Answer: Second row
The y intercept is 2
=============================================================
Explanation:
The y intercept always occurs when x = 0. Visually, the y intercept is the location where the graph crosses the y axis.
In the table, we see that x = 0 pairs up with y = f(x) = 2 in the second row. So we can say that the y intercept is 2.
Side note: the x intercept is 1 since it occurs when y = 0.
Can someone please help me out
Step-by-step explanation:
[tex] \sqrt{ - 81} = 9i \\ \sqrt{ - 11} = i \sqrt{11} \\ \sqrt{ - 20} = i \sqrt{20} [/tex]
Each of 8 students reported the number of movies they saw in the past year. This is what they reported:
11, 17, 14, 11, 4, 7, 11, 11
Find the mean and median number of movies that the students saw.
If necessary, round your answers to the nearest tenth.
Answer:
10.75
11
Step-by-step explanation:
the mean is the average, so add up all of the values and divide by 8 because there are 8 values :
(11 + 17 + 14 + 11 + 4 + 7 + 11 + 11)/8 = 10.75
the median is the middle value when the numbers are written in ascending or descending order :
4, 7, 11, 11, 11, 11, 14, 17
we can cross out the values on the ends, to get to the middle. if we do this, we are left with 11, 11
find the average of these numbers :
which is 11.
The graph of the function g(x) is given for #1 - 5.
1. Which of the following is the given function's
average rate of change on the interval PLS HELP. ASAP
Answer:
sorry mistalely hai Don Bosco school leave gareko he'llo you so much for your time and consideration and I will mark as the brillianest plzzzzzzzzzzzzzzzzzzzz seetq you so much for your time and consideration and I will mark as the brillianest plzzzzzzzzzzzzzzzzzzzz seetq you so much for your time and consideration and I will mark as the brillianest plzzzzzzzzzzzzzzzzzzzz seetq you so much for your time and consideration and I will mark as the brillianest plzzzzzzzzzzzzzzzzzzzz seetq you so much for
5/21 as a decimal rounded to 3 decimal places
[tex] \sf \: \frac{5}{21 } \: rounded \: to \: 3 \: decimal \: places \: is \: \boxed{ \underline{ \bf0.238}}. \\ \longrightarrow \sf \: Just \: divide \: 5 \: by \: 21 \: upto \: 3 \: decimal \: places \\ \sf \: to \: get \: the \: answer.[/tex]
HELP PLEASE!
Given that sin A=3/7, cos B=-2/5, and both AA and B are in quadrant II, find cos (A-B). Simplify to a single value and leave it in the form of a rational number.
First, recall that
cos(A - B) = cos(A) cos(B) + sin(A) sin(B)
so you just need to find cos(A) and sin(B).
Since both A and B end in the second quadrant, you know that
• cos(A) and cos(B) are both negative
• sin(A) and sin(B) are both positive
Then from the Pythagorean identity, you get
cos²(A) + sin²(A) = 1 ==> cos(A) = -√(1 - sin²(A)) = -2√10/7
cos²(B) + sin²(B) = 1 ==> sin(B) = +√(1 - cos²(B)) = √21/5
You'll end up with
cos(A - B) = (-2√10/7) (-2/5) + (3/7) (√21/5)
… = (4√10 + 3√21)/35
(which makes the last sentence in the question kind of confusing, because this expression doesn't get much simpler and it's certainly not a rational number)
The value of cos(A - B) is approximately 23/25
Given that A and B are in the second quadrant, we have
sin A = 3/7cos B = -2/5To find cos(A - B), we have to use trigonometric functions
cos(A - B) = cosAcosB + sinAsinB ...equation(i)
but
cos A[tex]cos^2A + sin^2A =1 \\cos^2A = 1 - sin^2A\\cos^2A = 1 - (\frac{3}{7})^2 = 1 - \frac{9}{49}= cosA= -\frac{2\sqrt{5} }{7}[/tex]
Having the value of cos A, let's solve for cosB
Cos Bcos B = -2/5
[tex]sin^2B = 1-cos^2B\\sin^2B = 1-(-\frac{2}{5})^2= 1-\frac{4}{25}\\sinB = \sqrt{\frac{21}{25} }=\frac{\sqrt{21} }{5}[/tex]
cos(A-B)substituting the values if sinA, cosA, sinB, cosB into equation(i) above;
[tex]cos(A-B)=cosAcosB+sinAsinB\\cos(A-B)=(-\frac{2\sqrt{5} }{7})(-\frac{2}{5})+(\frac{3}{7})(\frac{\sqrt{21} }{5})\\cos(A-B)=\frac{3\sqrt{21}+4\sqrt{5} }{35} \\cos(A-B) = 23/35[/tex]
The value of cos(A-B) is given above
Learn more on trigonometric functions here;
https://brainly.com/question/4326804
HELP!!!!!
