Answers
Answers:
Functions
y = -x+11y = 2x^2-6x+4y = -7Not functions
x = 3x^2+y^2 = 81y^2 = -5x-12=======================================================
Explanation:
A function is possible if and only if any given x input leads to exactly one y output.
For something like x^2+y^2 = 81, we can see that x = 0 leads to either y = 9 or y = -9. So this would not be a function. We would need x to pair with only y value to have it be a function.
We have the same thing going on with y^2 = -5x-12 as well.
For anything of the form x = k, where k is any real number, this is also not a function. We have one single input only and it leads to infinitely many outputs. So in a sense, this is even worse compared to the other examples.
-----------------
In summary, we have these three non-functions:
x = 3x^2+y^2 = 81y^2 = -5x-12Everything else is a function. You can use the vertical line test as a visual way to check.
Related Questions
Find the volume of each figure. Round your answers to the nearest tenth, if necessary
Answers
Answer:
1.92 m³
hopefully this answer can help you to answer the next question.
Simplify this expression.
I need u again pls
Answers
Answer:
The answer is the Second Option
Step-by-step explanation:
Answer:
the second one sqrt(10) + sqrt(15) -sqrt(14) - sqrt(21)
Step-by-step explanation:
The question is "find the lowest common multiple of 4 and 6"
with step by step explaination
Answers
Answer:
12
Step-by-step explanation:
4s multiples:
4,8,12,16,20,24
6s multiples:
6,12,18,24,30,36
lowest number that is a common multiple between both 4 and 6:
12
Answer: 2
Step-by-step explanation:
Can you help please answer will give Max points
Answers
Answer:
28 4/9
Step-by-step explanation:
5 1/3 times 5 1/3
Find the value of x in Circle O.
Answers
Answer:
x=8
Step-by-step explanation:
x^2+15^2=17^2, x=sqrt(64)=8
For what values of k does the equation (2k + 1)x^2 + 2x = 10x – 6 have two
real and equal roots?
Answers
The equation has two real and equal roots for [tex]k = \frac{5}{6}[/tex]
In this question, we use the concept of the solution of a quadratic equation to solve it, considering that a quadratic equation in the format:
[tex]ax^2 + bx + c = 0[/tex]
has two equal solutions if [tex]\Delta = b^2 - 4ac[/tex] is 0.
------------------------------------
In this question:
The equation is:
[tex](2k+1)x^2 + 2x = 10x - 6[/tex]
Placing in the correct format:
[tex](2k+1)x^2 + 2x - 10x + 6 = 0[/tex]
[tex](2k+1)x^2 - 8x + 6 = 0[/tex]
Thus, the coefficients are: [tex]a = 2k + 1, b = -8, c = 6[/tex]
------------------------------------
Delta:
We want it to be positive, so:
[tex]\Delta = b^2 - 4ac[/tex]
[tex]\Delta = 0[/tex]
[tex]b^2 - 4ac = 0[/tex]
[tex](-8)^2 - 4(2k+1)(6) = 0[/tex]
[tex]64 - 48k - 24 = 0[/tex]
[tex]-48k + 40 = 0[/tex]
[tex]-48k = -40[/tex]
[tex]48k = 40[/tex]
[tex]k = \frac{40}{48}[/tex]
[tex]k = \frac{5}{6}[/tex]
The equation has two real and equal roots for [tex]k = \frac{5}{6}[/tex]
A similar question is found at https://brainly.com/question/12144265
Find the discriminant of the quadratic equation x2 + 10x + 24 = 0 and use it to determine the number and types of solutions. b2 − 4ac
Answers
Answer:
Step-by-step explanation:
x² + 10x + 24 = 0
Discriminant = 10² - 4×1×24 = 4
The discriminant is positive, so there are two distinct, real solutions.
Answer:
The answer is C) 4; Two real solutions.
Step-by-step explanation:
x2 + 10x + 24 = 0 in the function
x2 resembles a
10x resembles b
24 resembles c
so, let's convert.
b2-4ac
(10) ^2 - 4(1)(24)
100 - 96
= 4
If a translation of (x,y) (x+6,y-10) is applied to figure ABCD, what are the coordinates of D?
