Answers
Related Questions
Illustrate the law of law of multiple proportions using the formation of SO2 and SO3 by sulphur and oxygen
Answers
As illustrated from law of multiple proportion, the mass of the oxygen which combined with a fixed mass of the sulphur is in simple whole number ratio of 2 is to 3 (2:3).
The law of Multiple proportion states that when two elements combine to form more than one compound, the mass of the second element, which combines with a fixed mass of the first element, will always be ratios of small whole numbers.
To illustrate the law of multiple proportion from sulphur and oxygen, we use the given compounds.
The reaction of oxygen with sulphur to form SO₂ and SO₃:
[tex]S \ + \ O_2 \ -----> SO_2\\\\2SO_2 \ + \ O_2 \ ---> \ 2SO_3[/tex]
atomic mass of oxygen = 16 g
atomic mass of sulphur = 32 g
In the formation of SO₂:mass of sulphur = 32 g and mass of oxygen = (2x16) = 32 g
In the formation of SO₃:mass of sulphur = 32 g and mass of oxygen = (3 x 16) = 48 g
Notice, while mass of sulphur is constant, mass of oxygen changed.
The ratio of mass of oxygen in the given two compounds = 32g : 48g = 2:3
Thus, based on the law of multiple proportion, the mass of the oxygen which combined with a fixed mass of the sulphur is in simple whole number ratio of 2 is to 3 (2:3).
Learn more here: https://brainly.com/question/15537778
When 0.60 mol NH 3 is decomposed in a 1 Liter flask at 850 K, the equilibrium concentration of NH3 is measured as 0.12 M. Given that ammonia decomposes according to the reaction
2 NH3(g) ⇌ N2(g) + 3 H2(g),
what is Kc for the reaction?
a. 0.16
b. 12.00
c. 1.44
d. 6.22
e. 0.75
Answers
Answer:
in a 1 Liter flask at 850 K, the equilibrium concentration of NH3 is measured as 0.12 M. Given that ammonia decomposes according to the reaction
2 NH3(g) ⇌ N2(g) + 3 H2(g),
what is Kc for the reaction?
a. 0.16
b. 12.00
c. 1.44
d. 6.22
e. 0.75
The response is 12.00 (b). Using the equation Kc = [N2][H2]3/[NH3]2, we can find the equilibrium constant Kc for the reaction 2 NH3(g) N2(g) + 3 H2(g).
What is the equilibrium concentration ?In this instance, the capacity of the flask is 1 litre, and the equilibrium concentration of NH3 is 0.12 M. Therefore, using the reaction's stoichiometry, it is possible to determine the equilibrium concentrations of N2 and H2.
Since 2 moles of NH3 break down into 1 mole of N2 and 3 moles of H2, the equilibrium concentrations of N2 and H2 are 0.06 M and 0.18 M, respectively. As a result, the equilibrium constant Kc = [N2][H2]3/[NH3]2 = (0.06)(0.18)3/0.122 = 12.00 may be computed.
Therefore, b. 12.00 is the right response. You should be aware that the equilibrium constant Kc is a value that is temperature-dependent and is only applicable at the specified temperature. As a result, Kc will have a varied value depending on the temperature. The temperature in this instance is 850 K, and the Kc value is 12.00.
Learn more about equilibrium at:
https://brainly.com/question/30694482
#SPJ2
Neha and Reha are playing see-saw. Neha is sitting 60 cm away from the fulcrum and Reha is sitting 40 cm away from the fulcrum. Calculate the effort that Reha should apply to lift Neha. The weight of Neha is 360 N.
Answers
Answer:
Reha should apply 540 N to lift Neha.
Explanation:
L = 360 N
LD = 60 m
E =?
ED = 40m
NOW
L * LD = E * ED
360 *60 = E*40
21600/40 = E
540 N = E
Which of the following statements is incorrect for the reaction of 1,3- butadiene with a substituted alkene CH2=CHX when X is a nitro group?
Answers
Answer:
hugsvsbsbbsnjsjsnsbsbbzbd
A graduated cylinder is filled with 20ml of water. A rock is dropped in to the graduated cyclinder and the volume of water rises to 30ml
inside the graduated cylinder. The mass of the rock is 23g. What is the density of the rock?
