Answers
Answer:
The answer will be Number C that is positively and part of the nucleus
Answer:
Part C best describes a proton, as it is positively charged and part on the nucleus
Related Questions
PLEASE HELP WILL GIVE LOTS OF POINTS!!!!!!!!!!!! What is the daughter particle if Uranium -234 undergoes beta decay? Write your answer in isotopic notation.
Answers
Answer:
Given nuclide is uranium-234.
If it undergoes beta decay then, what will be the daughter particle?
Explanation:
The beta particle decay increases the atomic number of the nuclide by one.
There is no change in the mass number of the nuclide.
The decay of beta particle from Uranium-234 is shown below:
It forms Np-93.
Write a balanced half-reaction for the oxidation of solid manganese dioxide to permanganate ion in basic aqueous solution. Be sure to add physical state symbols where appropriate.
Answers
Answer:
8 OH⁻(aq) + Mn(s) ⇒ MnO₄⁻(aq) + 4 H₂O(l) + 7 e⁻
Explanation:
Let's consider the following oxidation half-reaction that takes place in basic aqueous solution.
Mn(s) ⇒ MnO₄⁻(aq)
First, we will perform the mass balance. We will add 4 H₂O to the products side and 8 OH⁻ to the reactants side.
8 OH⁻(aq) + Mn(s) ⇒ MnO₄⁻(aq) + 4 H₂O(l)
Finally, we will perform the charge balance by adding 7 electrons to the products side.
8 OH⁻(aq) + Mn(s) ⇒ MnO₄⁻(aq) + 4 H₂O(l) + 7 e⁻
How many joules would be required to change the temperature of 250.0 g of aluminum from 15.0°C to 75.0°C? The specific heat capacity of a luminum is 24.2J/g°C.
Answers
the correct sequence where reactivity towards oxygen increases.
Answers
Answer:
Option D is good to go!
Explanation: as per the reactivity series more reactive substances will react with the counterpart substance.The most reactive substance here is calcium while the least reactive is aluminium, the magnesium comes in between.As per their reactivity, these substances will react with oxygen.
Explanation:
Using the following balanced equation, if you had 48 molecules of O2,
how many molecules of SO3 would you produce?
S8 + 12O2 --> 8SO3
Answers
Explanation:
hope this helps u understand:)
Name any three organic fertilizer using by farmers ?
Answers
Hope this helped :)
Answer:
Typical organic fertilizers include mineral sources, all animal waste including meat processing, manure, slurry, and guano, plant based fertilizers, such as compost, and biosolids.
A block is pulled 0.90 m to the right in 2.4 s. What is the block's average speed to the nearest hundredths of a m/s?
Answers
A gas at constant volume has a pressure of 2.80 atm at 400. K. What will be the pressure of the gas at 360. K? (4 points)
2.52 atm
2.94 atm
3.11 atm
3.78 atm
Answers
Option first 2.52 atm
Answer:
Solution given:
pressure 1[P1]=2.8atm
pressure 2[P2]=?
temperature [T1]=400k
temperature [T2]=360k
now
By using gas equation
P1V1/T1=P2V2/T2
since
volume is constant
P1/T1=P2/T2
2.8/400=P2/360
P2=2.8*360/400
P2= 2.52
Answer:
It's 2.52
Explanation:
This requires Gay-Lussac's Law, in which the relationship is P1 / T1 = P2 / T2. "P" stands for Pressure and "T" is Temperature. The first pressure is 2.80, the first temperature is 400 Kelvin, the second pressure is unknown (that's what your solving for), and your second temperature is 360 Kelvin. Because you don't have the second pressure, your equation will look like 2.80 atm x 360 K / 400. This will tell you that the pressure of the gas at 360 K will be 2.52.
I also took the test and it was correct.
A presión de 3atm, 7L de un gas a temperatura constante experimenta un cambio ocupando un volumen de 0,5L ¿Cuál será la presión que ejerce? ayuda
Answers
Answer:
La presión que ejerce es 42 atm.
Explanation:
La ley de Boyle relaciona la presión y el volumen y dice que el volumen ocupado por una determinada masa gaseosa a temperatura constante, es inversamente proporcional a la presión.
La ley de Boyle se expresa matemáticamente como:
P*V=k
Ahora es posible suponer que tienes un cierto volumen de gas V1 que se encuentra a una presión P1 al comienzo del experimento. Si varias el volumen de gas hasta un nuevo valor V2, entonces la presión cambiará a P2, y se cumplirá:
P1*V1= P2*V2
En este caso:
P1= 3 atmV1= 7 LP2= ?V2= 0.5 LReemplazando:
3 atm* 7 L= P2* 0.5 L
Resolviendo:
[tex]P2=\frac{3 atm*7 L}{0.5 L}[/tex]
P2= 42 atm
La presión que ejerce es 42 atm.
