help me I m stuck on this question

Answer:

Explanation:

How much force is acting on a certain area

The ratio of atoms in a compound is shown by the subscripts: option A.

When writing the chemical formula of a compound, the ratio of atoms in the compound is shown by the subscripts attached to the element in the compound.

For example, the chemical formula of the compound water is H₂O

From the formula, the ratio of hydrogen to oxygen is shown by the subscript:

The ratio of hydrogen to oxygen is H : O = 2 : 1

Therefore, the ratio of atoms in a compound is shown by the subscripts: option A.

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The ratio of atoms in a compound is shown by the chemical formula.

Chemical formula refers to a representation of a compound using the symbols of the elements that make up the compound. The ratio of atoms in the compound can easily be observed by looking at the subscripts in the chemical formula.

Hence, the ratio of atoms in a compound is shown by the chemical formula. The chemical formula of a compound serves as the identity of the compound.

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Answer:

η = 0.5 = 50%

Explanation:

The efficiency of the power cycle is given by the following formula:

[tex]\eta = \frac{W}{Q_1}\\\\\eta = \frac{Q_1-Q_2}{Q_1}[/tex]

where,

where,

η = efficiency = ?

Q₁ = heat received from hot reservoir = 1000 KJ

Q₂ = heat discharged to cold reservoir = 500 KJ

Therefore,

[tex]\eta = \frac{1000\ KJ-500\ KJ}{1000\ KJ}[/tex]

η = 0.5 = 50%

Answer:

a)   W = - 1.752 10⁻¹⁸ J,  b)    U = + 1.752 10⁻¹⁸ J

Explanation:

a) work is defined by

         W = F . x

the bold letters indicate vectors, in this case the force is electric

         F = q E

we substitute

         F = q E x

the charge of the electron is

         q = - e

         F = - e E x

let's calculate

         W = - 1.6 10⁻¹⁹  365  3 10⁻²

         W = - 1.752 10⁻¹⁸ J

b) the change in potential energy is

          U = q ΔV

the potential difference is

          ΔV = - E. Δs

we substitute

         U = - q E Δs

the charge of the electron is

           q = - e

          U = e E Δs

we calculate

           U = 1.6 10⁻¹⁹ 365  3 10⁻²

           U = + 1.752 10⁻¹⁸ J

Answer:

26467.21 N

Explanation:

Initial height of water ( h1 )  = 5 m

diameter of container ( d1 )= 100 cm

pressure inside the container ( p1 )= 0.850 atm

Diameter of faucet ( d2 )= 1 inch

Calculate the value of the net force on the side of container

lets assume ; pressure outside the container ( p2 ) = 1 atm

Fnet = ( P1A1  + mg ) - ( P2A2 )

       = [ ( 0.85 * 101325 ) ( π(1/2)^2 ) + mg ) - [ ( 101325 )( π )(0.0127)^2 ]

       = [ 16902.2766 + pvg ] - [ 51.3161 ]

where ; pvg = pAhg = 1000 * π ( 1/2 )^2 * 5 * 9.8 = 9616.25

       = [ 16902.2766 + 9616.25 ] - [ 51.3161 ]   = 26467.21 N ( downwards )

Answer:

C. 16 m E

Explanation:

Applying,

The law of addition of vector: Vector in the same direction are added while vector in opposite direction are substracted

From the question above,

Step 1: Total distance covered towards east = 10+12 = 22 m E

Step2: Total distance covered towards west = 6 m W

Therefore, the resultant distance traveled = 22-6 = 16 m E

Hence the right option is C. 16 m E

Answer:

5g/cm

Explanation:

denisty=mass/volume

100/20

5g/cm

Answer:

A spinning electron produces a magnetic field.

Explains the fine structure of Hydrogen lines.

C is found using the Pythagorean theorem:

C = sqrt(a^2 + b^2)

Answer:

646.6 nm

Explanation:

Using the data given, we fit a linear model :

Spectroscope Readings Known Helium Wavelengths (nm)

3.65 388.9

4.75 486.6

4.90 501.6

5.65 587.6

6.45 667.8

7.00 706.5

Using technology like excel to fit the model, the regression model obtained is :

Y = 97.96582X + 27.48458

Where, y is the predicted or corrected wavelength value.

