Hello please I need help

Answer:

hugsvsbsbbsnjsjsnsbsbbzbd

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[tex]\huge\mathfrak\purple{Hope \: it \: helps}[/tex]

Note : Because Many of My Dreams came true and I realized.

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what is the chemical formula of ( methane ) ??

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Answer:

[tex]CH_4[/tex]

Explanation:

Methane is a chemical compound with the formula CH4. ( One atom of carbon and four atoms of hydrogen).

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Answer:

What is that? I do not understand

Answer:

The two ways to measure mass are subtraction and taring.

Answer:

[tex]2.5\; \rm g[/tex] of [tex]\rm CaCO_{3}[/tex] would contain:

Explanation:

Look up the Avogadro constant: [tex]N_{\rm A} \approx 6.022 \times 10^{23}\; \rm mol^{-1}[/tex].

For example, "[tex]1\; \rm mol[/tex] of carbon atoms" would contain [tex]N_{\rm A}[/tex] carbon atoms (approximately [tex]6.022\times 10^{23}[/tex]) by definition.

Look up the relative atomic mass of carbon, calcium, and oxygen on a modern periodic table:

In other words, the mass of [tex]1\; \rm mol[/tex] of calcium atoms would be [tex]40.078\; \rm g[/tex]. The mass of [tex]1\; \rm mol\![/tex] of carbon atoms would be [tex]12.011\; \rm g[/tex], and the mass of [tex]1\; \rm mol \!\![/tex] of oxygen atoms would be [tex]15.999\; \rm g[/tex].

As the formula [tex]\rm CaCO_{3}[/tex] suggests, every formula unit of this ionic compound includes one calcium atom, one carbon atom, and three oxygen atoms. The formula mass of [tex]\rm CaCO_{3}\![/tex] would give the mass of every mole of [tex]\rm CaCO_{3}\!\![/tex] formula units.

Calculate the formula mass of [tex]\rm CaCO_{3}[/tex] from the relative atomic mass data:

[tex]\begin{aligned} & M({\rm CaCO_{3}}) \\ =\; & 40.078\; \rm g \cdot mol^{-1} \\ & + 12.011\; \rm g \cdot mol^{-1} \\ & + 3 \times (15.999\; \rm g \cdot mol^{-1}) \\ =\; & 100.086\; \rm g \cdot mol^{-1}\end{aligned}[/tex].

Calculate the number of [tex]\rm CaCO_{3}[/tex] formula units in that [tex]2.5\; \rm g[/tex] of this compound:

[tex]\begin{aligned}& n({\rm CaCO_{3}}) \\ =\; & \frac{m({\rm CaCO_{3}})}{M({\rm CaCO_{3}})} \\ =\; & \frac{2.5\; \rm g}{100.086\; \rm g \cdot mol^{-1}} \\ \approx\; & 0.025\; \rm mol\end{aligned}[/tex].

In other words, [tex]2.5\; \rm g[/tex] of [tex]\rm CaCO_{3}[/tex] would contain approximately [tex]0.025\; \rm mol[/tex] [tex]\rm CaCO_{3}\![/tex] formula units.

Again, there are one calcium atom, one carbon atom, and one oxygen atom in every [tex]\rm CaCO_{3}[/tex] formula unit. That approximately [tex]0.025\; \rm mol[/tex] [tex]\rm CaCO_{3}\![/tex] formula units would thus contain:

Make use of the Avogadro constant to convert the numbers.

For example, the number of calcium atoms in that approximately [tex]0.025\; \rm mol[/tex] of calcium atoms would be:

[tex]\begin{aligned} & N({\text{calcium}) \\ = \; & n({\text{calcium}) \cdot N_{\rm A} \\ \approx \; & 0.025\; \rm mol \times 6.022\times 10^{23} \cdot mol^{-1} \\ \approx \; & 1.5 \times 10^{22} \end{aligned}[/tex].

Likewise, the number of carbon atoms in that approximately [tex]0.025\; \rm mol[/tex] of carbon atoms would be:

[tex]\begin{aligned} & N({\text{carbon}) \\ = \; & n({\text{carbon}) \cdot N_{\rm A} \\ \approx \; & 0.025\; \rm mol \times 6.022\times 10^{23} \cdot mol^{-1} \\ \approx \; & 1.5 \times 10^{22} \end{aligned}[/tex].

The number of oxygen atoms in that approximately [tex]0.075\; \rm mol[/tex] of oxygen atoms would be:

[tex]\begin{aligned} & N({\text{oxygen}) \\ = \; & n({\text{oxygen}) \cdot N_{\rm A} \\ \approx \; & 0.075\; \rm mol \times 6.022\times 10^{23} \cdot mol^{-1} \\ \approx \; & 4.5 \times 10^{22} \end{aligned}[/tex].

Answer:34.28 Degree celcius

Explanation:The heat given is equal to the change in temperature multiplied by the mass and the specific heat capacity

This gives the equation:Q=mc∆T

Where Q=184,m=7, specific heat capacity=4.184,∆T=X-28,

But ∆T=Final temperature (T'')-Initial temperature (T')

Therefore the equation becomes

184=7×4.184(X-28)

Solving the remaining linear equation gives you X as 34.28°C

Answer:

d

Explanation:

it just makes alot of sense and you got this

Oxygen is a gas that belongs to the chalcogen family and is a reactive non-metal. It is an element, molecule, or pure substance. Thus, option A is correct.

