Help with Pythagorean theorem

Answer:

sorry

Step-by-step explanation:

polynomial is not given

question is incomplete

Answer:

5m

Step-by-step explanation:

5^(k-1)+5^(k-1)=m

Going to combine like terms on left:

2×5^(k-1)=m

Law of exponents applied:

2×5^k×5^(-1)=m

Reciprocal:

2×5^k×1/5=m

Multiply 5 on both sides to obtain the requested:

2×5^k=5m

Step-by-step explanation:

its on the picture.........

If both triangles are similar then ratio of sides will be same.

[tex]\\ \sf\longmapsto \dfrac{12}{14}=\dfrac{y}{21}[/tex]

[tex]\\ \sf\longmapsto 12(21)=14y[/tex]

[tex]\\ \sf\longmapsto 14y=252[/tex]

[tex]\\ \sf\longmapsto y=\dfrac{252}{14}[/tex]

[tex]\\ \sf\longmapsto y=18[/tex]

Answer:

y = 18

Step-by-step explanation:

Since the triangles are similar, the corresponding sides are in proportion, that is

[tex]\frac{BC}{EF}[/tex] = [tex]\frac{AC}{DF}[/tex] , substitute values

[tex]\frac{y}{12}[/tex] = [tex]\frac{21}{14}[/tex] ( cross- multiply )

14y = 252 ( divide both sides by 14 )

y = 18

Answer:

Equation of line is y = -8x + 21

Step-by-step explanation:

Slope, m = -8

General equation of line:

[tex]{ \boxed{ \bf{y = mx + c}}}[/tex]

At point (2, 5), y = 5 and x = 2:

[tex]{ \tt{5 = ( - 8 \times 2) + c}} \\ { \tt{c = 21}}[/tex]

Therefore:

[tex]{ \sf{y = - 8x + 21}}[/tex]

[tex]{ \underline{ \blue{ \sf{christ \:† \: alone }}}}[/tex]

arccos(2x) + arccos(x) = π/2

Apply cos to both sides, then expand the right side using the identity I mentioned in a comment:

cos(arccos(2x) + arccos(x)) = cos(π/2)

cos(arccos(2x)) cos(arccos(x)) - sin(arccos(2x)) sin(arccos(x)) = 0

Now think of arccos(2x) and arccos(x) as angles in two right triangles. Let θ = arccos(2x) and φ = arccos(x) (and let's also assume that both have measure between 0 and π/2). These are angles such that

cos(θ) = 2x

cos(φ) = x

In these triangles, you then have

sin(θ) = sin(arccos(2x)) = √(1 - 4x ²)

sin(φ) = sin(arccos(x)) = √(1 - x ²)

while

cos(θ) = cos(arccos(2x)) = 2x

cos(φ) = cos(arccos(x)) = x

So the original equation is transformed to

2x ² - √(1 - 4x ²) √(1 - x ²) = 0

Solve for x :

2x ² = √(1 - 4x ²) √(1 - x ²)

(2x ²)² = (√(1 - 4x ²) √(1 - x ²))²

4x ⁴ = (1 - 4x ²) (1 - x ²)

4x ⁴ = 1 - 5x ² + 4x ⁴

0 = 1 - 5x ²

x ² = 1/5

x = ± 1/√5

Now bearing in mind that we assume 0 < φ < π/2, we should have cos(φ) = x > 0, so we take the positive solution,

x = 1/√5

Answer:

Sales goal, S = Q. 10,000

Step-by-step explanation:

Given the following data;

To find his daily sales goal;

[tex] \frac {20}{100} * S = 2000 [/tex]

[tex] 0.2 * S = 2000 [/tex]

Dividing both sides by 0.2, we have;

[tex] S = \frac {2000}{0.2} [/tex]

Sales goal, S = Q. 10,000

Answer:

8 cm

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

So first let's write the information we got

Angle BAC = 90 degrees

Midpoint of BC = M

AC = 6cm

Am= 5cm

Also I found MC = BM, since it has a line that represents both lines are same

so to find it we have to Pythagoras theorem (A^2 + B^2 = C^2), well it is question we have the 'A value and C Value', also we need to find the value of B to find the length of MC and BM

A = 5

C = 6

so therefore to find B^2, we have to do the reverse, we don't add but subtract

C^2 - A^2 = B^2

___________________________________________________________

Moving on to Calculation

6^2 - 5^2 = B^2

36 - 25 = B^2

B^2 = 9

B = √9

B = 3

MC and BM Length =  3 cm

____________________________

Now, we know the length we again need to use Pythagoras theorem to solve this.

