Helpi
Identify the domain of the function shown in the graph.

9514 1404 393

Answer:

  B, C, H, D, F, A

Step-by-step explanation:

Starting with y = f(x), swap x and y to get x = f(y), then solve for y. The solution steps "undo" what is done to y, in reverse order. Y is ...

To "undo" these steps in reverse order, after swapping x and y, you must square both sides, add 21, then divide by 7.

If the left tiles are labeled A to H from top to bottom, the correct sequence of steps is ...

  B, C, H, D, F, A

Answer:

a. A normal quantile plot of the data follows a diagonal line, and the t-procedure is appropriate to use.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

In this question:

Sample size of 100 > 30, which means that we use the Central Limit Theorem, and thus, the sampling distribution is approximately normal, following a diagonal line, and since the standard deviation of the population is not know, we use the t-procedure. Thus, the correct answer is given by option a.

Answer:

its a

Step-by-step explanation:

trust did test

Answer:

domain:-16,-8,0,12

range:0,-11,12,14

9514 1404 393

Answer:

  50.24 cm

Step-by-step explanation:

Fill in the given numbers and do the arithmetic.

  s = rθ

  s = (24 cm)(2/3π) = (24 cm)(2/3)(3.14) = 50.24 cm

Answer:

D. 750(0.75)ˣ

Step-by-step explanation:

Let the new brightness be L'. Since our initial brightness L₀ reduces by 25 %, we have that L' = L₀ - 25% of L₀

L' = L₀ - 0.25L₀

L' = 0.75L₀

Adding the second screen, the new intensity is L" = L' - 25 % of L'  

L" = L' - 0.25 L'

L" = 0.75L'.

Since L' = 0.75L₀,

L" = 0.75L' = 0.75(0.75L₀) = 0.75²L₀

Adding the third screen, the new intensity is L"' = L'' - 25 % of L''  

L'" = L" - 0.25 L"

L"' = 0.75L".

Since L" = 0.75L' = 0.75²L₀

L"' = 0.75L" = 0.75(0.75²L₀) = 0.75³L₀

So, we see a pattern here.

The intensity after x screens is L = (0.75)ˣL₀

Since L₀ = 750 lumens,

L = 750(0.75)ˣ

Answer:

67. A

68. D

Step-by-step explanation:

I don't remember exactly the explanation, but I recommend you try to learn more about number lines sometime when you aren't under stress from schoolwork, because they're pretty simple questions to answer once you get a better understanding of them!

Answer:

y=¼x-6

Step-by-step explanation:

y=mx+c

y=¼x+-6

y=¼x-6

Answer:

3^5

Step-by-step explanation:

On the iPad it looks like that but the five is on the top right smaller

Answer:

3⁵

every 3 has it own power that is 1 however that .3 confused us

Answer:

RA = 24

Step-by-step explanation:

Since the triangle is isosceles ( 2 equal sides ) , then LU is a perpendicular bisector , so

AU = RU , that is

4r = 18 - 2r ( add 2r to both sides )

6r = 18 ( divide both sides by 6 )

r = 3

Then

RA = 18 - 2r + 4r = 18 + 2r = 18 + 2(3) = 18 + 6 = 24

Answer:

A seems to be correct

Step-by-step explanation:

Answer:

p = 15/x

x= -3

Step-by-step explanation:

For the first problem, we can expand the equation to 4px+4=64

then simplify it to:

4px=60

then divide 4x from both sides of the equation

p=60/4x

then simplify:

p=15/x

For the second problem:

plug in -5 for p so the equation would look like

4(-5x +1)=64

simplify

-20x=60

x= -3

Answer:

3/8

Step-by-step explanation:

the total number of possible results is 4×4=16.

out of these 16 only the results

1 2

1 3

1 4

2 2

2 3

3 2

are desired results. these are 6.

so the probability of a desired result is 6/16 = 3/8

Answer:

the wording (punctuation) of the question can lead to different interpretations....