This mod could be used to calculate the corrected wavelength for a given Spectroscope value :

Given a Spectroscope value of 6.32 ; the corrected wavelength is obtained by replacing x in the equation by 6.32 and calculate y ;

Y = 97.96582X + 27.48458

x = 6.32

Y = 97.96582(6.32) + 27.48458

Y = 619.1439824 + 27.48458

Y = 646.6285624

Corrected wavelength value is : 646.6

Answer:

E = 20.03 J

Explanation:

Given that,

The amount of charge that passes through the filament of a certain lightbulb in 2.00 s is 1.67 C,

Voltage, V = 12 V

We need to find the energy delivered to the lightbulb filament during 2.00 s.

The energy delivered is given by :

[tex]E=I^2Rt[/tex]. ....(1)

As,

[tex]I=\dfrac{q}{t}\\\\I=\dfrac{1.67}{2}\\\\I=0.835\ A[/tex]

As per Ohm's law, V = IR

[tex]R=\dfrac{V}{I}\\\\R=\dfrac{12}{0.835}\\\\R=14.37\ \Omega[/tex]

Using formula (1).

[tex]E=0.835^2\times 14.37\times 2\\\\=20.03\ J[/tex]

So, the energy delivered to the lightbulb filament is 20.03 J.

Explanation:

Given:

[tex]A_1[/tex] = 4.5 cm[tex]^2[/tex]

[tex]v_1[/tex] = 40 cm/s

[tex]v_2[/tex] = 90 cm/s

[tex]A_2[/tex] = ?

a) The continuity equation is given by

[tex]A_1v_1 = A_2v_2[/tex]

Solving for [tex]A_2[/tex],

[tex]A_2 = \dfrac{v_1}{v_2}A1 = \left(\dfrac{40\:\text{cm/s}}{90\:\text{cm/s}}\right)(4.5\:\text{cm}^2)[/tex]

[tex]= 2\:\text{cm}^2[/tex]

b) If the cross-sectional area is reduced by 50%, its new area [tex]A_2'[/tex] now is only 1 cm^2, which gives us a radius of

[tex]r = \sqrt{\dfrac{A_2'}{\pi}} = 0.564\:\text{cm}[/tex]

Answer:

The correct answer is "[tex]21.344^{\circ}[/tex]" and "[tex]39.56^{\circ}[/tex]".

Explanation:

According to the question,

Slit width,

[tex]d=\frac{1}{910 \ lines/mm}[/tex]

  [tex]=\frac{1}{910\times 10^3}[/tex]

  [tex]=1.099\times 10^{-6} \ m[/tex]

The condition far first order maxima will be:

⇒ [tex]d Sin \theta = 1 \lambda[/tex]

Now,

⇒ [tex]\Theta_{min} = Sin^{-1} (\frac{\lambda}{d} )[/tex]

             [tex]=Sin^{-1} (\frac{400\times 10^{-9}}{1.099\times 10^{-6}} )[/tex]

             [tex]=21.344^{\circ}[/tex]

⇒ [tex]\Theta_{max} = Sin^{-1} (\frac{\lambda}{d} )[/tex]

             [tex]=Sin^{-1} (\frac{700\times 10^{-9}}{1.099\times 10^{-6}} )[/tex]

             [tex]=39.56^{\circ}[/tex]

Answer:

The covalent bond is formed by pairs of electrons that are shared between two atom

Explanation:

The covalent bond is formed by pairs of electrons that are shared between two atoms, in general the electrons must have opposite spins to have a lower energy state.