Answers
Image of figure ABCD is missing and so i have attached it.
Answer:
D_new = (-1, - 12)
Step-by-step explanation:
From the figure attached, the current coordinates of D are; (-5, -2)
Now, we are told the figure undergoes a translation of (x,y) (x+6,y-10)
Thus, this means we add 6 to the x value and subtract 10 from the y-value.
Thus, new coordinate of D is;
> (-5 + 6, -2 - 10)
> (-1, - 12)
Answer:
1, -12
Step-by-step explanation:
D = -5, -2
|
-5 + 6 = 1
|
-10 and -2 is -12
1, -12
did it on edge, got it right.
instructions find the value of x
Answers
Answer:
Given two equal chords. Since the line from the centre is always equal, thus the lines that bisect the two chords are also equal. X=5
Rectangle ABCD is similar to rectangle JKLM. AB = 12, BC = 8, CD = 12, DA = 8, and JK = 15. What is the scale factor from JKLM to ABCD? Reduce all answers.
Answers
Answer:
4/5 or 0.8
Step-by-step explanation:
this problem description is not very precise. it leaves out the definition what corners or sides of JKLM correspond to corners and sides of ABCD.
I assume J and K correlate to A and B, and JK is a long side of JKLM.
so, we are going from JKLM to ABCD.
that means we are going from larger to smaller (as JK = 15 and therefore larger than AB = 12).
what is the scale factor to go from 15 to 12 ?
15 × x = 12
x = 12/15 = 4/5 or 0.8
Change 400cm into mm
Answers
Answer:
4,000mm
Step-by-step explanation:
I tryed my best
Answer:
mate...
cm to mm is by multiplying 10
400 * 10 = 4000mm
brainliest l m a o
pls help graph of function
Answers
Answer:
i: -1.3
ii: 1.3
Step-by-step explanation:
You literally have it.
I hope this helps!
pls ❤ and give brainliest pls
find the distance of gap d
Answers
Answer:
[tex]\displaystyle d \approx 15.8768[/tex]
Step-by-step explanation:
We want to find the distance of d or AB.
From the right triangle with a 35° angle, we know that:
[tex]\displaystyle \tan 35^\circ = \frac{50}{PB}[/tex]
And from the right triangle with a 42° angle, we know that:
[tex]\displaystyle \tan 42^\circ = \frac{50}{PA}[/tex]
AB is PA subtracted from PB. Thus:
[tex]\displaystyle d = AB = PB - PA[/tex]
From the first two equations, solve for PB and PA:
[tex]\displaystyle \frac{1}{\tan 35^\circ } = \frac{PB}{50} \Rightarrow PB = \frac{50}{\tan 35^\circ}[/tex]
And:
[tex]\displaystyle \frac{1}{\tan 42^\circ } = \frac{PA}{50} \Rightarrow PA = \frac{50}{\tan 42^\circ}[/tex]
Therefore:
[tex]\displaystyle d = AB = \frac{50}{\tan 35^\circ} - \frac{50}{\tan 42^\circ}[/tex]
Using a calculator:
[tex]\displaystyle d= AB \approx 15.8768[/tex]
Solve the following, where 0° < θ < 360°.
If cos θ=2/3 and tan θ<0
Find θ.
Answers
Answer:
The angle θ = 312°.
Step-by-step explanation:
0° < θ < 360°
If cos θ = 2/3 and tan θ < 0
As cos θ is positive and tan θ is negative so the angle is in fourth quadrant.
cos θ = 2/3
θ = 312°
please help me to solve this
Answers
Answer:
Step-by-step explanation:
a) 3x^2
b) (512)^-2/3=2^n
1/64=2^n
n=-6
There is a $30 fee to rent a tool from the local hardware store plus $6 per day. If Joe rents a jackhammer for 5 days, what is his total bill? The correct function for this situation is f(x) = 30x + 6.
O False
O True
Answers
The length, breadth and thickness of a brick is 18 cm, 8 cm, and 5 cm respectively. Find the area of the widest part of the brick. Also find the volume of the brick.