I assume that the question was >17 & even which is "5/19",

BUT... it can also be read as two questions

first >17 which is "10/19"

and second an even number which is "9/19"

BUT !!! I think that the question answer is 5/19

Step-by-step explanation:

Even Number  = 18/38 = 9/19

greater 17 = 20/38 = 10/19

Even & greater 17 = 10/38 = 5/19

Answer:

is it going to be 10.5

Step-by-step explanation:

I do not have any explanation

Answer: 0 (zero)

Step-by-step explanation:

Start Learning & start growing! edge2023

*DROPS THE MIC*

9514 1404 393

Answer:

  x = 19

  A = 30°

  B = C = 75°

Step-by-step explanation:

In an isosceles triangle, the angles opposite the congruent sides have the same measures.

  A = B

  3x +18 = 7x -58

  76 = 4x . . . . . . . . add 58-4x

  19 = x . . . . . . . . . divide by 4

Then the equal angles measure ...

  A = B = 3(19) +18 = 75

  C = 2(19) -8 = 30

Angles A, B, C measure 75°, 75°, 30°, respectively.

_____

Alternate solution

The sum of angles in a triangle is 180°, so you could write ...

  (3x +18) +(7x -58) +(2x -8) = 180

  12x = 228 . . . . . add 48

  x = 19 . . . . . divide by 12

Answer:

Please find the complete question and its solution in the attached file.

Step-by-step explanation:

Shortest had survived after 6741 hours [tex]2.5\%[/tex] of the lights burnt.

[tex]\to 0.15\% + 2.35\% = 2.50\%[/tex]

Answer:

Step-by-step explanation:

Total number of balls = 3 + 2 = 5

1)

a)

[tex]Probability \ of \ taking \ 2 \ black \ ball \ with \ replacement\\\\ = \frac{3C_1}{5C_1} \times \frac{3C_1}{5C_1} =\frac{3}{5} \times \frac{3}{5} = \frac{9}{25}\\\\[/tex]

b)

[tex]Probability \ of \ one \ black \ and \ one\ white \ with \ replacement \\\\= \frac{3C_1}{5C_1} \times \frac{2C_1}{5C_1} = \frac{3}{5} \times \frac{2}{5} = \frac{6}{25}[/tex]

c)

Probability of at least one black( means BB or BW or WB)

 [tex]=\frac{3}{5} \times \frac{3}{5} + \frac{3}{5} \times \frac{2}{5} + \frac{2}{5} \times \frac{3}{5} \\\\= \frac{9}{25} + \frac{6}{25} + \frac{6}{25}\\\\= \frac{21}{25}[/tex]

d)

Probability of at most one black ( means WW or WB or BW)

[tex]=\frac{2}{5} \times \frac{2}{5} + \frac{3}{5} \times \frac{2}{5} \times \frac{2}{5} + \frac{3}{5}\\\\= \frac{4}{25} + \frac{6}{25} + \frac{6}{25}\\\\=\frac{16}{25}[/tex]

2)

a) Probability both black without replacement

  [tex]=\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}[/tex]

b) Probability  of one black and one white

 [tex]=\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}[/tex]

c) Probability of at least one black ( BB or BW or WB)

 [tex]=\frac{3}{5} \times \frac{2}{4} + \frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{6}{20} + \frac{6}{20} \\\\=\frac{18}{20} \\\\=\frac{9}{10}[/tex]

d) Probability of at most one black ( BW or WW or WB)

 [tex]=\frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{1}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{2}{20} + \frac{6}{20} \\\\=\frac{14}{20}\\\\=\frac{7}{10}[/tex]

Answer:

Consider points (-1, 0) and (0, 1) :

[tex]{ \tt{slope = \frac{y _{2} - y _{1} }{x _{2} - x _{1} } }} \\ { \tt{slope = \frac{1 - 0}{0 - ( - 1)} }} \\ { \boxed{ \bf{slope = 1}}}[/tex]

Answer:

slope 1

Step-by-step explanation:

above ANS is correct mark it as branliest ANS

Answer:

This is pretty simple

Step-by-step explanation:

So the only thing you need to know about negatives and positives is that if your multiplying or dividing a number with 1 negative in the expreession/equation The answer will always result in a negative. If its 2 negatives its always positive. Thats all you need to know and then just solve it from there.

