HELP QUICK PLEASE!

Which additional information would suffice to prove AJKM AKIL by Side-Angle-Side?
O MK LJ
O MJ | LK
O ZJMKZKLJ
O ZJKM ZKIL

Answers

Answer 1

Answer: MK is congruent to LJ

Step-by-step explanation: If the legs of the triangle are equal then that must mean the hypotenuses are as well.

Related Questions

HELP ASAP ILL GIVE BRAINLIST

Construct the equation of the graph given. Label the intercept and categorize this graph a horizontal or vertical line.

Answers

Answer:

Horizontal line

Step-by-step explanation:

uehdjd

Find the value of x. Round the length to the nearest tenth.

Answers

Answer:

[tex]x=opposite\: side\: of \:22[/tex]

[tex]16=hypotenese[/tex]

[tex]sin22=opp/hyp[/tex]

[tex]sin22=\frac{x}{16}[/tex]

[tex]\Longrightarrow x=16\times sin22[/tex]

[tex]x=5.99[/tex]

[tex]x=6.0[/tex]

[tex]OAmalOHopeO[/tex]

Aila wants to solve the equation -2.3 – 5x = 10 – 2x. She uses a graphing program to graph the equations y = -2.3 – 5x and y = 10 – 2x. Use the graph to find the solution of -2.3 – 5x = 10 – 2x. Line graph with 2 lines. X axis ranges from negative 10 to 10; y axis range from 6 to negative 6; both lines cross x, y axes; do not pass through origin; intersect at (negative 4.1, 18.2). Both lines extend from bottom right to upper left quadrants.

Answers

Answer:

-4.1

Step-by-step explanation:

see screenshot below

Answers

Answer:

B only

Step-by-step explanation:

well to solve this question we can consider factor theorem which states that if a Polynomial f(x) is divided by a monomial x-a then x-a is a factor of f(x) if and only if f(a)=0

and to figure "a " we can consider the following equation:

[tex] \displaystyle x - a = 0[/tex]

substitute the given value of a:

[tex] \displaystyle x - 2= 0[/tex]

therefore,

[tex] \displaystyle x = 2[/tex]

option-1:

plugin the value of x to the function A(x):

[tex] \displaystyle A(2) = {2}^{3} + {2}^{2} + 4[/tex]

simplify which yields:

[tex] \displaystyle A(2) = 16[/tex]

since A(2)≠0 x-2 is not a factor of A(x)

option-2:

similarly substitute the value of x to the function B(x) which yields:

[tex] \displaystyle B(2) = {2}^{3} - {2}^{} - 6[/tex]

simplify:

[tex] \displaystyle B(2) =0[/tex]

so, B(2)=0 Hence x-2 is a factor of x³-x-6

option-3:

substitute the value of x to the function C(x)

[tex] \displaystyle C(2) = {2}^{4} + 3.{2}^{} - 10[/tex]

simplify:

[tex] \displaystyle C(2) =12[/tex]

as C(2)≠0 x-2 is not a factor of C(x)

option-4:

likewise plugin the value of x to the function D(x):

[tex] \displaystyle D(2) = {2}^{4} - 2.{2}^{3} - 2[/tex]

simplify and that yields:

[tex] \displaystyle D(2) = - 2[/tex]

therefore,D(2)≠0 hence,x-2 isn't a factor of D(-2)

[tex]\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}[/tex]

The factor

x-2=0x=2

we have find the value of x .

Now,

we have to select all the polynomial which has x-2 As a factor.

According to the question,

option A:-

[tex]A(x)=x^3+x^2+4\\\\A(2)=(2)^3+(2)^2+4\\\\=8+4+4\\\\16≠0[/tex]

so it is not a factor.

Option B:-

[tex]B(x)=x^3-x-6\\\\=B(2)=(2)^2-2-6\\\\0=0[/tex]

so it is a factor

Option C:-

[tex]C(x)=x^4+3x-10\\\\=C(2)=(2)^4+3(2)-10\\\\=16+6-10\\\\12≠0[/tex]

so it is not a factor

option D:-

[tex]D(x)=x^4-2x^3-2\\\\D(2)=(2)^4-2(2)^3-2\\\\=16-16-2\\\\-2≠0[/tex]

so it is not a factor

therefore:-

The option B is correct.

What are the domain and range of the inequality y < sqrt x+3+1

I don't get it I try to solve it but I just didn't get .

Answers

Given:

The inequality is:

[tex]y<\sqrt{x+3}+1[/tex]

To find:

The domain and range of the given inequality.

Solution:

We have,

[tex]y<\sqrt{x+3}+1[/tex]

The related equation is:

[tex]y=\sqrt{x+3}+1[/tex]

This equation is defined if:

[tex]x+3\geq 0[/tex]

[tex]x\geq -3[/tex]

In the given inequality, the sign of inequality is <, it means the points on the boundary line are not included in the solution set. Thus, -3 is not included in the domain.

So, the domain of the given inequality is x>-3.

We know that,

[tex]\sqrt{x+3}\geq 0[/tex]

[tex]\sqrt{x+3}+1\geq 0+1[/tex]

[tex]y\geq 1[/tex]

The points on the boundary line are not included in the solution set. Thus, 1 is not included in the range.

So, the domain of the given inequality is y>1.

Therefore, the correct option is A.

In a bowl of fruit, there are green grapes and black grapes in the ratio 3 : 4

If there are 24 green grapes, how many black grapes are there?

Answers

Answer:

Step-by-step explanation:

Green : black

3 4

We have 24 green

3+8=24

so multiply each side by 8

Green : black

3*8 4*8

24 32

There are 32 black grapes

Answer:

Step-by-step explanation:

By Question :-

Green grapes: Black grapes= 3:4

Let :-

Number of black grapes = x

Therefore,

GG/ BG = 3/4 24/x = 3/4 x = 24 × 4/3x = 8 × 4x = 32

0=(x-8)^2-100 Solve the problem using any type of way.

Answers

0 = (x-8)^2 -100

Add 100 to both sides

100 = (x-8)^2

Take the square root of both sides

10 = (x-8)

Remove the parentheses

10 = x-8

Add 8 to both sides

18 = x

Answer: x = 18

Which number is greater than 234,781,114?
A. 3.425 x 10 to the power of 6
B. 3.425 x 10 to the power of 8
C. 3.425 x 10 to the power of 7
D. 3.425 x 10 to the power of 5

Answers

Answer:

I think its B.

Step-by-step explanation:

sorry if i am wrong.

In triangle ABC, AC=13, BC=84, and AB=85. Find the measure of angle C

Answers

Given:

In triangle [tex]ABC, AC=13, BC=84, AB=85[/tex].

To find:

The measure of angle C.

Solution:

Law of Cosines:

[tex]\cos C=\dfrac{a^2+b^2-c^2}{2ab}[/tex]

[tex]\cos C=\dfrac{BC^2+AC^2-AB^2}{2(BC)(AC)}[/tex]

Substituting the given values, we get

[tex]\cos C=\dfrac{(84)^2+(13)^2-(85)^2}{2(84)(13)}[/tex]

[tex]\cos C=\dfrac{7056+169-7225}{2184}[/tex]

[tex]\cos C=\dfrac{0}{2184}[/tex]

[tex]\cos C=0[/tex]

Taking cos inverse on both sides, we get

[tex]C=\cos^{-1}(0)[/tex]

[tex]C=90^\circ[/tex]

Therefore, the measure of angle C is 90 degrees.

Answer:

eason

Step-by-step explanation:

boy

why did u read this