A pure substance is defined as a substance that cannot be physically separated into its constituent particles. They are known to have a definite and constant chemical composition. It can be a molecule, element, or compound.

An element is atomic species that cannot be broken into simple sub-particles by chemical processes. On the other hand, if an atomic element bonds to the same or different atom it forms a molecule.

Oxygen gas is an element composed of two atoms of oxygen and is a molecule as the two atoms are linked chemically. It is also a pure substance as it contains the same element.

Therefore, option A. oxygen gas is a pure substance, an element, and a molecule.

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Answer:

Reha should apply 540 N to lift Neha.

Explanation:

L = 360 N

LD  = 60 m

E =?

ED = 40m

NOW

L * LD = E * ED

360 *60 = E*40

21600/40 = E

540 N = E

Answer:

x-2 = 0

x = 2

hope this was help full

Answer:

in a 1 Liter flask at 850 K, the equilibrium concentration of NH3 is measured as 0.12 M. Given that ammonia decomposes according to the reaction

2 NH3(g) ⇌ N2(g) + 3 H2(g),

what is Kc for the reaction?

a. 0.16

b. 12.00

c. 1.44

d. 6.22

e. 0.75

The response is 12.00 (b). Using the equation Kc = [N2][H2]3/[NH3]2, we can find the equilibrium constant Kc for the reaction 2 NH3(g) N2(g) + 3 H2(g).

In this instance, the capacity of the flask is 1 litre, and the equilibrium concentration of NH3 is 0.12 M. Therefore, using the reaction's stoichiometry, it is possible to determine the equilibrium concentrations of N2 and H2.

Since 2 moles of NH3 break down into 1 mole of N2 and 3 moles of H2, the equilibrium concentrations of N2 and H2 are 0.06 M and 0.18 M, respectively. As a result, the equilibrium constant Kc = [N2][H2]3/[NH3]2 = (0.06)(0.18)3/0.122 = 12.00 may be computed.

Therefore, b. 12.00 is the right response. You should be aware that the equilibrium constant Kc is a value that is temperature-dependent and is only applicable at the specified temperature. As a result, Kc will have a varied value depending on the temperature. The temperature in this instance is 850 K, and the Kc value is 12.00.  

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Answer:

55/350

Explanation:

because the answer is in the middle of 50and 400

Answer:

c i think

Explanation:

Answer:

Precise

Explanation:

hope it helps!!!!!!!!

Answer:

MedlinePlus Drugs Information

Explanation:

Promethazine is in a class of medication called phenothiazines

Answer:

[tex]\boxed {\boxed {\sf 2.3 \ g/mL}}[/tex]

Explanation:

We are asked to find the density of a rock. Density is the substance's mass per unit volume. The formula for calculating density is:

[tex]\rho= \frac{m}{v}[/tex]

The mass of the rock is 23 grams. The volume was found using water displacement. A known amount of water was measured, the rock was added to the graduated cylinder, and the water level was recorded again. The volume is the difference between the final and initial water level. The graduated cylinder originally had 20 milliliters and the water rose to 30 milliliters.

Now we know the mass and the volume.

Substitute the values into the formula.

[tex]\rho= \frac{ 23 \ g }{30 \ mL}[/tex]

Divide.

[tex]\rho= 2.3 \ g/mL[/tex]

The density of the rock is 2.3 grams per milliliter.

Answer:

Lysosomes are predominantly found in eukaryotic animal cells and are responsible for breaking down cellular debris

Explanation:

Answer:

C. heat the substance to the boiling point.

Answer:

heat the substance

Explanation:

Answer:

the answer is mostly option a)XCl

Explanation:

Answer:

Copper (Cu), chemical element, a reddish, extremely ductile metal of Group 11 (Ib) of the periodic table that is an unusually good conductor of electricity and heat. Copper is found in the free metallic state in nature.

Explanation:

hope this helps:)

Answer:

The international system of units is basic on 7 units.

As illustrated from law of multiple proportion, the mass of the oxygen which combined with a fixed mass of the sulphur is in simple whole number ratio of 2 is to 3 (2:3).

The law of Multiple proportion states that when two elements combine to form more than one compound, the mass of the second element, which combines with a fixed mass of the first element, will always be ratios of small whole numbers.

To illustrate the law of multiple proportion from sulphur and oxygen, we use the given compounds.

The reaction of oxygen with sulphur to form SO₂ and SO₃:

[tex]S \ + \ O_2 \ -----> SO_2\\\\2SO_2 \ + \ O_2 \ ---> \ 2SO_3[/tex]

atomic mass of oxygen = 16 g

atomic mass of sulphur = 32 g

mass of sulphur = 32 g and mass of oxygen = (2x16) = 32 g

mass of sulphur = 32 g and mass of oxygen = (3 x 16) = 48 g

Notice, while mass of sulphur is constant, mass of oxygen changed.

The ratio of mass of oxygen in the given two compounds = 32g : 48g = 2:3

Thus, based on the law of multiple proportion, the mass of the oxygen which combined with a fixed mass of the sulphur is in simple whole number ratio of 2 is to 3 (2:3).

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Answer:

bubble and foam!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer:

Mixture is combination of two or more substances

Explanation:

The sugar would dissolve in water. You could then pour off the solution and wash the remaining sand with a bit more water. Heat the water to evaporate it from the sugar, and the two are separated.

Answer:

This is not a true solution because the colloidal dispersion is not completely homogeneous, and it does not have uniform properties throughout.

Explanation:

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