Answers
Answer:
area = 8 × 18 = 144 cm^2
volume 8×18×5 = 720cm^3
true or false. can someone help me w this??
Answers
Answer:
false
Step-by-step explanation:
it would be in the first quadrant
Answer:
False
Step-by-step explanation:
The real part is positive and the imaginary part is positive which put is in the first quadrant
If someone could help that would really be great. Thank you.!
Answers
the angles should add up to 180 degrees in a triangle, so if you do 180-105-30, you end up with 45 (hope that helps)
The temperature on a winter was -23 °F. The temerature rise by 5 °F when the sun came up. When the sun set again, the temperature dropped by. 7°F. Write and evaluate an exspression to find the temperature after the sun set.
Answers
Answer:
-25
Step-by-step explanation:
First, add 5 to -23 since the temperature is getting hotter.
so -23 +5= -18
Second, minus the answer by 7 since the temperature is now falling down after the sunset.
so -18 -7 = -25
or...
this step can be simplified as:
-23 +5 -7 =. -25
Which pair of polygons is congruent?
Answers
Answer:
C
Step-by-step explanation:
Polygon 3 and 5 are congruent cause they have the same length of side
plz help!! will mark brainliest!!
Answers
Answer:
correct me if I'm but i think the net cash flow is 3,790 because 2,040 a month income and 1,750 a month for other stuff. 2,040+1,750=3,790
Step-by-step explanation:
a. IfA= {a, b} and B = {p, q, r}, find A x B and B x A using tree diagram.
Answers
Answer:
Step-by-step explanation:
Please help me
A person starts walking from home and walks: 6 miles East 6 miles Southeast 3 miles South 5 miles Southwest 2 miles East This person has walked a total of 22Correct miles Find the total displacement vector for this walk: If this person walked straight home, they'd have to walk miles
Answers
Answer:
1) The total displacement vector is ((16 + √2)/2, -(6+11·√2)/2)
2) The number of miles they'd have to walk is approximately 13.856 miles
Step-by-step explanation:
1) The distance, direction, and location of the path of the walk the person takes, are listed as follows;
Start location, (0, 0)
6 miles East walk to location, (6, 0)
6 miles Southeast to location, (6 + 3·√2, -3·√2)
3 miles South to location, (6 + 3·√2, -3·√2 - 3)
5 miles Southwest to location, (6 + 3·√2 - 2.5·√2, -3·√2 - 3 - 2.5·√2)
2 miles East to location, (6 + 3·√2 - 2.5·√2 + 2, -3·√2 - 3 - 2.5·√2)
(6 + 3·√2 - 2.5·√2 + 2, -3·√2 - 3 - 2.5·√2) = ((16 + √2)/2, -(6+11·√2)/2)
Therefore the destination coordinates is ((16 + √2)/2, -(6+11·√2)/2)
The total displacement vector, [tex]\underset{d}{\rightarrow}[/tex] = ((16 + √2)/2, -(6+11·√2)/2)
d = (16 + √2)/2)·i - (6+11·√2)/2)·j
2) If the person walked straight home, the number of miles they'd have to walk, [tex]\left | \underset{d}{\rightarrow} \right |[/tex], is given as follows;
[tex]\left | \underset{d}{\rightarrow} \right | = \sqrt{\left(\dfrac{16 +\sqrt{2} }{2} \right)^2 + \left(-\dfrac{6 + 11 \cdot \sqrt{2} }{2} \right)^2 } = \sqrt{134 + 41 \cdot \sqrt{2} }[/tex]
Therefore;
If the person walked straight home, the number of miles they'd have to walk [tex]\left | \underset{d}{\rightarrow} \right | \approx 13.856 \ miles[/tex]
Câu 2. Cho hình thang cân ABCD (AB // CD, AB CD). Gọi O là giao điểm của AD và BC, E là giao điểm của AC và BD. Chứng minh rằng: | a) Tam giác AOB cân ở O.
b) Các tam giác ABD và BAC bằng nhau. C) EC = ED
d) OE là trung trực của AB và CD.