In this bond, the electrons are between the two atoms and are shared between them in such a way that there is a configuration of eight electrons in the orbit.

length= metre

mass= kg

time= second

temperature = kelvin

current= ampere

luminous intensity= candela

Amount of substance = mole

etc

I hope this will help you

stay safe

Answer:

1. Initial velocity = 24 m/s

2. Deceleration = –4 m/s²

Explanation:

From the question given above, the following data were obtained:

Distance travelled (s) = 72 m

Time (t) = 6 s

Final velocity (v) = 0 m/s

1. Determination of the initial velocity.

Distance travelled (s) = 72 m

Time (t) = 6 s

Final velocity (v) = 0 m/s

Initial velocity (u) =?

s = (u + v)t / 2

72 = (u + 0) × 6 / 2

72 = u × 3

Divide both side by 3

u = 72 / 3

u = 24 m/s

2. Determination of the deceleration.

Time (t) = 6 s

Final velocity (v) = 0 m/s

Initial velocity (u) = 24 m/s

Deceleration (a) =?

v = u + at

0 = 24 + (a × 6)

0 = 24 + 6a

Collect like terms

0 – 24 = 6a

–24 = 6a

Divide both side by 6

a = –24 / 6

a = –4 m/s²

Answer:

the amount of energy needed is 1.8 x 10¹⁷ J.

Explanation:

Given;

mass of the object, m₀ = 1 kg

velocity of the object, v = 0.866 c

By physics convection, c is the speed of light = 3 x 10⁸ m/s

The energy needed is calculated as follows;

E = Mc²

As the object approaches the speed of light, the change in the mass of the object is given by Einstein's relativity formula;

[tex]M = \frac{M_0}{\sqrt{1- \frac{v^2}{c^2} } } \\\\ M = \frac{1}{\sqrt{1- \frac{(0.866c)^2}{c^2} } }\\\\ M = \frac{1}{\sqrt{1- \frac{0.74996c^2}{c^2} } }\\\\ M = \frac{1}{\sqrt{0.25} } \\\\ M = 2 \ kg[/tex]

The energy required is calculated as;

E = 2 x (3 x 10⁸)²

E = 1.8 x 10¹⁷ J

Therefore, the amount of energy needed is 1.8 x 10¹⁷ J.

Answer:

speaker64

--------

34x

Explanation:

64-34

x

speaker

4

2

4

788

- circuit

voltage

100000

x.34

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Answer:

0.28 J

Explanation:

Let the mass of the object is 0.5 kg

The maximum velocity of the object is 1.06 m/s.

We need to find the kinetic energy at that time. It is given by :

[tex]K=\dfrac{1}{2}mv^2\\\\=\dfrac{1}{2}\times 0.5\times (1.06)^2\\\\K=0.28\ J[/tex]

So, the required kinetic energy is equal to 0.28 J.

Answer:

a)  I = 3.75 10⁴  kg  m², b)  w = 0.6 rad / s, c)  K = 6.75 10³ J, d) P = 6.75 10² W

Explanation:

This is a rotations exercise

a) the proper shape for a wheel is that of a rim where most of the weight is in the circumference plus the point weights of the people sitting on its periphery.

We are going to approximate the reda with a thin ring

           I = M r²

           I = 1500 5²

           I = 3.75 10⁴  kg  m²

b) angular and linear velocity are related

         v = w r

         w = v / r

         w = 3/5

         w = 0.6 rad / s

c) the expression for kinetic energy is

         K = ½ I w²

         K = ½ 3.75 10⁴   0.6²

         K = 6.75 10³ J

d) the power is

         P = W / t

to find the work we use the relationship between work and the variation of kinetic energy

         W = ΔK = K_f - K₀

the system part of rest wo = 0

         W = K_f

         W = 6.75 10³ J

we calculate

         P = 6.75 10³/10

         P = 6.75 10² W

Answer:

1) Law of Universal Gravitation     Gravity is an attractive force

5) General relativity               Gravity is due to the curvature of spacetime

Explanation:

In this exercise you are asked to relate the correct theory and its explanation

Theory Explanation

1) Law of Universal Gravitation              Gravity is an attractive force

2) Law of universal gravitation              Mass and distance affect force

3) Classical mechanics                           time and space are absolute

4) Special relativity                                 Time and space are relative

5) General relativity                                Gravity is due to the curvature of

                                                               spacetime

6) General relativity                                 Mass affects the curvature of space - time

Answer:

Explanation:

edge2022

Answer:

Distance between them is 4,200 meters.

Explanation:

Consinder car A:

[tex]{ \bf{distance = speed \times time }}[/tex]

substitute:

[tex]distance = 20 \times (2 \times 60) \\ = 2400 \: m[/tex]

Consider car B:

[tex]distance = 15 \times (2 \times 60) \\ = 1800 \: m[/tex]

since these cars move in opposite directions, distance between them is their summation:

[tex]distance \: between = { \sum(distance \: of \: each \: car)} \\ = 2400 + 1800 \\ = 4200 \: m[/tex]

Answer:

[tex]p.d' = 37.6 V[/tex]

Explanation:

From the question we are told that:

Potential difference [tex]p.d=18.8V[/tex]

New Capacitor [tex]C_1=C_2/2[/tex]

Generally the equation for Capacitor capacitance is mathematically given by

[tex]C=\frac{eA}{d}[/tex]

Generally the equation for New p.d' is mathematically given by

 [tex]C_2V=C_1*p.d'[/tex]

  [tex]p.d' = 2V[/tex]

 [tex]p.d'= 2 * 18.8[/tex]

 [tex]p.d' = 37.6 V[/tex]

Answer:

The answer is continuity ( D )

Explanation:

PLZ MARK AS BRAINLIEST

°F = 1.8°C + 32°

444.5°C  = 832.1°F

Over the first 16.4 m, the person performs

W = (60.0 N) (16.4 m) = 984 J

of work.

Over the remaining 6.88 m, they perform a varying amount of work according to

F(x) ≈ 60.0 N + (-8.72 N/m) x

where x is in meters. (-8.72 is the slope of the line segment connecting the points (0, 60.0) and (6.88, 0).) The work done over this interval can be obtained by integrating F(x) over the interval [0, 6.88 m] :

W = ∫₀⁶˙⁸⁸ F(x) dx ≈ 206.4 J

(Alternatively, you can plot F(x) and see that it's a triangle with base 6.88 m and height 60.0 N, so the work done is the same, 1/2 (6.88 m) (60.0 N) = 206.4 J.)

So the total work performed by the person on the box is

984 J + 206.4 J = 1190.4 J ≈ 1190 J

Explanation:

The wavelength of light λ=687 nm.

width of the slit, w=0.75 mm.

The diffraction formula for single slit diffraction is;

[tex]Sin\theta=\frac{m\lambda}{w}[/tex]

m here is an integer.

For small θ, sinθ≅ θ.

The formula changes to;

[tex]\theta=\frac{m\lambda}{w}[/tex].

The data in the question is missing. However, one put data in the above formula to find the unknown.

Answer:

Option A

Explanation:

From the question we are told that:

Mass [tex]m=0.20kg[/tex]

Velocity [tex]v=4m/s[/tex]

Generally the equation for momentum for Ball A is mathematically given by

Initial Momentum

 [tex]M_{a1}=mV[/tex]

 [tex]M_{a1}=0.2*4[/tex]

 [tex]M_{a1}=0.8[/tex]

Final Momentum

 [tex]M_{a2}=-0.8kgm/s[/tex]

Therefore

 [tex]\triangle M_a=-1.6kgm/s[/tex]

Generally the equation for momentum for Ball B is mathematically given by

Initial Momentum

 [tex]M_{b1}=mV[/tex]

 [tex]M_{b1}=0.2*4[/tex]

 [tex]M_{b1}=0.8[/tex]

Final Momentum

 [tex]M_{b2}=-0 kgm/s[/tex]

Therefore

 [tex]|\triangle M_a|>|\triangle Mb|[/tex]

Option A

Answer:

[tex]E=3.22*10^6 N/C[/tex]

Explanation:

From the question we are told that:

Separation Distance [tex]d=1.0cm =0.01m[/tex]

Potential difference [tex]V=3.22 * 10^4 V[/tex]

Generally the equation for Electric Field strength is mathematically given by

 [tex]E=\frac{v}{d}[/tex]

 [tex]E=\frac{3.22*10^4}{0.01}[/tex]

 [tex]E=3.22*10^6 N/C[/tex]