If anyone knows the answer please tell me as soon as possible PLEASE!!!!
Answer:
Plotting the points on graph and joining them gives a right angle triangle
Answer:
right angle triangle
Step-by-step explanation:
Slope = (Y1-Y2)/(X1-X2)
The slope of AC is 1/3. The slope of BC is -3. Therefore AC is perpendicular to BC (right angle).
what’s the answer help pls
Answer:
D should be the anwser if im not mistaken!
Step-by-step explanation:
rp= 6 cm and as u can tell the side where q,s lies is a little bit longer so itll be 1 cm longer the r,p!!
Answer:
7
Step-by-step explanation:
Triangle Proportionality Theorem : If a line parallel to one side of a triangle intersects the other two sides of the triangle, then the line divides these two sides proportionally.
[tex]\frac{RP}{PT}[/tex] = [tex]\frac{SQ}{QT}[/tex] Set up proportions
[tex]\frac{6}{18}[/tex] = [tex]\frac{x}{21}[/tex] Cross multiply
18x = 126 Divide to isolate x
x = 7
William wishes to view a frequency table for grouped data using his monthly credit card statements for the last 20 months, shown below. Construct the table for William using six classes. 1312, 1303, 809, 1477, 1263, 1444, 894, 1051, 1485, 1433, 1132, 1221, 1179, 945, 995, 1179, 1172, 1373, 906, 955 Provide your answer below: Lower Class Limit Upper Class Limit Frequency 809 1486
Frequency is the number of incidences of an occasion or value. A frequency table that displays the number of incidences of the goods and the number of times, and the further discussion can be defined as follows:
Lower class than adults who have little over two-thirds of a nationwide median's average household income.The higher class would include families with substantial wealth and biz incomes or where the primary breadwinner is utilized as a manager or a professional worker.Calculation:
[tex]lower\ \ \ \ \ \ \ \ \ upper \ \ \ \ \ \ \ \ \ frequency\\\\809\ \ \ \ \ \ \ \ \ 921 \ \ \ \ \ \ \ \ \ 3\\\\922 \ \ \ \ \ \ \ \ \ 1034 \ \ \ \ \ \ \ \ \ 3\\\\1035 \ \ \ \ \ \ \ \ \ 1147\ \ \ \ \ \ \ \ \ 2\\\\1148 \ \ \ \ \ \ \ \ \ 1260\ \ \ \ \ \ \ \ \ 4\\\\1261 \ \ \ \ \ \ \ \ \ 1373 \ \ \ \ \ \ \ \ \ 4\\\\1374 \ \ \ \ \ \ \ \ \ 1486\ \ \ \ \ \ \ \ \ 4[/tex]
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Which graphs are the graphs of even functions?
Use the diagram.
What is the length of }EG ?
A 1 B 4.4
C 10 D 16
Answer:
Option (D)
Step-by-step explanation:
Length of the bar EG = 1.6x
If F is a point on the bar such that,
EF + FG = EG
Measure of segment EF = 6
Measure of FG = x
By substituting measures of each side,
6 + x = 1.6x
1.6x - x = 6
0.6x = 6
x = 10
Length of EG = x + 6
= 10 + 6
= 16 units
Option (D) will be the correct option.
From the given diagram , the length of EG is 16
Given :
From the diagram , we can see that
EF=6, FG=x and EG=1.6x
We know that , EG=EF+FG
[tex]EG=EF+FG\\1.6x=6+x\\Solve \; for \; x\\1.6x-x=6\\0.6x=6\\divide by \; 0.6\\x=10[/tex]
Now we find out EG
EG=1.6x
Substitute 10 for x
[tex]EG=1.6x=1.6(10)=16\\[/tex]
EG=16
The length of EG is 16
Learn more : brainly.com/question/17259876
ASAP HELP!! PLEASEEEE!!