2.3g/ml
0.77g/ml
5g/ml
1.15g/ml
Answers
Answer:
[tex]\boxed {\boxed {\sf 2.3 \ g/mL}}[/tex]
Explanation:
We are asked to find the density of a rock. Density is the substance's mass per unit volume. The formula for calculating density is:
[tex]\rho= \frac{m}{v}[/tex]
The mass of the rock is 23 grams. The volume was found using water displacement. A known amount of water was measured, the rock was added to the graduated cylinder, and the water level was recorded again. The volume is the difference between the final and initial water level. The graduated cylinder originally had 20 milliliters and the water rose to 30 milliliters.
volume = final water level - initial water level volume = 30 mL - 20 mLvolume = 10 mLNow we know the mass and the volume.
m= 23 g v= 10 mLSubstitute the values into the formula.
[tex]\rho= \frac{ 23 \ g }{30 \ mL}[/tex]
Divide.
[tex]\rho= 2.3 \ g/mL[/tex]
The density of the rock is 2.3 grams per milliliter.
Choose the best possible answer for Q.No. A, B, and C.
The following is an acid-base reaction between sulfuric acid and aluminum hydroxide. Use the provided molar masses to answer the questions below:
molar
mass
3 H2SO4
+
2 Al(OH)3
⟶
Al2(SO4)3
+
6 H2O
g/mol
98.08
78.00
342.15
18.02
Note: You need to upload the documents for A, B, and C to show your work.
A. How many moles of sulfuric acid would be required to form 65.21g of Water?
moles of H2SO4 = ________
[ Select ]
B. How many grams of Aluminum Sulfate could be formed if 197.0g aluminum hydroxide reacts with sulfuric acid?
mass of Al2(SO4)3 = ________
[ Select ]
C. To determine the concentration of a sulfuric acid sample, a titration is performed with the above reaction. What is the concentration of the sulfuric acid if a 15.00mL sample reached its titration endpoint with 29.26mL of 0.2855M Al(OH)3?
Molarity of H2SO4 = ________
[ Select ]
Answers
Answer:
c i think
Explanation:
calculate the number of each atom in 2.5 gram of caco3
Answers
Answer:
[tex]2.5\; \rm g[/tex] of [tex]\rm CaCO_{3}[/tex] would contain:
Approximately [tex]1.5 \times 10^{22}[/tex] calcium atoms (approximately [tex]0.025\; \rm mol[/tex],)Approximately [tex]1.5 \times 10^{22}[/tex] carbon atoms (approximately [tex]0.025\; \rm mol[/tex],) andApproximately [tex]4.5 \times 10^{22}[/tex] oxygen atoms (approximately [tex]0.075\; \rm mol[/tex].)Explanation:
Look up the Avogadro constant: [tex]N_{\rm A} \approx 6.022 \times 10^{23}\; \rm mol^{-1}[/tex].
For example, "[tex]1\; \rm mol[/tex] of carbon atoms" would contain [tex]N_{\rm A}[/tex] carbon atoms (approximately [tex]6.022\times 10^{23}[/tex]) by definition.
Look up the relative atomic mass of carbon, calcium, and oxygen on a modern periodic table:
Calcium: [tex]40.078[/tex].Carbon: [tex]12.011[/tex].Oxygen: [tex]15.999[/tex].In other words, the mass of [tex]1\; \rm mol[/tex] of calcium atoms would be [tex]40.078\; \rm g[/tex]. The mass of [tex]1\; \rm mol\![/tex] of carbon atoms would be [tex]12.011\; \rm g[/tex], and the mass of [tex]1\; \rm mol \!\![/tex] of oxygen atoms would be [tex]15.999\; \rm g[/tex].
As the formula [tex]\rm CaCO_{3}[/tex] suggests, every formula unit of this ionic compound includes one calcium atom, one carbon atom, and three oxygen atoms. The formula mass of [tex]\rm CaCO_{3}\![/tex] would give the mass of every mole of [tex]\rm CaCO_{3}\!\![/tex] formula units.
Calculate the formula mass of [tex]\rm CaCO_{3}[/tex] from the relative atomic mass data:
[tex]\begin{aligned} & M({\rm CaCO_{3}}) \\ =\; & 40.078\; \rm g \cdot mol^{-1} \\ & + 12.011\; \rm g \cdot mol^{-1} \\ & + 3 \times (15.999\; \rm g \cdot mol^{-1}) \\ =\; & 100.086\; \rm g \cdot mol^{-1}\end{aligned}[/tex].
Calculate the number of [tex]\rm CaCO_{3}[/tex] formula units in that [tex]2.5\; \rm g[/tex] of this compound:
[tex]\begin{aligned}& n({\rm CaCO_{3}}) \\ =\; & \frac{m({\rm CaCO_{3}})}{M({\rm CaCO_{3}})} \\ =\; & \frac{2.5\; \rm g}{100.086\; \rm g \cdot mol^{-1}} \\ \approx\; & 0.025\; \rm mol\end{aligned}[/tex].