Answer:10.5
Explanation:
3atm x 7L / 0,5L = 10.5
Quando bajamos el volmen sube la presion y cuando bajamos la presion sube el volumen
Analyze the following chemical combinations
a) MgO
b)CaCl2
c) Na2O
Answers
a sample of silver has a volume of 6 cm^3 and a massage of 36 grams what's the samples density
Answers
Answer:
6g/cm³
Explanation:
Density of a substance can be calculated as follows:
Density = mass (g)/volume (cm³)
According to this question, a sample of silver has a volume of 6 cm³ and a mass of of 36g. The density will be
Density = 36/6
Density = 6g/cm³
20. Show a correct numerical setup for calculating the molarity of the KOH * (aq) solution. Then state the calculated value of the molarity .
Answers
Answer:
[tex]M_b = \frac{0.10M * 9.50mL}{3.80mL}[/tex] ---- The setup
[tex]M_b = 0.25M[/tex] --- The molarity of KOH
Explanation:
Given
I will answer the question with the attached titration data
Required
The set and the value of the molarity of KOH
First, calculate the volume of acid (HCL) used:
[tex]V_a = Final\ Reading - Initial\ Reading[/tex]
[tex]V_a = 25.00mL - 15.50mL[/tex]
[tex]V_a = 9.50mL[/tex]
Calculate the final volume of base (KOH) used:
[tex]V_b = Final\ Reading - Initial\ Reading[/tex]
[tex]V_b = 8.80mL - 5.00mL[/tex]
[tex]V_b = 3.80mL[/tex]
The numerical setup is calculated using::
[tex]M_a * V_a = M_b * V_b[/tex]
Where
[tex]V_a = 9.50mL[/tex]
[tex]V_b = 3.80mL[/tex]
[tex]M_a = 0.10M[/tex] --- the given molarity of HCL
So, we have:
[tex]M_a * V_a = M_b * V_b[/tex]
[tex]0.10M * 9.50mL = M_b * 3.80mL[/tex]
Make Mb the subject
[tex]M_b = \frac{0.10M * 9.50mL}{3.80mL}[/tex] ---- The correct numerical setup
The solution is then calculated as:
[tex]M_b = \frac{0.10M * 9.50mL}{3.80mL}[/tex]
[tex]M_b = \frac{0.10 * 9.50}{3.80}M[/tex]
[tex]M_b = \frac{0.95}{3.80}M[/tex]
[tex]M_b = 0.25M[/tex]
what's the common name for hydrogen oxide
Answers
Use the reaction N2(g) + 3H2(g) 2NH3(g) to answer the following questions
a. 1 pt: What does Le Châtelier's principle predict would happen to the equilibrium conditions if N2(g) + 3H2(g) were added to the system?
b. 1 pt: What would happen to the equilibrium if the pressure were decreased?
c. 2 pts: Write the equation for calculating Keq
d. 3 pts: Calculate the value for Keq given the following concentrations
[NH3] = 6 M
[H2] = 4 M
[N2] = 3 M
Answers
Answer:
Explanation:
a ) If N₂(g) and 3H₂(g) is added to the system , 2 moles of additional ammonia will be produced .
b ) If pressure is decreased , less amount of ammonia will be formed, because forward reaction reduces the pressure. So, reaction will take place in reverse direction.
c ) Keq = [ NH₃ ] ² / [ N₂ ] [ H₂]³
d ) Substituting the given values in the equation ,
Keq = [ 6M ] ² / [ 3M] [ 4M]³
= 36 / 3 x 64 M⁻²
= 18.75 x 10⁻² M⁻² .
This graph represents a population of molecules in a gas versus the distribution of the average velocity(speed) of its molecules in that population. Assume all molecules to be of the same mass. In reading the graph, it is important to note three things. One, is the most probable speed is at the peak of the curve. Secondly, the most probable speed increases as the temperature increases (so shift to the right), and the distribution broadens as it increases.
On the graph, indicate the average kinetic energy of the population.
Explain your answer.
What part of the graph indicates the temperature of the sample?
Explain your answer.
Sketch a curve that represents the distribution of molecules at a temperature below the one shown. Label it as T2. Describe both T and T2 in terms of their average kinetic energy. Be specific and detailed.
Submit your answer below.
Answers
Answer:
Part A
Given that the graph is symmetrical and bell shaped, the average kinetic energy is given by the midline of graph, which corresponds to the common speed of the highest number of the population
Part B
The formula for the average kinetic energy, K.E. = (3/2)·(R/NA)·T
Therefore, the part of the graph that indicates the temperature of the sample is the average kinetic energy. K.E.