Answer:
Step-by-step explanation:
5.1, please this is just a guess from using my head to calculate
You wait in line for hours to get the new special edition Nikes for $250, but you have to pay 5.3% in Virginia state sales tax. What is the total you will pay?
Answer:
263.25
Step-by-step explanation:
250 x .053 (5.3%) = 13.25 tax
250 + 13.25 = 263.25 price plus sales tax
Answer:
263.25
Step-by-step explanation:
Which of the following describes graphing y ≥ |x| + 4?
A. Translate y = |x| down 4 units and shade inside the V.
B. Translate y = |x| right 4 units and shade inside the V.
C. Translate y = |x| left 4 units and shade inside the V.
D. Translate y = |x| up 4 units and shade inside the V.
Answer:
The choose (D)
D. Translate y = |x| up 4 units and shade inside the V.
Given the sequence -14, -6, -2, 0, 1, ..., find the recursive formula.
write 5 lcms of 100 and 120
Answer:
The LCM of 100 and 120 is 600.
The LCM of 5 and 120 is 120.
LCM of 5 and 100 is 100.
Step-by-step explanation:
I think this is the answer . If it is not sorry .
Use the expression, X^2-7
What is the value of the expression above when n=5
Answer:
18
Step-by-step explanation:
X^2 - 7 =
Since we need to evaluate the expression when X = 5, we replace X with 5.
= 5^2 - 7
Now, according to the correct order of operations, we need to do the exponent first. 5^2 = 5 * 5 = 25
= 25 - 7
Finally, we subtract.
= 18
Answer: 18
The volumes of two similar solids are 512cm3 and 2197cm3. If the smaller solid has a surface are of 960cm2, find the surface area of the larger solid. Part 1: find the similarity ratio by taking the cube root of each volume. Show your work. Part 2: use your answer from part 1 to find the ratio of the surface areas. Show your work. Part 3: set up a proportion and solve to find the surface area of the larger solid.
Answer:
see below
Step-by-step explanation:
Part 1:
(512) ^ 1/3
-------------------
(2197) ^ 1/3
8
-----
13
The scale factor is 8:13
Part 2
The ratios of the areas is related by scale factor squared
8^2
-----
13^2
64
------
169
Part 3
64 960
------ = ----------------
169 SA larger
Using cross products
64 * SA = 169 * 960
64 SA = 162240
Divide each side by 64
64 SA/ 64 = 162240 / 64
SA = 2535
2535 cm^2
Which expression is equivalent to 4-2 _ 2-3
Answer:
16
Step-by-step explanation:
First you calculate the value
(2)÷2^-2
Then you simplify
2^4
=16
Use special right triangle ratios to find the lengths of the other leg and the hypotenuse
Answer:
leg = 18
hypotenuse = 18 sqrt(2)
Step-by-step explanation:
We know that sin theta = opp side / hypotenuse
sin 45 = 18 / hyp
hyp sin 45 = 18
hyp = 18 / sin 45
hyp = 18 sqrt(2)
Since this is an isosceles triangle ( the two angles are the same measure), the two legs have to be the same length
leg = 18
the lengths of the other leg and the hypotenuse
is 18 units and 18[tex]\sqrt{2}[/tex]units respectively.
Answer:
Solution given:
Let <C=<B=45°
AB=18 units
BC=?
AC=?
again
By using
By usingspecial right triangle ratios
sin C=opposite/hypotenuse=AB/AC=18/AC
Sin 45=18/AC
AC=18/sin45
AC=hypotenuse=18[tex]\sqrt{2}[/tex]units
again
Tan A=opposite/adjacent=BC/AB=BC/18
Tan45=BC/18
BC=Tan45*18
BC=length of another leg=18 units.
What are the steps to this problem (along with the answer)?
Answer:
x = 3
Step-by-step explanation:
In this piece-wise function, there are three defined sections, each for a different range of x. To find an x where y is -9, we have to set all parts of it equal to -9.