In other words, [tex]2.5\; \rm g[/tex] of [tex]\rm CaCO_{3}[/tex] would contain approximately [tex]0.025\; \rm mol[/tex] [tex]\rm CaCO_{3}\![/tex] formula units.
Again, there are one calcium atom, one carbon atom, and one oxygen atom in every [tex]\rm CaCO_{3}[/tex] formula unit. That approximately [tex]0.025\; \rm mol[/tex] [tex]\rm CaCO_{3}\![/tex] formula units would thus contain:
Approximately [tex]1 \times 0.025\; \rm mol = 0.025\; \rm mol[/tex] calcium atoms, Approximately [tex]1 \times 0.025\; \rm mol = 0.025\; \rm mol[/tex] carbon atoms, andApproximately [tex]3 \times 0.025\; \rm mol = 0.075\; \rm mol[/tex] oxygen atoms.Make use of the Avogadro constant to convert the numbers.
For example, the number of calcium atoms in that approximately [tex]0.025\; \rm mol[/tex] of calcium atoms would be:
[tex]\begin{aligned} & N({\text{calcium}) \\ = \; & n({\text{calcium}) \cdot N_{\rm A} \\ \approx \; & 0.025\; \rm mol \times 6.022\times 10^{23} \cdot mol^{-1} \\ \approx \; & 1.5 \times 10^{22} \end{aligned}[/tex].
Likewise, the number of carbon atoms in that approximately [tex]0.025\; \rm mol[/tex] of carbon atoms would be:
[tex]\begin{aligned} & N({\text{carbon}) \\ = \; & n({\text{carbon}) \cdot N_{\rm A} \\ \approx \; & 0.025\; \rm mol \times 6.022\times 10^{23} \cdot mol^{-1} \\ \approx \; & 1.5 \times 10^{22} \end{aligned}[/tex].
The number of oxygen atoms in that approximately [tex]0.075\; \rm mol[/tex] of oxygen atoms would be:
[tex]\begin{aligned} & N({\text{oxygen}) \\ = \; & n({\text{oxygen}) \cdot N_{\rm A} \\ \approx \; & 0.075\; \rm mol \times 6.022\times 10^{23} \cdot mol^{-1} \\ \approx \; & 4.5 \times 10^{22} \end{aligned}[/tex].
HELP PLEASE WILL MARK BRAINLIEST!!!!!!!
Answers
Answer:
Precise
Explanation:
hope it helps!!!!!!!!
2. An Isotope of technetium, mixed with sulphur and colloidally dispersed in water, is frequentyused in diagnosing various medical conditions because it is readily taken up by various tissues Prior to excretion. Explain why this important
mixture is not a true solution.
Answers
Answer:
This is not a true solution because the colloidal dispersion is not completely homogeneous, and it does not have uniform properties throughout.
Explanation:
hope i helped
If you wanted to increase the speed of
vaporization, you could
A. put the substance in the freezer.
B. place a lid on the substance.
C. heat the substance to the boiling point.
D. cool the substance to the freezing point.
>
Copyright © 2003 - 2021 Acellus Corporation. All Rights Reserved.
Answers
Answer:
C. heat the substance to the boiling point.
Answer:
heat the substance
Explanation:
If I have a bottle of compound X at a pressure of 45 atm and temperature of 100 °C, what will happen if I raise the temperature to 400 °C?*
Answers
Answer:
55/350
Explanation:
because the answer is in the middle of 50and 400
What is the final temperature of water given an initial temperature of 28 ˚C, a mass of 7 g, and heat (q) of 184 J (Specific Heat of water = 4.184 )?
Answers
Answer:34.28 Degree celcius
Explanation:The heat given is equal to the change in temperature multiplied by the mass and the specific heat capacity
This gives the equation:Q=mc∆T
Where Q=184,m=7, specific heat capacity=4.184,∆T=X-28,
But ∆T=Final temperature (T'')-Initial temperature (T')
Therefore the equation becomes
184=7×4.184(X-28)
Solving the remaining linear equation gives you X as 34.28°C
Element X forms the ion X22- What is the formula of the covalent compound X forms with chlorine?
A XCI
B XCl2
C XCl3
D XCl4
Answers
Answer:
the answer is mostly option a)XCl
Explanation:
In nature, Chlorine-35 isotopes (35 amu) make up 75
% of all chlorine. Chlorine-37 (37 amu) isotopes make
up 25 % of all chlorine,
Show your calculation for the AVG. Atomic Mass of
chlorine:
Answers
What is a mixture? How will you separate the components of a mixture containing sugar, sand and water?
Answers
Answer:
Mixture is combination of two or more substances
Explanation:
The sugar would dissolve in water. You could then pour off the solution and wash the remaining sand with a bit more water. Heat the water to evaporate it from the sugar, and the two are separated.
which function of lysosomes is carried out by vacuoles in plant cells
Answers
Answer:
Lysosomes are predominantly found in eukaryotic animal cells and are responsible for breaking down cellular debris
Explanation:
Which list only includes terms that describe oxygen gas, O2?
A. element, molecule, pure substance
B. atom, compound, molecule
C. atom, element, molecule
D. compound, molecule, pure substance
Answers
Answer:
d
Explanation:
it just makes alot of sense and you got this
Oxygen is a gas that belongs to the chalcogen family and is a reactive non-metal. It is an element, molecule, or pure substance. Thus, option A is correct.
What is a pure substance?A pure substance is defined as a substance that cannot be physically separated into its constituent particles. They are known to have a definite and constant chemical composition. It can be a molecule, element, or compound.
An element is atomic species that cannot be broken into simple sub-particles by chemical processes. On the other hand, if an atomic element bonds to the same or different atom it forms a molecule.
Oxygen gas is an element composed of two atoms of oxygen and is a molecule as the two atoms are linked chemically. It is also a pure substance as it contains the same element.
Therefore, option A. oxygen gas is a pure substance, an element, and a molecule.
Learn more about pure substance, here:
https://brainly.com/question/24462192
#SPJ2
3. If we remember seeing something happen, we can trust that it happened just as we think it did. True or False
Answers
[tex] \huge{ \underbrace{ \overbrace{True}}}[/tex]
.
[tex]\huge\mathfrak\purple{Hope \: it \: helps}[/tex]
Note : Because Many of My Dreams came true and I realized.
the internacional system of units is based on ?
Answers
Answer:
The international system of units is basic on 7 units.
Hope it helps you.3(b) The balloon did not burst when it is pressed onto 100 nails because
1. the nails are not sharp
2.the surface area of 100 nails produce high pressure on the balloon
3. the larger surface area of 100 nails produce low pressure on the balloon
3(c) To reduce pressure on the contact surface, we must apply force onto the .................... surface area.
1.largest
2.smallest
3. Any size of
Answers
3(c) to reduce pressure force must be applied to the largest surface area (1)
pressure = Force/Area
11) Calcium Chloride, CaCl2, can be used instead of road salt to melt the ice on roads during the winter. To determine how much calcium chloride had been used on a nearby road, a student took a sample of slush to analyze. The sample had a mass of 23.47g. When the solution was evaporated, the residue had a mass of 4.58g (assume that no other solutes were present).
a) What was the mass/mass percent of calcium chloride in the slush
b) How many grams of calcium chloride were present in 100g solution?
Answers
Answer:
What is that? I do not understand
what is joules? plz help
Answers
what is the chemical formula of ( methane ) ??
Answers
[tex]\huge{ \color{violet}{ \boxed{ \color{hotpink}{Answer}}}}[/tex]
what is the chemical formula of ( methane ) ??
» CH4[tex] \: [/tex]
--⚘ Mishi ChaeYoon ⚘--Answer:
[tex]CH_4[/tex]
Explanation:
Methane is a chemical compound with the formula CH4. ( One atom of carbon and four atoms of hydrogen).
------------------------
OAmalOHopeO
------------------------
identify 2 ways to measure mass
Answers
Answer:
The two ways to measure mass are subtraction and taring.
What kinds of questions cannot be answered by chemistry
Answers
I think?
Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answers
Answer:
bubble and foam!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
akshaishsushsusisneysisj
why does copper Cu (I) have a short lifespan
Answers
Answer:
Copper (Cu), chemical element, a reddish, extremely ductile metal of Group 11 (Ib) of the periodic table that is an unusually good conductor of electricity and heat. Copper is found in the free metallic state in nature.
Explanation:
hope this helps:)
What is the correct clases for this drugs
Promethazine
heelp me please
Answers
Answer:
MedlinePlus Drugs Information
Explanation:
Promethazine is in a class of medication called phenothiazines
what is x if x - 2 =0
Answers
Answer:
x-2 = 0
x = 2
hope this was help full
Which pair of reactants for a Grignard reaction does not give 2-phenylbutan-2-ol after an aqueous workup?