Answers
Answer:
Step-by-step explanation:
Ive never really understood 8th-9th grade volume, could use some help
Answers
The answer is B
Eplanation:
V = pi * r² * (h/3)
Then from here you just make h the subject of the formula:
h = (V * 3)/(pi * r²)
h = (393*3)/[3.14* (10/2)²]
h = 15.01910828 ft
which is rounded to 15 ft...B
:)
Use the points slope formula..
Answers
Answer:
y = -5/14 -13/7
Step-by-step explanation:
First find the slope
m = (y2-y1)/(x2-x1)
m = (1 - -4)/(-8 - 6)
= (1+4)/(-8-6)
= 5/-14
=-5/14
Point slope form is
y-y1 = m(x-x1)
y - -4 = -5/14(x-6)
y+4 = -5/14(x-6)
We want the equation in slope intercept form y = mx+b
Distribute
y+4 = -5/14x + 15/7
Subtract 4 from each side
y+4 -4= -5/14x + 15/7-4
y = -5/14x +15/7 - 28/7
y = -5/14 -13/7
PLSSSS HELP ME WHOEVER ANSWERS CORRECTLY GETS BRAINLIEST!!!!
1. How would we name the polynomial below? Think about degree and number of terms.
x^4 + 3x^2 - x
2. Simplify by adding
(x + 4) + (2x + 7)
3. Multiply
3x^2(5x^3)
4. Divide
8x^3y^5 / 4x^2y^3
Answers
Answer:
This is what you asked me just now.
Step-by-step explanation:
[100 Points]
SHOW YOUR WORK, PLEASE!
Answers
Answer:
691 251/256
Step-by-step explanation:
So basically exponents is how much time you time the same number
First on the top is 2 exponent 4. that is 2x2x2x2=16
Second is 3 exponent 3. 3x3x3=27
Third is 9 exponent 7. 9x9x9x9x9x9x9=4782969
Fourth is 4 exponent 6. 4x4x4x4x4x4=4096.
All together is 16/27x4782969/4096=691 251/256
BRAINLIEST Which equation could be solved using this application of the quadratic formula?
A.
x2 + 1 = 2x − 3
B.
x2 – 2x − 1 = 3
C.
x2 + 2x − 1 = 3
D.
x2 + 2x − 1 = -3
Answers
The quadratic equation that could be solved using the given application of the quadratic formula is x² + 2x - 1 = 3, which in standard form is x² + 2x - 4 = 0. Hence, option C is the right choice.
What is the quadratic formula?A standard quadratic equation of the form ax² + bx + c = 0, can be solved using the quadratic formula, which is given as:
[tex]x = \frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
How to solve the question?In the question, we are asked for the quadratic equation, which could be solved using this application of the quadratic formula:
[tex]x = \frac{-2\pm\sqrt{2^2-4(1)(-4)} }{2(1)}[/tex]
To find the quadratic equation for which we use the quadratic formula
[tex]x = \frac{-2\pm\sqrt{2^2-4(1)(-4)} }{2(1)}[/tex]
we compare this equation with the standard quadratic formula,
[tex]x = \frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
to get a = 1, b = 2, and c = -4, to get the standard quadratic equation, ax² + bx + c = 0, as (1)x² + (2)x + (-4) = 0, or x² + 2x - 4 = 0.
Now, we convert the given options in the standard form to check for the correct choice:
A. x² + 1 = 2x - 3 ⇒ x² - 2x + 4 = 0, which is not the correct choice.B . x² - 2x - 1 = 3 ⇒ x² - 2x - 4 = 0, which is not the correct choice.C. x² + 2x - 1 = 3 ⇒ x² + 2x - 4 = 0, which is the correct choice.D. x² + 2x - 1 = -3 ⇒ x² + 2x + 2 = 0, which is not the correct choice.Thus, the quadratic equation that could be solved using the given application of the quadratic formula is x² + 2x - 1 = 3, which in standard form is x² + 2x - 4 = 0. Hence, option C is the right choice.
Learn more about the quadratic formula at
https://brainly.com/question/1214333
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