Answer:

See explanation and picture below.

Step-by-step explanation:

In both multiplication and division of 2 numbers, different signs give you negative and equal signs give you positive.

In other words, positive & positive or negative and negative give you a positive answer.

Negative and positive or positive and negative give you negative answer.

Answer:

Test statistic = 1.25

Degree of freedom = 3

Step-by-step explanation:

The following data were obtained from 4 people

Pre-Test Value Post-test Value __ d

43 ________42 _________ 1

28_______ 29 ________ - 1

31 ________30 _________ 1

28 ________ 25 _________ 3

μd = (1 + - 1 + 1 + 3) / 4 = 4 /4 = 1

The mean difference, μd = 1

The standard deviation of difference, Sd = 1.6

The test statistic = μd / (Sd / √n)

Test statistic = 1 / (1.6/2) = 1 / 0.8

Test statistic = 1.25

Degree of freedom, = n - 1 = 4 - 1 = 3

FINAL ANSWER:

1

Step-by-step explanation:

[tex]\frac{2}{3} +\frac{1}{3}[/tex]

the denominators are the same so all we need to do is add.

[tex]\frac{2}{3} + \frac{1}{3} =\frac{3}{3}[/tex]

[tex]\frac{3}{3} =[/tex] 1 whole

final answer: 1

hope this answer helps you :)

have a great day and may God Bless You!

Answer:

Step-by-step explanation:

Given that:

[tex]f_x = \dfrac{x^2}{a^7-x^7}[/tex]

[tex]= \dfrac{x^2}{a^7(1-\dfrac{x^7}{a^7})}[/tex]

[tex]= \dfrac{x^2}{a^7}\Big(1-\dfrac{x^7}{a^7} \Big)^{-1}[/tex]

since  [tex]\Big((1-x)^{-1}= 1+x+x^2+x^3+...=\sum \limits ^{\infty}_{n=0}x^n\Big)[/tex]

Then, it implies that:

[tex]\implies \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\Big(\dfrac{x}{a} \Big)^{^7} \Big)^n[/tex]

[tex]= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x}{a} \Big)^{^{7n}}[/tex]

[tex]= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x^{7n}}{a^{7n}} \Big)}[/tex]

[tex]\mathbf{= \sum \limits ^{\infty}_{n=0} \dfrac{x^{7n+2}}{a^{7n+7}} }}[/tex]

Answer:

[tex]m = 12[/tex]

[tex]n =3[/tex]

Step-by-step explanation:

Given

[tex]P(x) = x^3 + mx^2 - nx - 10[/tex]

Required

The values of m and n

For x - 1;

we have:

[tex]x - 1 = 0[/tex]

[tex]x=1[/tex]

So:

[tex]P(1) = (1)^3 + m*(1)^2 - n*(1) - 10[/tex]

[tex]P(1) = 1 + m*1 - n*1 - 10[/tex]

[tex]P(1) = 1 + m - n - 10[/tex]

Collect like terms

[tex]P(1) = m - n + 1 - 10[/tex]

[tex]P(1) = m - n -9[/tex]

Because x - 1 divides the polynomial, then P(1) = 0;

So, we have:

[tex]m - n -9 = 0[/tex]

Add 9 to both sides

[tex]m - n = 9[/tex] --- (1)

For x + 2;

we have:

[tex]x + 2 = 0[/tex]

[tex]x = -2[/tex]

So:

[tex]P(-2) = (-2)^3 + m*(-2)^2 - n*(-2) - 10[/tex]

[tex]P(-2) = -8 + 4m + 2n - 10[/tex]

Collect like terms

[tex]P(-2) = 4m + 2n - 10 - 8[/tex]

[tex]P(-2) = 4m + 2n - 18[/tex]

x + 2 leaves a remainder of 36, means that P(-2) = 36;

So, we have:

[tex]4m + 2n - 18 = 36[/tex]

Collect like terms

[tex]4m + 2n = 36+18[/tex]

[tex]4m + 2n = 54[/tex]

Divide through by 2

[tex]2m + n=27[/tex] --- (2)