-x, x < -3
So, we can start by setting -x equal to -9 and solve for x:
-x = -9
x = 9
Our domain for this piece of the function is supposed to be x < -3. x = 9 does not fit into this range, meaning, in this range, there is no x for y = -9.
2x, -3 ≤ x ≤ -2
We can set the value 2x equal to -9 and, again, solve for x:
2x = -9
x = -4.5
The solution x = -4.5 does not fit into the defined domain of -3 ≤ x ≤ -2, therefore it is not a solution.
-x^2, x > -2
One last time, we can set -x^2 equal to -9 and solve for x:
-x^2 = -9
x^2 = 9
x = 3, x = -3
We are looking for a solution that fits into the domain, x > -2, x = -3 does not work, but x = 3 does.
In conclusion, the only solution where it fit the domain was x = 3
Answer:
x = 3
Step-by-step explanation:
x = - 3 in interval - 3 ≤ x ≤ - 2 then f(x) = 2x , so
f(- 3) = 2(- 3) = - 6 ≠ - 9
x = 9 in interval x > - 2 then f(x) = - x² , so
f(9) = - 9² = - 81 ≠ - 9
x = 3 in interval x > - 2 then f(x) = - x²
f(3) = - 3² = - 9
x = - 4.5 in the interval x < - 3 then f(x) = - x , so
f(- 4.5) = - (- 4.5) = 4.5
Thus
y = - 9 when x = 3
(c+d)^2+11(c+d)+30
Factor completely.
Answer:
firstable give c+b a polynomial value like x
so its will be x^2+11x+30
after the we have to factor it
30=6×5
and 11=6+5
so its will become
(x+6)×(x+5)=x^2+11x+30
x=c+d
(c+d+6)×(c+d+5)=(c+d)^2+11(c+d)+30
have a great day
Can you guys help me find x for both
Answer:
x = 6 and x = 9
Step-by-step explanation:
16
MN is half the length of KL
MN = [tex]\frac{1}{2}[/tex] × 12 = 6
--------------------------------------------
17
Δ LMN and Δ LJK are similar triangles, so the ratios of corresponding sides are equal, that is
[tex]\frac{LM}{LJ}[/tex] = [tex]\frac{MN}{JK}[/tex] , substitute values
[tex]\frac{x}{x+9}[/tex] = [tex]\frac{8.5}{17}[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )
2x = x + 9 ( subtract x from both sides )
x = 9
Prime numbers which are the sum and difference of other two prime numbers at the same time.
Answer:
Let a be the smaller of the two primes.
Now the middle of 2 primes is always even. So the middle number a+1 is divisible by 2.
Next the smaller of the primes when divided by 3 can have remainders 1,2.
1 is ruled out as possible remainder because then the remainder of a+2, the bigger of the primes would be (a+2) mod 3=(1+2) mod 3=3 mod 3=0,a contradiction since a prime number(except 3) when divided by 3 cannot have 0 as remainder.
So 2 is the only possible remainder of a. So the remainder of the bigger of the two primes when divided by 3 is (a+2) mod 3= (2+2) mod 3=4 mod 3=1.
This implies the middle number must have remainder (a+1)mod 3=(2+1)mod 3=3 mod 3=0. So the middle number is divisible by 3 also.
Hence a+1 is divisible by both 3 and 2 and since 2 and 3 have no common factors, so the middle number is divisible by 6
4. PLEASE HELP ME
Which of the quadratic functions has the widest graph?
A. y= -4/5x2
B. y= -4x2
C. y= 1/3x2
D. y= 0.3x2
Answer:
D. y= 0.3x2
Step-by-step explanation:
In quadratic functions, the value of a affects the wideness of the graph. The smaller the absolute value of a, the wider the graph. In these choices, 1/3 and 0.3 are the smallest. To understand which is smaller convert both to decimals; 1/3 is 0.3333 repeating. Therefore, 0.3 is slightly smaller and wider.
Please help me !!!!!!!!!!
Answer:
[tex]EF=6[/tex]
Step-by-step explanation:
In this problem, one is given a circle with two secants (that is a line that intersects a circle at two points). One is given certain measurements, the problem asks one to find the unknown measurements.
