Hellpppp I’m stuck......

Answer:

d. static

Step-by-step explanation:

This is a question about Java programming.

A class contains information about it's members(objects). Private, public or inline variables must be related to an object, that is, an object has to be created before the variable is acessed.

Static variables, otherwise, may pertain to the class, and not to the object, that is, and thus, the correct answer is given by option d.

Answer:

Step-by-step explanation:

The angles opposite each other when two lines cross. They are always equal.

here,vertically opposite angles are

angle RQW and angle TQU

angle RQV ang angle SQU

angle SQR and angle UQV

angle WQV and angle SQT

Answer:

C

Step-by-step explanation:

I've completed the test before. :)

Answer:

I am pretty sure its 30 students

9514 1404 393

Answer:

  9 +7i

Step-by-step explanation:

i^2 = -1, so i^8 = (-1)^4 = 1, and i^5 = (-1)^2×i = i

Then ...

  7i^5 +9i^8 = 7i +9 = 9 +7i

Answer:

A is the closest

Answer:

59.44

Step-by-step explanation:

Nine employees If an electronic company retired last year

The retirement ages are listed below

56, 65, 62, 53, 68, 58, 65, 52, 56

The mean retirement age can be calculated as follows

= 56+65+62+53+68+58+65+52+56/9

= 535/9

= 59.44

Hence the mean retirement age is 59.44

Answer:

6 cm

Step-by-step explanation:

Volume of a prism= Length X Width x height

750 = 25 x 5 x h

750= 125h

750/125 = 125h/125

h= 6

Answered by Gauthmath

Answer:   876

Step-by-step explanation:so all you need to do is go into  

Answer:

The center (-3, 0)

9514 1404 393

Answer:

Step-by-step explanation:

The desired parameters can be found by putting the equation into the standard form for the equation of a circle:

  (x -h)^2 +(y -k)^2 = r^2 . . . . . circle centered at (h, k) with radius r

The values of h and k will be half the coefficients of the linear x- and y-terms, respectively.

  x^2 +6x +9 +y^2 -7 = 9 . . . . . add 9 to complete the square

  (x +3)^2 +y^2 = 16 . . . . . . . . . add 7 to get the desired form

This equation shows us (h, k) = (-3, 0) and r = 4.

The center is (-3, 0), and the radius is 4.

Answer:

range is 6

Step-by-step explanation:

The smallest number in this data set is 1 mile, the largest is 7 miles

the range is the difference between the biggest and smallest number so 7-1 = 6. The range is 6

Answer:

The center is ( -2, 7) and the radius is 6

Step-by-step explanation:

A circle is written in the form

(x-h)^2 + (y-k)^2 = r^2  where (h,k) is the center and r is the radius

(x+2)^2+(y-7)^2=36

(x -  -2)^2+(y-7)^2=6^2

The center is ( -2, 7) and the radius is 6

Answer:

The answer is 220 cubic inches.

Step-by-step explanation:

To find the volume of the rectangular prism, use the formula for a rectangular prism, which is V= LWH. Next, plug in the information given from the question, and the formula will look like V= (10in) ([tex]5\frac{1}{2}[/tex] in) (4in).

Then, solve the equation for the answer, and the answer for the volume of the rectangular prism is 220 cubic inches.

Answer:

y = 48

Step-by-step explanation:

Start with the given 3y = 150.

Solve this for y by dividing both sides by 3:  y = 50

Then y - 2 = 50 - 2, or

        y    =    48

The value of y-2 is 48,

Two expressions connected by an equal sign makes an equation.

Given is an equation, 3y = 150

Solving for y,

3y = 150

y = 150 / 3

y = 50

therefore, y-2 = 50-2

= 48

Hence, the value of y-2 is 48,

Learn more about equations, click;

https://brainly.com/question/29657983

#SPJ2

Answer:

pls complete your question. what exactly are we supposed to calculate?

Answer:

-1  1/4 yards

Step-by-step explanation:

7 carries

-8.75 yards  total yardage

    -.8.75 / 7  =  -1.25 yards average per carry

In mixed number ?    -1  1/4 yards          

Answer:

a. Photographer A by $10

b. Photographer B by $25

Answer:

only 3) is true. EC is equidistant (the same distance) to BD

Step-by-step explanation:

since we have no coordinates or other specific distance information for the various points and lines, we can only confirm statements that must be true for any placement of the lines inside a circle with the described attributes.

the distance EC could be the same as CB, but if we move ED further up or down in the circle (still parallel to CB), we can easily see, that this is not a general case.

the same for CB and BD.

since CB and BD are airways parallel to each other, the symmetry principle of a circle requires that the distance of EC is airways equal to the distance of BD for all such possible pairs of parallel lines inside the circle.

the graph itself gives an example that the distance CB and the distance ED do not have to be the same. they can be for certain pairs of parallel lines in the circle, but not for all of them.

9514 1404 393

Answer:

Step-by-step explanation:

The angle shown is 75°. It is less than 90°, so is an acute angle. (The diagram is misleading in that respect.)

__

The two marked angles are vertical angles, so have the same measure.

  3x° = 75°

  x = 25 . . . . . . . . divide both sides by 3°

Answer:

[tex]\displaystyle y = 2sin\:1\frac{1}{3}\pi{x} + 3[/tex]

Step-by-step explanation:

[tex]\displaystyle \boxed{y = 2cos\:(1\frac{1}{3}\pi{x} - \frac{\pi}{2}) + 3} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 3 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{3}{8}} \hookrightarrow \frac{\frac{\pi}{2}}{1\frac{1}{3}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{2}} \hookrightarrow \frac{2}{1\frac{1}{3}\pi}\pi \\ Amplitude \hookrightarrow 2[/tex]

OR

[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 3 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{2}} \hookrightarrow \frac{2}{1\frac{1}{3}\pi}\pi \\ Amplitude \hookrightarrow 2[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although the exercise told you to write the sine equation based on the speculations it gave you, if you plan on writing your equation as a function of cosine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 2cos\:1\frac{1}{3}\pi{x} + 3,[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cosine graph [photograph on the right] is shifted [tex]\displaystyle \frac{3}{8}\:unit[/tex]to the left, which means that in order to match the sine graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle \frac{3}{8}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\frac{3}{8}} = \frac{\frac{\pi}{2}}{1\frac{1}{3}\pi}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 2cos\:(1\frac{1}{3}\pi{x} - \frac{\pi}{2}) + 3.[/tex]Now, with all that being said, in this case, sinse you ONLY have the exercise to wourk with, take a look at the above information next to [tex]\displaystyle Wavelength\:[Period].[/tex]It displays the formula on how to define each wavelength of the graph. You just need to remember that the B-term has [tex]\displaystyle \pi[/tex]in it as well, meaning both of them strike each other out, leaving you with just a fraction. Now, the amplitude is obvious to figure out because it is the A-term, so this is self-explanatory. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 3,[/tex]in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter what the vertical shift is, that will ALWAYS be the equation of the midline, and if viewed from a graph, no matter how far it shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

9514 1404 393

Answer:

  (9/34)√34 ≈ 1.543

Step-by-step explanation:

The second equation can be rewritten as ...

  6x -10y -12 = 0

  3x -5y -6 = 0

  3x -5y = 6

__

The formula for the distance from point (x, y) to line ax+by+c=0 is ...

  d = |ax+by+c|/√(a²+b²)

Then the distance from a point to the first line is ...

  d = |3x -5y +3|/√(3² +(-5)²)

We know from the rearrangement of the second equation that points on its line satisfy (3x-5y) = 6. Substituting this value for (3x -5y) in the distance formula gives ...

  d = |6 +3|/√34

Simplifying and rationalizing the denominator gives a distance of ...

  d = (9/34)√34 ≈ 1.543

Given:

The y-intercept of a line = 6

The slope of the line = [tex]-\dfrac{3}{2}[/tex]

To find:

The graph of the given line.

Solution:

The slope intercept form of a line is:

[tex]y=mx+b[/tex]

Where, m is the slope and b is the y-intercept.

Putting [tex]m=-\dfrac{3}{2}[/tex] and [tex]b=6[/tex] in the above equation, we get

[tex]y=-\dfrac{3}{2}x+6[/tex]

At [tex]x=0[/tex],

[tex]y=-\dfrac{3}{2}(0)+6[/tex]

[tex]y=0+6[/tex]

[tex]y=6[/tex]

At [tex]x=2[/tex],

[tex]y=-\dfrac{3}{2}(2)+6[/tex]

[tex]y=-3+6[/tex]

[tex]y=3[/tex]

Plot these two points (0,6) and (2,3) on a coordinate plane and connect them by a straight line to get the graph of the required line.

The required graph is shown below.

Step-by-step explanation:

This is called a nested function. Remember, math is a language.

We define a function where x is whatever we want it to be, f(x) = g(x) +10

but we have yet another function inside and itvs defined as g(x) = 3x - 18

if we were to write it out, it woukd be

f(x) = (3x - 18) + 10

Answer:

The correlation coefficient of the data is -0.13, which means as the weekly mileage increases, it has no effect on the average mile time.Step-by-step explanation:

The correlation coefficient of a data set describes how closely related two variables are. Correlation coefficients close to positive 1 show a strong positive correlation, while correlation coefficients close to negative 1 show a strong negative correlation. When a correlation coefficient is close to 0, it shows no correlation between the data.

For the given data set, calculate the correlation coefficient using technology.

This r-value is closer to 0 then it is to -1. Thus, the correlation coefficient of the data is -0.13, which means as the weekly mileage increases, it has no effect on the average mile time.

Answer:

The correlation coefficient of the data is -0.13, which means as the weekly mileage increases, it has no effect on the average mile time.Step-by-step explanation:

The correlation coefficient of a data set describes how closely related two variables are. Correlation coefficients close to positive 1 show a strong positive correlation, while correlation coefficients close to negative 1 show a strong negative correlation. When a correlation coefficient is close to 0, it shows no correlation between the data.

For the given data set, calculate the correlation coefficient using technology.

This r-value is closer to 0 then it is to -1. Thus, the correlation coefficient of the data is -0.13, which means as the weekly mileage increases, it has no effect on the average mile time.

Answer:

0.2514 = 25.14% of women have HDL below 45 mg/dl or less.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean HDL cholesterol levels of 55mg/dl with a standard deviation of 15 mg/dl.

This means that [tex]\mu = 55, \sigma = 15[/tex]

What proportion of women have HDL below 45 mg/dl or less?

This is the p-value of Z when X = 45. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{45 - 55}{15}[/tex]

[tex]Z = -0.67[/tex]

[tex]Z = -0.67[/tex] has a p-value of 0.2514

0.2514 = 25.14% of women have HDL below 45 mg/dl or less.

Answer:

6:8

Step-by-step explanation:

6 is the ratio of glass bottles and 8 is the plastic or you can put 3:4 because you divide the number b 2

Answer:

tn = 8n -7

Step-by-step explanation:

given : t2=9, t4=25

the formula is:

tn = t1 + (n-1) d

gonna find d first:

d = (25-9) /(4-2) = 16/2 = 8

and find tn1:

t1 = 9-8 = 1

so, tn = 1 + (n-1) (8) = 1 +8n -8

tn = 8n -7

Answer:

Solution given

n th term[tn]=?

1st term =a

difference =d

we have

t2=9

a+(n-1)d=9

a+(2-1)d=9

a+d=9

a=9-d..................[1]

again

t4=25

a+(n-1)d=25

a+(4-1)d=25

now

substituting value of a

9-d+3d=25

2d=25-9

d=16/2

d=8

substituting value of d in equation 1.

,a=9-8

a=1

we have

tn term =a+(n-1)d=1+(n-1)8=1+8n-8=8n-7

n th term =8n-7

Answer:

127.53 liters left after 10 minutes

Step-by-step explanation:

Let

[tex]A \to Amount[/tex]

[tex]t \to time[/tex]

Given

[tex]A(0) = 200[/tex] --- initial

[tex]A(5) = 200 * (1 - 20\%) = 160[/tex] --- the amount left, after 5 minutes

Required

[tex]A(10)[/tex] --- amount left after 5 minutes

To do this, we make use of:

[tex]A(t) = A(0) * e^{kt}[/tex]

[tex]A(5) = 160[/tex] implies that:

[tex]160 = 200 * e^{k*5}[/tex]

Divide both sides by 200

[tex]0.80 = e^{k*5}[/tex]

Take natural logarithm of both sides

[tex]\ln(0.80) = \ln(e^{k*5})[/tex]

[tex]\ln(0.80) = \ln(e^{5k})[/tex]

[tex]\ln(0.80) = 5k\ln(e)[/tex]

So, we have:

[tex]-0.223 = 5k[/tex]

Divide by 5

[tex]k = -0.045[/tex]

So, the function is:

[tex]A(t) = A(0) * e^{kt}[/tex]

[tex]A(t) = 200 * e^{-0.045t}[/tex]

The amount after 10 minutes is:

[tex]A(10) = 200 * e^{-0.045*10}[/tex]

[tex]A(10) = 200 * e^{-0.45}[/tex]

[tex]A(10) = 127.53[/tex]