Part C
At a lower temperature, the heat is less evenly distributed and we have the distribution T2 higher than T1
Please see the attached graph created with MS Visio
Explanation:
Nitrogen and sulfur oxide gases originate from all of the following, EXCEPT
A . lightening Strikes
B. Volcano eruptions
C. Car exhaust
D . Plant Respiration ANSWER IT FOR 50 PIONTS!!!!!!!!!!!!!
Answers
Answer:
the answer is D (つ°ヮ°)つ （＾ω＾）
How many Group 17 elements are in Period 3 of the Periodic Table? A) 1 B) 2 C) 3 D) 4
Answers
I hope that helps :)
Select the correct answer.
What does the empirical formula of a compound describe?
Ο Α. .
the type and number of atoms
OB.
the type and ratio of atoms
O C.
the number of atoms
OD
the type and mass of atoms
Reset
Next
Answers
Answer:
b
Explanation:
cause empirical formular is the elementary or the foundation for molecular formula and molecular formula depends on the empirical formula
which method would be best for separating the compounds of a mixture that is made from two diffrent liquids
Answers
Answer:
fractional distillation since ot depends on the different liquids to have different boiling points
what is the state of matter that takes shape of a container???
Answers
Answer:
Liquid and gas is the matter that takes shape of a container
It can also be called fluid since fluid is distributed into liquid and gas
Explanation:
I hope that is enough for your answer, hope this will help
23. What type of chemical reaction is: CH, + 0→ CO2 + H20
a. Combustion
b. Neutralization
C. Synthesis
d. Double Replacement
Answers
Answer:
combustion
Explanation:
bsnszisb idiej jeiieyv
expand write down the binomial expansion of (1+2x)^7in ascending power of x ,simplifying all the coefficient. use the expansion theory to calculate the value of (0.98)^7 correct to four decimal places.
Answers
Answer:
0.86812566700000000000000
The binomial expansion of (1+2x)^7in ascending power of x is 0.868125.
What are binomial expansions?The algebraic expression (x + y)n can be expanded according to the binomial theorem, which represents it as a sum of terms using separate exponents of the variables x and y.
Each word in a binomial expansion has a coefficient, which is a numerical value. A binomial is a two-term algebraic expression. Examples of binomials include a + b, x - y, and more.
When a binomial is raised to exponents 2 and 3, we can use a set of algebraic identities to determine the expansion. As an illustration, (a + b)2 = a2 + 2ab + b2.
By regrouping and combining like phrases, we can arrange our final response in ascending powers of x by placing the lowest power of x first and the highest power of x last.
Therefore, the binomial expansion of (1+2x)^7in ascending power of x is 0.868125.
To learn more about binomial expansions, refer to the link:
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Give me formula for
1)Aluminium chloride
2) Copper sulphate
3) Zinc Nitrate
3) Ammonium Carbonate
Answers
Answer:
1. AlCl₃
2. CuSO4
3. Zn(NO₃)₂
4. (NH4)2CO3
CuSO₄
Zn(NO₃)₂
(NH₄)₂CO₃
an archaeologist discovers an ancient wooden bowl. which isotope would most likely be used to determine its age?
a. carbon-12
b. carbon-14
c. uranium-238
d. oxygen-16
please and thank you to anyone who may know the answer.
Answers
Answer:
B
Explanation:
I need some help
3KOH + FeCl3 → Fe(OH)3 + 3KCl
How many moles of FeCl3 are needed to completely react with 3.0 g of KOH?
Answers
Answer:
0.0178
Explanation:
because you can work out the amount of moles in KOH using moles = mass/mr.
The mr of the KOH is 39.1+16+1=56.1 so you do
[tex] \frac{3}{56.1} [/tex]
which equals to 0.053475 so u 3SF which is 0.0535moles
than u uses the molar ratio which is 3 to 1
so 0.0535÷3=0.0178 which is the moles of FeCl3.
hope this make sense:)
Suppose you are titrating an acid solution with a base solution of known concentration. To calculate the concentration of the acid solution, use three steps. 1. Use the -------------- { (a) delivered volume (b) volume reading} of base --------------- { (a) after (b) to reach (c) before} the endpoint and the known concentration of the base solution to find the ------------ { (a) moles (b) mass (c) concentration} of base used. 2. Use the ------------ { (a) molar mass (b) dilution equation (c) molar ratio} to find the moles of acid from the moles of base. 3. Divide the moles of acid by the volume of -------------- { (a) base solution before (b) acid solution before (c) acid solution after} the titration to find the concentration of acid.
Answers
Answer:
1. (a) delivered volume, (b) to reach, (a) moles
2. (c) molar ratio
3. (b) acid solution before.
Explanation:
1. You must titrate the acid with a base solution of known concentration, and use the (a) delivered volume. At the endpoint, the moles of acid and base in the titration follows the chemical equation, thus, you need (b) to reach the endpoint. With volume and concentration of the base we can find its (a) moles
2. With the (c) molar ratio, we can relate the moles of base with the moles of acid
3. When we have the moles of acid, we just need the volume of (b) acid solution before the titration to find molarity of the acid.
Calculate the total energy, in kilojoules, that is needed to turn a 46 g block
of ice at -25 degrees C into water vapor at 100 degrees C.
Answers
Answer: The total energy, in kilojoules, that is needed to turn a 46 g block of ice at -25 degrees C into water vapor at 100 degrees C is 11.787 kJ.
Explanation:
Given: Mass = 46 g
Initial temperature = [tex]-25^{o}C[/tex]
Final temperature = [tex]100^{o}C[/tex]
Specific heat capacity of ice = 2.05 [tex]J/g^{o}C[/tex]
Formula used to calculate the energy is as follows.
[tex]q = m \times C \times (T_{2} - T_{1})[/tex]
where,
q = heat energy
m = mass
C = specific heat capacity
[tex]T_{1}[/tex] = initial temperature
[tex]T_{2}[/tex] = final temperature
Substitute the values into above formula as follows.
[tex]q = m \times C \times (T_{2} - T_{1})\\= 46 g \times 2.05 J/g^{o}C \times (100 - (-25))^{o}C\\= 11787.5 J (1 J = 0.001 kJ)\\= 11.787 kJ[/tex]
Thus, we can conclude that the total energy, in kilojoules, that is needed to turn a 46 g block of ice at -25 degrees C into water vapor at 100 degrees C is 11.787 kJ.
What is the volume of .750 M hydrochloride acid required to react completely with 25.00 mL of .290 M NaOH solution?
Answers
from
HCl + NaOH----> NaCl +H2O
n of acid=1
n of base=1
Molarity of acid=750M
Molarity of base=290M
volume of base=25ml
from
Va=Mb ×vb×na
Ma×nb
Va=290×25×1
750×1
Va=7250
750
Va=9.67ml
The volume of .750 M hydrochloride acid is required to react completely with 25.00 mL of .290 M NaOH solution is 9.67ml
HCl + NaOH----> NaCl +H2O
n of acid=1
n of base=1
Molarity of acid=750M
Molarity of base=290M
volume of base=25ml
Therefore,
Va=Mb ×vb×na
Ma×nb
Va=290×25×1
750×1
Va=7250
750
Hence,
Va=9.67ml
What is Hydrochloric acid?
Hydrochloric acid, also known as muriatic acid, is an aqueous solution of hydrogen chloride. It is a colorless solution with a distinctively pungent smell. It is classified as a strong acid. It is a component of the gastric acid in the digestive systems of most animal species, including humans. Hydrochloric acid is an important laboratory reagent and industrial chemical.
Learn more about Hydrochloric acid
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Which term refers to energy stored within the center of an atom?
A. Thermal energy
B. Nuclear energy
C. Chemical energy
D. Light energy
Answers
Answer: i'm pretty sure it's b if i remember correctly.
Explanation:
i learned this a while ago so i'm not completely sure.
La formula quimica de la molecula de agua H20 , si H = 1 gramos y O = 16 gramos . Cual es su composicion porcentual ? 88,88 % de O y 11,11 % de H 88,88 % de H Y 11,11% de O 80 % de O Y 20 % de H 90% de O Y 10 % de H
Answers
Answer:
88,88 % de O y 11,11 % de H
Explanation:
La composición porcentual se define como la masa que hay de cada mol de átomo en 100g. Las moles de agua en 100g son:
Masa molar agua:
2H = 2*1g/mol = 2g/mol
1O = 1*16g/mol = 16g/mol
Masa molar = 2 + 16 = 18g/mol
100g H2O * (1mol / 18g) = 5.556 moles H2O.
Moles de hidrógeno:
5.556 moles H2O * (2mol H / 1mol H2O) = 11.11 moles H
Moles Oxígeno = Moles H2O = 5.556 moles
La masa de hidrógeno es:
11.11mol * (1g/mol) 11.11g H
La masa de oxígeno es:
5.556 mol * (16g / 1mol) = 88.89g O
Así, el porcentaje de O es 88.89% y el de H es 11.11%. La opción correcta es:
88,88 % de O y 11,11 % de H