Add (1) and (2)

[tex]m + 2m - n + n = 9 +27[/tex]

[tex]3m =36[/tex]

Divide by 3

[tex]m = 12[/tex]

Substitute [tex]m = 12[/tex] in (1)

[tex]m - n =9[/tex]

Make n the subject

[tex]n = m - 9[/tex]

[tex]n = 12 - 9[/tex]

[tex]n =3[/tex]

Answer:

is it four I am not quite sure

Answer:

Dependent Samples t test

Step-by-step explanation:

The dependent samples t test also called the paired t test are employed in statistical analysis when sample measurement in a certain group is to be paired with the sample measurement on the other group. This is possible because the samples used in the two groups are usually the same. Hence, pairing the samples is feasible in this case. This is different from independent t test as the samples in the groups are entirely different and distinct. Hence, giving no chance to match the samples together. In the scenario described above, the same 20 people(samples) formed the same group of measurement.

Answer:

y = 65 + 20x

Step-by-step explanation:

Okay, when you're talking about linear equations try to find the fixed value, and then the changing one.

The fixed value will be by itself

The value that varies will have a variable next to it (x, y, z, whatever)

Then, the answer has to be

y = 65 + 20x

Answer:

Step-by-step explanation:

Given expressions are,

[tex]p=\frac{\sqrt{10}-\sqrt{5}}{\sqrt{10}+\sqrt{5}}[/tex] and [tex]q=\frac{\sqrt{10}+\sqrt{5}}{\sqrt{10}-\sqrt{5}}[/tex]

Remove the radicals from the denominator from both the expressions.

[tex]p=\frac{\sqrt{10}-\sqrt{5}}{\sqrt{10}+\sqrt{5}} \times \frac{\sqrt{10}-\sqrt{5}}{\sqrt{10}-\sqrt{5}}[/tex]

  [tex]=\frac{(\sqrt{10}-\sqrt{5})^2}{(\sqrt{10})^2-(\sqrt{5})^2}[/tex]

  [tex]=\frac{(\sqrt{10}-\sqrt{5})^2}{5}[/tex]

[tex]\sqrt{p}=\sqrt{\frac{(\sqrt{10}-\sqrt{5})^2}{5}}[/tex]

      [tex]=\frac{\sqrt{10}-\sqrt{5}}{\sqrt{5}}[/tex]

[tex]q=\frac{\sqrt{10}+\sqrt{5}}{\sqrt{10}-\sqrt{5}}[/tex]

  [tex]=\frac{\sqrt{10}+\sqrt{5}}{\sqrt{10}-\sqrt{5}}\times \frac{\sqrt{10}+\sqrt{5}}{\sqrt{10}+\sqrt{5}}[/tex]

  [tex]=\frac{(\sqrt{10}+\sqrt{5})^2}{(\sqrt{10})^2-(\sqrt{5})^2}[/tex]

  [tex]=\frac{(\sqrt{10}+\sqrt{5})^2}{5}[/tex]

[tex]\sqrt{q}=\sqrt{\frac{(\sqrt{10}+\sqrt{5})^2}{5}}[/tex]

     [tex]=\frac{(\sqrt{10}+\sqrt{5})}{\sqrt{5}}[/tex]

[tex]\sqrt{q}-\sqrt{p}-2\sqrt{pq}=\frac{(\sqrt{10}+\sqrt{5})}{\sqrt{5}}-\frac{(\sqrt{10}-\sqrt{5})}{\sqrt{5}}-2(\frac{(\sqrt{10}+\sqrt{5})}{\sqrt{5}})(\frac{(\sqrt{10}-\sqrt{5})}{\sqrt{5}})[/tex]

                           [tex]=\frac{1}{\sqrt{5}}(\sqrt{10}+\sqrt{5}-\sqrt{10}+\sqrt{5})-\frac{2}{5}[(\sqrt{10})^2-(\sqrt{5})^2)][/tex]

                           [tex]=\frac{1}{\sqrt{5}}(2\sqrt{5})-\frac{2}{5}(10-5)[/tex]

                           [tex]=2-2[/tex]

                           [tex]=0[/tex]