HELP ME PLS I NEEDA GET THIS RIGHT PLS PLS ITS PYTHAGOREAN THEOREM

Answer:

H^2 = P^2 + B^2

H^2 = ( 3 root 2 )^2 + ( 3 root 2)^2

H^2 = 18 + 18

H^2 = 36

H = 6

Hence , option A is correct

hope that helps ✌

Complete question is;

Roger and Rita each drive at a constant speed between Phoenix and San Diego. Each driver’s distance for the same section of the trip is displayed below. Who had a head start, and how many miles was the head start?

A) Rita had a 28-mile head start.

B) Roger had a 26-mile head start.

C) Roger had a 25-mile head start.

D) Rita had a 22-mile head start.

Answer:

A) Rita had a 28-mile head start.

Step-by-step explanation:

Let's assume that Roger travelled a distance of 60 miles

And that;

Rita travelled a distance of 32 miles

We are told that they travelled between Phoenix and San Diego.

Thus, it means that if they have different distances but covered same section of the trip, it means the one with higher distance started before the section of the trip.

Thus, it means that Rita had a head start of Roger since she covered only 32 miles.

Thus;

Rita had a head start of; 60 - 32 = 28 miles

Answer:

Step-by-step explanation:

This is quite a doozy, my friend. We will set up a d = rt table, fill it in...and pray.

The table will look like this before we even fill anything in:

            d        =        r        *        t

SUV

sedan

Ok now we start to pick apart the problem. Motion problems are the hardest of all story problems ever. This is because there are about 100 ways a motion problem can be presented. So far what we KNOW for an indisputable fact is that the distance from Georgetown to Greenville is 120 km. So we fill that in, making the table:

             d      =      r      *      t

SUV     120

sedan  120

The next part is derived from the sentence "After an hour, the SUV was 24 km ahead of the sedan." This tells us the rate of the SUV in terms of the sedan. If the SUV is 24 km ahead of the sedan in 1 hour, that tells us that the rate of the sedan is r and the rate of the SUV is r + 24 km/hr. BUT we have other times in this problem, one of them being 25 minutes. We have a problem here because the times either have to be in hours or minutes, but not both. So we will change that rate to km/min. Doing that:

24 [tex]\frac{km}{hr}[/tex] × [tex]\frac{1hr}{60min}=.4\frac{km}{min}[/tex] So now we can fill in the rates in the table:

            d      =      r      *      t

SUV    120    =   r + .4

sedan 120    =     r

They left at the same time, so now the table looks like this:

             d      =      r      *      t

SUV    120     =   r + .4  *      t

sedan  120    =      r      *      t

We will put in the time difference of 25 minutes in just a sec.

If d = rt, then the equation for each row is as follows:

SUV:   120 = (r + .4)t

sedan:   120 = rt

Since the times are the same (because they left at the same time, we will set the equations each equal to t. The distances are the same, too, I know that, but if we set the distances equal to each other and then solve the equations for a variable, the distances cancel each other out, leaving us with nowhere to go. Trust me, I tried that first! Didn't work.

Solving the first equation for time:

sedan:  [tex]\frac{120}{r}=t[/tex]  That's the easy one. Now the SUV. This is where that time difference of 25 minutes comes in from the last sentence. Let's think about what that sentence means in terms of the times of each of these vehicles. If the sedan arrived 25 minutes after the SUV, then the sedan was driving 25 minutes longer; conversely, if the sedan arrived 25 minutes after the SUV, then the SUV was driving 25 minutes less than the sedan. The latter explanation is the one I used in the equation. Again, if the SUV was driving 25 minutes less than the sedan, and the equations are solved for time, then the equation for the SUV in terms of time is

[tex]\frac{120}{r+.4}=t-25[/tex] and we solve that for t:

[tex]\frac{120}{r+.4}+25=t[/tex]

Again, going off the fact that times they both leave are the same, we set the equations equal to one another and solve for r:

[tex]\frac{120}{r+.4}+25=\frac{120}{r}[/tex]

I began by first multiplying everything through by (r + .4) to get rid of it in the denominator. Doing that:

[tex][r+.4](\frac{120}{r+.4}) +[r+.4](25)=[r+.4](\frac{120}{r})[/tex] which simplifies very nicely to

[tex]120+25(r+.4)=\frac{120}{r}(r+.4)[/tex]  So maybe it's not so nice. Let's keep going:

[tex]120+25r+10=\frac{120r}{r}+\frac{48}{r}[/tex] and keep going some more:

[tex]130+25r=120+\frac{48}{r}[/tex] and now we multiply everything through by r to get rid of THAT denominator:

[tex]r(130)+r(25r)=r(120)+r(\frac{48}{r})[/tex] giving us:

[tex]130r+25r^2=120r+48[/tex] Now we have a second degree polynomial we have to solve by factoring. Get everything on one side and factor using the quadratic formula.

[tex]25r^2+10r-48=0[/tex]

That factors to

r = 1.2 and r = -1.6 and both of those rates are in km/minute. First of all, we cannot have a negative rate (this is not physics where we are dealing with velocity which CAN be negative) so we throw out the -1.6 and convert the rate of 1.2 km/minute back to km/hr:

[tex]1.2\frac{km}{min}[/tex] × [tex]\frac{60min}{1hr}[/tex] and we get

r = 72 km/h, choice B.

Wow...what a pain THAT was, right?!

The answer is

w + c ≤ 32

w < 11

w - the number of acres of wheat

c - the number of acres of corn

Johanna will plant up to 32 acres on her farm with wheat and corn:

w + c ≤ 32

Fewer than 11 acres will be planted with wheat:

w < 11

The two inequalities are:

w + c ≤ 32

w < 11

Answer:

See explanation

Step-by-step explanation:

Given

[tex]Flat = 20[/tex]

[tex]Visit = 5[/tex]

Required

The function to represent x visits

This is calculated as:

[tex]f(x) = Flat + Visit * x[/tex]

So, we have:

[tex]f(x) = 20 + 5 * x[/tex]

[tex]f(x) = 20 + 5x[/tex]

The second question is incomplete; however, I will explain how to calculate the horizontal asymptote of a rational function.

For polynomials with the same degree (i.e. m = n), the horizontal asymptote is calculated by dividing the coefficients of the highest degrees.

e.g.

[tex]f(x) = \frac{6x^2 + 1}{3x^2 + 4}[/tex] ---the degrees of both is 2

So, the horizontal asymptote is:

[tex]y = 6/3[/tex]

[tex]y =2[/tex]

If the numerator has a higher degree, then there is no horizontal asymptote.

If the denominator has a higher degree, then the horizontal asymptote is:

[tex]y = 0[/tex]

Answer:

First one is B, Second is 5

Step-by-step explanation:

got it right on edge

Answer:

Supplementary angles

Step-by-step explanation:

Angles 1 and 2 form a straight line which is 180 degrees.

They are supplementary angles

Answer:

70 cents or 0.70 dollars

Step-by-step explanation:

one dime is 10 cents so if you have 7 than you have 70 cents

Answer:

A

Step-by-step explanation:

Additive inverse is (5/3) and multiplicative inverse is (-3/5). Their product is (-1)

Inverse means the opposite of something.

In this case the opposite of -5/3 is 5/3.

So the answer is: 5/3

Answer: Is this a question? Or statement Yes they can be angles

Step-by-step explanation:

Answer:

5 up and 2 to the right

Step-by-step explanation:

The center will be at the same spot as circle D, dilate by 3, then the dilation maps circle C into circle D.

