Angle AOC = 84so we just need to add Angle AOB and Angle BOC

now lets make the equation we that we will be using

∠AOB + ∠BOC = ∠AOC

3x + x = 84

4x = 84

x = 84 ÷ 4

x = 21

Step-by-step explanation:

Here, we have,

AOC=84°

AOB=3x

BOC=x

Now, the required equation will be;AOC=AOB+BOC[whole part axiom]

or, 84°=3x+x

or, 84°=4x

or, 84°÷4=x

or, x=21°

Thus, the equation to find the answer is AOC=AOB+BOC and the value of x is 21°.

The guitar's volume was amplified, but it was hard to hear the notes since it was so loud.

What word or phrase is a signal word that a context clue might be nearby to help determine the meaning of "amplified"?

Step-by-step explanation:

Answer:

D.

Step-by-step explanation:

$230 + $360 = $590

$590 - $253* = $337

$337

*( total sum of all the bills )

Here we want to see if the statement:

"A proper use of units can help us to determine the meaning of the slope of a linear function" is true or false.

We will see that it is true.

First, a general linear equation can be written as:

y = a*x + b

Where a is the slope, x is the independent variable, y is the dependent variable, and b is the y-intercept.

The proper use of units is:

y and b must have the same units.

x can have any type of units

The slope must have the quotient between the units of y and the units of x.

Where the proper use of units means that we have the same units on both sides of the expression.

Now, assume that we know the units of y and x.

For example:

y is miles  (then b is also in miles)

x is in hours

Then, with the proper use of units, we can see that the units of the slope are:

miles/hour, or miles per hour.

With this (only knowing the units of x and y) we can see that the slope will be a speed.

So yes, the proper use of units is really important, as this has a lot of information (particularly, the meaning of the slope in a linear equation)

Thus, the statement is true.

If you want to learn more, you can read:

https://brainly.com/question/20286983

Answer:

[tex]{ \underline{ \sf{x \: is \: \: \{ \frac{ - 5 + i \sqrt{35} }{10} \} } \: \: and \: \: \{ \frac{ - 5 - i \sqrt{35} }{10} \}} }[/tex]

Step-by-step explanation:

[tex]5 {x}^{2} + 4x + 3 = 0 [/tex]

from quadratic formular:

[tex]{ \sf{x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} }} [/tex]

general equation:

[tex] {ax}^{2} + bx + c = 0[/tex]

a is 5, b is 4 and c is 3:

substitute in formular:

[tex]{ \sf{x = \frac{ - 5± \sqrt{ {5}^{2} - (4 \times 5 \times 3) } }{(2 \times 5)} }} \\ \\ { \sf{x = \frac{ - 5± \sqrt{ - 35} }{10} }}[/tex]

but from complexes, i² = -1

[tex]{ \sf{x = \frac{ - 5± \sqrt{35 {i}^{2} } }{10} }} \\ \\ = { \sf{x = \frac{ - 5±i \sqrt{35} }{10} }}[/tex]

Answer:

B

Step-by-step explanation:

f^(-1) (x) = (x-1)/3

f^(-1) (10) = (10-1)/3 = 3.

Here <5=<8 then

[tex]\\ \sf\longmapsto <7+<8=90[/tex]

[tex]\\ \sf\longmapsto 29+<8=90[/tex]

[tex]\\ \sf\longmapsto <8=90-29[/tex]

[tex]\\ \sf\longmapsto <8=61[/tex]

Answer:

1833 miles is the total distance if the model airplane.

Answer:

g(f(x))=x^2 + 14x + 48

Step-by-step explanation:

you insert (x+7) into every x in the g(x) equation, so g(x)=(x+7)^2 - 1. then you simplify it by doing (x+7)(x+7) which gets you x^2 + 14x + 49. then you subtract the 1 from the equation to get g(f(x))=x^2 + 14x + 48.

(g o f) (x) = g ( f(x) )

= (x+7)² – 1

= x² + 14x+49 – 1

= x² + 14x+48

If you want, (f o g ) (x) below is the solution ^_^

(f o g ) (x) = f ( g(x) )

= g(x) + 7

= x²-1 +7

= x² +6

I hope I helped you^_^

Answer:

243

Step-by-step explanation:

the answer is 243 for number 6

Answer:

all you gotta do is do 2430 divided by ten

Answer:

it must be 2983548×2............

Step-by-step explanation:

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