Since we know

A = 5

B = 3

So..

A^2 + B^2 = C^2

5^2 + 3^2 = C^2

25 - 9 = C^2

C^2 = 16

C = √16

C = 4

Given:

The ratio and rates:

1. 30 ft. To 60.Ft

2. 51 males to 21 females

3. 1,500 meters in 6 seconds

4. $36 for 4 rounds of shrimp

To find:

The fraction in simple terms for the given ratio and rates.

Solution:

1. 30 ft. To 60.Ft

[tex]\dfrac{30\text{ ft}}{60\text{ ft}}=\dfrac{1}{2}[/tex]

2. 51 males to 21 females

[tex]\dfrac{51}{21}=\dfrac{17}{7}[/tex]

3. 1,500 meters in 6 seconds

[tex]\dfrac{1500\text{ meters}}{6\text{ seconds}}=250\text{ meter/second}[/tex]

4. $36 for 4 rounds of shrimp

[tex]\dfrac{\$ 36}{4}=\$ 9\text{ per round of shrimp}[/tex]

Answer:

y =x^2 +8x +15

factories form

y =( x+5 )( x+3 )

x intercept where the graph meet the x axis

y = x^2 +8x +15

let y =0

0 = x^2 +8x +15

0 = ( x + 5) (x+3)

o = x+5 or 0 = x+3

-5 = x or x = - 3

x intercept

(-5;0)

(-3 ;0)

axis of symmetry : where you will cut the graph into two half

x = - b/2a

x = - 8/2(1)

x = - 8/2

x = - 4

Domain

XER

Range

y > -1

Answer:

Option C, 93.6 mi³

Step-by-step explanation:

Volume of the triangular prism,

base area × height

= (8×3.9/2)×6

= 93.6 mi³

Answer:

Klog earned $135.45 altogether.

Step-by-step explanation:

Hours

Monday - Friday : 5 days / 3.5 hours

Saturday : 1 day / 4 hours

3.5 · 5 + 4

= 17.5 + 4

= 21.5

Money

$6.30 per hours / 21.5 hours

6.30 · 21.5

= $135.45

Answer:

y = 3/5×x + 1

Step-by-step explanation:

Slope intercept form y= mx + b

since slope = 3/5 => y= [tex]\frac{3}{5}[/tex]x + b

Plug point (-5,-2) to the equation -2 = [tex]\frac{3}{5}[/tex] x (-5) + b

=> b=1

Answer:

An integer is any rational number without a decimal or fraction. This includes negative numbers, and 0. But decimals and fractions are not integers.

Step-by-step explanation:

Brainliest, please!

Segment addition postulate states that given points X, and Z, on a line, a point Y, can be located between X, and Z, ony if we have;

XZ = XY + YZ

The length of the segment BD is 36  cm

The reason the above value is correct is as follows:

Known:

The ratio in which the points A, B, C, and D divide the line segment = 4:3:1

The length of segment AD = 72 cm

Required:

The length of BD

Method:

Calculate the length of BC and CD and add their values to get BD

Solution:

Let the ratios be given unit proportions of the segment AD such that we have;

AB = 4 units

BC = 3 units

CD = 1 unit

By segment addition postulate, we have;

AD = AB + BC + CD

∴ AD = 4 units + 3 units + 1 unit = 8 units = 72 cm

∴ 1 unit = 72 cm/8 = 9 cm

1 unit = 9 cm

BD = BC + CD by segment addition postulate

BC = 3 units = 3 × 1 unit

∴ BC = 3 × 9 cm = 27 cm

BC = 27 cm

CD = 1 unit

∴ CD = 9 cm

∴ BD = 27 cm + 9 cm = 36 cm

The length of segment BD = 36 cm

Learn more about segment addition postulate here:

https://brainly.com/question/17015321

Answer:

(x-9)(x+2)

Step-by-step explanation:

x^2-7x-18

What 2 numbers multiply to -18 and add to -7

-9*2 = -18

-9+2 = -7

(x-9)(x+2)

Answer:

Below.

Step-by-step explanation:

x^2 - 7x - 18

-9 * 2 = -18 and -9 +2 = -7 so the factors are:

(x - 9)(x + 2)

Answer:

[tex]3\sqrt{3}[/tex]

[tex]\left(\frac{\left(6\cdot \:\:\:sin\left(30\right)\right)}{sin\left(90\right)}\right)^2+x^2=36[/tex]

Step-by-step explanation:

Answer:

0.9

Step-by-step explanation:

100,000 in 90,000

The statistical question is; "What are the ages of the students in this class?

A statistical question is always aimed at data collection which can subsequently used for analysis and decision making. Statistical questions are asked in the course of research.

Among the two questions, the statistical question is; "What are the ages of the students in this class?

Learn more about statistics:https://brainly.com/question/8058700

#SPJ1

it´s a polygon. letter c (decagon) should be right

hope it helps :)

Answer:

x = 35

Step-by-step explanation:

Let x be the one of the other angles

X is also the third angle since we know they are equal

The sum of the angles of a triangle is 180

110+x+x = 180

110 +2x= 180

2x = 180-110

2x= 70

Divide by 2

2x/2 = 70/2

x = 35

Answer:

[tex]x = 35 \degree[/tex]

Step-by-step explanation:

Let the unknown angle be x

Unknown Angles are equal to each other so,

[tex]x + x + 110 = 180[/tex]

sum of the interior angles in a triangle is 180°

[tex]2x + 110 = 180 \\ 2x = 180 - 110 \\ 2x = 70 \\ \frac{2x}{2} = \frac{70}{2} \\ x = 35 \degree[/tex]

Answer:

see explanation

Step-by-step explanation:

Using x and y to represent the 2 numbers with x > y , then

x + y = 15 → (1)

x - y = 11 → (2)

Adding the 2 equations term by term to eliminate y

2x = 26 ( divide both sides by 2 )

x = 13

Substitute x = 13 into (1)

13 + y = 15 ( subtract 13 from both sides )

y = 2

The 2 numbers are 13 and 2

Answer:

- 2 x y^2+3 x^2 y -xy

-120

Step-by-step explanation:

xy – 2xy + 3x^2 y — 4x y^2 + 2xy^2

Combine like terms

xy – 2xy + 3x^2 y — 4x y^2 + 2xy^2

- x y+3 x^2 y - 2 x y^2

Let x = 4 y = -2

-(4)(-2) +3(4)^2 (-2) -2(4)(-2)^2

Exponents first

-(4)(-2) +3(16) (-2) -2(4)(4)

Multiply

+8 -96-32

Add and subtract

-120

Answer:

[tex]6(4c + 6d + 3})[/tex]

Step-by-step explanation:

Given

[tex]{24c + 36d + 18}[/tex]

Required

Apply distributive property

We have:

[tex]{24c + 36d + 18}[/tex]

Factor out 6 (to apply distributive property)

[tex]{24c + 36d + 18} = 6(4c + 6d + 3})[/tex]

Hence, the equivalent is:

[tex]6(4c + 6d + 3})[/tex]

9514 1404 393

Answer:

  B.  even

Step-by-step explanation:

Functions are classed according to what happens when x is replaced by -x.

  f(-x) = f(x) . . . even

  f(-x) = -f(x) . . . odd

__

Here, we have ...

  f(-x) = 2/(-x)^2 = 2/x^2 = f(x) . . . . an even function

Answer:

x= 3 and x= -3

Step-by-step explanation:

x^2 -9 = 0

Factor x^2-9

(x+3)(x-3)

If x+3=0, then x= -3

If x-3=0, then x= 3

Answer:

i) 37

ii) 120

iii) 157

Explanation:

i)

BCA = 180-ACD (Linear Pair)

BCA=180-60

BCA = 120

23+x+BCA=180

143+x=180 (Angle sum property)

x=37

ii) Since triangle ABD is equilateral all of its angles are 60

y+ADC=180

y = 180-ADC (Angles on straight line adds upto 180)

y=180-60

y = 120

iii) Using the values from part i and ii

x+y = 120+37

= 157

Must click thanks and mark brainliest

Answer:

I am odd number my digits add up to 7 i am bigger than 50 and smaller 100

a school has 2500 pupils. when 52 boys and 1/9 of the girls are absent, the number of the boys present is equal to the number of girls. how many pupils does the school have ?

Let the number of boys be x

Data :

Total pupils = 2500

Absent no. of boys and girls = 52 and 1/9

Now,

Remaining no of pupils = 2500 - 52 ➝ 2448

Hence, the no. of girls absent = 1/9 of 2448 ➝ 272

Therefore,

Total no. of pupils absent = 52 + 272 ➝ 324

No. of pupils present = 2500 - 324 ➝ 2176

Henceforth, 2176 pupils are present