Answer:

-3/2

Step-by-step explanation:

Using the slope formula, we can find the slope of the line shown

m = ( y2-y1)/(x2-x1)

    = ( -1-3)/(-3-3)

   = -4/-6

  = 2/3

A line that is perpendicular is the negative reciprocal

-1/ (2/3) = -3/2

Answer:

the slope is 0

Step-by-step explanation:

y2-y1/x2-x1=-1-3/-3-3

y=0

Answer: [tex]864\ m^2,\ 24\ m[/tex]

Step-by-step explanation:

Given

Perimeter of the rhombus is [tex]120\ m[/tex]

Length of one of the diagonal is [tex]d_1=36\ m[/tex]

All the sides of the rhombus are equal

[tex]\Rightarrow 4a=120\\\Rightarrow a=30\ m[/tex]

Area of the rhombus with side and one diagonal is

[tex]\Rightarrow \text{Area=}\dfrac{1}{2}d\sqrt{4a^2-d^2}[/tex]

Insert the values

[tex]\Rightarrow \text{Area=}\dfrac{1}{2}\times 36\times \sqrt{4\cdot 30^2-36^2}\\\\\Rightarrow \text{Area= }18\sqrt{3600-1296}\\\Rightarrow \text{Area= }18\times 48\\\Rightarrow \text{Area= }864\ m^2[/tex]

Area with two diagonals length can be given by

[tex]\Rightarrow \text{Area =}0.5\times d_1\times d_2 \\\text{Insert the values}\\\Rightarrow 864=36\times d_2\\\Rightarrow d_2=24\ m[/tex]

Thus, the area of the rhombus is [tex]864\ m^2[/tex] and the length of the other diagonal is [tex]24\ m[/tex]

Answer:

A. Parallel lines have the same slope

Step-by-step explanation:

The direction of parallel lines are the same and are not different, hence their slopes must be the same.

Answer:

4,1,-6

3,-3,-4

x-axis,5,0

2,-7,3

1,4,2

y-axis,0,-4

Step-by-step explanation:

Answer:

1800

Step-by-step explanation:

3.6 m=360 cm

2.4 m=240 cm

36×24=86400-the area of floor

8×6=48-the area of one tile

86400÷48=1800-the number of rectangular tiles

Answer:

y = -2x - 7

Step-by-step explanation:

y = mx + b

m = slope = -2

b = y-int. = -7

Plug them in, you get y = -2x - 7

Answer:

5

Step-by-step explanation:

The Fundamental theorem of Algebra states that a polynomial of degree n has n roots, some may be complex.

11[tex]x^{5}[/tex] + 5x - 3 = 0 ← is a polynomial of degree 5

Thus the equation will have 5 roots

Answer:

The correct answer is B. $13,875.

Step-by-step explanation:

Since X and Y are in partnership with capital contributions of $ 50000 and $ 30000 respectively, and the partnership agreement provides that profits are to be shared in proportion to capital contributions and each partner is entitled to 10% interest on capital, and profit for the year was $ 37000, to determine what was the total amount credited to Y’s current account at the end of the year the following calculation must be performed:

50,000 + 30,000 = 80,000

80,000 = 100

30,000 = X

30,000 x 100 / 80,000 = X

37.5 = X

37,000 x 0.375 = X

13.875 = X

Answer:

x = 60.6 units

Step-by-step explanation:

Hi there!

In this right triangle, we're given the measure of an angle, the side opposite that angle and another side adjacent to that angle (that is not the hypotenuse). In this circumstance, we can use the tangent ratio to help us solve for the missing side:

[tex]tan\theta=\frac{opp}{adj}[/tex]

Plug in the given information:

opp = 27, adj = x, θ = 24

[tex]tan(24)=\frac{27}{x}\\x=\frac{27}{tan(24)} \\x=60.6[/tex]

Therefore, the length of the missing side is 60.6 units when rounded to the nearest tenth.

I hope this helps!

Answer:

Step-by-step explanation:

15. = 2.39

and jus use mathaway lma

Answer:

siis  corretoed

Step-by-step explanation:

Answer:

1/27

Step-by-step explanation:

- substitute the variable with the given datas

[3^-5 * 3^4]^3 * [3^-4 * (-9)^3]^0

- use  the properties of power

(3^-1)^3 * 1

3^-3

(1/3)^3

1/27

The answer is number 3 i.e. 1/27

Answer:

1/4

Step-by-step explanation:

Each coin has a probability of 1/2 of landing on tails

What you do is multiply these probabilities together to get 1/4

Answer:

5 cm

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

let h be the hypotenuse , then

h² = 3² + 4² = 9 + 16 = 25 ( take the square root of both sides )

h = [tex]\sqrt{25}[/tex] = 5

Answer:

Apply the distributive property.

4

x

+

4

⋅

−

3

−

2

(

x

−

1

)

>

0

Multiply

4

by

−

3

.

4

x

−

12

−

2

(

x

−

1

)

>

0

Apply the distributive property.

4

x

−

12

−

2

x

−

2

⋅

−

1

>

0

Multiply

−

2

by

−

1

.

4

x

−

12

−

2

x

+

2

>

0

Given:- 4(x - 3) - 2(x - 1) > 0.

Solving It:-

4(x - 3) - 2(x - 1) > 0

4x - 12 - 2x + 2 > 0

2x -10 > 0

2x > 10

x > 10/2

x > 5

The ratio 2:3 means for every 2 inches on the original, the photocopy would be 3 inches.

3/2 = 1.5

The photocopied image is 1.5 times larger than the original.

Side BG on the original is side FG on the copy:

14 x 1.5 = 21 meters

FG = 21 meters

Answer:

FG = 21

Step-by-step explanation:

The ratio is 2:3

2               BC

----- = ----------------

3                FG

2              14

----- = ----------------

3                FG

Using cross products

2FG = 3*14

2FG = 42

Divide by 2

FG = 21

Answer:

26/35

Step-by-step explanation:

So we gotta add it together, so 1/7+0.6 or 1/7+3/5. Common denominator is 35, so the answer is 26/35

Answer:

A) 4.7 < x < -3

B) 1.14 < x < 1.09

Step-by-step explanation:

a)

x + 14 < 4x + 2 < 3x + 11

x + 14 < 4x

14 < 4x - x

14 < 3x

4.7 < x

2 < 3x + 11

2 - 11 < 3x

-9 < 3x

-3 < x

4.7 < x - 3 < x

4.7 < x < -3

b)

x + 8 < 8x - 6 < 5x + 12

x + 8 < 8x

8 < 8x - x

8 < 7x

1.14 < x

-6 < 5x + 12

12 < 5x + 6

12 < 11x

1.09 < x

1.14 < x 1.09 < x

1.14 < x < 1.09

Answer:

x>4

Step-by-step explanation:

3/(x-4) >0

Divide each side by 3

3/(x-4) * 1/3 >0*1/3

1/(x-4) >0

We know if 1/(x-4) >0 then x-4 > 0

x-4>0

Add 4 to each side

x-4+4 >0+4

x>4

[tex]\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}[/tex]

[tex]:\implies{\dfrac{3}{x-4}>0}\\\\:\hookrightarrow{\dfrac{3}{x-4}×\dfrac{1}{3}>0×\dfrac{1}{3}}\\\\:\longrightarrow{x-4>0}\\\\:\implies{x-4+4>0+4}\\\\ :\dashrightarrow{\sf{x>4}}[/tex]

Answer:

UV = 10

HG = 25

Step-by-step explanation:

UV = (11+9)/2 = 20/2 = 10

HG = (28+22)/2 = 50/2 = 25

Answer:

Below in bold.

Step-by-step explanation:

First problem:

The length of the mid segment is the mean of the 2 outer segments.

So it is (11+9)/2

= 20/2

= 10.

Second problem:

As above, it is (22+28) / 2

= 50/2

= 25.