The product of the lengths theorem gives a ratio between the lengths in the secants. Call the part of the secant that is inside the circle (inside), and the part of the secant between the exterior of the circle and the point of intersection of the secants (outside). The sum of (inside) and (outside) make up the entire secant, call this measurement (total). Remember, there are two secants, ([tex]secant_1[/tex]) and ([tex]secant_2[/tex]) in this situation. With these naming in mind, one can state the product of the length ratio as the following:
[tex]\frac{total_1}{outside_2}=\frac{total_2}{outside_1}[/tex]
Alternatively, one can state it like the following ratio:
[tex]\frac{inside_1+ouside_1}{outside_2}=\frac{inside_2+outside_2}{outside_1}[/tex]
Apply this ratio to the given problem, substitute the lengths of the sides of the secants in and solve for the unknown.
[tex]\frac{EF+FG}{HG}=\frac{SH+HG}{FG}[/tex]
[tex]\frac{2x+4}{5}=\frac{x+5}{4}[/tex]
Cross products, multiply the numerator and denominators of opposite sides of the fraction together,
[tex]\frac{2x+4}{5}=\frac{x+5}{4}[/tex]
[tex]4(2x+4)=5(x+5)[/tex]
Simplify,
[tex]4(2x+4)=5(x+5)[/tex]
[tex]8x+16=5x+25[/tex]
Inverse operations,
[tex]8x+16=5x+25[/tex]
[tex]3x+16=25\\3x=9\\x=3[/tex]
Substitute this value into the equation given for the measure of (EF),
[tex]EF=2x\\x=3\\\\EF=2x\\=2(3)\\=6[/tex]
A sector of a circle has an arc length of pi cm and a central angle of pi over 6 radians. What is the area of the sector?
Answer:
Area of sector is 6pi cm^2
Step-by-step explanation:
Mathematically pi radians is 180 degrees
thus pi/6 radians is 180/6 = 30 degrees
The formula for the length of an arc is;
theta/360 * 2 * pi * r
where theta in this case is 30 degrees
And the arc length is pi
so we have
30/360 * 2 * pi * r = pi
30/360 * 2 * r = 1
60r = 360
r = 360/60
r = 6 cm
Now the area of a sector is;
theta/360 * pi * r^2
30/360 * pi * 36
= 6pi cm^2
If Ф ∈ (0, pi/2) and tan(pi cosФ) = cot(pi sinФ), then cos(Ф- pi/4) is equal to?\
Answer:
please see the answer in the picture.
A wind turbine has blades 50m in diameter and an overall height (to the highest point) of 125m. If it has four blades instead of three, create four equations modelling the height of a point on the tip for each of the four blades.
Answer:
Blade A : H(θ) = 75 + 50 sin θ
Blade B : H(θ) = 75 + 50 sin(θ + 90° )
Blade C : H(θ) = 75 + 50 sin( θ + 180° )
Blade D : H(θ) = 75 + 50 sin( θ + 270° )
Step-by-step explanation:
Given data :
Diameter of blade = 50 m
overall height = 125 m
The four blades : Blade A , Blade B, Blade C, Blade D all moves in same direction hence they make 90° to each other.
Lets assume The blades are standing at θ with the horizontal
The four equation modelling the heights :
Blade A : H(θ) = 75 + 50 sin θ
Blade B : H(θ) = 75 + 50 sin(θ + 90° )
Blade C : H(θ) = 75 + 50 sin( θ + 180° )
Blade D : H(θ) = 75 + 50 sin( θ + 270° )
PLEASE HELP QUICK 30 POINTS !!!!!!
Ryan wants to make a triangular deck. He wants each side to be a different length.
Select three lengths he could use to make a triangle:
Side 1:
Side 2:
Side 3:
:: 3 feet
:: 10 feet
.: 20 feet
:: 25 feet
:: 60 feet
Answer:
10 ft, 20ft and 25 ft.
Step-by-step explanation:
10 ft, 20ft and 25 ft.
This will make a triangle as 25 < (10 + 20).
Answer:
Solution given:
one side of a triangle must be less than the sum of two other side .
by making these sense:
3<10+20
10<20+3
20<10+3not true
these three side are not possible.
again
10<20+25
20<25+10
25<20+10
these three side are true so
required side are:
Side 1:10
Side 2:25
Side 3:20
Find the missing segment in the image below
Answer:
8? not sure tho....
Step-by-step explanation: